The unreasonable effectiveness of tensor product. Renaud - - PowerPoint PPT Presentation

the unreasonable effectiveness of tensor product
SMART_READER_LITE
LIVE PREVIEW

The unreasonable effectiveness of tensor product. Renaud - - PowerPoint PPT Presentation

The unreasonable effectiveness of tensor product. Renaud Coulangeon, Universit Bordeaux 1 based on a joint work with Gabriele Nebe Banff, November 14, 2011 Introduction Let L and M be two Euclidean lattices Introduction Let L and M be two


slide-1
SLIDE 1

The unreasonable effectiveness of tensor product.

Renaud Coulangeon, Université Bordeaux 1 based on a joint work with Gabriele Nebe Banff, November 14, 2011

slide-2
SLIDE 2

Introduction

Let L and M be two Euclidean lattices

slide-3
SLIDE 3

Introduction

Let L and M be two Euclidean lattices i.e. free Z-modules of finite rank equipped with a positive definite bilinear form (inner product) denoted x · y

slide-4
SLIDE 4

Introduction

Let L and M be two Euclidean lattices i.e. free Z-modules of finite rank equipped with a positive definite bilinear form (inner product) denoted x · y

◮ min L = min0x∈L x · x

slide-5
SLIDE 5

Introduction

Let L and M be two Euclidean lattices i.e. free Z-modules of finite rank equipped with a positive definite bilinear form (inner product) denoted x · y

◮ min L = min0x∈L x · x ◮ det L = det Gram B for any Z-basis B of M.

slide-6
SLIDE 6

Introduction

Let L and M be two Euclidean lattices i.e. free Z-modules of finite rank equipped with a positive definite bilinear form (inner product) denoted x · y

◮ min L = min0x∈L x · x ◮ det L = det Gram B for any Z-basis B of M.

On L ⊗ M consider the inner product

(x ⊗ y) · (z ⊗ t) = (x · z) (y · t) .

slide-7
SLIDE 7

Introduction

Let L and M be two Euclidean lattices i.e. free Z-modules of finite rank equipped with a positive definite bilinear form (inner product) denoted x · y

◮ min L = min0x∈L x · x ◮ det L = det Gram B for any Z-basis B of M.

On L ⊗ M consider the inner product

(x ⊗ y) · (z ⊗ t) = (x · z) (y · t) .

◮ det(L ⊗ M) = det Ldim M det Mdim L.

slide-8
SLIDE 8

Introduction

Let L and M be two Euclidean lattices i.e. free Z-modules of finite rank equipped with a positive definite bilinear form (inner product) denoted x · y

◮ min L = min0x∈L x · x ◮ det L = det Gram B for any Z-basis B of M.

On L ⊗ M consider the inner product

(x ⊗ y) · (z ⊗ t) = (x · z) (y · t) .

◮ det(L ⊗ M) = det Ldim M det Mdim L. ◮ min(L ⊗ M) = min L · min M ?

slide-9
SLIDE 9

Introduction

Let L and M be two Euclidean lattices i.e. free Z-modules of finite rank equipped with a positive definite bilinear form (inner product) denoted x · y

◮ min L = min0x∈L x · x ◮ det L = det Gram B for any Z-basis B of M.

On L ⊗ M consider the inner product

(x ⊗ y) · (z ⊗ t) = (x · z) (y · t) .

◮ det(L ⊗ M) = det Ldim M det Mdim L. ◮ min(L ⊗ M) = min L · min M ? NO in general (one has to

consider non-split vectors t

i=1 xi ⊗ yi for t > 1).

slide-10
SLIDE 10

Nevertheless, it is hard to find counter examples :

slide-11
SLIDE 11

Nevertheless, it is hard to find counter examples :

◮ min(L ⊗ M) = min L · min M if dim L or dim M is less than 43,

and the minimal vectors of min(L ⊗ M) are split (Kitaoka).

slide-12
SLIDE 12

Nevertheless, it is hard to find counter examples :

◮ min(L ⊗ M) = min L · min M if dim L or dim M is less than 43,

and the minimal vectors of min(L ⊗ M) are split (Kitaoka).

