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Splitting Kramers degeneracy with superconducting phase difference - - PowerPoint PPT Presentation
Splitting Kramers degeneracy with superconducting phase difference - - PowerPoint PPT Presentation
Splitting Kramers degeneracy with superconducting phase difference Bernard van Heck, Shuo Mi (Leiden), Anton Akhmerov (Delft) arXiv:1408.1563 ESI, Vienna, 11 September 2014 Plan Using phase difference in a Josephson junction as a means of
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Time reversal breaking in a mesoscopic JJ
Several manifestations:
◮ Splitting of Kramer’s degeneracy (Chtchelkatchev&Nazarov, B´ eri&Bardarson&Beenakker) ◮ Closing of the induced gap ◮ Protected zero energy level crossings (switches in the ground
state fermion parity) P = Pf(iH)
◮ Spectral peak in the DOS (Ivanov, Altland&Bagrets)
ρ(E) = ρ0
- 1 + sin(2πE/δ)
2πE/δ
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Setup and formalism
Scattering matrices of electrons and holes: Sh(−E) = S∗
e (E)
Andreev reflection matrix: rA = ieiφi Bound state condition: Se(E)rASh(E)r∗
Aψ = e−2i arccos(E/∆)ψ
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Setup and formalism
Scattering matrices of electrons and holes: Sh(−E) = S∗
e (E)
Andreev reflection matrix: rA = ieiφi Bound state condition: S(E)rAS∗(−E)r∗
Aψ = e−2i arccos(E/∆)ψ
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Short junction limit
S(E) ≈ S(0) Lowest density of Andreev states, strongest effect phase difference
- n a single state.
Due to unitarity and time reversal symmetry of S the energies are given by En = ±∆
- 1 − Tn sin2(φ/2) (Beenakker)
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Why it won’t work
◮ Splitting of Kramers degeneracy ◮ Closing of the gap
1 E/∆ DOS
◮ Protected zero energy level crossings (switches in the ground
state fermion parity)
◮ Spectral peak in the DOS
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Why it won’t work
◮ Splitting of Kramers degeneracy :-(
δE ∼ E 2/ET < ∆2/ET
◮ Closing of the gap
1 E/∆ DOS
◮ Protected zero energy level crossings (switches in the ground
state fermion parity)
◮ Spectral peak in the DOS
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Why it won’t work
◮ Splitting of Kramers degeneracy :-(
δE ∼ E 2/ET < ∆2/ET
◮ Closing of the gap :-(
|E| ≥ ∆ cos(φ/2)
1 E/∆ DOS
◮ Protected zero energy level crossings (switches in the ground
state fermion parity)
◮ Spectral peak in the DOS
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Why it won’t work
◮ Splitting of Kramers degeneracy :-(
δE ∼ E 2/ET < ∆2/ET
◮ Closing of the gap :-(
|E| ≥ ∆ cos(φ/2)
1 E/∆ DOS
◮ Protected zero energy level crossings (switches in the ground
state fermion parity) :-(
◮ Spectral peak in the DOS
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Why it won’t work
◮ Splitting of Kramers degeneracy :-(
δE ∼ E 2/ET < ∆2/ET
◮ Closing of the gap :-(
|E| ≥ ∆ cos(φ/2)
1 E/∆ DOS
◮ Protected zero energy level crossings (switches in the ground
state fermion parity) :-(
◮ Spectral peak in the DOS :-(
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A big improvement
All the special properties of the spectrum originate from the small number of leads!
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Kramers degeneracy splitting
Take a Rashba quantum dot with E ∼ ESO, R lSO, and λ R
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Kramers degeneracy splitting
Take a Rashba quantum dot with E ∼ ESO, R lSO, and λ R Calculate the splitting between the lowest two Andreev levels
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Kramers degeneracy splitting
Take a Rashba quantum dot with E ∼ ESO, R lSO, and λ R Calculate the splitting between the lowest two Andreev levels
π 2π φ1 π 2π φ2 0.2 δE/∆
Kramers degeneracy is strongly broken.
