Shocks and surprises Ed Corrigan Department of Mathematical - - PowerPoint PPT Presentation

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Shocks and surprises Ed Corrigan Department of Mathematical - - PowerPoint PPT Presentation

Shocks and surprises Ed Corrigan Department of Mathematical Sciences, Durham University Galileo Galilei Institute, Florence September 2008 Based on work with Peter Bowcock and Cristina Zambon: P . Bowcock, EC, C. Zambon, IJMPA 19 (Suppl)


slide-1
SLIDE 1

Shocks and surprises

Ed Corrigan

Department of Mathematical Sciences, Durham University

Galileo Galilei Institute, Florence September 2008

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SLIDE 2

Based on work with Peter Bowcock and Cristina Zambon:

  • P

. Bowcock, EC, C. Zambon, IJMPA 19 (Suppl) 2004 (Text of a talk at the Landau Institute 2002)

  • P

. Bowcock, EC, C. Zambon, JHEP 0401 2004

  • EC, C. Zambon, JPA 37L 2004
  • P

. Bowcock, EC, C. Zambon, JHEP 0508 2005

  • EC, C. Zambon, JHEP 0707 2007

See also

  • G. Delfino, G. Mussardo, P

. Simonetti, PLB 328 1994, NPB 432 1994

  • R. Konik, A. LeClair, NPB 538 1999

and, for an alternative algebraic setting

  • M. Mintchev, E. Ragoucy, P

. Sorba, PLB 547 2002

slide-3
SLIDE 3

Based on work with Peter Bowcock and Cristina Zambon:

  • P

. Bowcock, EC, C. Zambon, IJMPA 19 (Suppl) 2004 (Text of a talk at the Landau Institute 2002)

  • P

. Bowcock, EC, C. Zambon, JHEP 0401 2004

  • EC, C. Zambon, JPA 37L 2004
  • P

. Bowcock, EC, C. Zambon, JHEP 0508 2005

  • EC, C. Zambon, JHEP 0707 2007

See also

  • G. Delfino, G. Mussardo, P

. Simonetti, PLB 328 1994, NPB 432 1994

  • R. Konik, A. LeClair, NPB 538 1999

and, for an alternative algebraic setting

  • M. Mintchev, E. Ragoucy, P

. Sorba, PLB 547 2002

slide-4
SLIDE 4

Based on work with Peter Bowcock and Cristina Zambon:

  • P

. Bowcock, EC, C. Zambon, IJMPA 19 (Suppl) 2004 (Text of a talk at the Landau Institute 2002)

  • P

. Bowcock, EC, C. Zambon, JHEP 0401 2004

  • EC, C. Zambon, JPA 37L 2004
  • P

. Bowcock, EC, C. Zambon, JHEP 0508 2005

  • EC, C. Zambon, JHEP 0707 2007

See also

  • G. Delfino, G. Mussardo, P

. Simonetti, PLB 328 1994, NPB 432 1994

  • R. Konik, A. LeClair, NPB 538 1999

and, for an alternative algebraic setting

  • M. Mintchev, E. Ragoucy, P

. Sorba, PLB 547 2002

slide-5
SLIDE 5

Based on work with Peter Bowcock and Cristina Zambon:

  • P

. Bowcock, EC, C. Zambon, IJMPA 19 (Suppl) 2004 (Text of a talk at the Landau Institute 2002)

  • P

. Bowcock, EC, C. Zambon, JHEP 0401 2004

  • EC, C. Zambon, JPA 37L 2004
  • P

. Bowcock, EC, C. Zambon, JHEP 0508 2005

  • EC, C. Zambon, JHEP 0707 2007

See also

  • G. Delfino, G. Mussardo, P

. Simonetti, PLB 328 1994, NPB 432 1994

  • R. Konik, A. LeClair, NPB 538 1999

and, for an alternative algebraic setting

  • M. Mintchev, E. Ragoucy, P

. Sorba, PLB 547 2002

slide-6
SLIDE 6

Based on work with Peter Bowcock and Cristina Zambon:

  • P

. Bowcock, EC, C. Zambon, IJMPA 19 (Suppl) 2004 (Text of a talk at the Landau Institute 2002)

  • P

. Bowcock, EC, C. Zambon, JHEP 0401 2004

  • EC, C. Zambon, JPA 37L 2004
  • P

. Bowcock, EC, C. Zambon, JHEP 0508 2005

  • EC, C. Zambon, JHEP 0707 2007

See also

  • G. Delfino, G. Mussardo, P

. Simonetti, PLB 328 1994, NPB 432 1994

  • R. Konik, A. LeClair, NPB 538 1999

and, for an alternative algebraic setting

  • M. Mintchev, E. Ragoucy, P

. Sorba, PLB 547 2002

slide-7
SLIDE 7

Based on work with Peter Bowcock and Cristina Zambon:

  • P

. Bowcock, EC, C. Zambon, IJMPA 19 (Suppl) 2004 (Text of a talk at the Landau Institute 2002)

  • P

. Bowcock, EC, C. Zambon, JHEP 0401 2004

  • EC, C. Zambon, JPA 37L 2004
  • P

. Bowcock, EC, C. Zambon, JHEP 0508 2005

  • EC, C. Zambon, JHEP 0707 2007

See also

  • G. Delfino, G. Mussardo, P

. Simonetti, PLB 328 1994, NPB 432 1994

  • R. Konik, A. LeClair, NPB 538 1999

and, for an alternative algebraic setting

  • M. Mintchev, E. Ragoucy, P

. Sorba, PLB 547 2002

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SLIDE 8

Typical shock (or bore) in fluid mechanics:

  • eg flow flips from supersonic to subsonic,
  • eg abrupt change of depth in a channel.
  • Velocity field changes rapidly over a small distance,
  • Model by a discontinuity in v(x, t),
  • Nevertheless, there are conserved quantities - mass,

momentum, for example.

  • Are shocks allowed in integrable QFT?
  • If yes, what are their properties?
slide-9
SLIDE 9

Typical shock (or bore) in fluid mechanics:

  • eg flow flips from supersonic to subsonic,
  • eg abrupt change of depth in a channel.
  • Velocity field changes rapidly over a small distance,
  • Model by a discontinuity in v(x, t),
  • Nevertheless, there are conserved quantities - mass,

momentum, for example.

  • Are shocks allowed in integrable QFT?
  • If yes, what are their properties?
slide-10
SLIDE 10

Typical shock (or bore) in fluid mechanics:

  • eg flow flips from supersonic to subsonic,
  • eg abrupt change of depth in a channel.
  • Velocity field changes rapidly over a small distance,
  • Model by a discontinuity in v(x, t),
  • Nevertheless, there are conserved quantities - mass,

momentum, for example.

  • Are shocks allowed in integrable QFT?
  • If yes, what are their properties?
slide-11
SLIDE 11

Typical shock (or bore) in fluid mechanics:

  • eg flow flips from supersonic to subsonic,
  • eg abrupt change of depth in a channel.
  • Velocity field changes rapidly over a small distance,
  • Model by a discontinuity in v(x, t),
  • Nevertheless, there are conserved quantities - mass,

momentum, for example.

  • Are shocks allowed in integrable QFT?
  • If yes, what are their properties?
slide-12
SLIDE 12

Typical shock (or bore) in fluid mechanics:

  • eg flow flips from supersonic to subsonic,
  • eg abrupt change of depth in a channel.
  • Velocity field changes rapidly over a small distance,
  • Model by a discontinuity in v(x, t),
  • Nevertheless, there are conserved quantities - mass,

momentum, for example.

  • Are shocks allowed in integrable QFT?
  • If yes, what are their properties?
slide-13
SLIDE 13

Typical shock (or bore) in fluid mechanics:

  • eg flow flips from supersonic to subsonic,
  • eg abrupt change of depth in a channel.
  • Velocity field changes rapidly over a small distance,
  • Model by a discontinuity in v(x, t),
  • Nevertheless, there are conserved quantities - mass,

momentum, for example.

  • Are shocks allowed in integrable QFT?
  • If yes, what are their properties?
slide-14
SLIDE 14

Typical shock (or bore) in fluid mechanics:

  • eg flow flips from supersonic to subsonic,
  • eg abrupt change of depth in a channel.
  • Velocity field changes rapidly over a small distance,
  • Model by a discontinuity in v(x, t),
  • Nevertheless, there are conserved quantities - mass,

momentum, for example.

  • Are shocks allowed in integrable QFT?
  • If yes, what are their properties?
slide-15
SLIDE 15

Typical shock (or bore) in fluid mechanics:

  • eg flow flips from supersonic to subsonic,
  • eg abrupt change of depth in a channel.
  • Velocity field changes rapidly over a small distance,
  • Model by a discontinuity in v(x, t),
  • Nevertheless, there are conserved quantities - mass,

momentum, for example.

  • Are shocks allowed in integrable QFT?
  • If yes, what are their properties?
slide-16
SLIDE 16

Typical shock (or bore) in fluid mechanics:

  • eg flow flips from supersonic to subsonic,
  • eg abrupt change of depth in a channel.
  • Velocity field changes rapidly over a small distance,
  • Model by a discontinuity in v(x, t),
  • Nevertheless, there are conserved quantities - mass,

momentum, for example.

  • Are shocks allowed in integrable QFT?
  • If yes, what are their properties?
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SLIDE 17

Consider the x-axis with a shock located at x0 . . .

  • . . .

u(x, t) x0 v(x, t) How to sew the two fields together at x0? Expect, in a Lagrangian description, L(u, v) = θ(x0 − x)L(u) + θ(x − x0)L(v) + δ(x − x0)B(u, v), where B(u, v) could depend on u, v, ut, vt, . . . .

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SLIDE 18

Consider the x-axis with a shock located at x0 . . .

  • . . .

u(x, t) x0 v(x, t) How to sew the two fields together at x0? Expect, in a Lagrangian description, L(u, v) = θ(x0 − x)L(u) + θ(x − x0)L(v) + δ(x − x0)B(u, v), where B(u, v) could depend on u, v, ut, vt, . . . .

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SLIDE 19

Consider the x-axis with a shock located at x0 . . .

  • . . .

u(x, t) x0 v(x, t) How to sew the two fields together at x0? Expect, in a Lagrangian description, L(u, v) = θ(x0 − x)L(u) + θ(x − x0)L(v) + δ(x − x0)B(u, v), where B(u, v) could depend on u, v, ut, vt, . . . .

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SLIDE 20

Consider the x-axis with a shock located at x0 . . .

  • . . .

u(x, t) x0 v(x, t) How to sew the two fields together at x0? Expect, in a Lagrangian description, L(u, v) = θ(x0 − x)L(u) + θ(x − x0)L(v) + δ(x − x0)B(u, v), where B(u, v) could depend on u, v, ut, vt, . . . .

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SLIDE 21

Example: u, v are free Klein-Gordon fields with mass m B(u, v) = −λ 2uv + (ux + vx) 2 (u − v) leading to (∂2 + m2)u = x < 0 (∂2 + m2)v = x > 0 u = v x = x0 vx − ux = λu x = x0 This is a basic δ-impurity.