◮ The first dimension where a counter-example is known to exist

is 292 (non explicit !), unpublished result of Steinberg (see Milnor and Husemoller book Symmetric bilinear forms p.47).

slide-13
SLIDE 13

Nevertheless, it is hard to find counter examples :

◮ min(L ⊗ M) = min L · min M if dim L or dim M is less than 43,

and the minimal vectors of min(L ⊗ M) are split (Kitaoka).

◮ The first dimension where a counter-example is known to exist

is 292 (non explicit !), unpublished result of Steinberg (see Milnor and Husemoller book Symmetric bilinear forms p.47). Remark : If one considers the similar problem for the tensor product of (Hermitian) lattices over the ring of integers of an imaginary quadratic field, explicit examples with min (L ⊗OK M) < min L min M are relatively easy to construct in small dimension.

slide-14
SLIDE 14

Theorem (Korkine-Zolotareff, 1877)

Lattices achieving a local maximum of density are perfect.

slide-15
SLIDE 15

Theorem (Korkine-Zolotareff, 1877)

Lattices achieving a local maximum of density are perfect. In terms of positive definite quadratic forms :

slide-16
SLIDE 16

Theorem (Korkine-Zolotareff, 1877)

Lattices achieving a local maximum of density are perfect. In terms of positive definite quadratic forms : L = PZn

  • A = P′P ∈ Sn(R)>0
slide-17
SLIDE 17

Theorem (Korkine-Zolotareff, 1877)

Lattices achieving a local maximum of density are perfect. In terms of positive definite quadratic forms : L = PZn

  • A = P′P ∈ Sn(R)>0

min L = min A = min

0X∈Zn A[X]

slide-18
SLIDE 18

Theorem (Korkine-Zolotareff, 1877)

Lattices achieving a local maximum of density are perfect. In terms of positive definite quadratic forms : L = PZn

  • A = P′P ∈ Sn(R)>0

min L = min A = min

0X∈Zn A[X]

attained on a finite set S(A) of integral vectors

slide-19
SLIDE 19

Theorem (Korkine-Zolotareff, 1877)

Lattices achieving a local maximum of density are perfect. In terms of positive definite quadratic forms : L = PZn

  • A = P′P ∈ Sn(R)>0

min L = min A = min

0X∈Zn A[X]

attained on a finite set S(A) of integral vectors

Definition

A (resp. L) is perfect if Span XX′, X ∈ S(A) = Sn(R).

slide-20
SLIDE 20

Proposition

If dim L or dim M is less than 43, then L ⊗ M is not locally densest.

slide-21
SLIDE 21

Proposition

If dim L or dim M is less than 43, then L ⊗ M is not locally densest. Proof : set ℓ = dim L, m = dim M. Kitaoka’s result implies that the minimal vectors of L ⊗ M are split. Consequently, setting rL⊗M = dim Span (X ⊗ Y)(X ⊗ Y)′ , X ⊗ Y ∈ S(L ⊗ M) one has rL⊗M ≤ ℓ(ℓ + 1) 2 m(m + 1) 2

< ℓm(ℓm + 1)

2

.

slide-22
SLIDE 22

Proposition

If dim L or dim M is less than 43, then L ⊗ M is not locally densest. Proof : set ℓ = dim L, m = dim M. Kitaoka’s result implies that the minimal vectors of L ⊗ M are split. Consequently, setting rL⊗M = dim Span (X ⊗ Y)(X ⊗ Y)′ , X ⊗ Y ∈ S(L ⊗ M) one has rL⊗M ≤ ℓ(ℓ + 1) 2 m(m + 1) 2

< ℓm(ℓm + 1)

2

.

  • In particular, there is no hope to obtain extremal modular lattices in

this way.

slide-23
SLIDE 23

Tensor product of Hermitian lattices

K/Q an imaginary quadratic field, with ring of integers OK.

