The QCD crossover
from Lattice QCD
July 25, 2018 Patrick Steinbrecher HotQCD collaboration
The QCD crossover from Lattice QCD July 25, 2018 Patrick - - PowerPoint PPT Presentation
The QCD crossover from Lattice QCD July 25, 2018 Patrick Steinbrecher HotQCD collaboration The QCD phase diagram July 25, 2018 Patrick Steinbrecher Slide 1 Quantum Chromodynamics from first principles #configurations m s /m l =27, N
July 25, 2018 Patrick Steinbrecher HotQCD collaboration
July 25, 2018 Patrick Steinbrecher Slide 1
from first principles
Lattice QCD
HISQ action Nσ = 4Nτ
physical quarks
2 light quarks 1 strange quark ms/ml = 27
mπ ≃ 138 MeV
10k 100k 1M 135 145 155 165 175 #configurations T [MeV] ms/ml=27, Nτ=16 12 8 6
July 25, 2018 Patrick Steinbrecher Slide 2
everything continuum extrapolated
subtracted condensate Σsub ≡ ms(Σu + Σd) − (mu + md)Σs with Σf = T V ∂ ∂mf ln Z subtracted susceptibility χsub ≡ T V ms ∂ ∂mu + ∂ ∂md
χdisc is defined as χsub without connected part
July 25, 2018 Patrick Steinbrecher Slide 3
d2 dT 2 Σsub f 4
K
≡ 0 and d dT χsub f 4
K
≡ 0
July 25, 2018 Patrick Steinbrecher Slide 4
two crossover temperatures: T0 (Σsub) and T0 (χsub)
for ml → 0: pseudo-critical temperatures converge to the chiral transition temperature T 0
c
at finite quark mass it is given by maximum of O(4) universal scaling functions (Thursday talk, Sheng-Tai Li, Chiral phase transition) χm = m1/δ−1
l
fχ(z) + reg. χt = m(β−1)/βδ
l
f ′
G(z) + reg.
for ml → 0
χt ∼ ∂TΣsub and χt ∼ ∂2
µBΣsub
χm ∼ χsub and χm ∼ χdisc
July 25, 2018 Patrick Steinbrecher Slide 5 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4
1 2 3 z ∼ (T-Tc
0)/ml 1/(β δ)
O(4): fχ(z) f’G(z)
50 100 150 200 250 135 145 155 165 175 χsub/fk
4
T [MeV] ms/ml=27, Nτ=16 12 8 6
July 25, 2018 Patrick Steinbrecher Slide 6
50 100 150 200 250 135 145 155 165 175 χsub/fk
4
T [MeV] ms/ml=27, Nτ=16 12 8 6
July 25, 2018 Patrick Steinbrecher Slide 6
0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 135 145 155 165 175 µQ=µS=0
Σ/2
T [MeV] ms/ml=27, Nτ=12 8 6
July 25, 2018 Patrick Steinbrecher Slide 7
HotQCD preliminary
20 40 60 80 100 120 135 145 155 165 175
Σ/dT
T [MeV] ms/ml=27, Nτ=12 6 8
July 25, 2018 Patrick Steinbrecher Slide 8
HotQCD preliminary
150 152 154 156 158 160 162 164 166 c
t i n u u m N
τ
= 1 6 N
τ
= 1 2 N
τ
= 8 N
τ
= 6
HotQCD preliminary
Tc(µB=0) [MeV] 1/Nτ
2
χdisc χsub Σsub ∂µB
2 Σsub
∂µB
2 χdisc
156.5 ± 1.5 MeV
July 25, 2018 Patrick Steinbrecher Slide 9
140 145 150 155 160 165 170 Σsub χdisc χsub ∂µB
2 Σ s u b
∂µB
2 χ d i s c
Σsub, Bonati2015 χtot, Bazavov2012 Σsub, Borsanyi2010 T0 [MeV]
July 25, 2018 Patrick Steinbrecher Slide 10 HotQCD preliminary
d2 dT 2 Σsub(T, µB) f 4
K
≡ 0 and d dT χdisc(T, µB) f 4
K
≡ 0
July 25, 2018 Patrick Steinbrecher Slide 11
need Taylor expansion in T and µB around (T0, 0)
(just notation)
simplest case µQ = µS = 0 subtracted condensate Σsub f 4
K
=
∞
cΣ
n
n! ˆ µn
B
with cΣ
n = ∂Σsub/f 4 K
∂ˆ µn
B
disconnected susceptibility χdisc f 4
K
=
∞
cχ
n
n! ˆ µn
B
with cχ
n = ∂χdisc/f 4 K
∂ˆ µn
B
July 25, 2018 Patrick Steinbrecher Slide 12
July 25, 2018 Patrick Steinbrecher Slide 13
135 145 155 165 175 nS=0, nQ/nB=0.4 c2
Σ/2
T [MeV] ms/ml=27, Nτ=12 8 6
10 20 30 135 145 155 165 175 nS=0, nQ/nB=0.4 T dc2
Σ/dT
T [MeV] ms/ml=27, Nτ=12 6 8