  • Typically, a δ-impurity has reflection and transmission;
  • For interacting fields, a δ-impurity is not, generally,

integrable (eg Goodman, Holmes and Weinstein, Physica D161 2002)

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SLIDE 22

Example: u, v are free Klein-Gordon fields with mass m B(u, v) = −λ 2uv + (ux + vx) 2 (u − v) leading to (∂2 + m2)u = x < 0 (∂2 + m2)v = x > 0 u = v x = x0 vx − ux = λu x = x0 This is a basic δ-impurity.

  • Typically, a δ-impurity has reflection and transmission;
  • For interacting fields, a δ-impurity is not, generally,

integrable (eg Goodman, Holmes and Weinstein, Physica D161 2002)

slide-23
SLIDE 23

Example: u, v are free Klein-Gordon fields with mass m B(u, v) = −λ 2uv + (ux + vx) 2 (u − v) leading to (∂2 + m2)u = x < 0 (∂2 + m2)v = x > 0 u = v x = x0 vx − ux = λu x = x0 This is a basic δ-impurity.

  • Typically, a δ-impurity has reflection and transmission;
  • For interacting fields, a δ-impurity is not, generally,

integrable (eg Goodman, Holmes and Weinstein, Physica D161 2002)

slide-24
SLIDE 24

Example: u, v are free Klein-Gordon fields with mass m B(u, v) = −λ 2uv + (ux + vx) 2 (u − v) leading to (∂2 + m2)u = x < 0 (∂2 + m2)v = x > 0 u = v x = x0 vx − ux = λu x = x0 This is a basic δ-impurity.

  • Typically, a δ-impurity has reflection and transmission;
  • For interacting fields, a δ-impurity is not, generally,

integrable (eg Goodman, Holmes and Weinstein, Physica D161 2002)

slide-25
SLIDE 25

Example: u, v are free Klein-Gordon fields with mass m B(u, v) = −λ 2uv + (ux + vx) 2 (u − v) leading to (∂2 + m2)u = x < 0 (∂2 + m2)v = x > 0 u = v x = x0 vx − ux = λu x = x0 This is a basic δ-impurity.

  • Typically, a δ-impurity has reflection and transmission;
  • For interacting fields, a δ-impurity is not, generally,

integrable (eg Goodman, Holmes and Weinstein, Physica D161 2002)

slide-26
SLIDE 26

Example: u, v are free Klein-Gordon fields with mass m B(u, v) = −λ 2uv + (ux + vx) 2 (u − v) leading to (∂2 + m2)u = x < 0 (∂2 + m2)v = x > 0 u = v x = x0 vx − ux = λu x = x0 This is a basic δ-impurity.

  • Typically, a δ-impurity has reflection and transmission;
  • For interacting fields, a δ-impurity is not, generally,

integrable (eg Goodman, Holmes and Weinstein, Physica D161 2002)

slide-27
SLIDE 27

Example: u, v are free Klein-Gordon fields with mass m B(u, v) = −λ 2uv + (ux + vx) 2 (u − v) leading to (∂2 + m2)u = x < 0 (∂2 + m2)v = x > 0 u = v x = x0 vx − ux = λu x = x0 This is a basic δ-impurity.

  • Typically, a δ-impurity has reflection and transmission;
  • For interacting fields, a δ-impurity is not, generally,

integrable (eg Goodman, Holmes and Weinstein, Physica D161 2002)

slide-28
SLIDE 28

Example: u, v are free Klein-Gordon fields with mass m B(u, v) = −λ 2uv + (ux + vx) 2 (u − v) leading to (∂2 + m2)u = x < 0 (∂2 + m2)v = x > 0 u = v x = x0 vx − ux = λu x = x0 This is a basic δ-impurity.

  • Typically, a δ-impurity has reflection and transmission;
  • For interacting fields, a δ-impurity is not, generally,

integrable (eg Goodman, Holmes and Weinstein, Physica D161 2002)

slide-29
SLIDE 29

Defects of shock-type

Start with a single selected point on the x-axis, say x = 0, and as before denote the field to the left of it (x < 0) by u, and to the right (x > 0) by v, with field equations in their respective domains: ∂2u = −∂U ∂u , x < 0 ∂2v = −∂V ∂v , x > 0

  • How can the fields be ‘sewn’ together in a manner preserving

integrability?

  • First, consider a simple argument and return to the general

question afterwards

slide-30
SLIDE 30

Defects of shock-type

Start with a single selected point on the x-axis, say x = 0, and as before denote the field to the left of it (x < 0) by u, and to the right (x > 0) by v, with field equations in their respective domains: ∂2u = −∂U ∂u , x < 0 ∂2v = −∂V ∂v , x > 0

  • How can the fields be ‘sewn’ together in a manner preserving

integrability?

  • First, consider a simple argument and return to the general

question afterwards

slide-31
SLIDE 31

Defects of shock-type

Start with a single selected point on the x-axis, say x = 0, and as before denote the field to the left of it (x < 0) by u, and to the right (x > 0) by v, with field equations in their respective domains: ∂2u = −∂U ∂u , x < 0 ∂2v = −∂V ∂v , x > 0

  • How can the fields be ‘sewn’ together in a manner preserving

integrability?

  • First, consider a simple argument and return to the general

question afterwards

slide-32
SLIDE 32
  • Potential problem: there is a distinguished point, translation

symmetry is lost and the conservation laws - at least some of them - (for example, momentum), are violated unless the impurity has the property of adding by compensating terms. Consider the field contributions to momentum: P = −

−∞

dx utux −

−∞

dx vtvx. Then, using the field equations, 2 ˙ P is given by = −

−∞

dx

  • u2

t + u2 x − 2U(u)

  • x −

∞ dx

  • v2

t + v2 x − 2V(v)

  • x

= −

  • u2

t + u2 x − 2U(u)

  • x=0 +
  • v2

t + v2 x − 2V(v)

  • x=0

= −2dPs dt (?).

slide-33
SLIDE 33
  • Potential problem: there is a distinguished point, translation

symmetry is lost and the conservation laws - at least some of them - (for example, momentum), are violated unless the impurity has the property of adding by compensating terms. Consider the field contributions to momentum: P = −

−∞

dx utux −

−∞

dx vtvx. Then, using the field equations, 2 ˙ P is given by = −

−∞

dx

  • u2

t + u2 x − 2U(u)

  • x −

∞ dx

  • v2

t + v2 x − 2V(v)

  • x

= −

  • u2

t + u2 x − 2U(u)

  • x=0 +
  • v2

t + v2 x − 2V(v)

  • x=0

= −2dPs dt (?).

slide-34
SLIDE 34
  • Potential problem: there is a distinguished point, translation

symmetry is lost and the conservation laws - at least some of them - (for example, momentum), are violated unless the impurity has the property of adding by compensating terms. Consider the field contributions to momentum: P = −

−∞

dx utux −

−∞

dx vtvx. Then, using the field equations, 2 ˙ P is given by = −

−∞

dx

  • u2

t + u2 x − 2U(u)

  • x −

∞ dx

  • v2

t + v2 x − 2V(v)

  • x

= −

  • u2

t + u2 x − 2U(u)

  • x=0 +
  • v2

t + v2 x − 2V(v)

  • x=0

= −2dPs dt (?).

slide-35
SLIDE 35

If there are ‘sewing’ conditions for which the last step is valid then P + Ps will be conserved, with Ps a function of u, v, and possibly derivatives, evaluated at x = 0. (Note: this does not happen for a δ-impurity.)

slide-36
SLIDE 36

If there are ‘sewing’ conditions for which the last step is valid then P + Ps will be conserved, with Ps a function of u, v, and possibly derivatives, evaluated at x = 0. (Note: this does not happen for a δ-impurity.)

slide-37
SLIDE 37

Next, consider the energy density and calculate ˙ E = [uxut]0 − [vxvt]0. Setting ux = vt + X(u, v), vx = ut + Y(u, v) we find ˙ E = utX − vtY. This is a total time derivative provided for some S X = −∂S ∂u , Y = ∂S ∂v . Then ˙ E = −dS dt , and E + S is conserved, with S a function of the fields evaluated at the shock.

slide-38
SLIDE 38

Next, consider the energy density and calculate ˙ E = [uxut]0 − [vxvt]0. Setting ux = vt + X(u, v), vx = ut + Y(u, v) we find ˙ E = utX − vtY. This is a total time derivative provided for some S X = −∂S ∂u , Y = ∂S ∂v . Then ˙ E = −dS dt , and E + S is conserved, with S a function of the fields evaluated at the shock.

slide-39
SLIDE 39

Next, consider the energy density and calculate ˙ E = [uxut]0 − [vxvt]0. Setting ux = vt + X(u, v), vx = ut + Y(u, v) we find ˙ E = utX − vtY. This is a total time derivative provided for some S X = −∂S ∂u , Y = ∂S ∂v . Then ˙ E = −dS dt , and E + S is conserved, with S a function of the fields evaluated at the shock.

slide-40
SLIDE 40

Next, consider the energy density and calculate ˙ E = [uxut]0 − [vxvt]0. Setting ux = vt + X(u, v), vx = ut + Y(u, v) we find ˙ E = utX − vtY. This is a total time derivative provided for some S X = −∂S ∂u , Y = ∂S ∂v . Then ˙ E = −dS dt , and E + S is conserved, with S a function of the fields evaluated at the shock.

slide-41
SLIDE 41

This argument strongly suggests that the only chance will be sewing conditions of the form ux = vt − ∂S ∂u , vx = ut + ∂S ∂v , where S depends on both fields evaluated at x = 0, leading to ˙ P = vt ∂S ∂u + ut ∂S ∂v − 1 2 ∂S ∂u 2 + 1 2 ∂S ∂v 2 + (U − V). This is a total time derivative provided the first piece is a perfect differential and the second piece vanishes. Thus, ∂S ∂u = −∂Ps ∂v , ∂S ∂v = −∂Ps ∂u ....

slide-42
SLIDE 42

This argument strongly suggests that the only chance will be sewing conditions of the form ux = vt − ∂S ∂u , vx = ut + ∂S ∂v , where S depends on both fields evaluated at x = 0, leading to ˙ P = vt ∂S ∂u + ut ∂S ∂v − 1 2 ∂S ∂u 2 + 1 2 ∂S ∂v 2 + (U − V). This is a total time derivative provided the first piece is a perfect differential and the second piece vanishes. Thus, ∂S ∂u = −∂Ps ∂v , ∂S ∂v = −∂Ps ∂u ....

slide-43
SLIDE 43

This argument strongly suggests that the only chance will be sewing conditions of the form ux = vt − ∂S ∂u , vx = ut + ∂S ∂v , where S depends on both fields evaluated at x = 0, leading to ˙ P = vt ∂S ∂u + ut ∂S ∂v − 1 2 ∂S ∂u 2 + 1 2 ∂S ∂v 2 + (U − V). This is a total time derivative provided the first piece is a perfect differential and the second piece vanishes. Thus, ∂S ∂u = −∂Ps ∂v , ∂S ∂v = −∂Ps ∂u ....

slide-44
SLIDE 44

.... and ∂2S ∂v2 = ∂2S ∂u2 , 1 2 ∂S ∂u 2 − 1 2 ∂S ∂v 2 = U(u) − V(v).