DK/Q (resp. dK) its different (resp. discriminant).

V ≃ K m endowed with a positive definite Hermitian form h. L a Hermitian lattice i.e. L = a1e1 ⊕ · · · ⊕ amem, where {e1, . . . , em} is a K-basis of V ≃ K m and the ais are fractional ideals in K. The discriminant of a pseudo-basis {e1, . . . , em} is det (h(ei, ej)). For any 1 ≤ r ≤ m = rankOK L we define dr(L) as the minimal discriminant of a free OK-sublattice of rank r of L. In particular, one has d1(L) = min(L) := min{h(v, v) | 0 v ∈ L}.

slide-24
SLIDE 24

The (Hermitian) dual of a Hermitian lattice L is defined as L# = y ∈ V | h(y, L) ⊂ OK

.

By restriction of scalars, an OK-lattice of rank m can be viewed as a Z-lattice of rank 2m, with inner product defined by x · y = TrK/Q h(x, y). The dual L∗ of L with respect to that inner product is linked to L# by L∗ = D−1

K/QL#.

The minimum of L, viewed as an ordinary Z-lattice, is twice its "Hermitian" minimum d1(L).

slide-25
SLIDE 25

Contrarily to the tensor product over Z, and rather surprisingly, the tensor product over imaginary quadratic fields has proved to be successful in constructing extremal lattices (see Bachoc-Nebe 1998).

slide-26
SLIDE 26

Contrarily to the tensor product over Z, and rather surprisingly, the tensor product over imaginary quadratic fields has proved to be successful in constructing extremal lattices (see Bachoc-Nebe 1998). Nevertheless, this happens only exceptionally :

slide-27
SLIDE 27

Contrarily to the tensor product over Z, and rather surprisingly, the tensor product over imaginary quadratic fields has proved to be successful in constructing extremal lattices (see Bachoc-Nebe 1998). Nevertheless, this happens only exceptionally : in general, the tensor product of Hermitian lattices fails to produce "dense" lattices (as does the tensor product of lattices over Z).

slide-28
SLIDE 28

Contrarily to the tensor product over Z, and rather surprisingly, the tensor product over imaginary quadratic fields has proved to be successful in constructing extremal lattices (see Bachoc-Nebe 1998). Nevertheless, this happens only exceptionally : in general, the tensor product of Hermitian lattices fails to produce "dense" lattices (as does the tensor product of lattices over Z). Any vector in a tensor product L ⊗OK M may be expressed as a sum

r

  • i=1

li ⊗ mi

  • f split vectors. The minimal number of summands in such an

expression is called the rank of z.

slide-29
SLIDE 29

Contrarily to the tensor product over Z, and rather surprisingly, the tensor product over imaginary quadratic fields has proved to be successful in constructing extremal lattices (see Bachoc-Nebe 1998). Nevertheless, this happens only exceptionally : in general, the tensor product of Hermitian lattices fails to produce "dense" lattices (as does the tensor product of lattices over Z). Any vector in a tensor product L ⊗OK M may be expressed as a sum

r

  • i=1

li ⊗ mi

  • f split vectors. The minimal number of summands in such an

expression is called the rank of z. The following proposition allows for an estimation of the minimal Hermitian norm of a tensor product L ⊗OK M:

slide-30
SLIDE 30

Proposition

Let L and M be Hermitian lattices. Then for any vector z ∈ L ⊗OK M

  • f rank r one has

h(z, z) ≥ r dr(L)1/rdr(M)1/r. (1)

slide-31
SLIDE 31

Proposition

Let L and M be Hermitian lattices. Then for any vector z ∈ L ⊗OK M

  • f rank r one has

h(z, z) ≥ r dr(L)1/rdr(M)1/r. (1) Moreover, a vector z of rank r in L ⊗OK M for which equality holds in (1) exists if and only if M and L contain minimal r-sections Mr and Lr such that Mr ≃ L#

r .

slide-32
SLIDE 32

Proposition

Let L and M be Hermitian lattices. Then for any vector z ∈ L ⊗OK M

  • f rank r one has

h(z, z) ≥ r dr(L)1/rdr(M)1/r. (1) Moreover, a vector z of rank r in L ⊗OK M for which equality holds in (1) exists if and only if M and L contain minimal r-sections Mr and Lr such that Mr ≃ L#

r .