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Protected level crossings
Once again, try a random quantum dot:
π 2π φ1 π 2π φ2 1 Emin
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Protected level crossings
Once again, try a random quantum dot:
π 2π φ1 π 2π φ2 1 Emin
Level crossings are allowed.
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Protected level crossings
Are level crossings allowed for any (φ1, φ2)?
π 2π φ1 π 2π φ2 0.2 Podd
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Protected level crossings
Are level crossings allowed for any (φ1, φ2)?
π 2π φ1 π 2π φ2 0.2 Podd
No: the gap may only close when all the clockwise phase differences are smaller (or larger) than π.
(Note that this result holds for any junction)
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Proof
- 1. The expression for Andreev spectrum:
SrAS∗r∗
Aψ = ω2ψ,
E = ∆ Im ω
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Proof
- 1. The expression for Andreev spectrum:
SrAS∗r∗
Aψ = ω2ψ,
E = ∆ Im ω
- 2. The simplified expression for Andreev spectrum:
(SrA − rAST)ψ = 2eiα |E|
∆ ψ
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Proof
- 1. The expression for Andreev spectrum:
SrAS∗r∗
Aψ = ω2ψ,
E = ∆ Im ω
- 2. The simplified expression for Andreev spectrum:
(SrA − rAST)ψ = 2eiα |E|
∆ ψ
- 3. S = −ST due to time reversal.
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Proof
- 1. The expression for Andreev spectrum:
SrAS∗r∗
Aψ = ω2ψ,
E = ∆ Im ω
- 2. The simplified expression for Andreev spectrum:
(SrA − rAST)ψ = 2eiα |E|
∆ ψ
- 3. S = −ST due to time reversal.
- 4. This means Sψ ≡ ψ′,
S(rAψ) = 2|E|eiα
∆
ψ − (rAψ′)
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Proof
- 1. The expression for Andreev spectrum:
SrAS∗r∗
Aψ = ω2ψ,
E = ∆ Im ω
- 2. The simplified expression for Andreev spectrum:
(SrA − rAST)ψ = 2eiα |E|
∆ ψ
- 3. S = −ST due to time reversal.
- 4. This means Sψ ≡ ψ′,
S(rAψ) = 2|E|eiα
∆
ψ − (rAψ′)
- 5. The necessary and sufficient condition for existence of a
unitary S: ∃ψ, ψ′ : ψ| rA |ψ + ψ′| rA |ψ′ = 2|E|
∆
eiχ ψ′|ψ .
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Proof II
- 1. We get:
|E| ≥ 1
2 ∆ |ψ| rA |ψ + ψ′| rA |ψ′| .
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Proof II
- 1. We get:
|E| ≥ 1
2 ∆ |ψ| rA |ψ + ψ′| rA |ψ′| .
- 2. Graphical solution:
- 3. The lower bound on the gap:
E ≥ ∆ min
i,j cos φi−φj 2
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Gap closing and the spectral peak
Both phenomena are visible In the ensemble (averaging over random antisymmetric S)
0.0 0.2 0.4 0.6 0.8
ǫ/∆
10 20
ρ(ǫ) × ∆
RMT
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Gap closing and the spectral peak
Both phenomena are visible In the ensemble (averaging over random antisymmetric S)
0.0 0.2 0.4 0.6 0.8
ǫ/∆
10 20
ρ(ǫ) × ∆
RMT
In a single realization (averaging over chemical potential)
π 2π φ2 ≡ 2π − φ1 ∆ ǫ
Rashba dot, lso/R = 0.2, l/R = 0.4
ρ(ǫ) [a.u.]
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Conclusions
◮ Superconducting phase difference can strongly break time
reversal symmetry in a Josephson junction.
◮ This requires more than two superconducting leads. ◮ Spin degeneracy is split by a large fraction of ∆. ◮ The induced superconducting gap only closes in a a finite
subregion of the phase space.
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