SLIDE 24 Result
¯ c) = lim r→∞ 2π
⇣ 2πmφ ¯ φ(0)r3 ¯ φ(r) ˆ f (σ) (r) ⌘1/2
∞
Y
J=1/2
B @ J ¯ φ(0)f (η)
J (r)
⇣ f (T )
J
(r) ⌘2 mφr ¯ φ(r) ˆ f (σ)
J
(r) ⇣ ˆ f (T )
J
(r) ⌘2 1 C A
−(2J+1)2/2
A(Aµ,ϕ) =
∞
Y
J=0
det M(S,L,ϕ)
J
det c M(S,L,ϕ)
J
!−(2J+1)2/2 det M(T )
J
det c M(T )
J
!−(2J+1)2
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MS = ln VG +
MS ,
MS =
1 3 + 2g2 |λ| + g4 |λ|2 1 + γE + ln µR 2
|λ|2 31 3 − π2
4 − 1 3γE − 2 ln AG − 1 2 ln |λ| 8 + 1 2 ln π − 3 2Sσ(zg) − 3 2 ln Γ(1 − zg)Γ(2 + zg). (
We can calculate it analytically with the MS-bar renormalization! [A. Andreassen, W. Frost, M. D. Schwartz; ’17, S. Chigusa, T. Moroi, YS; ’18]