Polygons as optimal shapes with convexity constraint Jimmy Lamboley - - PowerPoint PPT Presentation

polygons as optimal shapes with convexity constraint
SMART_READER_LITE
LIVE PREVIEW

Polygons as optimal shapes with convexity constraint Jimmy Lamboley - - PowerPoint PPT Presentation

Polygons as optimal shapes with convexity constraint Jimmy Lamboley Arian Novruzi Ecole Normale Sup erieure de Cachan University of Ottawa Antenne de Bretagne, France Ontario, Canada Conference on Applied Inverse Problems Non-smooth


slide-1
SLIDE 1

Polygons as optimal shapes with convexity constraint

Jimmy Lamboley Arian Novruzi ´ Ecole Normale Sup´ erieure de Cachan University of Ottawa Antenne de Bretagne, France Ontario, Canada Conference on Applied Inverse Problems

Non-smooth Optimization in Inverse Problems

Vienna, Austria, July 20-24

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-2
SLIDE 2

The problem

We consider the problem min

  • j(u) :=
  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} , (1) where G(θ, u, p) : ❚ × (0, ∞) × ❘ → ❘, ❚ = [0, 2π). When (1) has for solution a polygon? We are interested also in min {j(u), u ∈ W 1,∞(❚), u′′ + u ≥ 0, m(u) := 1

2

dθ u2 = m0 > 0

  • .

(2)

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-3
SLIDE 3

The problem

We consider the problem min

  • j(u) :=
  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} , (1) where G(θ, u, p) : ❚ × (0, ∞) × ❘ → ❘, ❚ = [0, 2π). When (1) has for solution a polygon? We are interested also in min {j(u), u ∈ W 1,∞(❚), u′′ + u ≥ 0, m(u) := 1

2

dθ u2 = m0 > 0

  • .

(2)

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-4
SLIDE 4

The problem

We consider the problem min

  • j(u) :=
  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} , (1) where G(θ, u, p) : ❚ × (0, ∞) × ❘ → ❘, ❚ = [0, 2π). When (1) has for solution a polygon? We are interested also in min {j(u), u ∈ W 1,∞(❚), u′′ + u ≥ 0, m(u) := 1

2

dθ u2 = m0 > 0

  • .

(2)

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-5
SLIDE 5

The problem

We consider the problem min

  • j(u) :=
  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} , (1) where G(θ, u, p) : ❚ × (0, ∞) × ❘ → ❘, ❚ = [0, 2π). When (1) has for solution a polygon? We are interested also in min {j(u), u ∈ W 1,∞(❚), u′′ + u ≥ 0, m(u) := 1

2

dθ u2 = m0 > 0

  • .

(2)

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-6
SLIDE 6

Motivation

  • T. Lachand-Robert and M.A. Peletier

Newton’s problem: Find U0 solution of: min{E(U), U ∈ Fad}, E(U) =

dx 1 + |∇U|2 Fad = {U : Ω → [0, M] : with graph in conv. env. of ∂Ω × {0} ∪ {U = M} × {M}} Ω ⊂ ❘2 a disk, M > 0 Newton found a radially symmetric minimizer In 1996, Brock, Ferone, and Kawohl: the minimizer is not radially symmetric min{G(θ, u, p) := h1(u) − p2h2(u), u ∈ Fad}, with Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Here u characterizes N := {U = M} The minimizer u0: supp(u′′

0 + u0) is finite

The set N0 := {U0 = M} is a regular polygon centered in Ω

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-7
SLIDE 7

Motivation

  • T. Lachand-Robert and M.A. Peletier

Newton’s problem: Find U0 solution of: min{E(U), U ∈ Fad}, E(U) =

dx 1 + |∇U|2 Fad = {U : Ω → [0, M] : with graph in conv. env. of ∂Ω × {0} ∪ {U = M} × {M}} Ω ⊂ ❘2 a disk, M > 0 Newton found a radially symmetric minimizer In 1996, Brock, Ferone, and Kawohl: the minimizer is not radially symmetric min{G(θ, u, p) := h1(u) − p2h2(u), u ∈ Fad}, with Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Here u characterizes N := {U = M} The minimizer u0: supp(u′′

0 + u0) is finite

The set N0 := {U0 = M} is a regular polygon centered in Ω

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-8
SLIDE 8

Motivation

  • T. Lachand-Robert and M.A. Peletier

Newton’s problem: Find U0 solution of: min{E(U), U ∈ Fad}, E(U) =

dx 1 + |∇U|2 Fad = {U : Ω → [0, M] : with graph in conv. env. of ∂Ω × {0} ∪ {U = M} × {M}} Ω ⊂ ❘2 a disk, M > 0 Newton found a radially symmetric minimizer In 1996, Brock, Ferone, and Kawohl: the minimizer is not radially symmetric min{G(θ, u, p) := h1(u) − p2h2(u), u ∈ Fad}, with Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Here u characterizes N := {U = M} The minimizer u0: supp(u′′

0 + u0) is finite

The set N0 := {U0 = M} is a regular polygon centered in Ω

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-9
SLIDE 9

Motivation

  • T. Lachand-Robert and M.A. Peletier

Newton’s problem: Find U0 solution of: min{E(U), U ∈ Fad}, E(U) =

dx 1 + |∇U|2 Fad = {U : Ω → [0, M] : with graph in conv. env. of ∂Ω × {0} ∪ {U = M} × {M}} Ω ⊂ ❘2 a disk, M > 0 Newton found a radially symmetric minimizer In 1996, Brock, Ferone, and Kawohl: the minimizer is not radially symmetric min{G(θ, u, p) := h1(u) − p2h2(u), u ∈ Fad}, with Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Here u characterizes N := {U = M} The minimizer u0: supp(u′′

0 + u0) is finite

The set N0 := {U0 = M} is a regular polygon centered in Ω

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-10
SLIDE 10

Motivation

  • T. Lachand-Robert and M.A. Peletier

Newton’s problem: Find U0 solution of: min{E(U), U ∈ Fad}, E(U) =

dx 1 + |∇U|2 Fad = {U : Ω → [0, M] : with graph in conv. env. of ∂Ω × {0} ∪ {U = M} × {M}} Ω ⊂ ❘2 a disk, M > 0 Newton found a radially symmetric minimizer In 1996, Brock, Ferone, and Kawohl: the minimizer is not radially symmetric min{G(θ, u, p) := h1(u) − p2h2(u), u ∈ Fad}, with Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Here u characterizes N := {U = M} The minimizer u0: supp(u′′

0 + u0) is finite

The set N0 := {U0 = M} is a regular polygon centered in Ω

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-11
SLIDE 11

Motivation

  • T. Lachand-Robert and M.A. Peletier

Newton’s problem: Find U0 solution of: min{E(U), U ∈ Fad}, E(U) =

dx 1 + |∇U|2 Fad = {U : Ω → [0, M] : with graph in conv. env. of ∂Ω × {0} ∪ {U = M} × {M}} Ω ⊂ ❘2 a disk, M > 0 Newton found a radially symmetric minimizer In 1996, Brock, Ferone, and Kawohl: the minimizer is not radially symmetric min{G(θ, u, p) := h1(u) − p2h2(u), u ∈ Fad}, with Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Here u characterizes N := {U = M} The minimizer u0: supp(u′′

0 + u0) is finite

The set N0 := {U0 = M} is a regular polygon centered in Ω

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-12
SLIDE 12

Motivation

  • T. Lachand-Robert and M.A. Peletier

Newton’s problem: Find U0 solution of: min{E(U), U ∈ Fad}, E(U) =

dx 1 + |∇U|2 Fad = {U : Ω → [0, M] : with graph in conv. env. of ∂Ω × {0} ∪ {U = M} × {M}} Ω ⊂ ❘2 a disk, M > 0 Newton found a radially symmetric minimizer In 1996, Brock, Ferone, and Kawohl: the minimizer is not radially symmetric min{G(θ, u, p) := h1(u) − p2h2(u), u ∈ Fad}, with Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Here u characterizes N := {U = M} The minimizer u0: supp(u′′

