three
play

three what is the scale? what is the size in a particular - PowerPoint PPT Presentation

A RCHITECTURAL S TRUCTURES : Structural Math F ORM, B EHAVIOR, AND D ESIGN ARCH 331 quantify environmental loads D R. A NNE N ICHOLS how big is it? S PRING 2019 evaluate geometry and angles lecture where is it? three what is


  1. A RCHITECTURAL S TRUCTURES : Structural Math F ORM, B EHAVIOR, AND D ESIGN ARCH 331 • quantify environmental loads D R. A NNE N ICHOLS – how big is it? S PRING 2019 • evaluate geometry and angles lecture – where is it? three – what is the scale? – what is the size in a particular direction? • quantify what happens in the structure forces and – how big are the internal forces? – how big should the beam be? moments Forces & Moments 1 Architectural Structures F2009abn Lecture 3 ARCH 331 Structural Planning 32 Foundations Structures F2008abn Lecture 3 ARCH 331 Physics for Structures Structural Math • measures • physics takes observable phenomena and relates the measurement with rules: – US customary & SI mathematical relationships • need Units US SI Length in, ft, mi mm, cm, m – reference frame Volume gallon liter – measure of length, mass, time, direction, Mass lb mass g, kg velocity, acceleration, work, heat, Force lb force N, kN electricity, light Temperature F C – calculations & geometry Structural Planning 34 Foundations Structures F2008abn Structural Planning 33 Foundations Structures F2008abn Lecture 3 ARCH 331 Lecture 3 ARCH 331 1

  2. Physics for Structures Language • scalars – any quantity • symbols for operations: +,-, /, x • symbols for relationships: (), =, <, > • vectors - quantities with direction • algorithms   – like displacements 2 5 2 2 1     – cancellation    – summation results in 5 6 6 2 3 3 – factors the “ straight line path ” x 1 6  – signs from start to end 3 – ratios and proportions y 10 3  – normal vector is perpendicular to – power of a number 1000 something – conversions, ex. 1X = 10 Y 10 Y 1 X  or 1 – operations on both sides of equality z 1 X 10 Y x Structural Planning 35 Foundations Structures F2008abn Structural Planning 36 Foundations Structures F2008abn Lecture 3 ARCH 331 Lecture 3 ARCH 331 On-line Practice Geometry • eCampus / Study Aids • angles – right = 90º – acute < 90º – obtuse > 90º –  = 180º • triangles B b  h  – area 2 A C – hypotenuse   2 2 2 AB AC BC – total of angles = 180º Structural Planning 37 Architectural Structures F2008abn Structural Planning 38 Foundations Structures F2008abn Lecture 3 ARCH 331 Lecture 3 ARCH 331 2

  3. Geometry Geometry • lines and relation to angles – intersection of a line with    parallel lines results in identical  – parallel lines can ’ t intersect   angles   – perpendicular lines cross at 90º – two lines intersect in the same – intersection of two lines is a point way, the angles are identical – opposite angles are equal when    two lines cross     Structural Planning 39 Foundations Structures F2008abn Structural Planning 40 Foundations Structures F2008abn Lecture 3 ARCH 331 Lecture 3 ARCH 331 Geometry Geometry – sides of two angles are parallel and – sides of two angles bisect a right angle (90 ), the angles are complimentary intersect opposite way, the angles are supplementary - the sum is 180°      90      – right angle bisects a straight line, – two angles that sum to 90° are said to be remaining angles complimentary are complimentary        90   Structural Planning 41 Foundations Structures F2008abn Forces & Moments 12 Foundations Structures F2009abn Lecture 3 ARCH 331 Lecture 3 ARCH 331 3

  4. Geometry Trigonometry – similar triangles have proportional sides • for right triangles B A AB AC BC   opposite side AB     sin sin AD AE DE C hypotenuse CB  B E C A  A adjacent side AC     D  cos cos hypotenuse CB A C   AB AC BC   opposite side AB            tan tan A B A C B C  adjacent side AC   C B SOHCAHTOA B  Structural Planning 43 Foundations Structures F2008abn Structural Planning 44 Foundations Structures F2008abn Lecture 3 ARCH 331 Lecture 3 ARCH 331 Trigonometry Trigonometry • cartesian coordinate system • for angles starting at positive x – sin is y side – origin at 0,0 Y Y 6 – cos is x side 6 – coordinates 5 5 4 4 in (x,y) pairs Quadrant II Quadrant I 3 3 2 2 – x & y have sin<0 for 180-360° 1 1 cos<0 for 90-270° 0 X 0 signs X -6 -5 -4 -3 -2 -1 -1 0 1 2 3 4 5 6 -1 tan<0 for 90-180° -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 -2 -2 tan<0 for 270-360° -3 -3 Quadrant III Quadrant IV -4 -4 -5 -5 -6 -6 Structural Planning 46 Foundations Structures F2008abn Structural Planning 45 Foundations Structures F2008abn Lecture 3 ARCH 331 Lecture 3 ARCH 331 4