Proof : Arithmetic-geometric mean inequality.

slide-33
SLIDE 33

An extremal unimodular lattice in dimension 72

From now on, K = Q[

√ −7] = Q[α], where α2 − α + 2 = 0 so that OK = Z[α].

slide-34
SLIDE 34

An extremal unimodular lattice in dimension 72

From now on, K = Q[

√ −7] = Q[α], where α2 − α + 2 = 0 so that OK = Z[α].

The Barnes lattice Pb is a Hermitian lattice of rank 3 over Z[α], with Hermitian Gram matrix

         

2

α −1 β

2

α −1 β

2

          .

slide-35
SLIDE 35

An extremal unimodular lattice in dimension 72

From now on, K = Q[

√ −7] = Q[α], where α2 − α + 2 = 0 so that OK = Z[α].

The Barnes lattice Pb is a Hermitian lattice of rank 3 over Z[α], with Hermitian Gram matrix

         

2

α −1 β

2

α −1 β

2

          .

Then Pb is Hermitian unimodular, Pb = P#

b and has Hermitian

minimum min(Pb) = 2

slide-36
SLIDE 36

An extremal unimodular lattice in dimension 72

From now on, K = Q[

√ −7] = Q[α], where α2 − α + 2 = 0 so that OK = Z[α].

The Barnes lattice Pb is a Hermitian lattice of rank 3 over Z[α], with Hermitian Gram matrix

         

2

α −1 β

2

α −1 β

2

          .

Then Pb is Hermitian unimodular, Pb = P#

b and has Hermitian

minimum min(Pb) = 2

as a Z-lattice, it is 6-dimensional, modular of level 7 and

minimum 4 (extremal).

slide-37
SLIDE 37

An extremal unimodular lattice in dimension 72

From now on, K = Q[

√ −7] = Q[α], where α2 − α + 2 = 0 so that OK = Z[α].

The Barnes lattice Pb is a Hermitian lattice of rank 3 over Z[α], with Hermitian Gram matrix

         

2

α −1 β

2

α −1 β

2

          .

Then Pb is Hermitian unimodular, Pb = P#

b and has Hermitian

minimum min(Pb) = 2

as a Z-lattice, it is 6-dimensional, modular of level 7 and

minimum 4 (extremal). Fact :

  • 1. d1(Pb) = 2.
  • 2. d2(Pb) = 2.
  • 3. d3(Pb) = 1.
slide-38
SLIDE 38

Michael Hentschel classified all Hermitian Z[α]-structures on the even unimodular Z-lattices of dimension 24.

slide-39
SLIDE 39

Michael Hentschel classified all Hermitian Z[α]-structures on the even unimodular Z-lattices of dimension 24.

exactly nine such Z[α] structures (Pi, h) (1 ≤ i ≤ 9) such that (Pi, traceZ[α]/Z ◦ h) Λ is the Leech lattice.

slide-40
SLIDE 40

Michael Hentschel classified all Hermitian Z[α]-structures on the even unimodular Z-lattices of dimension 24.

exactly nine such Z[α] structures (Pi, h) (1 ≤ i ≤ 9) such that (Pi, traceZ[α]/Z ◦ h) Λ is the Leech lattice. nine 36-dimensional Hermitian Z[α]-lattice Ri defined by

Ri := Pb ⊗Z[α] Pi

slide-41
SLIDE 41

Michael Hentschel classified all Hermitian Z[α]-structures on the even unimodular Z-lattices of dimension 24.

