Random Matrix Eigenvalue Problems in Probabilistic Structural - - PowerPoint PPT Presentation

2 June 2005

Random Matrix Eigenvalue Problems in Probabilistic Structural Mechanics

S Adhikari

Department of Aerospace Engineering, University of Bristol, Bristol, U.K. URL: http://www.aer.bris.ac.uk/contact/academic/adhikari/home.html

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Outline of the Presentation

Random eigenvalue problem Existing methods Exact methods Perturbation methods Asymptotic analysis of multidimensional integrals Joint moments and pdf of the natural frequencies Numerical examples & results Conclusions

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Random Eigenvalue Problem

The random eigenvalue problem of undamped or proportionally damped linear systems: K(x)φj = ω2

jM(x)φj

(1) ωj natural frequencies; φj eigenvectors; M(x) ∈ RN×N mass matrix and K(x) ∈ RN×N stiffness matrix. x ∈ Rm is random parameter vector with pdf px(x) = e−L(x) −L(x) is the log-likelihood function.

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The Objectives

The aim is to obtain the joint probability density function of the natural frequencies and the eigenvectors in this work we look at the joint statistics of the eigenvalues while several papers are available on the distribution of individual eigenvalues, only first-order perturbation results are available for the joint pdf of the eigenvalues

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Exact Joint pdf

Without any loss of generality the original eigenvalue problem can be expressed by H(x)ψj = ω2

jψj

(2) where H(x) = M−1/2(x)K(x)M−1/2(x) ∈ RN×N and ψj = M1/2φj

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Exact Joint pdf

The joint probability (following Muirhead, 1982) density function of the natural frequencies of an N-dimensional linear positive definite dynamic system is given by p Ω (ω1, ω2, · · · , ωN) = πN 2/2 Γ(N/2)

• i<j≤N
• ω2

j − ω2 i

• O(N)

pH

• ΨΩ2ΨT

(dΨ) (3) where H = M−1/2KM−1/2 & pH(H) is the pdf of H.

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Limitations of the Exact Method

the multidimensional integral over the

• rthogonal group O(N) is difficult to carry out in

practice and exact closed-form results can be derived only for few special cases the derivation of an expression of the joint pdf of the system matrix pH(H) is non-trivial even if the joint pdf of the random system parameters x is known

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Limitations of the Exact Method

even one can overcome the previous two problems, the joint pdf of the natural frequencies given by Eq. (3) is ‘too much information’ to be useful for practical problems because it is not easy to ‘visualize’ the joint pdf in the space of N natural frequencies, and the derivation of the marginal density functions of the natural frequencies from Eq. (3) is not straightforward, especially when N is large.

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Eigenvalues of GOE Matrices

Suppose the system matrix H is from a Gaussian

• rthogonal ensemble (GOE). The pdf of H:

pH(H) = exp

• −θ2Trace
• H2

+ θ1Trace (H) + θ0

• The joint pdf of the natural frequencies:

p Ω (ω1, ω2, · · · , ωN) = exp

• −

N

• j=1

θ2ω4

j − θ1ω2 j − θ0

• i<j
• ω2

j − ω2 i

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Perturbation Method

Taylor series expansion of ωj(x) about the mean x = µ ωj(x) ≈ ωj(µ) + dT

ωj(µ) (x − µ)

+ 1 2 (x − µ)T Dωj(µ) (x − µ) Here dωj(µ) ∈ Rm and Dωj(µ) ∈ Rm×m are respec- tively the gradient vector and the Hessian matrix of ωj(x) evaluated at x = µ.

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Joint Statistics

Joint statistics of the natural frequencies can be

• btained provided it is assumed that the x is
• Gaussian. Assuming x ∼ N(µ, Σ), first few

cumulants can be obtained as κ(1,0)

jk

= E [ωj] = ωj + 1 2Trace

• DωjΣ
• ,

κ(0,1)

jk

= E [ωk] = ωk + 1 2Trace (DωkΣ) , κ(1,1)

jk

= Cov (ωj, ωk) = 1 2Trace

• DωjΣ
• (DωkΣ)
• + dT

ωjΣdωk

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Multidimensional Integrals

We want to evaluate an m-dimensional integral over the unbounded domain Rm: J =

• R

m e−f(x) dx

Assume f(x) is smooth and at least twice differentiable The maximum contribution to this integral comes from the neighborhood where f(x) reaches its global minimum, say θ ∈ Rm