  • By setting S = f(u + v) + g(u − v) and differentiating the left

hand side of the functional equation with respect to u and v one finds: f ′′′g′ = g′′′f ′. If neither of f or g is constant we also have f ′′′ f ′ = g′′′ g′ = γ2, where γ is constant (possibly zero). Thus....

slide-45
SLIDE 45

.... and ∂2S ∂v2 = ∂2S ∂u2 , 1 2 ∂S ∂u 2 − 1 2 ∂S ∂v 2 = U(u) − V(v).

  • By setting S = f(u + v) + g(u − v) and differentiating the left

hand side of the functional equation with respect to u and v one finds: f ′′′g′ = g′′′f ′. If neither of f or g is constant we also have f ′′′ f ′ = g′′′ g′ = γ2, where γ is constant (possibly zero). Thus....

slide-46
SLIDE 46

.... and ∂2S ∂v2 = ∂2S ∂u2 , 1 2 ∂S ∂u 2 − 1 2 ∂S ∂v 2 = U(u) − V(v).

  • By setting S = f(u + v) + g(u − v) and differentiating the left

hand side of the functional equation with respect to u and v one finds: f ′′′g′ = g′′′f ′. If neither of f or g is constant we also have f ′′′ f ′ = g′′′ g′ = γ2, where γ is constant (possibly zero). Thus....

slide-47
SLIDE 47

.... and ∂2S ∂v2 = ∂2S ∂u2 , 1 2 ∂S ∂u 2 − 1 2 ∂S ∂v 2 = U(u) − V(v).

  • By setting S = f(u + v) + g(u − v) and differentiating the left

hand side of the functional equation with respect to u and v one finds: f ′′′g′ = g′′′f ′. If neither of f or g is constant we also have f ′′′ f ′ = g′′′ g′ = γ2, where γ is constant (possibly zero). Thus....

slide-48
SLIDE 48

....the possibilities for f, g are restricted to: f ′(u + v) = f1eγ(u+v) + f2e−γ(u+v) g′(u − v) = g1eγ(u−v) + g2e−γ(u−v), for γ = 0, and quadratic polynomials for γ = 0. Various choices

  • f the coefficients will provide sine-Gordon, Liouville, massless

free (γ = 0); or, massive free (γ = 0). In the latter case, setting U(u) = m2u2/2, V(v) = m2v2/2, the shock function S turns out to be S(u, v) = mσ 4 (u + v)2 + m 4σ(u − v)2, where σ is a free parameter.

slide-49
SLIDE 49

....the possibilities for f, g are restricted to: f ′(u + v) = f1eγ(u+v) + f2e−γ(u+v) g′(u − v) = g1eγ(u−v) + g2e−γ(u−v), for γ = 0, and quadratic polynomials for γ = 0. Various choices

  • f the coefficients will provide sine-Gordon, Liouville, massless

free (γ = 0); or, massive free (γ = 0). In the latter case, setting U(u) = m2u2/2, V(v) = m2v2/2, the shock function S turns out to be S(u, v) = mσ 4 (u + v)2 + m 4σ(u − v)2, where σ is a free parameter.

slide-50
SLIDE 50

....the possibilities for f, g are restricted to: f ′(u + v) = f1eγ(u+v) + f2e−γ(u+v) g′(u − v) = g1eγ(u−v) + g2e−γ(u−v), for γ = 0, and quadratic polynomials for γ = 0. Various choices

  • f the coefficients will provide sine-Gordon, Liouville, massless

free (γ = 0); or, massive free (γ = 0). In the latter case, setting U(u) = m2u2/2, V(v) = m2v2/2, the shock function S turns out to be S(u, v) = mσ 4 (u + v)2 + m 4σ(u − v)2, where σ is a free parameter.

slide-51
SLIDE 51
  • Note: there is a Lagrangian description of this type of ‘shock’:

L = θ(−x)L(u) + δ(x) uvt − utv 2 − S(u, v)

  • + θ(x)L(v)

The usual E-L equations provide both the field equations for u, v in their respective domains and the ’sewing’ conditions.

  • Note:

In the free case, with a wave incident from the left half-line u =

  • eikx + Re−ikx

e−iωt, v = Teikxe−iωt, ω2 = k2 + m2, we find: R = 0, T = − (iω − m sinh η) (ik + m cosh η), σ = e−η.

slide-52
SLIDE 52
  • Note: there is a Lagrangian description of this type of ‘shock’:

L = θ(−x)L(u) + δ(x) uvt − utv 2 − S(u, v)

  • + θ(x)L(v)

The usual E-L equations provide both the field equations for u, v in their respective domains and the ’sewing’ conditions.

  • Note:

In the free case, with a wave incident from the left half-line u =

  • eikx + Re−ikx

e−iωt, v = Teikxe−iωt, ω2 = k2 + m2, we find: R = 0, T = − (iω − m sinh η) (ik + m cosh η), σ = e−η.

slide-53
SLIDE 53
  • Note: there is a Lagrangian description of this type of ‘shock’:

L = θ(−x)L(u) + δ(x) uvt − utv 2 − S(u, v)

  • + θ(x)L(v)

The usual E-L equations provide both the field equations for u, v in their respective domains and the ’sewing’ conditions.

  • Note:

In the free case, with a wave incident from the left half-line u =

  • eikx + Re−ikx

e−iωt, v = Teikxe−iωt, ω2 = k2 + m2, we find: R = 0, T = − (iω − m sinh η) (ik + m cosh η), σ = e−η.

slide-54
SLIDE 54
  • Note: there is a Lagrangian description of this type of ‘shock’:

L = θ(−x)L(u) + δ(x) uvt − utv 2 − S(u, v)

  • + θ(x)L(v)

The usual E-L equations provide both the field equations for u, v in their respective domains and the ’sewing’ conditions.

  • Note:

In the free case, with a wave incident from the left half-line u =

  • eikx + Re−ikx

e−iωt, v = Teikxe−iωt, ω2 = k2 + m2, we find: R = 0, T = − (iω − m sinh η) (ik + m cosh η), σ = e−η.

slide-55
SLIDE 55
  • Note: there is a Lagrangian description of this type of ‘shock’:

L = θ(−x)L(u) + δ(x) uvt − utv 2 − S(u, v)

  • + θ(x)L(v)

The usual E-L equations provide both the field equations for u, v in their respective domains and the ’sewing’ conditions.

  • Note:

In the free case, with a wave incident from the left half-line u =

  • eikx + Re−ikx

e−iωt, v = Teikxe−iωt, ω2 = k2 + m2, we find: R = 0, T = − (iω − m sinh η) (ik + m cosh η), σ = e−η.

slide-56
SLIDE 56
  • Note: there is a Lagrangian description of this type of ‘shock’:

L = θ(−x)L(u) + δ(x) uvt − utv 2 − S(u, v)

  • + θ(x)L(v)

The usual E-L equations provide both the field equations for u, v in their respective domains and the ’sewing’ conditions.

  • Note:

In the free case, with a wave incident from the left half-line u =

  • eikx + Re−ikx

e−iωt, v = Teikxe−iωt, ω2 = k2 + m2, we find: R = 0, T = − (iω − m sinh η) (ik + m cosh η), σ = e−η.

slide-57
SLIDE 57

sine-Gordon

Choosing u, v to be sine-Gordon fields (and scaling the coupling and mass parameters to unity), we take: S(u, v) = 2

  • σ cos u + v

2 + σ−1 cos u − v 2

  • to find

x < x0 : ∂2u = − sin u, x > x0 : ∂2v = − sin v, x = x0 : ux = vt − σ sin u + v 2 − σ−1 sin u − v 2 , x = x0 : vx = ut + σ sin u + v 2 − σ−1 sin u − v 2 . The last two expressions are a Bäcklund transformation frozen at x = x0.

slide-58
SLIDE 58

sine-Gordon

Choosing u, v to be sine-Gordon fields (and scaling the coupling and mass parameters to unity), we take: S(u, v) = 2

  • σ cos u + v

2 + σ−1 cos u − v 2

  • to find

x < x0 : ∂2u = − sin u, x > x0 : ∂2v = − sin v, x = x0 : ux = vt − σ sin u + v 2 − σ−1 sin u − v 2 , x = x0 : vx = ut + σ sin u + v 2 − σ−1 sin u − v 2 . The last two expressions are a Bäcklund transformation frozen at x = x0.

slide-59
SLIDE 59

sine-Gordon

Choosing u, v to be sine-Gordon fields (and scaling the coupling and mass parameters to unity), we take: S(u, v) = 2

  • σ cos u + v

2 + σ−1 cos u − v 2

  • to find

x < x0 : ∂2u = − sin u, x > x0 : ∂2v = − sin v, x = x0 : ux = vt − σ sin u + v 2 − σ−1 sin u − v 2 , x = x0 : vx = ut + σ sin u + v 2 − σ−1 sin u − v 2 . The last two expressions are a Bäcklund transformation frozen at x = x0.

slide-60
SLIDE 60
  • What happens to a soliton when it encounters a shock of this

kind? Consider a soliton incident from x < 0 (any point will do), then it will not be possible to satisfy the sewing conditions (in general) unless a similar soliton emerges into the region x > 0. eiu/2 = 1 + iE 1 − iE , eiv/2 = 1 + izE 1 − izE , E = eax+bt+c, a = cosh θ, b = − sinh θ. Here z is to be determined. As previously, set σ = e−η.

  • We find

z = coth η − θ 2

  • .

This result has some intriguing consequences....

slide-61
SLIDE 61
  • What happens to a soliton when it encounters a shock of this

kind? Consider a soliton incident from x < 0 (any point will do), then it will not be possible to satisfy the sewing conditions (in general) unless a similar soliton emerges into the region x > 0. eiu/2 = 1 + iE 1 − iE , eiv/2 = 1 + izE 1 − izE , E = eax+bt+c, a = cosh θ, b = − sinh θ. Here z is to be determined. As previously, set σ = e−η.

  • We find

z = coth η − θ 2

  • .

This result has some intriguing consequences....

slide-62
SLIDE 62
  • What happens to a soliton when it encounters a shock of this

kind? Consider a soliton incident from x < 0 (any point will do), then it will not be possible to satisfy the sewing conditions (in general) unless a similar soliton emerges into the region x > 0. eiu/2 = 1 + iE 1 − iE , eiv/2 = 1 + izE 1 − izE , E = eax+bt+c, a = cosh θ, b = − sinh θ. Here z is to be determined. As previously, set σ = e−η.