0 + u0) is finite

The set N0 := {U0 = M} is a regular polygon centered in Ω

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-13
SLIDE 13

Motivation

  • T. Lachand-Robert and M.A. Peletier

Newton’s problem: Find U0 solution of: min{E(U), U ∈ Fad}, E(U) =

dx 1 + |∇U|2 Fad = {U : Ω → [0, M] : with graph in conv. env. of ∂Ω × {0} ∪ {U = M} × {M}} Ω ⊂ ❘2 a disk, M > 0 Newton found a radially symmetric minimizer In 1996, Brock, Ferone, and Kawohl: the minimizer is not radially symmetric min{G(θ, u, p) := h1(u) − p2h2(u), u ∈ Fad}, with Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Here u characterizes N := {U = M} The minimizer u0: supp(u′′

0 + u0) is finite

The set N0 := {U0 = M} is a regular polygon centered in Ω

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-14
SLIDE 14

Motivation

  • T. Lachand-Robert and M.A. Peletier

Newton’s problem: Find U0 solution of: min{E(U), U ∈ Fad}, E(U) =

dx 1 + |∇U|2 Fad = {U : Ω → [0, M] : with graph in conv. env. of ∂Ω × {0} ∪ {U = M} × {M}} Ω ⊂ ❘2 a disk, M > 0 Newton found a radially symmetric minimizer In 1996, Brock, Ferone, and Kawohl: the minimizer is not radially symmetric min{G(θ, u, p) := h1(u) − p2h2(u), u ∈ Fad}, with Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Here u characterizes N := {U = M} The minimizer u0: supp(u′′

0 + u0) is finite

The set N0 := {U0 = M} is a regular polygon centered in Ω

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-15
SLIDE 15

Motivation

  • T. Lachand-Robert and M.A. Peletier

Newton’s problem: Find U0 solution of: min{E(U), U ∈ Fad}, E(U) =

dx 1 + |∇U|2 Fad = {U : Ω → [0, M] : with graph in conv. env. of ∂Ω × {0} ∪ {U = M} × {M}} Ω ⊂ ❘2 a disk, M > 0 Newton found a radially symmetric minimizer In 1996, Brock, Ferone, and Kawohl: the minimizer is not radially symmetric min{G(θ, u, p) := h1(u) − p2h2(u), u ∈ Fad}, with Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Here u characterizes N := {U = M} The minimizer u0: supp(u′′

0 + u0) is finite

The set N0 := {U0 = M} is a regular polygon centered in Ω

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-16
SLIDE 16

Motivation

Figure: Minimizer U0 as a function of M

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-17
SLIDE 17

Motivation

Figure: Minimizer U0 as a function of M

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-18
SLIDE 18

Motivation

  • M. Crouzeix

motivated by abstract operator theory: G(θ, u, p) = h(p/u), u = 1

r

and Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Optimal shapes are polygons Furthermore:

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-19
SLIDE 19

Motivation

  • M. Crouzeix

motivated by abstract operator theory: G(θ, u, p) = h(p/u), u = 1

r

and Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Optimal shapes are polygons Furthermore:

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-20
SLIDE 20

Motivation

  • M. Crouzeix

motivated by abstract operator theory: G(θ, u, p) = h(p/u), u = 1

r

and Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Optimal shapes are polygons Furthermore:

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-21
SLIDE 21

Motivation

  • M. Crouzeix

motivated by abstract operator theory: G(θ, u, p) = h(p/u), u = 1

r

and Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Optimal shapes are polygons Furthermore:

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-22
SLIDE 22

Motivation

  • M. Crouzeix

motivated by abstract operator theory: G(θ, u, p) = h(p/u), u = 1

r

and Fad = {u regular enough, u′′ + u ≥ 0, 0 < a ≤ u ≤ b} Optimal shapes are polygons Furthermore:

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-23
SLIDE 23

The problem: shape problem with convexity constraint

Our initial problem is: min{J(Ω), Ω convex, Ω ∈ Sad}, where Sad is a set of 2-dimensional admissible shapes, J : Sad → ❘ is a shape functional Parametrization of Ω:

W 1,∞(❚) := W 1,∞

loc (❘) ∩ {2π-periodic}

Ωu :=

  • (r, θ) ∈ [0, 2π] ×
  • 0,

1 u(θ)

  • ,

0 < u ∈ W 1,∞(❚)

  • .

The curvature: κ(Ωu) =

u′′+u (1+u′2)3/2 .

If u ∈ W 1,∞(❚), we say that u′′ + u ≥ 0 if ∀ v ∈ W 1,∞(❚) with v ≥ 0,

  • uv − u′v′

dθ ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-24
SLIDE 24

The problem: shape problem with convexity constraint

Our initial problem is: min{J(Ω), Ω convex, Ω ∈ Sad}, where Sad is a set of 2-dimensional admissible shapes, J : Sad → ❘ is a shape functional Parametrization of Ω:

W 1,∞(❚) := W 1,∞

loc (❘) ∩ {2π-periodic}

Ωu :=

  • (r, θ) ∈ [0, 2π] ×
  • 0,

1 u(θ)

  • ,

0 < u ∈ W 1,∞(❚)

  • .

The curvature: κ(Ωu) =

u′′+u (1+u′2)3/2 .

If u ∈ W 1,∞(❚), we say that u′′ + u ≥ 0 if ∀ v ∈ W 1,∞(❚) with v ≥ 0,

  • uv − u′v′

dθ ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-25
SLIDE 25

The problem: shape problem with convexity constraint

Our initial problem is: min{J(Ω), Ω convex, Ω ∈ Sad}, where Sad is a set of 2-dimensional admissible shapes, J : Sad → ❘ is a shape functional Parametrization of Ω:

W 1,∞(❚) := W 1,∞

loc (❘) ∩ {2π-periodic}

Ωu :=

  • (r, θ) ∈ [0, 2π] ×
  • 0,

1 u(θ)

  • ,

0 < u ∈ W 1,∞(❚)

  • .

The curvature: κ(Ωu) =

u′′+u (1+u′2)3/2 .

If u ∈ W 1,∞(❚), we say that u′′ + u ≥ 0 if ∀ v ∈ W 1,∞(❚) with v ≥ 0,

  • uv − u′v′

dθ ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-26
SLIDE 26

The problem: shape problem with convexity constraint

Our initial problem is: min{J(Ω), Ω convex, Ω ∈ Sad}, where Sad is a set of 2-dimensional admissible shapes, J : Sad → ❘ is a shape functional Parametrization of Ω:

W 1,∞(❚) := W 1,∞

loc (❘) ∩ {2π-periodic}

Ωu :=

  • (r, θ) ∈ [0, 2π] ×
  • 0,

1 u(θ)

  • ,

0 < u ∈ W 1,∞(❚)

  • .

The curvature: κ(Ωu) =

u′′+u (1+u′2)3/2 .

If u ∈ W 1,∞(❚), we say that u′′ + u ≥ 0 if ∀ v ∈ W 1,∞(❚) with v ≥ 0,

  • uv − u′v′

dθ ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-27
SLIDE 27

The problem: shape problem with convexity constraint

Our initial problem is: min{J(Ω), Ω convex, Ω ∈ Sad}, where Sad is a set of 2-dimensional admissible shapes, J : Sad → ❘ is a shape functional Parametrization of Ω:

W 1,∞(❚) := W 1,∞

loc (❘) ∩ {2π-periodic}

Ωu :=

  • (r, θ) ∈ [0, 2π] ×
  • 0,

1 u(θ)

  • ,

0 < u ∈ W 1,∞(❚)

  • .

The curvature: κ(Ωu) =

u′′+u (1+u′2)3/2 .