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Multidimensional Integrals

Therefore, at x = θ ∂f(x) ∂xk = 0, ∀k

• r

df (θ) = 0 Expand f(x) in a Taylor series about θ: J =

• R

m e

−

• f(θ)+ 1

2(x−θ) TDf(θ)(x−θ)+ε(x,θ)

• dx

= e−f(θ)

• R

m e− 1 2(x−θ) TDf(θ)(x−θ)−ε(x,θ) dx

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Multidimensional Integrals

The error ε(x, θ) depends on higher derivatives of f(x) at x = θ. If they are small compared to f (θ) their contribution will negligible to the value of the

• integral. So we assume that f(θ) is large so that
• 1

f (θ)D(j)(f (θ))

• → 0

for j > 2 where D(j)(f (θ)) is jth order derivative of f(x) eval- uated at x = θ. Under such assumptions ε(x, θ) → 0.

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Multidimensional Integrals

Use the coordinate transformation: ξ = (x − θ) D−1/2

f

(θ) The Jacobian: J = Df (θ)−1/2 The integral becomes: J ≈ e−f(θ)

• R

m Df (θ)−1/2 e

− 1

2

ξ

Tξ

• dξ
• r

J ≈ (2π)m/2e−f(θ) Df (θ)−1/2

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Moments of Single Eigenvalues

An arbitrary rth order moment of the natural frequencies can be obtained from µ(r)

j

= E

• ωr

j(x)

• =
• R

m ωr

j(x)px(x) dx

=

• R

m e−(L(x)−r ln ωj(x)) dx,

r = 1, 2, 3 · · · Previous result can be used by choosing f(x) = L(x) − r ln ωj(x)

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Moments of Single Eigenvalues

After some simplifications µ(r)

j

≈ (2π)m/2ωr

j(θ)e−L(θ)

• DL(θ) + 1

rdL(θ)dL(θ)T − r ωj(θ)Dωj(θ)

• −1/2

r = 1, 2, 3, · · · θ is obtained from: dωj(θ)r = ωj(θ)dL(θ)

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Maximum Entropy pdf

Constraints for u ∈ [0, ∞]: ∞ pωj(u)du = 1 ∞ urpωj(u)du = µ(r)

j ,

r = 1, 2, 3, · · · , n Maximizing Shannon’s measure of entropy S = − ∞

0 pωj(u) ln pωj(u)du, the pdf of ωj is

pωj(u) = e−{ρ0+n

i=1 ρiui} = e−ρ0e− n i=1 ρiui,

u ≥ 0

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Maximum Entropy pdf

Taking first two moments, the resulting pdf is a truncated Gaussian density function pωj(u) = 1 √ 2πσj Φ ( ωj/σj) exp

• −(u −

ωj)2 2σ2

j

• where σ2

j = µ(2) j

− ω2

j

Ensures that the probability of any natural frequencies becoming negative is zero

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Joint Moments of Two Eigenvalues

Arbitrary r − s-th order joint moment of two natural frequencies µ(rs)

jl

= E

• ωr

j(x)ωs l (x)

• =
• R

m exp {− (L(x) − r ln ωj(x) − s ln ωl(x))} dx,

r = 1, 2, 3 · · · Choose f(x) = L(x) − r ln ωj(x) − s ln ωl(x)

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Joint Moments of Two Eigenvalues

After some simplifications µ(rs)

jl

≈ (2π)m/2ωr

j(θ)ωs l (θ) exp {−L (θ)} Df (θ)−1/2

where θ is obtained from: dL(θ) = r ωj(θ)dωj(θ) + s ωl(θ)dωl(θ) and Df (θ) = DL(θ) +

r ω2

j(θ)dωj(θ)dωj(θ)T −

r ωj(θ)Dωj(θ) + s ω2

l (θ)dωl(θ)dωl(θ)T −

s ωl(θ)Dωl(θ)

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Joint Moments of Multiple Eigenvalues

We want to obtain µ(r1r2···rn)

j1j2···jn

=

• R

m

• ωr1

j1(x)ωr2 j2(x) · · · ωrn jn(x)