  • We find

z = coth η − θ 2

  • .

This result has some intriguing consequences....

slide-63
SLIDE 63
  • What happens to a soliton when it encounters a shock of this

kind? Consider a soliton incident from x < 0 (any point will do), then it will not be possible to satisfy the sewing conditions (in general) unless a similar soliton emerges into the region x > 0. eiu/2 = 1 + iE 1 − iE , eiv/2 = 1 + izE 1 − izE , E = eax+bt+c, a = cosh θ, b = − sinh θ. Here z is to be determined. As previously, set σ = e−η.

  • We find

z = coth η − θ 2

  • .

This result has some intriguing consequences....

slide-64
SLIDE 64
  • What happens to a soliton when it encounters a shock of this

kind? Consider a soliton incident from x < 0 (any point will do), then it will not be possible to satisfy the sewing conditions (in general) unless a similar soliton emerges into the region x > 0. eiu/2 = 1 + iE 1 − iE , eiv/2 = 1 + izE 1 − izE , E = eax+bt+c, a = cosh θ, b = − sinh θ. Here z is to be determined. As previously, set σ = e−η.

  • We find

z = coth η − θ 2

  • .

This result has some intriguing consequences....

slide-65
SLIDE 65

Suppose θ > 0.

  • η < θ implies z < 0; ie the soliton emerges as an anti-soliton.
  • The final state will contain a discontinuity of magnitude 4π at

x = 0.

  • η = θ implies z = 0 and there is no emerging soliton.
  • The energy-momentum of the soliton is captured by the

‘defect’.

  • The eventual configuration will have a discontinuity of

magnitude 2π at x = 0.

  • η > θ implies z > 0; ie the soliton retains its character.

Thus, the ‘defect’ or ‘shock’ can be seen as a new feature within the sine-Gordon model.

slide-66
SLIDE 66

Suppose θ > 0.

  • η < θ implies z < 0; ie the soliton emerges as an anti-soliton.
  • The final state will contain a discontinuity of magnitude 4π at

x = 0.

  • η = θ implies z = 0 and there is no emerging soliton.
  • The energy-momentum of the soliton is captured by the

‘defect’.

  • The eventual configuration will have a discontinuity of

magnitude 2π at x = 0.

  • η > θ implies z > 0; ie the soliton retains its character.

Thus, the ‘defect’ or ‘shock’ can be seen as a new feature within the sine-Gordon model.

slide-67
SLIDE 67

Suppose θ > 0.

  • η < θ implies z < 0; ie the soliton emerges as an anti-soliton.
  • The final state will contain a discontinuity of magnitude 4π at

x = 0.

  • η = θ implies z = 0 and there is no emerging soliton.
  • The energy-momentum of the soliton is captured by the

‘defect’.

  • The eventual configuration will have a discontinuity of

magnitude 2π at x = 0.

  • η > θ implies z > 0; ie the soliton retains its character.

Thus, the ‘defect’ or ‘shock’ can be seen as a new feature within the sine-Gordon model.

slide-68
SLIDE 68

Suppose θ > 0.

  • η < θ implies z < 0; ie the soliton emerges as an anti-soliton.
  • The final state will contain a discontinuity of magnitude 4π at

x = 0.

  • η = θ implies z = 0 and there is no emerging soliton.
  • The energy-momentum of the soliton is captured by the

‘defect’.

  • The eventual configuration will have a discontinuity of

magnitude 2π at x = 0.

  • η > θ implies z > 0; ie the soliton retains its character.

Thus, the ‘defect’ or ‘shock’ can be seen as a new feature within the sine-Gordon model.

slide-69
SLIDE 69

Suppose θ > 0.

  • η < θ implies z < 0; ie the soliton emerges as an anti-soliton.
  • The final state will contain a discontinuity of magnitude 4π at

x = 0.

  • η = θ implies z = 0 and there is no emerging soliton.
  • The energy-momentum of the soliton is captured by the

‘defect’.

  • The eventual configuration will have a discontinuity of

magnitude 2π at x = 0.

  • η > θ implies z > 0; ie the soliton retains its character.

Thus, the ‘defect’ or ‘shock’ can be seen as a new feature within the sine-Gordon model.

slide-70
SLIDE 70

Suppose θ > 0.

  • η < θ implies z < 0; ie the soliton emerges as an anti-soliton.
  • The final state will contain a discontinuity of magnitude 4π at

x = 0.

  • η = θ implies z = 0 and there is no emerging soliton.
  • The energy-momentum of the soliton is captured by the

‘defect’.

  • The eventual configuration will have a discontinuity of

magnitude 2π at x = 0.

  • η > θ implies z > 0; ie the soliton retains its character.

Thus, the ‘defect’ or ‘shock’ can be seen as a new feature within the sine-Gordon model.

slide-71
SLIDE 71

Suppose θ > 0.

  • η < θ implies z < 0; ie the soliton emerges as an anti-soliton.
  • The final state will contain a discontinuity of magnitude 4π at

x = 0.

  • η = θ implies z = 0 and there is no emerging soliton.
  • The energy-momentum of the soliton is captured by the

‘defect’.

  • The eventual configuration will have a discontinuity of

magnitude 2π at x = 0.

  • η > θ implies z > 0; ie the soliton retains its character.

Thus, the ‘defect’ or ‘shock’ can be seen as a new feature within the sine-Gordon model.

slide-72
SLIDE 72

Suppose θ > 0.

  • η < θ implies z < 0; ie the soliton emerges as an anti-soliton.
  • The final state will contain a discontinuity of magnitude 4π at

x = 0.

  • η = θ implies z = 0 and there is no emerging soliton.
  • The energy-momentum of the soliton is captured by the

‘defect’.

  • The eventual configuration will have a discontinuity of

magnitude 2π at x = 0.

  • η > θ implies z > 0; ie the soliton retains its character.

Thus, the ‘defect’ or ‘shock’ can be seen as a new feature within the sine-Gordon model.

slide-73
SLIDE 73

Comments and questions....

  • The shock is local so there could be several shocks located at

x = x1 < x2 < x3 < · · · < xn; these behave independently each contributing a factor zi for a total ‘delay’ of z = z1z2 . . . zn.

  • When several solitons pass a defect each component is

affected separately

  • This means that at most one of them can be ‘filtered out’

(since the components of a multisoliton in the sine-Gordon model must have different rapidities).

  • Can solitons be controlled? (Eg see EC, Zambon, 2004.)
  • Since a soliton can be absorbed, can a starting configuration

with u = 0, v = 2π decay into a soliton?

  • No, there is no way to tell the time at which the decay would
  • ccur (and presumably quantum mechanics would be needed

to provide the probability of decay as a function of time).

slide-74
SLIDE 74

Comments and questions....

  • The shock is local so there could be several shocks located at

x = x1 < x2 < x3 < · · · < xn; these behave independently each contributing a factor zi for a total ‘delay’ of z = z1z2 . . . zn.

  • When several solitons pass a defect each component is

affected separately

  • This means that at most one of them can be ‘filtered out’

(since the components of a multisoliton in the sine-Gordon model must have different rapidities).

  • Can solitons be controlled? (Eg see EC, Zambon, 2004.)
  • Since a soliton can be absorbed, can a starting configuration

with u = 0, v = 2π decay into a soliton?

  • No, there is no way to tell the time at which the decay would
  • ccur (and presumably quantum mechanics would be needed

to provide the probability of decay as a function of time).

slide-75
SLIDE 75

Comments and questions....

  • The shock is local so there could be several shocks located at

x = x1 < x2 < x3 < · · · < xn; these behave independently each contributing a factor zi for a total ‘delay’ of z = z1z2 . . . zn.

  • When several solitons pass a defect each component is

affected separately

  • This means that at most one of them can be ‘filtered out’

(since the components of a multisoliton in the sine-Gordon model must have different rapidities).

  • Can solitons be controlled? (Eg see EC, Zambon, 2004.)
  • Since a soliton can be absorbed, can a starting configuration

with u = 0, v = 2π decay into a soliton?

  • No, there is no way to tell the time at which the decay would
  • ccur (and presumably quantum mechanics would be needed

to provide the probability of decay as a function of time).

slide-76
SLIDE 76

Comments and questions....

  • The shock is local so there could be several shocks located at

x = x1 < x2 < x3 < · · · < xn; these behave independently each contributing a factor zi for a total ‘delay’ of z = z1z2 . . . zn.

  • When several solitons pass a defect each component is

affected separately

  • This means that at most one of them can be ‘filtered out’

(since the components of a multisoliton in the sine-Gordon model must have different rapidities).

  • Can solitons be controlled? (Eg see EC, Zambon, 2004.)
  • Since a soliton can be absorbed, can a starting configuration

with u = 0, v = 2π decay into a soliton?

  • No, there is no way to tell the time at which the decay would
  • ccur (and presumably quantum mechanics would be needed

to provide the probability of decay as a function of time).

slide-77
SLIDE 77

Comments and questions....

  • The shock is local so there could be several shocks located at

x = x1 < x2 < x3 < · · · < xn; these behave independently each contributing a factor zi for a total ‘delay’ of z = z1z2 . . . zn.

  • When several solitons pass a defect each component is

affected separately

  • This means that at most one of them can be ‘filtered out’

(since the components of a multisoliton in the sine-Gordon model must have different rapidities).

  • Can solitons be controlled? (Eg see EC, Zambon, 2004.)
  • Since a soliton can be absorbed, can a starting configuration

with u = 0, v = 2π decay into a soliton?

  • No, there is no way to tell the time at which the decay would
  • ccur (and presumably quantum mechanics would be needed

to provide the probability of decay as a function of time).

slide-78
SLIDE 78

Comments and questions....

  • The shock is local so there could be several shocks located at

x = x1 < x2 < x3 < · · · < xn; these behave independently each contributing a factor zi for a total ‘delay’ of z = z1z2 . . . zn.

  • When several solitons pass a defect each component is

affected separately

  • This means that at most one of them can be ‘filtered out’

(since the components of a multisoliton in the sine-Gordon model must have different rapidities).

  • Can solitons be controlled? (Eg see EC, Zambon, 2004.)
  • Since a soliton can be absorbed, can a starting configuration

with u = 0, v = 2π decay into a soliton?

  • No, there is no way to tell the time at which the decay would
  • ccur (and presumably quantum mechanics would be needed

to provide the probability of decay as a function of time).

slide-79
SLIDE 79

Comments and questions....

  • The shock is local so there could be several shocks located at

x = x1 < x2 < x3 < · · · < xn; these behave independently each contributing a factor zi for a total ‘delay’ of z = z1z2 . . . zn.

  • When several solitons pass a defect each component is

affected separately

  • This means that at most one of them can be ‘filtered out’

(since the components of a multisoliton in the sine-Gordon model must have different rapidities).

  • Can solitons be controlled? (Eg see EC, Zambon, 2004.)
  • Since a soliton can be absorbed, can a starting configuration

with u = 0, v = 2π decay into a soliton?

