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EE201/MSE207 Lecture 16 Variational principle (Ch. 7) Only Sec. 7.1 Theorem: For an arbitrary | , the ground state energy satisfies inequality = Proof is simple. Let us expand =


  1. EE201/MSE207 Lecture 16 Variational principle (Ch. 7) Only Sec. 7.1 Theorem: For an arbitrary |πœ”βŒͺ , the ground state energy 𝐹 𝑕 satisfies inequality 𝐹 𝑕 ≀ πœ” 𝐼 πœ” = 〈 𝐼βŒͺ Proof is simple. Let us expand πœ” = π‘œ 𝑑 π‘œ |πœ” π‘œ βŒͺ . Then since 𝐹 π‘œ β‰₯ 𝐹 𝑕 , we get 𝐼 = π‘œ 𝑑 π‘œ 2 𝐹 π‘œ β‰₯ 𝐹 𝑕 π‘œ 𝑑 π‘œ 2 = 𝐹 𝑕 This theorem can be useful to estimate 𝐹 𝑕 (or at least to find an upper bound) Idea: Use trial wavefunctions |πœ”βŒͺ with many adjustable parameters and minimize 〈 𝐼βŒͺ . Hopefully min 〈 𝐼βŒͺ is close to 𝐹 𝑕 . Extensions of this method can also be used to find |πœ” 𝑕 βŒͺ , first-excited state energy and wavefunction (using subspace orthogonal to |πœ” 𝑕 βŒͺ ), second-excited state, etc.

  2. EE201/MSE207 Lecture 16 Band structure (back to Ch. 5) Band structure for electrons is a consequence of a periodic potential in a lattice (due to periodic arrangement of atoms). For simplicity let us consider 1D case π‘Š 𝑦 + 𝑏 = π‘Š(𝑦) (periodic with lattice constant 𝑏 ) Bloch’s theorem: If π‘Š 𝑦 + 𝑏 = π‘Š(𝑏) , then for an eigenstate of energy πœ”(𝑦 + 𝑏) = 𝑓 𝑗𝐿𝑏 πœ” 𝑦 (almost periodic, β€œ quasimomentum ” ℏ𝐿 ) Therefore πœ” 𝑦 = 𝑓 𝑗𝐿𝑦 πœ”(𝑦) , πœ” 𝑦 + 𝑏 = πœ”(𝑦) with periodic πœ”(𝑦) Proof Introduce displacement operator 𝐸 , so that 𝐸𝑔(𝑦) = 𝑔(𝑦 + 𝑏) . It commutes with Hamiltonian, 𝐸, 𝐼 = 0 , therefore common eigenfunctions. πœ” 𝑦 + 𝑏 = πœ‡ πœ” 𝑦 If πœ‡ β‰  1 , then πœ” would increase or decrease exponentially Therefore πœ‡ = 1 , can denote πœ‡ = 𝑓 𝑗𝐿𝑏 .

  3. Periodic boundary condition for Bloch’s theorem πœ”(𝑦 + 𝑏) = 𝑓 𝑗𝐿𝑏 πœ” 𝑦 β‡’ π‘Š 𝑦 + 𝑏 = π‘Š 𝑏 Usually people use periodic boundary condition in using Bloch’s theorem πœ” 𝑦 + 𝑂𝑏 = πœ”(𝑦) for 𝑂 β‹™ 1 atoms in a (1D) sample Why? Because it does not matter, but makes calculations simpler 𝐿 = 2πœŒπ‘œ 𝑂𝑏 , π‘œ = 0, Β±1, Β±2, … Then This gives 𝑂 different values of 𝐿 (the same 𝑓 𝑗𝐿𝑏 if Ξ”π‘œ = 𝑂 ): 𝑂 states in a band for 𝑂 atoms Since 𝑂 is very large, 𝐿 is almost continuous.

  4. Simple example: β€œDirac comb” 𝑂 β€œatoms” Dirac comb: 𝑂 π‘Š 𝑦 = 𝛽 π‘˜=1 πœ€(𝑦 βˆ’ π‘˜π‘) (wrapped around) βˆ’ ℏ 2 𝑒 2 πœ” 𝑦 + π‘Š 𝑦 πœ” 𝑦 = 𝐹 πœ” 𝑦 𝑒𝑦 2 2𝑛 0 < 𝑦 < 𝑏 β‡’ πœ” 𝑦 = 𝐡 sin(𝑙𝑦) + 𝐢 cos 𝑙𝑦 , 𝑙 = 2𝑛𝐹/ℏ From Bloch’s theorem we know that at βˆ’π‘ < 𝑦 < 0 , πœ” 𝑦 = 𝑓 βˆ’π‘—πΏπ‘ [𝐡 sin 𝑙(𝑦 + 𝑏) + 𝐢 cos 𝑙(𝑦 + 𝑏) ] 𝐢 = 𝑓 βˆ’π‘—πΏπ‘ [𝐡 sin 𝑙𝑏 + 𝐢 cos(𝑙𝑏)] πœ” 0 + 0 = πœ” 0 βˆ’ 0 β‡’ πœ” β€² 0 + 0 βˆ’ πœ” β€² 0 βˆ’ 0 = ( 2𝑛𝛽 ℏ 2 ) πœ”(0) β‡’ 𝑙𝐡 βˆ’ 𝑓 βˆ’π‘—πΏπ‘ [𝑙𝐡 cos 𝑙𝑏 βˆ’ 𝑙𝐢 sin(𝑙𝑏) ] = ( 2𝑛𝛽 ℏ 2 ) 𝐢 From these two equations we find (eliminating 𝐡 and 𝐢 ) cos 𝐿𝑏 = cos 𝑙𝑏 + 𝑛𝛽𝑏 sin(𝑙𝑏) ℏ 2 𝑙𝑏