• px(x) dx

It can be shown that µ(r1r2···rn)

j1j2···jn

≈ (2π)m/2 ωr1

j1 (θ) ωr2 j2 (θ) · · · ωrn jn (θ)

• exp {−L (θ)} Df (θ)−1/2

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Joint Moments of Multiple Eigenvalues

Here θ is obtained from dL(θ) = r1 ωj1(θ)dωj1(θ)+ r2 ωj1(θ)dωj2(θ)+· · · rn ωjn(θ)dωjn(θ) and the Hessian matrix is given by Df (θ) = DL(θ)+

jn,rn

• j = j1, j2, · · ·

r = r1, r2, · · · r ω2

j (θ)dωj(θ)dωj(θ)T −

r ωj (θ)Dωj(θ)

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Example System

Undamped three degree-of-freedom random system:

m1 m2 m3 k

4

k

5

k

1

k

3

k

2

k

6

mi = 1.0 kg for i = 1, 2, 3; ki = 1.0 N/m for i = 1, · · · , 5 and k6 = 3.0 N/m

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Example System

mi = mi (1 + ǫmxi), i = 1, 2, 3 ki = ki (1 + ǫkxi+3), i = 1, · · · , 6 Vector of random variables: x = {x1, · · · , x9}T ∈ R9 x is standard Gaussian, µ = 0 and Σ = I Strength parameters ǫm = 0.15 and ǫk = 0.20

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Computational Methods

Following four methods are compared

• 1. First-order perturbation
• 2. Second-order perturbation
• 3. Asymptotic method
• 4. Monte Carlo Simulation (15K samples) - can be

considered as benchmark. The percentage error: Error = (•) − (•)MCS (•)MCS × 100

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Scatter of the Eigenvalues

1 1.5 2 2.5 3 3.5 4 100 200 300 400 500 600 700 800 900 1000 Samples Eigenvalues, ωj (rad/s) ω1 ω2 ω3

Statistical scatter of the natural frequencies ω1 = 1, ω2 = 2, and ω3 = 3

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Error in the Mean Values

1 2 3 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1

Eigenvalue number j Percentage error wrt MCS

1st−order perturbation 2nd−order perturbation Asymptotic method

Error in the mean values

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Error in Covariance Matrix

(1,1) (1,2) (1,3) (2,2) (2,3) (3,3) 2 4 6 8 10 12 14 16 Elements of the covariance matrix Percentage error wrt MCS 1st−order perturbation 2nd−order perturbation Asymptotic method

Error in the elements of the covariance matrix

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Mean and Covariance

Using the asymptotic method, the mean and covariance matrix of the natural frequencies are

• btained as

µΩ = {0.9962, 2.0102, 3.0312}T and ΣΩ =   0.5319 0.5643 0.7228 0.5643 2.5705 0.9821 0.7228 0.9821 8.7292   × 10−2 Individual pdf and joint pdf of the natural frequencies are computed using these values.

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Individual pdf

0.5 1 1.5 2 2.5 3 3.5 4 4.5 1 2 3 4 5 6 Natural frequencies (rad/s) pdf of the natural frequencies Asymptotic method Monte Carlo Simulation

Individual pdf of the natural frequencies

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Analytical Joint pdf

Joint pdf using asymptotic method

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Joint pdf from MCS

Joint pdf from Monte Carlo Simulation

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Contours of the joint pdf

0.8 1 1.2 1.4 1.6 1.8 2 2.2 2.4 2.6 1.5 2 2.5 3 3.5 4 (ω1,ω3) (ω1,ω2) (ω2,ω3) ωj (rad/s) ωk (rad/s) Asymptotic method Monte Carlo Simulation

Contours of the joint pdf

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Conclusions

Statistics of the natural frequencies of linear stochastic dynamic systems has been considered usual assumption of small randomness is not employed in this study. a general expression of the joint pdf of the natural frequencies of linear stochastic systems has been given

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Conclusions

a closed-form expression is obtained for the general order joint moments of the eigenvalues it was observed that the natural frequencies are not jointly Gaussian even they are so individually future studies will consider joint statistics of the eigenvalues and eigenvectors and dynamic response analysis using eigensolution distributions

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References

Muirhead, R. J. (1982), Aspects of Multivariate Statistical Theory, John Wiely and Sons, New York, USA.

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