  • No, there is no way to tell the time at which the decay would
  • ccur (and presumably quantum mechanics would be needed

to provide the probability of decay as a function of time).

slide-80
SLIDE 80

Comments and questions....

  • The shock is local so there could be several shocks located at

x = x1 < x2 < x3 < · · · < xn; these behave independently each contributing a factor zi for a total ‘delay’ of z = z1z2 . . . zn.

  • When several solitons pass a defect each component is

affected separately

  • This means that at most one of them can be ‘filtered out’

(since the components of a multisoliton in the sine-Gordon model must have different rapidities).

  • Can solitons be controlled? (Eg see EC, Zambon, 2004.)
  • Since a soliton can be absorbed, can a starting configuration

with u = 0, v = 2π decay into a soliton?

  • No, there is no way to tell the time at which the decay would
  • ccur (and presumably quantum mechanics would be needed

to provide the probability of decay as a function of time).

slide-81
SLIDE 81
  • Checking integrability

Adapt an idea from Bowcock, EC, Dorey, Rietdijk, 1995. Two regions overlapping the shock location: x > a, x < b with a < x0 < b. . . .

  • . . .

a b In each region, write down a Lax pair representation: ˆ a(a)

t

= a(a)

t

− 1 2θ(x − a)

  • ux − vt + ∂S

∂u

  • ˆ

a(a)

x

= θ(a − x)a(a)

x

ˆ a(b)

t

= a(b)

t

− 1 2θ(b − x)

  • vx − ut − ∂S

∂u

  • ˆ

a(b)

x

= θ(x − b)a(b)

x

slide-82
SLIDE 82
  • Checking integrability

Adapt an idea from Bowcock, EC, Dorey, Rietdijk, 1995. Two regions overlapping the shock location: x > a, x < b with a < x0 < b. . . .

  • . . .

a b In each region, write down a Lax pair representation: ˆ a(a)

t

= a(a)

t

− 1 2θ(x − a)

  • ux − vt + ∂S

∂u

  • ˆ

a(a)

x

= θ(a − x)a(a)

x

ˆ a(b)

t

= a(b)

t

− 1 2θ(b − x)

  • vx − ut − ∂S

∂u

  • ˆ

a(b)

x

= θ(x − b)a(b)

x

slide-83
SLIDE 83
  • Checking integrability

Adapt an idea from Bowcock, EC, Dorey, Rietdijk, 1995. Two regions overlapping the shock location: x > a, x < b with a < x0 < b. . . .

  • . . .

a b In each region, write down a Lax pair representation: ˆ a(a)

t

= a(a)

t

− 1 2θ(x − a)

  • ux − vt + ∂S

∂u

  • ˆ

a(a)

x

= θ(a − x)a(a)

x

ˆ a(b)

t

= a(b)

t

− 1 2θ(b − x)

  • vx − ut − ∂S

∂u

  • ˆ

a(b)

x

= θ(x − b)a(b)

x

slide-84
SLIDE 84
  • Checking integrability

Adapt an idea from Bowcock, EC, Dorey, Rietdijk, 1995. Two regions overlapping the shock location: x > a, x < b with a < x0 < b. . . .

  • . . .

a b In each region, write down a Lax pair representation: ˆ a(a)

t

= a(a)

t

− 1 2θ(x − a)

  • ux − vt + ∂S

∂u

  • ˆ

a(a)

x

= θ(a − x)a(a)

x

ˆ a(b)

t

= a(b)

t

− 1 2θ(b − x)

  • vx − ut − ∂S

∂u

  • ˆ

a(b)

x

= θ(x − b)a(b)

x

slide-85
SLIDE 85
  • Checking integrability

Adapt an idea from Bowcock, EC, Dorey, Rietdijk, 1995. Two regions overlapping the shock location: x > a, x < b with a < x0 < b. . . .

  • . . .

a b In each region, write down a Lax pair representation: ˆ a(a)

t

= a(a)

t

− 1 2θ(x − a)

  • ux − vt + ∂S

∂u

  • ˆ

a(a)

x

= θ(a − x)a(a)

x

ˆ a(b)

t

= a(b)

t

− 1 2θ(b − x)

  • vx − ut − ∂S

∂u

  • ˆ

a(b)

x

= θ(x − b)a(b)

x

slide-86
SLIDE 86
  • Checking integrability

Adapt an idea from Bowcock, EC, Dorey, Rietdijk, 1995. Two regions overlapping the shock location: x > a, x < b with a < x0 < b. . . .

  • . . .

a b In each region, write down a Lax pair representation: ˆ a(a)

t

= a(a)

t

− 1 2θ(x − a)

  • ux − vt + ∂S

∂u

  • ˆ

a(a)

x

= θ(a − x)a(a)

x

ˆ a(b)

t

= a(b)

t

− 1 2θ(b − x)

  • vx − ut − ∂S

∂u

  • ˆ

a(b)

x

= θ(x − b)a(b)

x

slide-87
SLIDE 87
  • Checking integrability

Adapt an idea from Bowcock, EC, Dorey, Rietdijk, 1995. Two regions overlapping the shock location: x > a, x < b with a < x0 < b. . . .

  • . . .

a b In each region, write down a Lax pair representation: ˆ a(a)

t

= a(a)

t

− 1 2θ(x − a)

  • ux − vt + ∂S

∂u

  • ˆ

a(a)

x

= θ(a − x)a(a)

x

ˆ a(b)

t

= a(b)

t

− 1 2θ(b − x)

  • vx − ut − ∂S

∂u

  • ˆ

a(b)

x

= θ(x − b)a(b)

x

slide-88
SLIDE 88

Where, a(a)

t

= uxH/2 +

  • i

eαiu/2 λEαi − λ−1Eαi

  • a(a)

x

= utH/2 +

  • i

eαiu/2 λEαi + λ−1Eαi

  • ,

α0 = −α1 are the two roots of the extended su(2) (ie a(1)

1 )

algebra, and H, Eαi are the usual generators of su(2). There are similar expressions for a(b)

t

, a(b)

x .

Then ∂ta(a)

x

− ∂xa(a)

t

+

  • a(a)

t

, a(a)

x

  • = 0 ⇔ sine Gordon
slide-89
SLIDE 89

The zero curvature condition for the components of the Lax pairs ˆ at, ˆ ax in the two regions imply:

  • The field equations for u, v in x < a and x > b,

respectively,

  • The shock conditions at a, b,
  • For a < x < b the fields are constant,
  • For a < x < b there should be a ‘gauge transformation’ κ

so that ∂tκ = κa(b)

t

− a(a)

t

κ This setup requires the previous expression for S(u, v) when κ = e−vH/2 ˜ κ euH/2 and ˜ κ = |α1|H + σ λ (Eα0 + Eα1) . That is S(u, v) = σ

1

  • eαi(u+v)/2 + σ−1

1

  • eαi(u−v)/2.
slide-90
SLIDE 90

The zero curvature condition for the components of the Lax pairs ˆ at, ˆ ax in the two regions imply:

  • The field equations for u, v in x < a and x > b,

respectively,

  • The shock conditions at a, b,
  • For a < x < b the fields are constant,
  • For a < x < b there should be a ‘gauge transformation’ κ

so that ∂tκ = κa(b)

t

− a(a)

t

κ This setup requires the previous expression for S(u, v) when κ = e−vH/2 ˜ κ euH/2 and ˜ κ = |α1|H + σ λ (Eα0 + Eα1) . That is S(u, v) = σ

1

  • eαi(u+v)/2 + σ−1

1

  • eαi(u−v)/2.
slide-91
SLIDE 91

The zero curvature condition for the components of the Lax pairs ˆ at, ˆ ax in the two regions imply:

  • The field equations for u, v in x < a and x > b,

respectively,

  • The shock conditions at a, b,
  • For a < x < b the fields are constant,
  • For a < x < b there should be a ‘gauge transformation’ κ

so that ∂tκ = κa(b)

t

− a(a)

t

κ This setup requires the previous expression for S(u, v) when κ = e−vH/2 ˜ κ euH/2 and ˜ κ = |α1|H + σ λ (Eα0 + Eα1) . That is S(u, v) = σ

1

  • eαi(u+v)/2 + σ−1

1

  • eαi(u−v)/2.
slide-92
SLIDE 92

The zero curvature condition for the components of the Lax pairs ˆ at, ˆ ax in the two regions imply:

  • The field equations for u, v in x < a and x > b,

respectively,

  • The shock conditions at a, b,
  • For a < x < b the fields are constant,
  • For a < x < b there should be a ‘gauge transformation’ κ

so that ∂tκ = κa(b)

t

− a(a)

t

κ This setup requires the previous expression for S(u, v) when κ = e−vH/2 ˜ κ euH/2 and ˜ κ = |α1|H + σ λ (Eα0 + Eα1) . That is S(u, v) = σ

1

  • eαi(u+v)/2 + σ−1

1

  • eαi(u−v)/2.
slide-93
SLIDE 93

The zero curvature condition for the components of the Lax pairs ˆ at, ˆ ax in the two regions imply:

  • The field equations for u, v in x < a and x > b,

respectively,

  • The shock conditions at a, b,
  • For a < x < b the fields are constant,
  • For a < x < b there should be a ‘gauge transformation’ κ

so that ∂tκ = κa(b)

t

− a(a)

t

κ This setup requires the previous expression for S(u, v) when κ = e−vH/2 ˜ κ euH/2 and ˜ κ = |α1|H + σ λ (Eα0 + Eα1) . That is S(u, v) = σ

1

  • eαi(u+v)/2 + σ−1

1

  • eαi(u−v)/2.
slide-94
SLIDE 94

The zero curvature condition for the components of the Lax pairs ˆ at, ˆ ax in the two regions imply:

  • The field equations for u, v in x < a and x > b,

respectively,

  • The shock conditions at a, b,
  • For a < x < b the fields are constant,
  • For a < x < b there should be a ‘gauge transformation’ κ

so that ∂tκ = κa(b)

t

− a(a)

t

κ This setup requires the previous expression for S(u, v) when κ = e−vH/2 ˜ κ euH/2 and ˜ κ = |α1|H + σ λ (Eα0 + Eα1) . That is S(u, v) = σ

1

  • eαi(u+v)/2 + σ−1

1

  • eαi(u−v)/2.
slide-95
SLIDE 95

The zero curvature condition for the components of the Lax pairs ˆ at, ˆ ax in the two regions imply:

  • The field equations for u, v in x < a and x > b,

respectively,

  • The shock conditions at a, b,
  • For a < x < b the fields are constant,
  • For a < x < b there should be a ‘gauge transformation’ κ

so that ∂tκ = κa(b)

t

− a(a)

t

κ This setup requires the previous expression for S(u, v) when κ = e−vH/2 ˜ κ euH/2 and ˜ κ = |α1|H + σ λ (Eα0 + Eα1) . That is S(u, v) = σ

1

  • eαi(u+v)/2 + σ−1

1

  • eαi(u−v)/2.
slide-96
SLIDE 96
  • Description of a shock defect in sine-Gordon quantum field

theory. Assume σ > 0 then...