  5. Dirac comb (cont.) 𝑂 π‘Š 𝑦 = 𝛽 π‘˜=1 πœ€(𝑦 βˆ’ π‘˜π‘) cos 𝐿𝑏 = cos 𝑙𝑏 + 𝑛𝛽𝑏 sin(𝑙𝑏) ℏ 2 𝑙𝑏 𝑂 states 𝐿𝑏 = 2πœŒπ‘œ 𝑂 gap 𝑂 states gap gap gap gap 2 nd band 1 st band 3 rd band 𝑂 states 𝑛𝛽𝑏 = 10 ℏ 2 𝑂 states 𝑙𝑏 (∝ 𝐹) 𝑂 states per band ( Γ— 2 spin) Gaps become smaller, eventually continuum

  6. Bands Gaps become smaller, eventually continuum If one electron per atom ( π‘Ÿ = 1 ), then half a band is filled (good conductor) If π‘Ÿ = 2 , then one band is filled completely (insulator or semiconductor; cannot slightly excite electrons) If π‘Ÿ = 3 , then 1.5 bands are filled (good conductor) If π‘Ÿ = 4 , then again insulator or semiconductor Etc. Metals usually have π‘Ÿ = 1 𝑂 states per band ( Γ— 2 spin)

  7. Bands (cont.) ∝ 𝐹 cos 𝐿𝑏 = . . . ℏ𝐿 is quasimomentum (behaves as momentum) βˆ’πœŒ/𝑏 𝜌/𝑏 2𝜌/𝑏 (Brillouin zone) Periodic: 2𝜌/𝑏 𝐹 = ℏ 2 𝑙 2 For a free particle 2𝑛 Define effective mass 𝑛 eff via Δ𝐹 = ℏ 2 𝐿 2 Δ𝐹 = ℏ 2 (Δ𝐿) 2 or even 2𝑛 eff 2𝑛 eff 𝑒𝐿 2 = ℏ 2 𝑒 2 𝐹 (similar to bands in semiconductors) or even 𝑛 eff

  8. Quasimomentum ℏ𝐿 behaves as momentum Let us add small force 𝐺 (e.g., due to electric field acting on electron, 𝐺 = βˆ’π‘“β„° ). Then Ξ”π‘Š = βˆ’πΊπ‘¦ and therefore 𝐹 β†’ 𝐹 βˆ’ 𝐺𝑦 (for the same 𝐿 ). From Bloch’s theorem we know πœ” 𝑦 = 𝑓 𝑗𝐿𝑦 πœ” 𝐿 (𝑦) ∝ 𝑓 𝑗𝐿𝑦 on the large scale Adding time dependence, we get (on the large scale) Ξ¨ 𝑦, 𝑒 ∝ 𝑓 𝑗𝐿𝑦 𝑓 βˆ’π‘— πΉβˆ’πΊπ‘¦ 𝑒 = 𝑓 𝑗 𝐿+ 𝐺𝑒 ℏ 𝑦 𝑓 βˆ’π‘—πΉπ‘’/ℏ ℏ 𝐿 β†’ 𝐿 + 𝐺 𝑒(ℏ𝐿) ℏ 𝑒 β‡’ = 𝐺 It means 𝑒𝑒 We see that ℏ𝐿 behaves as momentum (so named quasimomentum) (for validity of this approach we need very small 𝐺 ) Actually, significant oversimplification in this approach; this rather a hint. 𝑒 β€² ℏ) 𝑒𝑒 β€² 𝑒 𝐹(𝐿+𝐺 𝐺𝑒 ℏ)𝑦 𝑓 βˆ’ 𝑗 ℏ 𝑓 𝑗(𝐿+ πœ” 𝐿+𝐺 𝑒 ℏ (𝑦) More rigorously, 0 is an approximate solution of SE (straightforward to check). Also, makes sense for energy change: 𝐺𝑀 𝑕𝑠 = ℏ 𝑒𝐿 ℏ 𝑒𝐿 = 𝑒𝐹 𝑒𝐹 𝑒𝑒 . 𝑒𝑒

  9. End of material included into the final exam Following lectures are important, but not needed for the exam

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