Section3.4 Solving Rational Equations and Radical Equations - - PowerPoint PPT Presentation

section3 4
SMART_READER_LITE
LIVE PREVIEW

Section3.4 Solving Rational Equations and Radical Equations - - PowerPoint PPT Presentation

Section3.4 Solving Rational Equations and Radical Equations RationalEquations Method 1. Find the least common denominator for every fraction and multiply both sides of the equation by this. This should cancel out all the fractions. 2. Solve


slide-1
SLIDE 1

Section3.4

Solving Rational Equations and Radical Equations

slide-2
SLIDE 2

RationalEquations

slide-3
SLIDE 3

Method

  • 1. Find the least common denominator for every fraction and multiply

both sides of the equation by this. This should cancel out all the fractions.

  • 2. Solve the equation to find potential solutions.
  • 3. Some of the answers you found might not be solutions! Check your

answers against the domain of the original problem. Since the

  • riginal problem has fractions, you have to make sure you never

divide by zero.

slide-4
SLIDE 4

Example

Solve for x:

  • 1. 2

5 − x + 1 4 = x 10

slide-5
SLIDE 5

Example

Solve for x:

  • 1. 2

5 − x + 1 4 = x 10 x = 3

7

slide-6
SLIDE 6

Example

Solve for x:

  • 1. 2

5 − x + 1 4 = x 10 x = 3

7

  • 2. x + 3

x − 2 + 3 x − 3 = −5 x2 − 5x + 6

slide-7
SLIDE 7

Example

Solve for x:

  • 1. 2

5 − x + 1 4 = x 10 x = 3

7

  • 2. x + 3

x − 2 + 3 x − 3 = −5 x2 − 5x + 6 x = −5

slide-8
SLIDE 8

Example

Solve for x:

  • 1. 2

5 − x + 1 4 = x 10 x = 3

7

  • 2. x + 3

x − 2 + 3 x − 3 = −5 x2 − 5x + 6 x = −5 3. 6 x + 3 + 2 x = 5x − 3 x2 − 9

slide-9
SLIDE 9

Example

Solve for x:

  • 1. 2

5 − x + 1 4 = x 10 x = 3

7

  • 2. x + 3

x − 2 + 3 x − 3 = −5 x2 − 5x + 6 x = −5 3. 6 x + 3 + 2 x = 5x − 3 x2 − 9 x = −1 or x = 6

slide-10
SLIDE 10

SquareRootEquations

slide-11
SLIDE 11

Method

  • 1. Isolate a single root on one side of the equation.
  • 2. Square both sides to cancel out the root.
  • 3. Repeat steps 1 and 2 for any other roots.
  • 4. Solve the equation to find potential solutions.
  • 5. Check the answers in the original equation - some of them might

not actually be solutions!

slide-12
SLIDE 12

Example

Solve for x:

  • 1. √4x + 9 + 3x = 2x − 1
slide-13
SLIDE 13

Example

Solve for x:

  • 1. √4x + 9 + 3x = 2x − 1

x = −2

slide-14
SLIDE 14

Example

Solve for x:

  • 1. √4x + 9 + 3x = 2x − 1

x = −2

  • 2. √y + 1 + √y − 2 = 3
slide-15
SLIDE 15

Example

Solve for x:

  • 1. √4x + 9 + 3x = 2x − 1

x = −2

  • 2. √y + 1 + √y − 2 = 3

y = 3

slide-16
SLIDE 16

SolveforOneVariablein TermsofOthers

slide-17
SLIDE 17

Examples

  • 1. Solve for y: xy + z

wy + z = 3

slide-18
SLIDE 18

Examples

  • 1. Solve for y: xy + z

wy + z = 3 y = 2z x − 3w

slide-19
SLIDE 19

Examples

  • 1. Solve for y: xy + z

wy + z = 3 y = 2z x − 3w

  • 2. Solve for c: 1

a + 1 b = 1 c

slide-20
SLIDE 20

Examples

  • 1. Solve for y: xy + z

wy + z = 3 y = 2z x − 3w

  • 2. Solve for c: 1

a + 1 b = 1 c c = ab a + b