  • Expect Pure transmission compatible with the bulk

S-matrix;

  • Expect Two different ‘transmission’ matrices (since the

topological charge on a defect can only change by ±2 as a soliton/anti-soliton passes).

  • Expect Transmission matrix with even shock labels ought

to be unitary, the transmission matrix with odd labels might not be;

  • Expect Since time reversal is no longer a symmetry, expect

left to right and right to left transmission to be different (though related).

slide-97
SLIDE 97
  • Description of a shock defect in sine-Gordon quantum field

theory. Assume σ > 0 then...

  • Expect Pure transmission compatible with the bulk

S-matrix;

  • Expect Two different ‘transmission’ matrices (since the

topological charge on a defect can only change by ±2 as a soliton/anti-soliton passes).

  • Expect Transmission matrix with even shock labels ought

to be unitary, the transmission matrix with odd labels might not be;

  • Expect Since time reversal is no longer a symmetry, expect

left to right and right to left transmission to be different (though related).

slide-98
SLIDE 98
  • Description of a shock defect in sine-Gordon quantum field

theory. Assume σ > 0 then...

  • Expect Pure transmission compatible with the bulk

S-matrix;

  • Expect Two different ‘transmission’ matrices (since the

topological charge on a defect can only change by ±2 as a soliton/anti-soliton passes).

  • Expect Transmission matrix with even shock labels ought

to be unitary, the transmission matrix with odd labels might not be;

  • Expect Since time reversal is no longer a symmetry, expect

left to right and right to left transmission to be different (though related).

slide-99
SLIDE 99
  • Description of a shock defect in sine-Gordon quantum field

theory. Assume σ > 0 then...

  • Expect Pure transmission compatible with the bulk

S-matrix;

  • Expect Two different ‘transmission’ matrices (since the

topological charge on a defect can only change by ±2 as a soliton/anti-soliton passes).

  • Expect Transmission matrix with even shock labels ought

to be unitary, the transmission matrix with odd labels might not be;

  • Expect Since time reversal is no longer a symmetry, expect

left to right and right to left transmission to be different (though related).

slide-100
SLIDE 100
  • Description of a shock defect in sine-Gordon quantum field

theory. Assume σ > 0 then...

  • Expect Pure transmission compatible with the bulk

S-matrix;

  • Expect Two different ‘transmission’ matrices (since the

topological charge on a defect can only change by ±2 as a soliton/anti-soliton passes).

  • Expect Transmission matrix with even shock labels ought

to be unitary, the transmission matrix with odd labels might not be;

  • Expect Since time reversal is no longer a symmetry, expect

left to right and right to left transmission to be different (though related).

slide-101
SLIDE 101
  • Description of a shock defect in sine-Gordon quantum field

theory. Assume σ > 0 then...

  • Expect Pure transmission compatible with the bulk

S-matrix;

  • Expect Two different ‘transmission’ matrices (since the

topological charge on a defect can only change by ±2 as a soliton/anti-soliton passes).

  • Expect Transmission matrix with even shock labels ought

to be unitary, the transmission matrix with odd labels might not be;

  • Expect Since time reversal is no longer a symmetry, expect

left to right and right to left transmission to be different (though related).

slide-102
SLIDE 102

T bβ

aα (θ)

✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α β a b a + α = b + β, |β − α| = 0, 2, a, b = ±1, α, β ∈ Z

slide-103
SLIDE 103

T bβ

aα (θ)

✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α β a b a + α = b + β, |β − α| = 0, 2, a, b = ±1, α, β ∈ Z

slide-104
SLIDE 104

T bβ

aα (θ)

✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α β a b a + α = b + β, |β − α| = 0, 2, a, b = ±1, α, β ∈ Z

slide-105
SLIDE 105

T bβ

aα (θ)

✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α β a b a + α = b + β, |β − α| = 0, 2, a, b = ±1, α, β ∈ Z

slide-106
SLIDE 106

Schematic triangle relation

✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α γ b a e f

✑✑✑✑✑ ✑

✑✑✑✑✑ ✑ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α γ b a e f Scd

ab(Θ) T fβ dα(θa)T eγ cβ (θb) = T dβ bα (θb)T cγ aβ (θa)Sef cd(Θ)

With Θ = θa − θb and sums over the ‘internal’ indices β, c, d.

  • Satisfied separately by evenT and oddT.
  • The solution was found by Konik and LeClair, 1999.
slide-107
SLIDE 107

Schematic triangle relation

✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α γ b a e f

✑✑✑✑✑ ✑

✑✑✑✑✑ ✑ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α γ b a e f Scd

ab(Θ) T fβ dα(θa)T eγ cβ (θb) = T dβ bα (θb)T cγ aβ (θa)Sef cd(Θ)

With Θ = θa − θb and sums over the ‘internal’ indices β, c, d.

  • Satisfied separately by evenT and oddT.
  • The solution was found by Konik and LeClair, 1999.
slide-108
SLIDE 108

Schematic triangle relation

✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α γ b a e f

✑✑✑✑✑ ✑

✑✑✑✑✑ ✑ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α γ b a e f Scd

ab(Θ) T fβ dα(θa)T eγ cβ (θb) = T dβ bα (θb)T cγ aβ (θa)Sef cd(Θ)

With Θ = θa − θb and sums over the ‘internal’ indices β, c, d.

  • Satisfied separately by evenT and oddT.
  • The solution was found by Konik and LeClair, 1999.
slide-109
SLIDE 109

Schematic triangle relation

✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α γ b a e f

✑✑✑✑✑ ✑

✑✑✑✑✑ ✑ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α γ b a e f Scd

ab(Θ) T fβ dα(θa)T eγ cβ (θb) = T dβ bα (θb)T cγ aβ (θa)Sef cd(Θ)

With Θ = θa − θb and sums over the ‘internal’ indices β, c, d.

  • Satisfied separately by evenT and oddT.
  • The solution was found by Konik and LeClair, 1999.
slide-110
SLIDE 110

Schematic triangle relation

✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α γ b a e f

✑✑✑✑✑ ✑

✑✑✑✑✑ ✑ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁ ✁

α γ b a e f Scd

ab(Θ) T fβ dα(θa)T eγ cβ (θb) = T dβ bα (θb)T cγ aβ (θa)Sef cd(Θ)

With Θ = θa − θb and sums over the ‘internal’ indices β, c, d.

  • Satisfied separately by evenT and oddT.
  • The solution was found by Konik and LeClair, 1999.
slide-111
SLIDE 111

Zamolodchikov’s sine-Gordon S-matrix - reminder Scd

ab(Θ) = ρ(Θ)

    A C B B C A     where A(Θ) = qx2 x1 − x1 qx2 , B(Θ) = x1 x2 − x2 x1 , C(Θ) = q − 1 q and ρ(Θ) = Γ(1 + z)Γ(1 − γ − z) 2πi

  • 1

Rk(Θ)Rk(iπ − Θ) Rk(Θ) = Γ(2kγ + z)Γ(1 + 2kγ + z) Γ((2k + 1)γ + z)Γ(1 + (2k + 1)γ + z), z = iγ/π.

slide-112
SLIDE 112

The Zamolodchikov S-matrix depends on the rapidity variables θ and the bulk coupling β via x = eγθ, q = eiπγ, γ = 8π β2 − 1, and it is also useful to define the variable Q = e4π2i/β2 = √−q.

  • K-L solutions have the form

T bβ

aα (θ) = f(q, x)

  • Qα δβ

α

q−1/2eγ(θ−η) δβ−2

α

q−1/2 eγ(θ−η) δβ+2

α

Q−α δβ

α

  • where f(q, x) is not uniquely determined but, for a unitary

transmission matrix should satisfy....

slide-113
SLIDE 113

The Zamolodchikov S-matrix depends on the rapidity variables θ and the bulk coupling β via x = eγθ, q = eiπγ, γ = 8π β2 − 1, and it is also useful to define the variable Q = e4π2i/β2 = √−q.

  • K-L solutions have the form

T bβ

aα (θ) = f(q, x)

  • Qα δβ

α

q−1/2eγ(θ−η) δβ−2

α

q−1/2 eγ(θ−η) δβ+2

α

Q−α δβ

α

  • where f(q, x) is not uniquely determined but, for a unitary

transmission matrix should satisfy....

slide-114
SLIDE 114

....namely ¯ f(q, x) = f(q, qx) f(q, x)f(q, qx) =

  • 1 + e2γ(θ−η)−1

A slightly alternative discussion of these points is given in Bowcock, EC, Zambon, 1995, where most of the properties noted below are also described.

  • A ‘minimal’ solution has the following form

f(q, x) = eiπ(1+γ)/4 1 + ieγ(θ−η) r(x) ¯ r(x), where it is convenient to put z = iγ(θ − η)/2π and r(x) =

  • k=0

Γ(kγ + 1/4 − z)Γ((k + 1)γ + 3/4 − z) Γ((k + 1/2)γ + 1/4 − z)Γ((k + 1/2)γ + 3/4 − z)

slide-115
SLIDE 115

....namely ¯ f(q, x) = f(q, qx) f(q, x)f(q, qx) =

  • 1 + e2γ(θ−η)−1

A slightly alternative discussion of these points is given in Bowcock, EC, Zambon, 1995, where most of the properties noted below are also described.

  • A ‘minimal’ solution has the following form

f(q, x) = eiπ(1+γ)/4 1 + ieγ(θ−η) r(x) ¯ r(x), where it is convenient to put z = iγ(θ − η)/2π and r(x) =

  • k=0

Γ(kγ + 1/4 − z)Γ((k + 1)γ + 3/4 − z) Γ((k + 1/2)γ + 1/4 − z)Γ((k + 1/2)γ + 3/4 − z)

slide-116
SLIDE 116

....namely ¯ f(q, x) = f(q, qx) f(q, x)f(q, qx) =

  • 1 + e2γ(θ−η)−1

A slightly alternative discussion of these points is given in Bowcock, EC, Zambon, 1995, where most of the properties noted below are also described.

  • A ‘minimal’ solution has the following form

f(q, x) = eiπ(1+γ)/4 1 + ieγ(θ−η) r(x) ¯ r(x), where it is convenient to put z = iγ(θ − η)/2π and r(x) =

  • k=0

Γ(kγ + 1/4 − z)Γ((k + 1)γ + 3/4 − z) Γ((k + 1/2)γ + 1/4 − z)Γ((k + 1/2)γ + 3/4 − z)

slide-117
SLIDE 117

T bβ

aα (θ) = f(q, x)

  • Qα δβ

α

q−1/2eγ(θ−η) δβ−2

α

q−1/2 eγ(θ−η) δβ+2

α

Q−α δβ

α

  • Remarks (θ > 0): it is tempting to suppose η (possibly

renormalized) is the same parameter as in the classical model.