5 10 15 135 145 155 165 175 nS=0, nQ/nB=0.4 c2
χ/2
T [MeV] ms/ml=27, Nτ=12 8 6
500 1000 135 145 155 165 175 nS=0, nQ/nB=0.4 T dc2
χ/dT
T [MeV] ms/ml=27, Nτ=12 6 8 HotQCD preliminary HotQCD preliminary HotQCD preliminary HotQCD preliminary
Tc(µB) T0 = 1 − κ2 µB T0 2 − κ4 µB T0 4 + O(µ6
B)
Taylor expansion in µ and T of: d dT χdisc(T, µB) f 4
K
= (...)µ2
B + (...)µ4 B + ... = 0
has to be zero order by order κ2 = 1 2T 2 T0
∂cχ
2
∂T
2
∂2cχ ∂T 2
July 25, 2018 Patrick Steinbrecher Slide 14
0.005 0.01 0.015 0.02 0.025 0.005 0.01 0.015 0.02 0.025 0.03 0.035 nS=0, nQ/nB=0.4, ms/ml=27 1/Nτ
2
χdisc: κ2 κ4
HotQCD preliminary
July 25, 2018 Patrick Steinbrecher Slide 15
130 135 140 145 150 155 160 165 170 50 100 150 200 250 300 350 400 Tc [MeV] µB [MeV] nS=0, nQ/nB=0.4
HotQCD preliminary
crossover line: O(µB
4)
constant: ε s freeze-out: STAR ALICE
STAR: arxiv:1701.07065 ALICE: arxiv:1408.6403
0.005 0.01 0.015 0.02 Σsub χdisc Σsub, Bellwied2015 κ2 κ4 nS=0, nQ/nB=0.4
July 25, 2018 Patrick Steinbrecher Slide 16 HotQCD preliminary
Tc(µX) T0 = 1 − κX
2
µX T0 2 − κX
4
µX T0 4 + O(µ6
X)
0.000 0.010 0.020 0.030 0.040 X = B B nS=0 nQ/nB=0.4 S I Q
HotQCD preliminary
κ2
X
κ4
X July 25, 2018 Patrick Steinbrecher Slide 17 Bonati 2018: X = B, µS = 0 κ2 = 0.0145(25)
Baryon-number fluctuations σ2
B
Vf 3
K
= 1 Vf 3
K
∂ ln Z ∂ˆ µ2
B
=
∞
cB
n
n! ˆ µn
B
with cB
n =
1 Vf 3
K
∂ ln Z ∂ˆ µn+2
B
σ2
B couples to condensate −
→ diverges at a critical point study increase along the crossover line σ2
B(Tc(µB), µB) − σ2 B(T0, 0)
σ2
B(T0, 0)
= λ2 µB T0 2 + λ4 µB T0 4 + · · ·
July 25, 2018 Patrick Steinbrecher Slide 18
0.2 0.4 0.6 0.8 1 1.2 50 100 150 200 250 300 nS=0, nQ/nB=0.4 σB
2(Tc(µB),µB)/σB 2(T0,0) - 1
µB [MeV]
HotQCD preliminary
O(µB
4)
O(µB
2)
HRG
July 25, 2018 Patrick Steinbrecher Slide 19
0.2 0.4 0.6 50 100 150 200 250 300 nS=0, nQ/nB=0.4 χdisc(Tc(µB),µB)/χdisc(T0,0) - 1 µB [MeV]
HotQCD preliminary
O(µB
4)
O(µB
2)
20 40 60 80 100 135 145 155 165 175 185 195 nS=0, nQ/nB=0.4 χdisc/fk
4
T [MeV] Nτ=8, O(µB
6)
HotQCD preliminary
µB = 0.0 MeV 125.0 MeV 200.0 MeV
July 25, 2018 Patrick Steinbrecher Slide 20
σ2
B and χdisc show no indication for a narrowing crossover
e.g. expansion of the pressure around µB =0
(for µQ ≡ µS ≡ 0)
P T 4 =
1 n!χB
n ˆ
µn
B ,
χB
n =
1 VT 3 ∂n ln Z ∂ˆ µn
B
analysis of convergence radius can determine bound on the location of a critical point: r P
2n =
2n
χB
2n+2
, r χ
2n =
2n
χB
2n+2
if not → no critical point on real axis
July 25, 2018 Patrick Steinbrecher Slide 21
1 2 3 4 5 6 7 8 9 135 140 145 150 155 rn
χ -- estimator for µB crit/T
T [MeV]
2017: lower bound for r4
χ
estimator r2
χ
D’Elia et al., 2016, r4
χ
Datta et al., 2016 Fodor, Katz, 2004
1 2 3 4 5 6 7 8 9 135 140 145 150 155
r2
χ,HRG
disfavored region for the location of a critical point r4
χ,HRG
r6
χ,HRG
July 25, 2018 Patrick Steinbrecher Slide 22
crossover starts at T0 = 156.5 ± 1.5 MeV crossover curvature for strangeness neutral system
Tc(µB) T0
= 1 − κ2
T0
2 − κ4
T0
4 + O(µ6
B)
κ2 = 0.0123 ± 0.003 κ4 = 0.000131 ± 0.0041
for µB < 250 MeV and ns = 0, nQ/nB = 0.4
crossover along const. entropy density and energy density chemical freeze-out might be close to crossover no indication for critical point
July 25, 2018 Patrick Steinbrecher Slide 23
July 25, 2018 Patrick Steinbrecher Slide 24