If u ∈ W 1,∞(❚), we say that u′′ + u ≥ 0 if ∀ v ∈ W 1,∞(❚) with v ≥ 0,

  • uv − u′v′

dθ ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-28
SLIDE 28

The problem: shape problem with convexity constraint

Our initial problem is: min{J(Ω), Ω convex, Ω ∈ Sad}, where Sad is a set of 2-dimensional admissible shapes, J : Sad → ❘ is a shape functional Parametrization of Ω:

W 1,∞(❚) := W 1,∞

loc (❘) ∩ {2π-periodic}

Ωu :=

  • (r, θ) ∈ [0, 2π] ×
  • 0,

1 u(θ)

  • ,

0 < u ∈ W 1,∞(❚)

  • .

The curvature: κ(Ωu) =

u′′+u (1+u′2)3/2 .

If u ∈ W 1,∞(❚), we say that u′′ + u ≥ 0 if ∀ v ∈ W 1,∞(❚) with v ≥ 0,

  • uv − u′v′

dθ ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-29
SLIDE 29

The problem: shape problem with convexity constraint

Our initial problem is: min{J(Ω), Ω convex, Ω ∈ Sad}, where Sad is a set of 2-dimensional admissible shapes, J : Sad → ❘ is a shape functional Parametrization of Ω:

W 1,∞(❚) := W 1,∞

loc (❘) ∩ {2π-periodic}

Ωu :=

  • (r, θ) ∈ [0, 2π] ×
  • 0,

1 u(θ)

  • ,

0 < u ∈ W 1,∞(❚)

  • .

The curvature: κ(Ωu) =

u′′+u (1+u′2)3/2 .

If u ∈ W 1,∞(❚), we say that u′′ + u ≥ 0 if ∀ v ∈ W 1,∞(❚) with v ≥ 0,

  • uv − u′v′

dθ ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-30
SLIDE 30

The problem: reformulation

For u ∈ W 1,∞(❚):

Ωu is convex ⇐ ⇒ u′′ + u ≥ 0 in M(❚) straight lines on ∂Ωu: {u′′ + u = 0} corners on the boundary ∂Ωu: u′′ + u = αnδn

We consider: find u0 ∈ Fad: j(u0) = min{j(u) :=

  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, u ∈ Fad}, where Fad is a set of convenient admissible functions. Choices of Fad: i) Fad :=

  • u : ∂Ωu ⊂ A(a, b) :=
  • (r, θ) :

1 b ≤ r ≤ 1 a

ii) Fad := {u : u ∈ C(m0)}, C(m0) :=

  • u :

1 2

dθ u2 = m0

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-31
SLIDE 31

The problem: reformulation

For u ∈ W 1,∞(❚):

Ωu is convex ⇐ ⇒ u′′ + u ≥ 0 in M(❚) straight lines on ∂Ωu: {u′′ + u = 0} corners on the boundary ∂Ωu: u′′ + u = αnδn

We consider: find u0 ∈ Fad: j(u0) = min{j(u) :=

  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, u ∈ Fad}, where Fad is a set of convenient admissible functions. Choices of Fad: i) Fad :=

  • u : ∂Ωu ⊂ A(a, b) :=
  • (r, θ) :

1 b ≤ r ≤ 1 a

ii) Fad := {u : u ∈ C(m0)}, C(m0) :=

  • u :

1 2

dθ u2 = m0

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-32
SLIDE 32

The problem: reformulation

For u ∈ W 1,∞(❚):

Ωu is convex ⇐ ⇒ u′′ + u ≥ 0 in M(❚) straight lines on ∂Ωu: {u′′ + u = 0} corners on the boundary ∂Ωu: u′′ + u = αnδn

We consider: find u0 ∈ Fad: j(u0) = min{j(u) :=

  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, u ∈ Fad}, where Fad is a set of convenient admissible functions. Choices of Fad: i) Fad :=

  • u : ∂Ωu ⊂ A(a, b) :=
  • (r, θ) :

1 b ≤ r ≤ 1 a

ii) Fad := {u : u ∈ C(m0)}, C(m0) :=

  • u :

1 2

dθ u2 = m0

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-33
SLIDE 33

The problem: reformulation

For u ∈ W 1,∞(❚):

Ωu is convex ⇐ ⇒ u′′ + u ≥ 0 in M(❚) straight lines on ∂Ωu: {u′′ + u = 0} corners on the boundary ∂Ωu: u′′ + u = αnδn

We consider: find u0 ∈ Fad: j(u0) = min{j(u) :=

  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, u ∈ Fad}, where Fad is a set of convenient admissible functions. Choices of Fad: i) Fad :=

  • u : ∂Ωu ⊂ A(a, b) :=
  • (r, θ) :

1 b ≤ r ≤ 1 a

ii) Fad := {u : u ∈ C(m0)}, C(m0) :=

  • u :

1 2

dθ u2 = m0

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-34
SLIDE 34

The problem: reformulation

For u ∈ W 1,∞(❚):

Ωu is convex ⇐ ⇒ u′′ + u ≥ 0 in M(❚) straight lines on ∂Ωu: {u′′ + u = 0} corners on the boundary ∂Ωu: u′′ + u = αnδn

We consider: find u0 ∈ Fad: j(u0) = min{j(u) :=

  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, u ∈ Fad}, where Fad is a set of convenient admissible functions. Choices of Fad: i) Fad :=

  • u : ∂Ωu ⊂ A(a, b) :=
  • (r, θ) :

1 b ≤ r ≤ 1 a

ii) Fad := {u : u ∈ C(m0)}, C(m0) :=

  • u :

1 2

dθ u2 = m0

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-35
SLIDE 35

The problem: reformulation

For u ∈ W 1,∞(❚):

Ωu is convex ⇐ ⇒ u′′ + u ≥ 0 in M(❚) straight lines on ∂Ωu: {u′′ + u = 0} corners on the boundary ∂Ωu: u′′ + u = αnδn

We consider: find u0 ∈ Fad: j(u0) = min{j(u) :=

  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, u ∈ Fad}, where Fad is a set of convenient admissible functions. Choices of Fad: i) Fad :=

  • u : ∂Ωu ⊂ A(a, b) :=
  • (r, θ) :

1 b ≤ r ≤ 1 a

ii) Fad := {u : u ∈ C(m0)}, C(m0) :=

  • u :

1 2

dθ u2 = m0

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-36
SLIDE 36

The problem: reformulation

For u ∈ W 1,∞(❚):

Ωu is convex ⇐ ⇒ u′′ + u ≥ 0 in M(❚) straight lines on ∂Ωu: {u′′ + u = 0} corners on the boundary ∂Ωu: u′′ + u = αnδn

We consider: find u0 ∈ Fad: j(u0) = min{j(u) :=

  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, u ∈ Fad}, where Fad is a set of convenient admissible functions. Choices of Fad: i) Fad :=

  • u : ∂Ωu ⊂ A(a, b) :=
  • (r, θ) :

1 b ≤ r ≤ 1 a

ii) Fad := {u : u ∈ C(m0)}, C(m0) :=

  • u :

1 2

dθ u2 = m0

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-37
SLIDE 37

The problem: reformulation

For u ∈ W 1,∞(❚):

Ωu is convex ⇐ ⇒ u′′ + u ≥ 0 in M(❚) straight lines on ∂Ωu: {u′′ + u = 0} corners on the boundary ∂Ωu: u′′ + u = αnδn

We consider: find u0 ∈ Fad: j(u0) = min{j(u) :=

  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, u ∈ Fad}, where Fad is a set of convenient admissible functions. Choices of Fad: i) Fad :=

  • u : ∂Ωu ⊂ A(a, b) :=
  • (r, θ) :

1 b ≤ r ≤ 1 a

ii) Fad := {u : u ∈ C(m0)}, C(m0) :=

  • u :

1 2

dθ u2 = m0

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-38
SLIDE 38

The problem: reformulation

For u ∈ W 1,∞(❚):