exactly nine such Z[α] structures (Pi, h) (1 ≤ i ≤ 9) such that (Pi, traceZ[α]/Z ◦ h) Λ is the Leech lattice. nine 36-dimensional Hermitian Z[α]-lattice Ri defined by

Ri := Pb ⊗Z[α] Pi so that (Ri, traceZ[α]/Z ◦ h) is an even unimodular lattice in dimension 72.

slide-42
SLIDE 42

Michael Hentschel classified all Hermitian Z[α]-structures on the even unimodular Z-lattices of dimension 24.

exactly nine such Z[α] structures (Pi, h) (1 ≤ i ≤ 9) such that (Pi, traceZ[α]/Z ◦ h) Λ is the Leech lattice. nine 36-dimensional Hermitian Z[α]-lattice Ri defined by

Ri := Pb ⊗Z[α] Pi so that (Ri, traceZ[α]/Z ◦ h) is an even unimodular lattice in dimension 72.

Theorem (C., Nebe, 2011)

The (Hermitian) minimum of the lattices Ri is either 3 or 4. The number of vectors of norm 3 in Ri is equal to the representation number of Pi for the sublattice Pb. In particular min(Ri) = 4 if and

  • nly if the Hermitian Leech lattice Pi does not contain a sublattice

isomorphic to Pb.

slide-43
SLIDE 43

Theorem (C., Nebe, 2011)

The (Hermitian) minimum of the lattices Ri is either 3 or 4. The number of vectors of norm 3 in Ri is equal to the representation number of Pi for the sublattice Pb. In particular min(Ri) = 4 if and

  • nly if the Hermitian Leech lattice Pi does not contain a sublattice

isomorphic to Pb.

slide-44
SLIDE 44

Theorem (C., Nebe, 2011)

The (Hermitian) minimum of the lattices Ri is either 3 or 4. The number of vectors of norm 3 in Ri is equal to the representation number of Pi for the sublattice Pb. In particular min(Ri) = 4 if and

  • nly if the Hermitian Leech lattice Pi does not contain a sublattice

isomorphic to Pb. Proof : One checks easily that d1(Ri) = 2 and d2(Ri) = 12 7 . Together with the values of d1(Pb) and d2(Pb) computed before, it shows that vectors of rank 1 and 2 have Hermitian norm at least 4. As for vectors of rank 3, one checks easily that they have norm at least 3, and the case of equality is analysed via the previous proposition.

slide-45
SLIDE 45

To summarize, one has, for each of the nine Hermitian structures P1, . . . , P9 of the Leech lattice over Z[α], the following alternative :

◮ either Pi contains a sublattice isometric to Pb, in which case

Ri := Pb ⊗Z[α] Pi is not extremal (min Ri = 3)

◮ or Pi does not contain any sublattice isometric to Pb, in which

case Ri := Pb ⊗Z[α] Pi is extremal (min Ri = 4)

slide-46
SLIDE 46

To summarize, one has, for each of the nine Hermitian structures P1, . . . , P9 of the Leech lattice over Z[α], the following alternative :

◮ either Pi contains a sublattice isometric to Pb, in which case

Ri := Pb ⊗Z[α] Pi is not extremal (min Ri = 3)

◮ or Pi does not contain any sublattice isometric to Pb, in which

case Ri := Pb ⊗Z[α] Pi is extremal (min Ri = 4) It turns out that exactly one (out of nine) of the Hermitian lattices P1, . . . , P9 is in the second case, giving rise to an extremal lattice.

slide-47
SLIDE 47

To summarize, one has, for each of the nine Hermitian structures P1, . . . , P9 of the Leech lattice over Z[α], the following alternative :

◮ either Pi contains a sublattice isometric to Pb, in which case

Ri := Pb ⊗Z[α] Pi is not extremal (min Ri = 3)