  • η < 0 - the off-diagonal entries dominate;
  • θ > η > 0 - the off-diagonal entries dominate;
  • η > θ > 0 - the diagonal entries dominate;
  • These are the same features we saw in the classical

soliton-shock scattering.

  • θ = η is not special but there is a simple pole nearby at

θ = η − iπ 2γ → η, β → 0

slide-118
SLIDE 118

T bβ

aα (θ) = f(q, x)

  • Qα δβ

α

q−1/2eγ(θ−η) δβ−2

α

q−1/2 eγ(θ−η) δβ+2

α

Q−α δβ

α

  • Remarks (θ > 0): it is tempting to suppose η (possibly

renormalized) is the same parameter as in the classical model.

  • η < 0 - the off-diagonal entries dominate;
  • θ > η > 0 - the off-diagonal entries dominate;
  • η > θ > 0 - the diagonal entries dominate;
  • These are the same features we saw in the classical

soliton-shock scattering.

  • θ = η is not special but there is a simple pole nearby at

θ = η − iπ 2γ → η, β → 0

slide-119
SLIDE 119

T bβ

aα (θ) = f(q, x)

  • Qα δβ

α

q−1/2eγ(θ−η) δβ−2

α

q−1/2 eγ(θ−η) δβ+2

α

Q−α δβ

α

  • Remarks (θ > 0): it is tempting to suppose η (possibly

renormalized) is the same parameter as in the classical model.

  • η < 0 - the off-diagonal entries dominate;
  • θ > η > 0 - the off-diagonal entries dominate;
  • η > θ > 0 - the diagonal entries dominate;
  • These are the same features we saw in the classical

soliton-shock scattering.

  • θ = η is not special but there is a simple pole nearby at

θ = η − iπ 2γ → η, β → 0

slide-120
SLIDE 120

T bβ

aα (θ) = f(q, x)

  • Qα δβ

α

q−1/2eγ(θ−η) δβ−2

α

q−1/2 eγ(θ−η) δβ+2

α

Q−α δβ

α

  • Remarks (θ > 0): it is tempting to suppose η (possibly

renormalized) is the same parameter as in the classical model.

  • η < 0 - the off-diagonal entries dominate;
  • θ > η > 0 - the off-diagonal entries dominate;
  • η > θ > 0 - the diagonal entries dominate;
  • These are the same features we saw in the classical

soliton-shock scattering.

  • θ = η is not special but there is a simple pole nearby at

θ = η − iπ 2γ → η, β → 0

slide-121
SLIDE 121

T bβ

aα (θ) = f(q, x)

  • Qα δβ

α

q−1/2eγ(θ−η) δβ−2

α

q−1/2 eγ(θ−η) δβ+2

α

Q−α δβ

α

  • Remarks (θ > 0): it is tempting to suppose η (possibly

renormalized) is the same parameter as in the classical model.

  • η < 0 - the off-diagonal entries dominate;
  • θ > η > 0 - the off-diagonal entries dominate;
  • η > θ > 0 - the diagonal entries dominate;
  • These are the same features we saw in the classical

soliton-shock scattering.

  • θ = η is not special but there is a simple pole nearby at

θ = η − iπ 2γ → η, β → 0

slide-122
SLIDE 122

T bβ

aα (θ) = f(q, x)

  • Qα δβ

α

q−1/2eγ(θ−η) δβ−2

α

q−1/2 eγ(θ−η) δβ+2

α

Q−α δβ

α

  • Remarks (θ > 0): it is tempting to suppose η (possibly

renormalized) is the same parameter as in the classical model.

  • η < 0 - the off-diagonal entries dominate;
  • θ > η > 0 - the off-diagonal entries dominate;
  • η > θ > 0 - the diagonal entries dominate;
  • These are the same features we saw in the classical

soliton-shock scattering.

  • θ = η is not special but there is a simple pole nearby at

θ = η − iπ 2γ → η, β → 0

slide-123
SLIDE 123

T bβ

aα (θ) = f(q, x)

  • Qα δβ

α

q−1/2eγ(θ−η) δβ−2

α

q−1/2 eγ(θ−η) δβ+2

α

Q−α δβ

α

  • Remarks (θ > 0): it is tempting to suppose η (possibly

renormalized) is the same parameter as in the classical model.

  • η < 0 - the off-diagonal entries dominate;
  • θ > η > 0 - the off-diagonal entries dominate;
  • η > θ > 0 - the diagonal entries dominate;
  • These are the same features we saw in the classical

soliton-shock scattering.

  • θ = η is not special but there is a simple pole nearby at

θ = η − iπ 2γ → η, β → 0

slide-124
SLIDE 124

T bβ

aα (θ) = f(q, x)

  • Qα δβ

α

q−1/2eγ(θ−η) δβ−2

α

q−1/2 eγ(θ−η) δβ+2

α

Q−α δβ

α

  • Remarks (θ > 0): it is tempting to suppose η (possibly

renormalized) is the same parameter as in the classical model.

  • η < 0 - the off-diagonal entries dominate;
  • θ > η > 0 - the off-diagonal entries dominate;
  • η > θ > 0 - the diagonal entries dominate;
  • These are the same features we saw in the classical

soliton-shock scattering.

  • θ = η is not special but there is a simple pole nearby at

θ = η − iπ 2γ → η, β → 0

slide-125
SLIDE 125
  • This pole is like a resonance, with complex energy,

E = ms cosh θ = ms(cosh η cos(π/2γ) − i sinh η sin(π/2γ)) and a ‘width’ proportional to sin(π/2γ). Using this pole and a bootstrap to define oddT leads to a non-unitary transmission matrix - interpret as the instability corresponding to the classical feature noted at θ = η.

  • The Zamolodchikov S-matrix has ‘breather’ poles

corresponding to soliton-anti-soliton bound states at Θ = iπ(1 − n/γ), n = 1, 2, ..., nmax; use the bootstrap to define the transmission factors for breathers and find for the lightest breather: T(θ) = −i sinh

  • θ−η

2

− iπ

4

  • sinh
  • θ−η

2

+ iπ

4

slide-126
SLIDE 126
  • This pole is like a resonance, with complex energy,

E = ms cosh θ = ms(cosh η cos(π/2γ) − i sinh η sin(π/2γ)) and a ‘width’ proportional to sin(π/2γ). Using this pole and a bootstrap to define oddT leads to a non-unitary transmission matrix - interpret as the instability corresponding to the classical feature noted at θ = η.

  • The Zamolodchikov S-matrix has ‘breather’ poles

corresponding to soliton-anti-soliton bound states at Θ = iπ(1 − n/γ), n = 1, 2, ..., nmax; use the bootstrap to define the transmission factors for breathers and find for the lightest breather: T(θ) = −i sinh

  • θ−η

2

− iπ

4

  • sinh
  • θ−η

2

+ iπ

4

slide-127
SLIDE 127
  • This pole is like a resonance, with complex energy,

E = ms cosh θ = ms(cosh η cos(π/2γ) − i sinh η sin(π/2γ)) and a ‘width’ proportional to sin(π/2γ). Using this pole and a bootstrap to define oddT leads to a non-unitary transmission matrix - interpret as the instability corresponding to the classical feature noted at θ = η.

  • The Zamolodchikov S-matrix has ‘breather’ poles

corresponding to soliton-anti-soliton bound states at Θ = iπ(1 − n/γ), n = 1, 2, ..., nmax; use the bootstrap to define the transmission factors for breathers and find for the lightest breather: T(θ) = −i sinh

  • θ−η

2

− iπ

4

  • sinh
  • θ−η

2

+ iπ

4

slide-128
SLIDE 128
  • This pole is like a resonance, with complex energy,

E = ms cosh θ = ms(cosh η cos(π/2γ) − i sinh η sin(π/2γ)) and a ‘width’ proportional to sin(π/2γ). Using this pole and a bootstrap to define oddT leads to a non-unitary transmission matrix - interpret as the instability corresponding to the classical feature noted at θ = η.

  • The Zamolodchikov S-matrix has ‘breather’ poles

corresponding to soliton-anti-soliton bound states at Θ = iπ(1 − n/γ), n = 1, 2, ..., nmax; use the bootstrap to define the transmission factors for breathers and find for the lightest breather: T(θ) = −i sinh

  • θ−η

2

− iπ

4

  • sinh
  • θ−η

2

+ iπ

4

slide-129
SLIDE 129

....This is simple and coincides with the expression we calculated previously in the linearised model.

  • This is also amenable to perturbative calculation and it works
  • ut (with a renormalised η) - See Bajnok and Simon, 2007.
  • The diagonal terms in the soliton transmission matrix are

strange because they treat solitons (a factor Qα) and anti-solitons (a factor Q−α) differently

  • this feature is directly attributable to the Lagrangian term

δ(x)(uvt − vut)

slide-130
SLIDE 130

....This is simple and coincides with the expression we calculated previously in the linearised model.

  • This is also amenable to perturbative calculation and it works
  • ut (with a renormalised η) - See Bajnok and Simon, 2007.
  • The diagonal terms in the soliton transmission matrix are

strange because they treat solitons (a factor Qα) and anti-solitons (a factor Q−α) differently

  • this feature is directly attributable to the Lagrangian term

δ(x)(uvt − vut)

slide-131
SLIDE 131

....This is simple and coincides with the expression we calculated previously in the linearised model.

  • This is also amenable to perturbative calculation and it works
  • ut (with a renormalised η) - See Bajnok and Simon, 2007.
  • The diagonal terms in the soliton transmission matrix are

strange because they treat solitons (a factor Qα) and anti-solitons (a factor Q−α) differently

  • this feature is directly attributable to the Lagrangian term

δ(x)(uvt − vut)

slide-132
SLIDE 132

....This is simple and coincides with the expression we calculated previously in the linearised model.

  • This is also amenable to perturbative calculation and it works
  • ut (with a renormalised η) - See Bajnok and Simon, 2007.
  • The diagonal terms in the soliton transmission matrix are

strange because they treat solitons (a factor Qα) and anti-solitons (a factor Q−α) differently

  • this feature is directly attributable to the Lagrangian term

δ(x)(uvt − vut)

slide-133
SLIDE 133

Consider the x-axis with a shock located at x0 and asymptotic values of the fields . . .

  • . . .

u = 2aπ/β x0 v = 2bπ/β Compare (0, 0) and (a, b) in functional integral representations: u → u − 2aπ/β, v → v − 2bπ/β, A → A + δA with δA = π β ∞

−∞

dt(avt − but) = π β (aδv − bδu)x0 Soliton: (a, b) → (a − 1, b − 1), so δu = δv = −2π/β Anti-soliton: (a, b) → (a + 1, b + 1), so δu = δv = 2π/β

slide-134
SLIDE 134

Consider the x-axis with a shock located at x0 and asymptotic values of the fields . . .