Ωu is convex ⇐ ⇒ u′′ + u ≥ 0 in M(❚) straight lines on ∂Ωu: {u′′ + u = 0} corners on the boundary ∂Ωu: u′′ + u = αnδn

We consider: find u0 ∈ Fad: j(u0) = min{j(u) :=

  • ❚ G(θ, u, u′)dθ,

u ∈ W 1,∞(❚), u′′ + u ≥ 0, u ∈ Fad}, where Fad is a set of convenient admissible functions. Choices of Fad: i) Fad :=

  • u : ∂Ωu ⊂ A(a, b) :=
  • (r, θ) :

1 b ≤ r ≤ 1 a

ii) Fad := {u : u ∈ C(m0)}, C(m0) :=

  • u :

1 2

dθ u2 = m0

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-39
SLIDE 39

Main results: existence

The problem (1) (with inclusion in A(a, b)) has a solution if, for example,

j(u) is continuous in H1(❚), because {u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} is strongly compact in H1(❚)

The problem (2) (with area constraint)

the question is more case specific. For example: maximization of the perimeter: non-existence However, existence may be proved for many further functionals

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-40
SLIDE 40

Main results: existence

The problem (1) (with inclusion in A(a, b)) has a solution if, for example,

j(u) is continuous in H1(❚), because {u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} is strongly compact in H1(❚)

The problem (2) (with area constraint)

the question is more case specific. For example: maximization of the perimeter: non-existence However, existence may be proved for many further functionals

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-41
SLIDE 41

Main results: existence

The problem (1) (with inclusion in A(a, b)) has a solution if, for example,

j(u) is continuous in H1(❚), because {u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} is strongly compact in H1(❚)

The problem (2) (with area constraint)

the question is more case specific. For example: maximization of the perimeter: non-existence However, existence may be proved for many further functionals

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-42
SLIDE 42

Main results: existence

The problem (1) (with inclusion in A(a, b)) has a solution if, for example,

j(u) is continuous in H1(❚), because {u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} is strongly compact in H1(❚)

The problem (2) (with area constraint)

the question is more case specific. For example: maximization of the perimeter: non-existence However, existence may be proved for many further functionals

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-43
SLIDE 43

Main results: existence

The problem (1) (with inclusion in A(a, b)) has a solution if, for example,

j(u) is continuous in H1(❚), because {u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} is strongly compact in H1(❚)

The problem (2) (with area constraint)

the question is more case specific. For example: maximization of the perimeter: non-existence However, existence may be proved for many further functionals

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-44
SLIDE 44

Main results: existence

The problem (1) (with inclusion in A(a, b)) has a solution if, for example,

j(u) is continuous in H1(❚), because {u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} is strongly compact in H1(❚)

The problem (2) (with area constraint)

the question is more case specific. For example: maximization of the perimeter: non-existence However, existence may be proved for many further functionals

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-45
SLIDE 45

Main results: existence

The problem (1) (with inclusion in A(a, b)) has a solution if, for example,

j(u) is continuous in H1(❚), because {u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} is strongly compact in H1(❚)

The problem (2) (with area constraint)

the question is more case specific. For example: maximization of the perimeter: non-existence However, existence may be proved for many further functionals

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-46
SLIDE 46

Main results: existence

The problem (1) (with inclusion in A(a, b)) has a solution if, for example,

j(u) is continuous in H1(❚), because {u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} is strongly compact in H1(❚)

The problem (2) (with area constraint)

the question is more case specific. For example: maximization of the perimeter: non-existence However, existence may be proved for many further functionals

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-47
SLIDE 47

Main results: existence

The problem (1) (with inclusion in A(a, b)) has a solution if, for example,

j(u) is continuous in H1(❚), because {u ∈ W 1,∞(❚), u′′ + u ≥ 0, a ≤ u ≤ b} is strongly compact in H1(❚)

The problem (2) (with area constraint)

the question is more case specific. For example: maximization of the perimeter: non-existence However, existence may be proved for many further functionals

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-48
SLIDE 48

Main results: regularity

Theorem 0.1

1 Let G = G(θ, u, p) ∈ C2(❚ × ❘ × ❘). Set j(u) =

  • ❚ G(θ, u, u′).

2 Let u0 be a solution of (1) or (2) and assume that G satisfies:

Gpp(θ, u0, u′

0) < 0,

∀θ ∈ ❚. (3)

3 If u0 is a solution of (1), then:

Su0 ∩ I is finite for any I = (γ1, γ2) ⊂ {a < u0(θ) < b}, and in particular, Ωu0 is locally polygonal inside the annulus A(a, b).

4 If u0 > 0 is a solution of (2), then Su0 ∩ ❚ is finite, and so

Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-49
SLIDE 49

Main results: regularity

Theorem 0.1

1 Let G = G(θ, u, p) ∈ C2(❚ × ❘ × ❘). Set j(u) =

  • ❚ G(θ, u, u′).

2 Let u0 be a solution of (1) or (2) and assume that G satisfies:

Gpp(θ, u0, u′

0) < 0,

∀θ ∈ ❚. (3)

3 If u0 is a solution of (1), then:

Su0 ∩ I is finite for any I = (γ1, γ2) ⊂ {a < u0(θ) < b}, and in particular, Ωu0 is locally polygonal inside the annulus A(a, b).

4 If u0 > 0 is a solution of (2), then Su0 ∩ ❚ is finite, and so

Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-50
SLIDE 50

Main results: regularity

Theorem 0.1

1 Let G = G(θ, u, p) ∈ C2(❚ × ❘ × ❘). Set j(u) =

  • ❚ G(θ, u, u′).

2 Let u0 be a solution of (1) or (2) and assume that G satisfies:

Gpp(θ, u0, u′

0) < 0,

∀θ ∈ ❚. (3)

3 If u0 is a solution of (1), then:

Su0 ∩ I is finite for any I = (γ1, γ2) ⊂ {a < u0(θ) < b}, and in particular, Ωu0 is locally polygonal inside the annulus A(a, b).

4 If u0 > 0 is a solution of (2), then Su0 ∩ ❚ is finite, and so

Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-51
SLIDE 51

Main results: regularity

Theorem 0.1

1 Let G = G(θ, u, p) ∈ C2(❚ × ❘ × ❘). Set j(u) =

  • ❚ G(θ, u, u′).

2 Let u0 be a solution of (1) or (2) and assume that G satisfies:

Gpp(θ, u0, u′

0) < 0,

∀θ ∈ ❚. (3)

3 If u0 is a solution of (1), then:

Su0 ∩ I is finite for any I = (γ1, γ2) ⊂ {a < u0(θ) < b}, and in particular, Ωu0 is locally polygonal inside the annulus A(a, b).

4 If u0 > 0 is a solution of (2), then Su0 ∩ ❚ is finite, and so

Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-52
SLIDE 52

Main results: regularity

Theorem 0.1

1 Let G = G(θ, u, p) ∈ C2(❚ × ❘ × ❘). Set j(u) =

  • ❚ G(θ, u, u′).

2 Let u0 be a solution of (1) or (2) and assume that G satisfies:

Gpp(θ, u0, u′

0) < 0,

∀θ ∈ ❚. (3)

3 If u0 is a solution of (1), then:

Su0 ∩ I is finite for any I = (γ1, γ2) ⊂ {a < u0(θ) < b}, and in particular, Ωu0 is locally polygonal inside the annulus A(a, b).

4 If u0 > 0 is a solution of (2), then Su0 ∩ ❚ is finite, and so

Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-53
SLIDE 53

Main results: regularity

Theorem 0.1

1 Let G = G(θ, u, p) ∈ C2(❚ × ❘ × ❘). Set j(u) =

  • ❚ G(θ, u, u′).

