QTL Association Mapping
1 / 38
QTL Association Mapping 1 / 38 Introduction to Quantitative Trait - - PowerPoint PPT Presentation
QTL Association Mapping 1 / 38 Introduction to Quantitative Trait Mapping We previously focused on obtaining variance components of a quantitative trait to determine the proportion of the variance of the trait that can be attributed to both
1 / 38
2 / 38
3 / 38
◮ QTL association mapping ◮ Contribution of a QTL to the variance of a quantitative trait ◮ Statistical power for detecting QTL in GWAS
4 / 38
ij +δij = µG +αi +αj +δij
5 / 38
1 +δij
1 is the number of copies of the type A1 allele in genotype
6 / 38
Var (X) = Regression Variance + Residual Variance = Additive Variance + Dominance Variance
15 7 / 38
8 / 38
Aa aa cholesterol
9 / 38
Aa aa cholesterol
10 / 38
Aa aa cholesterol
11 / 38
Aa aa cholesterol
12 / 38
◮ population structure, i.e., ancestry differences among sample individuals ◮ relatedness among the sampled individuals, some of which might be
13 / 38
14 / 38
◮ Test for association between genotype and trait value
Histogram of Trait Values
Population 1 Population 2
◮ Blue population has higher trait values. ◮ Different allele frequency in each population
15 / 38
16 / 38
17 / 38
1,...G s n)T is n ×1 vector of the genotypes,
i = 0,1, or 2, according to whether individual i has,
18 / 38
g Ψ)
g represents additive genetic variance and Ψ is a matrix of pairwise
e I)
e represents non-genetic variance due to non-genetic effects
19 / 38
S
s=1
i −2ˆ
j −2ˆ
Kang, Hyun Min, et al. (2010) ”Variance component model to account for sample structure in genome-wide association studies.” Nature genetics 42
20 / 38
g and σ2 e , are then estimated using either
g ˆ
e I in the likelihood with fixed ˆ
21 / 38
g and σ2 e are then estimated,
g ˆ
e I
g and ˆ
e only once from model (1) to reduce
22 / 38
g and ˆ
e for
Zhou and Stephens (2012) ”Genome-wide efficient mixed-model analysis for association studies” Nature Genetics 44
23 / 38
24 / 38
25 / 38
26 / 38
27 / 38
1
1 for large N
ε
28 / 38
Y = 1.
Y = β 2 1 σ2 X +σ2 ε = 2p(1−p)β 2 1 +σ2 ε
s = 2p(1−p)β 2 1 , so we have σ2 Y = h2 s +σ2 ε
s (note that we assume that trait is standardized such that
Y = 1)
29 / 38
ε = 1−h2 s , so we can write Var( ˆ
ε
ε
s
1
s
s
s = 2p(1−p)β 2 1
30 / 38
s
s
31 / 38
32 / 38
23 33 / 38
– >.10+10C%<a%mI4I%-'%mI4d – h*+,-.-+-./0%-(+.-1C%n%/+(%0E8?+.,0;%
Disease Number
Percent of Heritability Measure Explained Heritability Measure Age-related macular degeneration 5 50% Sibling recurrence risk Crohn’s disease 32 20% Genetic risk (liability) Systemic lupus erythematosus 6 15% Sibling recurrence risk Type 2 diabetes 18 6% Sibling recurrence risk HDL cholesterol 7 5.2% Phenotypic variance Height 40 5% Phenotypic variance Early onset myocardial infarction 9 2.8% Phenotypic variance Fasting glucose 4 1.5% Phenotypic variance
34 / 38
35 / 38
#$%&'()*)+,$-$./$,0**********************#$%&'()*1$2)+,$-$./$,0
Q1 M1 Q2 M2 Q1 M2 Q2 M1 Q1 M1 Q2 M2 Q1 M2 Q2 M1 Q1 M1 Q1 M1 Q2 M2 Q2 M2 Q1 M1 Q2 M2 Q1 M1 Q2 M2 36 / 38
[Ardlie et al. 2002]
5 37 / 38
s
s
s
38 / 38