◮ or Pi does not contain any sublattice isometric to Pb, in which

case Ri := Pb ⊗Z[α] Pi is extremal (min Ri = 4) It turns out that exactly one (out of nine) of the Hermitian lattices P1, . . . , P9 is in the second case, giving rise to an extremal lattice. This step requires a rather heavy computation using MAGMA.

slide-48
SLIDE 48

To summarize, one has, for each of the nine Hermitian structures P1, . . . , P9 of the Leech lattice over Z[α], the following alternative :

◮ either Pi contains a sublattice isometric to Pb, in which case

Ri := Pb ⊗Z[α] Pi is not extremal (min Ri = 3)

◮ or Pi does not contain any sublattice isometric to Pb, in which

case Ri := Pb ⊗Z[α] Pi is extremal (min Ri = 4) It turns out that exactly one (out of nine) of the Hermitian lattices P1, . . . , P9 is in the second case, giving rise to an extremal lattice. This step requires a rather heavy computation using MAGMA. Question : can one find a more direct argument to prove that one

  • f the Pi, say P1, does not contain any sublattice isometric to Pb

while the eight others do ?

slide-49
SLIDE 49

Slopes of lattices, tensor product of semi-stable lattices.

L ⊂∈ Rn a lattice. We may assume, up to scaling, that det L = 1. The profile of L is defined as follows (Grayson ’84, Stuhler ’76):

slide-50
SLIDE 50

Slopes of lattices, tensor product of semi-stable lattices.

L ⊂∈ Rn a lattice. We may assume, up to scaling, that det L = 1. The profile of L is defined as follows (Grayson ’84, Stuhler ’76):

log det M dim M (0,0) (n,0) (1, log(min L))

for every primitive sublattice M of L, plot

(dim M, log det M)

slide-51
SLIDE 51

Slopes of lattices, tensor product of semi-stable lattices.

L ⊂∈ Rn a lattice. We may assume, up to scaling, that det L = 1. The profile of L is defined as follows (Grayson ’84, Stuhler ’76):

dim M log det M

for every primitive sublattice M of L, plot

(dim M, log det M)

add the vertical lines (0, ∞) and (n, ∞) and take the convex hull of the resulting set of points.

slide-52
SLIDE 52

Slopes of lattices, tensor product of semi-stable lattices.

L ⊂∈ Rn a lattice. We may assume, up to scaling, that det L = 1. The profile of L is defined as follows (Grayson ’84, Stuhler ’76):

dim M log det M

for every primitive sublattice M of L, plot

(dim M, log det M)

add the vertical lines (0, ∞) and (n, ∞) and take the convex hull of the resulting set of points. The profile of L is the polygonal boundary

  • f this convex hull.
slide-53
SLIDE 53

Slopes of lattices, tensor product of semi-stable lattices.

L ⊂∈ Rn a lattice. We may assume, up to scaling, that det L = 1. The profile of L is defined as follows (Grayson ’84, Stuhler ’76):

dim M log det M

for every primitive sublattice M of L, plot

(dim M, log det M)

add the vertical lines (0, ∞) and (n, ∞) and take the convex hull of the resulting set of points. The profile of L is the polygonal boundary

  • f this convex hull.

minimal slope = minM⊂L log det M dim M

slide-54
SLIDE 54

Slopes of lattices, tensor product of semi-stable lattices.

L ⊂∈ Rn a lattice. We may assume, up to scaling, that det L = 1. The profile of L is defined as follows (Grayson ’84, Stuhler ’76):

dim M log det M

for every primitive sublattice M of L, plot

(dim M, log det M)

add the vertical lines (0, ∞) and (n, ∞) and take the convex hull of the resulting set of points. The profile of L is the polygonal boundary

  • f this convex hull.

minimal slope = minM⊂L log det M dim M = log mink (dkL)1/k

slide-55
SLIDE 55

Slopes of lattices, tensor product of semi-stable lattices.