2 Let u0 be a solution of (1) or (2) and assume that G satisfies:

Gpp(θ, u0, u′

0) < 0,

∀θ ∈ ❚. (3)

3 If u0 is a solution of (1), then:

Su0 ∩ I is finite for any I = (γ1, γ2) ⊂ {a < u0(θ) < b}, and in particular, Ωu0 is locally polygonal inside the annulus A(a, b).

4 If u0 > 0 is a solution of (2), then Su0 ∩ ❚ is finite, and so

Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-54
SLIDE 54

Main results: regularity

Theorem 0.1

1 Let G = G(θ, u, p) ∈ C2(❚ × ❘ × ❘). Set j(u) =

  • ❚ G(θ, u, u′).

2 Let u0 be a solution of (1) or (2) and assume that G satisfies:

Gpp(θ, u0, u′

0) < 0,

∀θ ∈ ❚. (3)

3 If u0 is a solution of (1), then:

Su0 ∩ I is finite for any I = (γ1, γ2) ⊂ {a < u0(θ) < b}, and in particular, Ωu0 is locally polygonal inside the annulus A(a, b).

4 If u0 > 0 is a solution of (2), then Su0 ∩ ❚ is finite, and so

Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-55
SLIDE 55

Main results: regularity (cont’d)

Theorem 0.2 (inclusion in annulus A(a, b))

1 Let j(u) =

  • ❚ G(u, u′), u0 be a solution of (1). Assume that

2 (i) G = G(u, p) is a C2 function and

Gpp < 0 on {(u0(θ), u′

0(θ)), θ ∈ ❚},

3 (ii) The function p → G(a, p) is even and one of the

followings holds

(ii.1): Gu(a, 0) < 0, or (ii.2): Gu(a, 0) = 0 and Gu(u0, u′

0)u0 + Gp(u0, u′ 0)u′ 0 ≤ 0,

4 (iii) The function p → G(·, p) is even and Gu ≥ 0 near (b, 0). 5 Then Su0 is finite, i.e. Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-56
SLIDE 56

Main results: regularity (cont’d)

Theorem 0.2 (inclusion in annulus A(a, b))

1 Let j(u) =

  • ❚ G(u, u′), u0 be a solution of (1). Assume that

2 (i) G = G(u, p) is a C2 function and

Gpp < 0 on {(u0(θ), u′

0(θ)), θ ∈ ❚},

3 (ii) The function p → G(a, p) is even and one of the

followings holds

(ii.1): Gu(a, 0) < 0, or (ii.2): Gu(a, 0) = 0 and Gu(u0, u′

0)u0 + Gp(u0, u′ 0)u′ 0 ≤ 0,

4 (iii) The function p → G(·, p) is even and Gu ≥ 0 near (b, 0). 5 Then Su0 is finite, i.e. Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-57
SLIDE 57

Main results: regularity (cont’d)

Theorem 0.2 (inclusion in annulus A(a, b))

1 Let j(u) =

  • ❚ G(u, u′), u0 be a solution of (1). Assume that

2 (i) G = G(u, p) is a C2 function and

Gpp < 0 on {(u0(θ), u′

0(θ)), θ ∈ ❚},

3 (ii) The function p → G(a, p) is even and one of the

followings holds

(ii.1): Gu(a, 0) < 0, or (ii.2): Gu(a, 0) = 0 and Gu(u0, u′

0)u0 + Gp(u0, u′ 0)u′ 0 ≤ 0,

4 (iii) The function p → G(·, p) is even and Gu ≥ 0 near (b, 0). 5 Then Su0 is finite, i.e. Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-58
SLIDE 58

Main results: regularity (cont’d)

Theorem 0.2 (inclusion in annulus A(a, b))

1 Let j(u) =

  • ❚ G(u, u′), u0 be a solution of (1). Assume that

2 (i) G = G(u, p) is a C2 function and

Gpp < 0 on {(u0(θ), u′

0(θ)), θ ∈ ❚},

3 (ii) The function p → G(a, p) is even and one of the

followings holds

(ii.1): Gu(a, 0) < 0, or (ii.2): Gu(a, 0) = 0 and Gu(u0, u′

0)u0 + Gp(u0, u′ 0)u′ 0 ≤ 0,

4 (iii) The function p → G(·, p) is even and Gu ≥ 0 near (b, 0). 5 Then Su0 is finite, i.e. Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-59
SLIDE 59

Main results: regularity (cont’d)

Theorem 0.2 (inclusion in annulus A(a, b))

1 Let j(u) =

  • ❚ G(u, u′), u0 be a solution of (1). Assume that

2 (i) G = G(u, p) is a C2 function and

Gpp < 0 on {(u0(θ), u′

0(θ)), θ ∈ ❚},

3 (ii) The function p → G(a, p) is even and one of the

followings holds

(ii.1): Gu(a, 0) < 0, or (ii.2): Gu(a, 0) = 0 and Gu(u0, u′

0)u0 + Gp(u0, u′ 0)u′ 0 ≤ 0,

4 (iii) The function p → G(·, p) is even and Gu ≥ 0 near (b, 0). 5 Then Su0 is finite, i.e. Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-60
SLIDE 60

Main results: regularity (cont’d)

Theorem 0.2 (inclusion in annulus A(a, b))

1 Let j(u) =

  • ❚ G(u, u′), u0 be a solution of (1). Assume that

2 (i) G = G(u, p) is a C2 function and

Gpp < 0 on {(u0(θ), u′

0(θ)), θ ∈ ❚},

3 (ii) The function p → G(a, p) is even and one of the

followings holds

(ii.1): Gu(a, 0) < 0, or (ii.2): Gu(a, 0) = 0 and Gu(u0, u′

0)u0 + Gp(u0, u′ 0)u′ 0 ≤ 0,

4 (iii) The function p → G(·, p) is even and Gu ≥ 0 near (b, 0). 5 Then Su0 is finite, i.e. Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-61
SLIDE 61

Main results: regularity (cont’d)

Theorem 0.2 (inclusion in annulus A(a, b))

1 Let j(u) =

  • ❚ G(u, u′), u0 be a solution of (1). Assume that

2 (i) G = G(u, p) is a C2 function and

Gpp < 0 on {(u0(θ), u′

0(θ)), θ ∈ ❚},

3 (ii) The function p → G(a, p) is even and one of the

followings holds

(ii.1): Gu(a, 0) < 0, or (ii.2): Gu(a, 0) = 0 and Gu(u0, u′

0)u0 + Gp(u0, u′ 0)u′ 0 ≤ 0,

4 (iii) The function p → G(·, p) is even and Gu ≥ 0 near (b, 0). 5 Then Su0 is finite, i.e. Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-62
SLIDE 62

Main results: regularity (cont’d)

Theorem 0.2 (inclusion in annulus A(a, b))

1 Let j(u) =

  • ❚ G(u, u′), u0 be a solution of (1). Assume that

2 (i) G = G(u, p) is a C2 function and

Gpp < 0 on {(u0(θ), u′

0(θ)), θ ∈ ❚},

3 (ii) The function p → G(a, p) is even and one of the

followings holds

(ii.1): Gu(a, 0) < 0, or (ii.2): Gu(a, 0) = 0 and Gu(u0, u′

0)u0 + Gp(u0, u′ 0)u′ 0 ≤ 0,

4 (iii) The function p → G(·, p) is even and Gu ≥ 0 near (b, 0). 5 Then Su0 is finite, i.e. Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-63
SLIDE 63

Main results: regularity (cont’d)

Example Consider J(Ωu) = λm(Ωu) − P(Ωu) = λ 2

1 u2 −

  • u2 + |u′|2

u2 , with m(Ωu) the area, P(Ωu) the perimeter, and λ ∈ [0, +∞] The minimization of J within convex sets and ∂Ω ⊂ A(a, b) is in general a non trivial problem When λ = 0, the solution is the disk of radius 1

a

When λ = +∞, the solution is the disk of radius 1

b

λ ∈ (0, ∞): any solution is locally polygonal inside A(a, b) Gpp = − 1 (u2 + p2)3/2 , Gu(u, 0) = u − λ u3 From Theorem 0.2, if λ ∈ (a, b) then any solution is a polygon