  • . . .

u = 2aπ/β x0 v = 2bπ/β Compare (0, 0) and (a, b) in functional integral representations: u → u − 2aπ/β, v → v − 2bπ/β, A → A + δA with δA = π β ∞

−∞

dt(avt − but) = π β (aδv − bδu)x0 Soliton: (a, b) → (a − 1, b − 1), so δu = δv = −2π/β Anti-soliton: (a, b) → (a + 1, b + 1), so δu = δv = 2π/β

slide-135
SLIDE 135

Consider the x-axis with a shock located at x0 and asymptotic values of the fields . . .

  • . . .

u = 2aπ/β x0 v = 2bπ/β Compare (0, 0) and (a, b) in functional integral representations: u → u − 2aπ/β, v → v − 2bπ/β, A → A + δA with δA = π β ∞

−∞

dt(avt − but) = π β (aδv − bδu)x0 Soliton: (a, b) → (a − 1, b − 1), so δu = δv = −2π/β Anti-soliton: (a, b) → (a + 1, b + 1), so δu = δv = 2π/β

slide-136
SLIDE 136

Consider the x-axis with a shock located at x0 and asymptotic values of the fields . . .

  • . . .

u = 2aπ/β x0 v = 2bπ/β Compare (0, 0) and (a, b) in functional integral representations: u → u − 2aπ/β, v → v − 2bπ/β, A → A + δA with δA = π β ∞

−∞

dt(avt − but) = π β (aδv − bδu)x0 Soliton: (a, b) → (a − 1, b − 1), so δu = δv = −2π/β Anti-soliton: (a, b) → (a + 1, b + 1), so δu = δv = 2π/β

slide-137
SLIDE 137

Consider the x-axis with a shock located at x0 and asymptotic values of the fields . . .

  • . . .

u = 2aπ/β x0 v = 2bπ/β Compare (0, 0) and (a, b) in functional integral representations: u → u − 2aπ/β, v → v − 2bπ/β, A → A + δA with δA = π β ∞

−∞

dt(avt − but) = π β (aδv − bδu)x0 Soliton: (a, b) → (a − 1, b − 1), so δu = δv = −2π/β Anti-soliton: (a, b) → (a + 1, b + 1), so δu = δv = 2π/β

slide-138
SLIDE 138

Consider the x-axis with a shock located at x0 and asymptotic values of the fields . . .

  • . . .

u = 2aπ/β x0 v = 2bπ/β Compare (0, 0) and (a, b) in functional integral representations: u → u − 2aπ/β, v → v − 2bπ/β, A → A + δA with δA = π β ∞

−∞

dt(avt − but) = π β (aδv − bδu)x0 Soliton: (a, b) → (a − 1, b − 1), so δu = δv = −2π/β Anti-soliton: (a, b) → (a + 1, b + 1), so δu = δv = 2π/β

slide-139
SLIDE 139

Consider the x-axis with a shock located at x0 and asymptotic values of the fields . . .

  • . . .

u = 2aπ/β x0 v = 2bπ/β Compare (0, 0) and (a, b) in functional integral representations: u → u − 2aπ/β, v → v − 2bπ/β, A → A + δA with δA = π β ∞

−∞

dt(avt − but) = π β (aδv − bδu)x0 Soliton: (a, b) → (a − 1, b − 1), so δu = δv = −2π/β Anti-soliton: (a, b) → (a + 1, b + 1), so δu = δv = 2π/β

slide-140
SLIDE 140

....leads to relative changes of phase e±2iπ2(a−b)/β2,

  • r

Q±α/2. Note: the labelling of states by the integers representing the ‘vacuum’ states at x = ±∞ leads to a slightly different representation of the transmission matrix than that shown

  • before. However they are related by a change of basis

Bowcock, EC, Zambon, 2005.

slide-141
SLIDE 141

....leads to relative changes of phase e±2iπ2(a−b)/β2,

  • r

Q±α/2. Note: the labelling of states by the integers representing the ‘vacuum’ states at x = ±∞ leads to a slightly different representation of the transmission matrix than that shown

  • before. However they are related by a change of basis

Bowcock, EC, Zambon, 2005.

slide-142
SLIDE 142

....leads to relative changes of phase e±2iπ2(a−b)/β2,

  • r

Q±α/2. Note: the labelling of states by the integers representing the ‘vacuum’ states at x = ±∞ leads to a slightly different representation of the transmission matrix than that shown

  • before. However they are related by a change of basis

Bowcock, EC, Zambon, 2005.

slide-143
SLIDE 143

Further questions....

  • Moving shocks can be constructed in sine-Gordon theory but

their quantum scattering is not yet completely analysed, though there is a candidate S-matrix compatible with the soliton transmission matrix. (see Bowcock, EC, Zambon, 2005)

  • Other field theories - shocks can be constructed within the

a(1)

r

affine Toda field theories (Bowcock, EC, Zambon, 2004) and there are several types of transmission matrices, though

  • nly partially analysed (EC, Zambon, 2007).
  • NLS, KdV, mKdV (EC, Zambon, 2006; Caudrelier 2006)
  • Fermions and SUSY field theories (Gomes, Ymai, Zimerman)
  • Bäcklund transformations are mysterious but appear to be

essential for these types of integrable defect.

  • can they be realised in any physical system?
  • might they be technologically useful? To control solitons?
slide-144
SLIDE 144

Further questions....

  • Moving shocks can be constructed in sine-Gordon theory but

their quantum scattering is not yet completely analysed, though there is a candidate S-matrix compatible with the soliton transmission matrix. (see Bowcock, EC, Zambon, 2005)

  • Other field theories - shocks can be constructed within the

a(1)

r

affine Toda field theories (Bowcock, EC, Zambon, 2004) and there are several types of transmission matrices, though

  • nly partially analysed (EC, Zambon, 2007).
  • NLS, KdV, mKdV (EC, Zambon, 2006; Caudrelier 2006)
  • Fermions and SUSY field theories (Gomes, Ymai, Zimerman)
  • Bäcklund transformations are mysterious but appear to be

essential for these types of integrable defect.

  • can they be realised in any physical system?
  • might they be technologically useful? To control solitons?
slide-145
SLIDE 145

Further questions....

  • Moving shocks can be constructed in sine-Gordon theory but

their quantum scattering is not yet completely analysed, though there is a candidate S-matrix compatible with the soliton transmission matrix. (see Bowcock, EC, Zambon, 2005)

  • Other field theories - shocks can be constructed within the

a(1)

r

affine Toda field theories (Bowcock, EC, Zambon, 2004) and there are several types of transmission matrices, though

  • nly partially analysed (EC, Zambon, 2007).
  • NLS, KdV, mKdV (EC, Zambon, 2006; Caudrelier 2006)
  • Fermions and SUSY field theories (Gomes, Ymai, Zimerman)
  • Bäcklund transformations are mysterious but appear to be

essential for these types of integrable defect.

  • can they be realised in any physical system?
  • might they be technologically useful? To control solitons?
slide-146
SLIDE 146

Further questions....

  • Moving shocks can be constructed in sine-Gordon theory but

their quantum scattering is not yet completely analysed, though there is a candidate S-matrix compatible with the soliton transmission matrix. (see Bowcock, EC, Zambon, 2005)

  • Other field theories - shocks can be constructed within the

a(1)

r

affine Toda field theories (Bowcock, EC, Zambon, 2004) and there are several types of transmission matrices, though

  • nly partially analysed (EC, Zambon, 2007).
  • NLS, KdV, mKdV (EC, Zambon, 2006; Caudrelier 2006)
  • Fermions and SUSY field theories (Gomes, Ymai, Zimerman)
  • Bäcklund transformations are mysterious but appear to be

essential for these types of integrable defect.

  • can they be realised in any physical system?
  • might they be technologically useful? To control solitons?
slide-147
SLIDE 147

Further questions....

  • Moving shocks can be constructed in sine-Gordon theory but

their quantum scattering is not yet completely analysed, though there is a candidate S-matrix compatible with the soliton transmission matrix. (see Bowcock, EC, Zambon, 2005)

  • Other field theories - shocks can be constructed within the

a(1)

r

affine Toda field theories (Bowcock, EC, Zambon, 2004) and there are several types of transmission matrices, though

  • nly partially analysed (EC, Zambon, 2007).
  • NLS, KdV, mKdV (EC, Zambon, 2006; Caudrelier 2006)
  • Fermions and SUSY field theories (Gomes, Ymai, Zimerman)
  • Bäcklund transformations are mysterious but appear to be

essential for these types of integrable defect.

  • can they be realised in any physical system?
  • might they be technologically useful? To control solitons?
slide-148
SLIDE 148

Further questions....

  • Moving shocks can be constructed in sine-Gordon theory but

their quantum scattering is not yet completely analysed, though there is a candidate S-matrix compatible with the soliton transmission matrix. (see Bowcock, EC, Zambon, 2005)

  • Other field theories - shocks can be constructed within the

a(1)

r

affine Toda field theories (Bowcock, EC, Zambon, 2004) and there are several types of transmission matrices, though

  • nly partially analysed (EC, Zambon, 2007).
  • NLS, KdV, mKdV (EC, Zambon, 2006; Caudrelier 2006)
  • Fermions and SUSY field theories (Gomes, Ymai, Zimerman)
  • Bäcklund transformations are mysterious but appear to be

essential for these types of integrable defect.

  • can they be realised in any physical system?
  • might they be technologically useful? To control solitons?
slide-149
SLIDE 149

Further questions....

  • Moving shocks can be constructed in sine-Gordon theory but

their quantum scattering is not yet completely analysed, though there is a candidate S-matrix compatible with the soliton transmission matrix. (see Bowcock, EC, Zambon, 2005)

  • Other field theories - shocks can be constructed within the

a(1)

r

affine Toda field theories (Bowcock, EC, Zambon, 2004) and there are several types of transmission matrices, though

  • nly partially analysed (EC, Zambon, 2007).
  • NLS, KdV, mKdV (EC, Zambon, 2006; Caudrelier 2006)
  • Fermions and SUSY field theories (Gomes, Ymai, Zimerman)
  • Bäcklund transformations are mysterious but appear to be

essential for these types of integrable defect.

  • can they be realised in any physical system?
  • might they be technologically useful? To control solitons?
slide-150
SLIDE 150

Further questions....

  • Moving shocks can be constructed in sine-Gordon theory but

their quantum scattering is not yet completely analysed, though there is a candidate S-matrix compatible with the soliton transmission matrix. (see Bowcock, EC, Zambon, 2005)

  • Other field theories - shocks can be constructed within the

a(1)

r

affine Toda field theories (Bowcock, EC, Zambon, 2004) and there are several types of transmission matrices, though

  • nly partially analysed (EC, Zambon, 2007).
  • NLS, KdV, mKdV (EC, Zambon, 2006; Caudrelier 2006)
  • Fermions and SUSY field theories (Gomes, Ymai, Zimerman)
  • Bäcklund transformations are mysterious but appear to be

essential for these types of integrable defect.

  • can they be realised in any physical system?
  • might they be technologically useful? To control solitons?