Section5.6 Applications and Models: Growth and Decay; Com- pound - - PowerPoint PPT Presentation

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Section5.6 Applications and Models: Growth and Decay; Com- pound - - PowerPoint PPT Presentation

Section5.6 Applications and Models: Growth and Decay; Com- pound Interest Exponential Growth A quantity that experiences exponential growth will increase according to the equation P ( t ) = P 0 e kt where t is the time (in any given units)


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Section5.6

Applications and Models: Growth and Decay; Com- pound Interest

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SLIDE 2

Exponential Growth

A quantity that experiences exponential growth will increase according to the equation P(t) = P0ekt where t is the time (in any given units)

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Exponential Growth

A quantity that experiences exponential growth will increase according to the equation P(t) = P0ekt where t is the time (in any given units) P(t) is the amount at time t

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SLIDE 4

Exponential Growth

A quantity that experiences exponential growth will increase according to the equation P(t) = P0ekt where t is the time (in any given units) P(t) is the amount at time t P0 is the initial quantity.

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Exponential Growth

A quantity that experiences exponential growth will increase according to the equation P(t) = P0ekt where t is the time (in any given units) P(t) is the amount at time t P0 is the initial quantity. k (which needs to be positive) is the exponential growth rate.

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Exponential Growth (continued)

A quantity that experiences exponential growth also has a corresponding doubling time. If the doubling time is T, then the population will increase according to the equation P(t) = P0ekt, where k = ln 2 T Notice you can also solve for T to get the equation T = ln 2

k

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Examples

  • 1. The exponential growth rate of a population of rabbits is 11.6% per
  • month. What is the doubling time?
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Examples

  • 1. The exponential growth rate of a population of rabbits is 11.6% per
  • month. What is the doubling time?

About 6 months.

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Examples

  • 1. The exponential growth rate of a population of rabbits is 11.6% per
  • month. What is the doubling time?

About 6 months.

  • 2. A sample of bacteria is growing in a Petri dish. There were originally

2 thousand cells, and after 2 hours there are now 5 thousand cells. How long will it take for there to be 8 thousand cells?

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Examples

  • 1. The exponential growth rate of a population of rabbits is 11.6% per
  • month. What is the doubling time?

About 6 months.

  • 2. A sample of bacteria is growing in a Petri dish. There were originally

2 thousand cells, and after 2 hours there are now 5 thousand cells. How long will it take for there to be 8 thousand cells? About 3 hours.

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Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0

  • 1 + r

n

nt where t is the time (in years)

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Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0

  • 1 + r

n

nt where t is the time (in years) P(t) is the total amount of money at time t

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SLIDE 13

Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0

  • 1 + r

n

nt where t is the time (in years) P(t) is the total amount of money at time t P0 is the principal - or initial amount of the investment.

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SLIDE 14

Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0

  • 1 + r

n

nt where t is the time (in years) P(t) is the total amount of money at time t P0 is the principal - or initial amount of the investment. r is the interest rate.

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SLIDE 15

Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0

  • 1 + r

n

nt where t is the time (in years) P(t) is the total amount of money at time t P0 is the principal - or initial amount of the investment. r is the interest rate. n is the number of times the interest is compounded per year.

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SLIDE 16

Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0

  • 1 + r

n

nt where t is the time (in years) P(t) is the total amount of money at time t P0 is the principal - or initial amount of the investment. r is the interest rate. n is the number of times the interest is compounded per year. Page 327 has a chart with key words to help figure out what n is.

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Continuously Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0ekt where t is the time (in years)

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SLIDE 18

Continuously Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0ekt where t is the time (in years) P(t) is the total amount of money at time t

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Continuously Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0ekt where t is the time (in years) P(t) is the total amount of money at time t P0 is the principal - or initial amount of the investment.

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Continuously Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0ekt where t is the time (in years) P(t) is the total amount of money at time t P0 is the principal - or initial amount of the investment. k is the nominal interest rate.

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Continuously Compounded Interest

An an investment earning continuously compounded interest grows according to the formula: P(t) = P0ekt where t is the time (in years) P(t) is the total amount of money at time t P0 is the principal - or initial amount of the investment. k is the nominal interest rate. Notice that this is exactly the same as the formula for exponential

  • growth. Problems involving exponential growth and continuously

compounded interest work exactly the same.