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-64
SLIDE 64

Main results: regularity (cont’d)

Example Consider J(Ωu) = λm(Ωu) − P(Ωu) = λ 2

1 u2 −

  • u2 + |u′|2

u2 , with m(Ωu) the area, P(Ωu) the perimeter, and λ ∈ [0, +∞] The minimization of J within convex sets and ∂Ω ⊂ A(a, b) is in general a non trivial problem When λ = 0, the solution is the disk of radius 1

a

When λ = +∞, the solution is the disk of radius 1

b

λ ∈ (0, ∞): any solution is locally polygonal inside A(a, b) Gpp = − 1 (u2 + p2)3/2 , Gu(u, 0) = u − λ u3 From Theorem 0.2, if λ ∈ (a, b) then any solution is a polygon

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-65
SLIDE 65

Main results: regularity (cont’d)

Example Consider J(Ωu) = λm(Ωu) − P(Ωu) = λ 2

1 u2 −

  • u2 + |u′|2

u2 , with m(Ωu) the area, P(Ωu) the perimeter, and λ ∈ [0, +∞] The minimization of J within convex sets and ∂Ω ⊂ A(a, b) is in general a non trivial problem When λ = 0, the solution is the disk of radius 1

a

When λ = +∞, the solution is the disk of radius 1

b

λ ∈ (0, ∞): any solution is locally polygonal inside A(a, b) Gpp = − 1 (u2 + p2)3/2 , Gu(u, 0) = u − λ u3 From Theorem 0.2, if λ ∈ (a, b) then any solution is a polygon

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-66
SLIDE 66

Main results: regularity (cont’d)

Example Consider J(Ωu) = λm(Ωu) − P(Ωu) = λ 2

1 u2 −

  • u2 + |u′|2

u2 , with m(Ωu) the area, P(Ωu) the perimeter, and λ ∈ [0, +∞] The minimization of J within convex sets and ∂Ω ⊂ A(a, b) is in general a non trivial problem When λ = 0, the solution is the disk of radius 1

a

When λ = +∞, the solution is the disk of radius 1

b

λ ∈ (0, ∞): any solution is locally polygonal inside A(a, b) Gpp = − 1 (u2 + p2)3/2 , Gu(u, 0) = u − λ u3 From Theorem 0.2, if λ ∈ (a, b) then any solution is a polygon

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-67
SLIDE 67

Main results: regularity (cont’d)

Example Consider J(Ωu) = λm(Ωu) − P(Ωu) = λ 2

1 u2 −

  • u2 + |u′|2

u2 , with m(Ωu) the area, P(Ωu) the perimeter, and λ ∈ [0, +∞] The minimization of J within convex sets and ∂Ω ⊂ A(a, b) is in general a non trivial problem When λ = 0, the solution is the disk of radius 1

a

When λ = +∞, the solution is the disk of radius 1

b

λ ∈ (0, ∞): any solution is locally polygonal inside A(a, b) Gpp = − 1 (u2 + p2)3/2 , Gu(u, 0) = u − λ u3 From Theorem 0.2, if λ ∈ (a, b) then any solution is a polygon

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-68
SLIDE 68

Main results: regularity (cont’d)

Example Consider J(Ωu) = λm(Ωu) − P(Ωu) = λ 2

1 u2 −

  • u2 + |u′|2

u2 , with m(Ωu) the area, P(Ωu) the perimeter, and λ ∈ [0, +∞] The minimization of J within convex sets and ∂Ω ⊂ A(a, b) is in general a non trivial problem When λ = 0, the solution is the disk of radius 1

a

When λ = +∞, the solution is the disk of radius 1

b

λ ∈ (0, ∞): any solution is locally polygonal inside A(a, b) Gpp = − 1 (u2 + p2)3/2 , Gu(u, 0) = u − λ u3 From Theorem 0.2, if λ ∈ (a, b) then any solution is a polygon

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-69
SLIDE 69

Main results: regularity (cont’d)

Example Consider J(Ωu) = λm(Ωu) − P(Ωu) = λ 2

1 u2 −

  • u2 + |u′|2

u2 , with m(Ωu) the area, P(Ωu) the perimeter, and λ ∈ [0, +∞] The minimization of J within convex sets and ∂Ω ⊂ A(a, b) is in general a non trivial problem When λ = 0, the solution is the disk of radius 1

a

When λ = +∞, the solution is the disk of radius 1

b

λ ∈ (0, ∞): any solution is locally polygonal inside A(a, b) Gpp = − 1 (u2 + p2)3/2 , Gu(u, 0) = u − λ u3 From Theorem 0.2, if λ ∈ (a, b) then any solution is a polygon

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-70
SLIDE 70

Main results: regularity (cont’d)

Example Consider J(Ωu) = λm(Ωu) − P(Ωu) = λ 2

1 u2 −

  • u2 + |u′|2

u2 , with m(Ωu) the area, P(Ωu) the perimeter, and λ ∈ [0, +∞] The minimization of J within convex sets and ∂Ω ⊂ A(a, b) is in general a non trivial problem When λ = 0, the solution is the disk of radius 1

a

When λ = +∞, the solution is the disk of radius 1

b

λ ∈ (0, ∞): any solution is locally polygonal inside A(a, b) Gpp = − 1 (u2 + p2)3/2 , Gu(u, 0) = u − λ u3 From Theorem 0.2, if λ ∈ (a, b) then any solution is a polygon

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-71
SLIDE 71

Proofs: optimality conditions

Theorem 0.3 (inclusion in A(a, b))

1 If u0 is solves (1) and j ∈ C1(H1(❚); ❘), then there exist

0 ≤ ζ0 ∈ H1(❚), µa, µb ∈ M+(❚) such that {ζ0 = 0}⊂Su0, Supp(µa)⊂{u0 = a}, Supp(µb)⊂{u0 = b}.

2 v ∈ H1(❚):

j′(u0)v = ζ0 + ζ′′

0 , vU′×U +

vdµa −

vdµb.

3 Moreover, ∀ v ∈ H1(❚) such that ∃λ ∈ ❘ with

       v′′ + v ≥ λ(u′′

0 + u0)

v ≥ λ(u0 − a), v ≤ λ(u0 − b), ζ0 + ζ′′

0 , vU′×U

+

  • ❚ vd(µa − µb) = 0,

⇒ j′′(u0)(v, v) ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-72
SLIDE 72

Proofs: optimality conditions

Theorem 0.3 (inclusion in A(a, b))

1 If u0 is solves (1) and j ∈ C1(H1(❚); ❘), then there exist

0 ≤ ζ0 ∈ H1(❚), µa, µb ∈ M+(❚) such that {ζ0 = 0}⊂Su0, Supp(µa)⊂{u0 = a}, Supp(µb)⊂{u0 = b}.

2 v ∈ H1(❚):

j′(u0)v = ζ0 + ζ′′

0 , vU′×U +

vdµa −

vdµb.

3 Moreover, ∀ v ∈ H1(❚) such that ∃λ ∈ ❘ with

       v′′ + v ≥ λ(u′′

0 + u0)

v ≥ λ(u0 − a), v ≤ λ(u0 − b), ζ0 + ζ′′

0 , vU′×U

+

  • ❚ vd(µa − µb) = 0,

⇒ j′′(u0)(v, v) ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-73
SLIDE 73

Proofs: optimality conditions

Theorem 0.3 (inclusion in A(a, b))

1 If u0 is solves (1) and j ∈ C1(H1(❚); ❘), then there exist

0 ≤ ζ0 ∈ H1(❚), µa, µb ∈ M+(❚) such that {ζ0 = 0}⊂Su0, Supp(µa)⊂{u0 = a}, Supp(µb)⊂{u0 = b}.