  5. Trigonometry Algebra • equations (something = something) • for all triangles  C • constants – sides A, B & C are opposite B angles  ,  &   – real numbers or shown with a, b, c...  • unknown terms, variables A – LAW of SINES – names like R, F, x, y    sin sin sin   • linear equations A B C – unknown terms have no exponents – LAW of COSINES • simultaneous equations     2 2 2 A B C 2 BC cos – variable set satisfies all equations Structural Planning 47 Foundations Structures F2008abn Structural Planning 48 Foundations Structures F2008abn Lecture 3 ARCH 331 Lecture 3 ARCH 331 Algebra Algebra • solving one equation • solving one equations – only works with one variable – only works with one variable      – ex: – ex: 2 x 1 0 2 x 1 4 x 5     2 1 1 0 1 x • add to both sides • subtract from both sides 2       x 1 2 x 1 2 x 4 x 5 2 x  x • divide both sides • subtract from both sides 2 1        1 5 2 x 5 5 2 2      • get x by itself on a side  • divide both sides 6 3 2 2 x x 1   2   2 2 2 • get x by itself on a side   x 3 Structural Planning 49 Foundations Structures F2008abn Structural Planning 50 Foundations Structures F2008abn Lecture 3 ARCH 331 Lecture 3 ARCH 331 5

  6. Algebra Forces • solving two equation • statics – only works with two variables – physics of forces and reactions on bodies  y  – ex: 2 x 3 8 and systems  y  – equilibrium (bodies at rest) • look for term similarity 12 x 3 6 • can we add or subtract to eliminate one term? • forces – something that exerts on an object:      2 x 3 y 12 x 3 y 8 6 • add • motion 14  x 14 • tension 14 x 14 • get x by itself on a side    x 1 • compression 14 14 Structural Planning 51 Foundations Structures F2008abn Point Equilibrium 2 Foundations Structures F2008abn Lecture 3 ARCH 331 Lecture 4 ARCH 331 Force Force Characteristics • applied at a point • “ action of one body on another that affects the state of motion or rest of the • magnitude body ” – Imperial units: lb, k (kips) • Newton ’ s 3 rd law: – SI units: N (newtons), kN – for every force of action • direction there is an equal and opposite reaction along the same line (tail) (tip) http://www.physics.umd.edu Point Equilibrium 3 Foundations Structures F2008abn Point Equilibrium 4 Foundations Structures F2008abn Lecture 4 ARCH 331 Lecture 4 ARCH 331 6

  7. Forces on Rigid Bodies Transmissibility • for statics, the bodies are ideally rigid • the force stays on the same line of action • can translate • truck can ’ t tell the difference and rotate • internal forces are translate rotate – in bodies = – between bodies (connections) • external forces act on bodies • only valid for EXTERNAL forces Point Equilibrium 5 Foundations Structures F2008abn Point Equilibrium 6 Foundations Structures F2008abn Lecture 4 ARCH 331 Lecture 4 ARCH 331 Force System Types Force System Types • collinear • coplanar Point Equilibrium 7 Foundations Structures F2008abn Point Equilibrium 8 Foundations Structures F2008abn Lecture 4 ARCH 331 Lecture 4 ARCH 331 7

  8. Force System Types Adding Vectors • space • graphically – parallelogram law R • diagonal F • long for 3 or more vectors P – tip-to-tail • more convenient F R with lots of vectors P Point Equilibrium 9 Foundations Structures F2008abn Point Equilibrium 10 Foundations Structures F2008abn Lecture 4 ARCH 331 Lecture 4 ARCH 331 Force Components Trigonometry • convenient to resolve into 2 vectors • F x is negative   • at right angles – 90 to 270 Y 6 • F y is negative • in a “ nice ” coordinate system F 5 y 4   Quadrant II Quadrant I •  is between F x and F from F x – 180 to 360 3 F y 2  • tan is positive 1 x F x   F cos F x F F 0 X -1 F y – quads I & III -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 F y   -2 F sin F y -3 • tan is negative Quadrant III Quadrant IV -4   F x 2 2 F x F F F -5 x y – quads II & IV -6 F   y tan F Point Equilibrium 11 Foundations Structures F2008abn x Point Equilibrium 12 Foundations Structures F2008abn Lecture 4 ARCH 331 Lecture 4 ARCH 331 8

Download Presentation
Download Policy: The content available on the website is offered to you 'AS IS' for your personal information and use only. It cannot be commercialized, licensed, or distributed on other websites without prior consent from the author. To download a presentation, simply click this link. If you encounter any difficulties during the download process, it's possible that the publisher has removed the file from their server.

Recommend


More recommend