L ⊂∈ Rn a lattice. We may assume, up to scaling, that det L = 1. The profile of L is defined as follows (Grayson ’84, Stuhler ’76):

dim M log det M

for every primitive sublattice M of L, plot

(dim M, log det M)

add the vertical lines (0, ∞) and (n, ∞) and take the convex hull of the resulting set of points. The profile of L is the polygonal boundary

  • f this convex hull.

minimal slope = minM⊂L log det M dim M = log mink (dkL)1/k (dkL = minimal determinant of k-dimensional sublattices of L)

slide-56
SLIDE 56

From now on, we set

µ(L) = mink (dkL)1/k

slide-57
SLIDE 57

From now on, we set

µ(L) = mink (dkL)1/k

and we denote by κ(L) the set of k such that µ(L) = (dkL)1/k.

slide-58
SLIDE 58

From now on, we set

µ(L) = mink (dkL)1/k

and we denote by κ(L) the set of k such that µ(L) = (dkL)1/k. Examples :

dim M log det M

µ(L) = min L , κ(L) = 1.

slide-59
SLIDE 59

From now on, we set

µ(L) = mink (dkL)1/k

and we denote by κ(L) the set of k such that µ(L) = (dkL)1/k. Examples :

dim M log det M

µ(L) = min L , κ(L) = 1.

◮ If L is unimodular, µ(L) = det L.

slide-60
SLIDE 60

From now on, we set

µ(L) = mink (dkL)1/k

and we denote by κ(L) the set of k such that µ(L) = (dkL)1/k. Let Sk(L) be the set of minimal sublattices of dimension k of L.

slide-61
SLIDE 61

From now on, we set

µ(L) = mink (dkL)1/k

and we denote by κ(L) the set of k such that µ(L) = (dkL)1/k. Let Sk(L) be the set of minimal sublattices of dimension k of L.

Proposition (Grayson)

There exists a unique sublattice M0 of L such that

  • 1. (det M0)1/ det M0 = µ(L)
  • 2. M0 ⊃ Sk(L) for any k ∈ κ(L).
slide-62
SLIDE 62

From now on, we set

µ(L) = mink (dkL)1/k

and we denote by κ(L) the set of k such that µ(L) = (dkL)1/k. Let Sk(L) be the set of minimal sublattices of dimension k of L.

Proposition (Grayson)

There exists a unique sublattice M0 of L such that

  • 1. (det M0)1/ det M0 = µ(L)
  • 2. M0 ⊃ Sk(L) for any k ∈ κ(L).

When µ(L) = det L (i.e. M0 = L), we say that L is semi-stable.

slide-63
SLIDE 63

Conjecture (Bost)

For any lattices L and M, one has

µ(L ⊗ M) = µ(L)µ(M).

(equivalently the tensor product of semi-stable lattices is semi-stable)

slide-64
SLIDE 64

Conjecture (Bost)

For any lattices L and M, one has

µ(L ⊗ M) = µ(L)µ(M).

(equivalently the tensor product of semi-stable lattices is semi-stable)

◮ True if dim M + dim L < 5 (De Shalit, Parzanchevski, preprint

2006).

slide-65
SLIDE 65

Conjecture (Bost)

For any lattices L and M, one has

µ(L ⊗ M) = µ(L)µ(M).

(equivalently the tensor product of semi-stable lattices is semi-stable)

◮ True if dim M + dim L < 5 (De Shalit, Parzanchevski, preprint

2006).

◮ True if Aut M or Aut L acts irreducibly (Gaudron-Rémond,

preprint 2011).

slide-66
SLIDE 66

Conjecture (Bost)

For any lattices L and M, one has

µ(L ⊗ M) = µ(L)µ(M).

(equivalently the tensor product of semi-stable lattices is semi-stable)

◮ True if dim M + dim L < 5 (De Shalit, Parzanchevski, preprint

2006).

◮ True if Aut M or Aut L acts irreducibly (Gaudron-Rémond,

preprint 2011).

◮ For further information on this conjecture, see

Yves André On nef and semistable hermitian lattices, and their behaviour under tensor product

http://arxiv.org/abs/1008.1553