2 v ∈ H1(❚):

j′(u0)v = ζ0 + ζ′′

0 , vU′×U +

vdµa −

vdµb.

3 Moreover, ∀ v ∈ H1(❚) such that ∃λ ∈ ❘ with

       v′′ + v ≥ λ(u′′

0 + u0)

v ≥ λ(u0 − a), v ≤ λ(u0 − b), ζ0 + ζ′′

0 , vU′×U

+

  • ❚ vd(µa − µb) = 0,

⇒ j′′(u0)(v, v) ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-74
SLIDE 74

Proofs: optimality conditions

Theorem 0.3 (inclusion in A(a, b))

1 If u0 is solves (1) and j ∈ C1(H1(❚); ❘), then there exist

0 ≤ ζ0 ∈ H1(❚), µa, µb ∈ M+(❚) such that {ζ0 = 0}⊂Su0, Supp(µa)⊂{u0 = a}, Supp(µb)⊂{u0 = b}.

2 v ∈ H1(❚):

j′(u0)v = ζ0 + ζ′′

0 , vU′×U +

vdµa −

vdµb.

3 Moreover, ∀ v ∈ H1(❚) such that ∃λ ∈ ❘ with

       v′′ + v ≥ λ(u′′

0 + u0)

v ≥ λ(u0 − a), v ≤ λ(u0 − b), ζ0 + ζ′′

0 , vU′×U

+

  • ❚ vd(µa − µb) = 0,

⇒ j′′(u0)(v, v) ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-75
SLIDE 75

Proofs: optimality conditions

Theorem 0.3 (inclusion in A(a, b))

1 If u0 is solves (1) and j ∈ C1(H1(❚); ❘), then there exist

0 ≤ ζ0 ∈ H1(❚), µa, µb ∈ M+(❚) such that {ζ0 = 0}⊂Su0, Supp(µa)⊂{u0 = a}, Supp(µb)⊂{u0 = b}.

2 v ∈ H1(❚):

j′(u0)v = ζ0 + ζ′′

0 , vU′×U +

vdµa −

vdµb.

3 Moreover, ∀ v ∈ H1(❚) such that ∃λ ∈ ❘ with

       v′′ + v ≥ λ(u′′

0 + u0)

v ≥ λ(u0 − a), v ≤ λ(u0 − b), ζ0 + ζ′′

0 , vU′×U

+

  • ❚ vd(µa − µb) = 0,

⇒ j′′(u0)(v, v) ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-76
SLIDE 76

Proofs: optimality conditions

Theorem 0.3 (inclusion in A(a, b))

1 If u0 is solves (1) and j ∈ C1(H1(❚); ❘), then there exist

0 ≤ ζ0 ∈ H1(❚), µa, µb ∈ M+(❚) such that {ζ0 = 0}⊂Su0, Supp(µa)⊂{u0 = a}, Supp(µb)⊂{u0 = b}.

2 v ∈ H1(❚):

j′(u0)v = ζ0 + ζ′′

0 , vU′×U +

vdµa −

vdµb.

3 Moreover, ∀ v ∈ H1(❚) such that ∃λ ∈ ❘ with

       v′′ + v ≥ λ(u′′

0 + u0)

v ≥ λ(u0 − a), v ≤ λ(u0 − b), ζ0 + ζ′′

0 , vU′×U

+

  • ❚ vd(µa − µb) = 0,

⇒ j′′(u0)(v, v) ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-77
SLIDE 77

Proofs: optimality conditions

Theorem 0.3 (inclusion in A(a, b))

1 If u0 is solves (1) and j ∈ C1(H1(❚); ❘), then there exist

0 ≤ ζ0 ∈ H1(❚), µa, µb ∈ M+(❚) such that {ζ0 = 0}⊂Su0, Supp(µa)⊂{u0 = a}, Supp(µb)⊂{u0 = b}.

2 v ∈ H1(❚):

j′(u0)v = ζ0 + ζ′′

0 , vU′×U +

vdµa −

vdµb.

3 Moreover, ∀ v ∈ H1(❚) such that ∃λ ∈ ❘ with

       v′′ + v ≥ λ(u′′

0 + u0)

v ≥ λ(u0 − a), v ≤ λ(u0 − b), ζ0 + ζ′′

0 , vU′×U

+

  • ❚ vd(µa − µb) = 0,

⇒ j′′(u0)(v, v) ≥ 0.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-78
SLIDE 78

Proofs: optimality conditions (remarks)

Ioffe A. D - Tihomirov V. M., Maurer H. - Zowe J. Abstract setting: U, Y real Banach, ∅ = K ⊂ Y closed convex cone, f : U → ❘, g : U → Y , min{f (u), u ∈ U, g(u) ∈ K}. Proposition 0.4 Let u0 ∈ U solve the min. problem. Assume f , g are C2 at u0 and g′(u0)(U) = Y . Then,

(i) ∃ l ∈ Y ′

+ : f ′(u0) = l ◦ g ′(u0) and l(g(u0)) = 0, where

Y ′

+ = {l ∈ Y ′; ∀ k ∈ K, l(k) ≥ 0 }

(ii) Set L(u) := f (u) − l(g(u)). Then F ′′(u0)(v, v) ≥ 0, ∀v ∈ Tu0, Tu0 =

  • v ∈ U; f ′(u0)(v) = 0,

g ′(u0)(v) ∈ Kg(u0) = {K + λg(u0); λ ∈ ❘}

  • .
  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-79
SLIDE 79

Proofs: optimality conditions (remarks)

Ioffe A. D - Tihomirov V. M., Maurer H. - Zowe J. Abstract setting: U, Y real Banach, ∅ = K ⊂ Y closed convex cone, f : U → ❘, g : U → Y , min{f (u), u ∈ U, g(u) ∈ K}. Proposition 0.4 Let u0 ∈ U solve the min. problem. Assume f , g are C2 at u0 and g′(u0)(U) = Y . Then,

(i) ∃ l ∈ Y ′

+ : f ′(u0) = l ◦ g ′(u0) and l(g(u0)) = 0, where

Y ′

+ = {l ∈ Y ′; ∀ k ∈ K, l(k) ≥ 0 }

(ii) Set L(u) := f (u) − l(g(u)). Then F ′′(u0)(v, v) ≥ 0, ∀v ∈ Tu0, Tu0 =

  • v ∈ U; f ′(u0)(v) = 0,

g ′(u0)(v) ∈ Kg(u0) = {K + λg(u0); λ ∈ ❘}

  • .
  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-80
SLIDE 80

Proofs: optimality conditions (remarks)

Ioffe A. D - Tihomirov V. M., Maurer H. - Zowe J. Abstract setting: U, Y real Banach, ∅ = K ⊂ Y closed convex cone, f : U → ❘, g : U → Y , min{f (u), u ∈ U, g(u) ∈ K}. Proposition 0.4 Let u0 ∈ U solve the min. problem. Assume f , g are C2 at u0 and g′(u0)(U) = Y . Then,

(i) ∃ l ∈ Y ′

+ : f ′(u0) = l ◦ g ′(u0) and l(g(u0)) = 0, where

Y ′

+ = {l ∈ Y ′; ∀ k ∈ K, l(k) ≥ 0 }

(ii) Set L(u) := f (u) − l(g(u)). Then F ′′(u0)(v, v) ≥ 0, ∀v ∈ Tu0, Tu0 =

  • v ∈ U; f ′(u0)(v) = 0,

g ′(u0)(v) ∈ Kg(u0) = {K + λg(u0); λ ∈ ❘}

  • .
  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-81
SLIDE 81

Proofs: optimality conditions (remarks)

Ioffe A. D - Tihomirov V. M., Maurer H. - Zowe J. Abstract setting: U, Y real Banach, ∅ = K ⊂ Y closed convex cone, f : U → ❘, g : U → Y , min{f (u), u ∈ U, g(u) ∈ K}. Proposition 0.4 Let u0 ∈ U solve the min. problem. Assume f , g are C2 at u0 and g′(u0)(U) = Y . Then,