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Example

Suppose that $82, 000 is invested at 4 1

2% interest, compounded

  • quarterly. Find the function for the amount to which the investmnt

grows after t years. ✩ ✩

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Example

Suppose that $82, 000 is invested at 4 1

2% interest, compounded

  • quarterly. Find the function for the amount to which the investmnt

grows after t years. P(t) = 82000(1.01125)4t ✩ ✩

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Example

Suppose that $82, 000 is invested at 4 1

2% interest, compounded

  • quarterly. Find the function for the amount to which the investmnt

grows after t years. P(t) = 82000(1.01125)4t A father wishes to invest money to help pay for his son’s college

  • education. The investment earns 5% compounded continuously.

How much should he invest when his son is born so that he’ll have ✩50,000 when his son turns 18? ✩

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Example

Suppose that $82, 000 is invested at 4 1

2% interest, compounded

  • quarterly. Find the function for the amount to which the investmnt

grows after t years. P(t) = 82000(1.01125)4t A father wishes to invest money to help pay for his son’s college

  • education. The investment earns 5% compounded continuously.

How much should he invest when his son is born so that he’ll have ✩50,000 when his son turns 18? ✩20328.48

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Exponential Decay

A quantity that experiences exponential decay will decrease according to the equation P(t) = P0e−kt where t is the time (in any given units)

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Exponential Decay

A quantity that experiences exponential decay will decrease according to the equation P(t) = P0e−kt where t is the time (in any given units) P(t) is the amount at time t

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Exponential Decay

A quantity that experiences exponential decay will decrease according to the equation P(t) = P0e−kt where t is the time (in any given units) P(t) is the amount at time t P0 is the initial quantity.

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Exponential Decay

A quantity that experiences exponential decay will decrease according to the equation P(t) = P0e−kt where t is the time (in any given units) P(t) is the amount at time t P0 is the initial quantity. k (which needs to be positive) is the decay rate.

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Exponential Decay (continued)

A quantity that experiences exponential decay also has a corresponding half-life. If the half-life if T, then the sample will decrease according to the equation P(t) = P0e−kt, where k = ln 2 T Notice you can also solve for T to get the equation T = ln 2

k

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SLIDE 31

Example

The half-life of radium-226 is 1600 years. Find the decay rate.

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Example

The half-life of radium-226 is 1600 years. Find the decay rate. k =

ln 2 1600 ≈ 0.0004332 = 0.04332% per year

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Newton’s Law of Cooling

An object that’s hotter/colder than it’s surrounding environment will cool off/heat up according to the equation T(t) = T0 + (T1 − T0)e−kt where t is the time (in any given units)

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Newton’s Law of Cooling

An object that’s hotter/colder than it’s surrounding environment will cool off/heat up according to the equation T(t) = T0 + (T1 − T0)e−kt where t is the time (in any given units) T(t) is temperature of the object at time t

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Newton’s Law of Cooling

An object that’s hotter/colder than it’s surrounding environment will cool off/heat up according to the equation T(t) = T0 + (T1 − T0)e−kt where t is the time (in any given units) T(t) is temperature of the object at time t T0 is temperature of the surrounding environment

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SLIDE 36

Newton’s Law of Cooling

An object that’s hotter/colder than it’s surrounding environment will cool off/heat up according to the equation T(t) = T0 + (T1 − T0)e−kt where t is the time (in any given units) T(t) is temperature of the object at time t T0 is temperature of the surrounding environment T1 is the initial temperature of the object

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SLIDE 37

Newton’s Law of Cooling

An object that’s hotter/colder than it’s surrounding environment will cool off/heat up according to the equation T(t) = T0 + (T1 − T0)e−kt where t is the time (in any given units) T(t) is temperature of the object at time t T0 is temperature of the surrounding environment T1 is the initial temperature of the object k is a constant that depends on the physical properties of the object and its surrounding. It will change based on how easily they transfer heat to each other.

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Example

A roasted turkey is taken from an oven when its temperature has reached 185◦F and is placed on a table in a room where the temperature is 75◦F. If the temperature is 150◦ in half an hour, what is the temperature after 45 minutes?

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Example

A roasted turkey is taken from an oven when its temperature has reached 185◦F and is placed on a table in a room where the temperature is 75◦F. If the temperature is 150◦ in half an hour, what is the temperature after 45 minutes? 137◦F