(i) ∃ l ∈ Y ′

+ : f ′(u0) = l ◦ g ′(u0) and l(g(u0)) = 0, where

Y ′

+ = {l ∈ Y ′; ∀ k ∈ K, l(k) ≥ 0 }

(ii) Set L(u) := f (u) − l(g(u)). Then F ′′(u0)(v, v) ≥ 0, ∀v ∈ Tu0, Tu0 =

  • v ∈ U; f ′(u0)(v) = 0,

g ′(u0)(v) ∈ Kg(u0) = {K + λg(u0); λ ∈ ❘}

  • .
  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-82
SLIDE 82

Proofs: optimality conditions (remarks)

Ioffe A. D - Tihomirov V. M., Maurer H. - Zowe J. Abstract setting: U, Y real Banach, ∅ = K ⊂ Y closed convex cone, f : U → ❘, g : U → Y , min{f (u), u ∈ U, g(u) ∈ K}. Proposition 0.4 Let u0 ∈ U solve the min. problem. Assume f , g are C2 at u0 and g′(u0)(U) = Y . Then,

(i) ∃ l ∈ Y ′

+ : f ′(u0) = l ◦ g ′(u0) and l(g(u0)) = 0, where

Y ′

+ = {l ∈ Y ′; ∀ k ∈ K, l(k) ≥ 0 }

(ii) Set L(u) := f (u) − l(g(u)). Then F ′′(u0)(v, v) ≥ 0, ∀v ∈ Tu0, Tu0 =

  • v ∈ U; f ′(u0)(v) = 0,

g ′(u0)(v) ∈ Kg(u0) = {K + λg(u0); λ ∈ ❘}

  • .
  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-83
SLIDE 83

Proofs: optimality conditions (remarks)

Ioffe A. D - Tihomirov V. M., Maurer H. - Zowe J. Abstract setting: U, Y real Banach, ∅ = K ⊂ Y closed convex cone, f : U → ❘, g : U → Y , min{f (u), u ∈ U, g(u) ∈ K}. Proposition 0.4 Let u0 ∈ U solve the min. problem. Assume f , g are C2 at u0 and g′(u0)(U) = Y . Then,

(i) ∃ l ∈ Y ′

+ : f ′(u0) = l ◦ g ′(u0) and l(g(u0)) = 0, where

Y ′

+ = {l ∈ Y ′; ∀ k ∈ K, l(k) ≥ 0 }

(ii) Set L(u) := f (u) − l(g(u)). Then F ′′(u0)(v, v) ≥ 0, ∀v ∈ Tu0, Tu0 =

  • v ∈ U; f ′(u0)(v) = 0,

g ′(u0)(v) ∈ Kg(u0) = {K + λg(u0); λ ∈ ❘}

  • .
  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-84
SLIDE 84

Proofs: optimality conditions (remarks)

U = H1(❚), Y = H−1(❚) × H1(❚) × H1(❚), K = Y+, g(u) = (u′′ + u, u − a, b − u) Easy to find

ζ0d(u′′

0 + u0) = 0,

ζ0d(v′′ + v) ≥ 0, for all v′′ + v ≥ 0 We find that ζ0 satisfies furthermore ζ0 ≥ 0, ζ0(u′′

0 + u0) = 0

The second order optimality condition is necessary Example: Consider G(u, p) = −1

2

p

u

2. = −

  • {u′′

0 +u0>0}

u′ u0 v u0 ′ =

  • {u′′

0 +u0>0}

u′ u0 ′ v u0 u0 = AeBθ

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-85
SLIDE 85

Proofs: optimality conditions (remarks)

U = H1(❚), Y = H−1(❚) × H1(❚) × H1(❚), K = Y+, g(u) = (u′′ + u, u − a, b − u) Easy to find

ζ0d(u′′

0 + u0) = 0,

ζ0d(v′′ + v) ≥ 0, for all v′′ + v ≥ 0 We find that ζ0 satisfies furthermore ζ0 ≥ 0, ζ0(u′′

0 + u0) = 0

The second order optimality condition is necessary Example: Consider G(u, p) = −1

2

p

u

2. = −

  • {u′′

0 +u0>0}

u′ u0 v u0 ′ =

  • {u′′

0 +u0>0}

u′ u0 ′ v u0 u0 = AeBθ

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-86
SLIDE 86

Proofs: optimality conditions (remarks)

U = H1(❚), Y = H−1(❚) × H1(❚) × H1(❚), K = Y+, g(u) = (u′′ + u, u − a, b − u) Easy to find

ζ0d(u′′

0 + u0) = 0,

ζ0d(v′′ + v) ≥ 0, for all v′′ + v ≥ 0 We find that ζ0 satisfies furthermore ζ0 ≥ 0, ζ0(u′′

0 + u0) = 0

The second order optimality condition is necessary Example: Consider G(u, p) = −1

2

p

u

2. = −

  • {u′′

0 +u0>0}

u′ u0 v u0 ′ =

  • {u′′

0 +u0>0}

u′ u0 ′ v u0 u0 = AeBθ

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-87
SLIDE 87

Proofs: optimality conditions (remarks)

U = H1(❚), Y = H−1(❚) × H1(❚) × H1(❚), K = Y+, g(u) = (u′′ + u, u − a, b − u) Easy to find

ζ0d(u′′

0 + u0) = 0,

ζ0d(v′′ + v) ≥ 0, for all v′′ + v ≥ 0 We find that ζ0 satisfies furthermore ζ0 ≥ 0, ζ0(u′′

0 + u0) = 0

The second order optimality condition is necessary Example: Consider G(u, p) = −1

2

p

u

2. = −

  • {u′′

0 +u0>0}

u′ u0 v u0 ′ =

  • {u′′

0 +u0>0}

u′ u0 ′ v u0 u0 = AeBθ

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-88
SLIDE 88

Proofs: optimality conditions (remarks)

U = H1(❚), Y = H−1(❚) × H1(❚) × H1(❚), K = Y+, g(u) = (u′′ + u, u − a, b − u) Easy to find

ζ0d(u′′

0 + u0) = 0,

ζ0d(v′′ + v) ≥ 0, for all v′′ + v ≥ 0 We find that ζ0 satisfies furthermore ζ0 ≥ 0, ζ0(u′′

0 + u0) = 0

The second order optimality condition is necessary Example: Consider G(u, p) = −1

2

p

u

2. = −

  • {u′′

0 +u0>0}

u′ u0 v u0 ′ =

  • {u′′

0 +u0>0}

u′ u0 ′ v u0 u0 = AeBθ

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-89
SLIDE 89

Proofs: optimality conditions (remarks)

U = H1(❚), Y = H−1(❚) × H1(❚) × H1(❚), K = Y+, g(u) = (u′′ + u, u − a, b − u) Easy to find

ζ0d(u′′

0 + u0) = 0,

ζ0d(v′′ + v) ≥ 0, for all v′′ + v ≥ 0 We find that ζ0 satisfies furthermore ζ0 ≥ 0, ζ0(u′′

0 + u0) = 0

The second order optimality condition is necessary Example: Consider G(u, p) = −1

2

p

u

2. = −

  • {u′′

0 +u0>0}

u′ u0 v u0 ′ =

  • {u′′

0 +u0>0}

u′ u0 ′ v u0 u0 = AeBθ

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-90
SLIDE 90

Proofs: optimality conditions (remarks)

U = H1(❚), Y = H−1(❚) × H1(❚) × H1(❚), K = Y+, g(u) = (u′′ + u, u − a, b − u) Easy to find

ζ0d(u′′

0 + u0) = 0,

ζ0d(v′′ + v) ≥ 0, for all v′′ + v ≥ 0 We find that ζ0 satisfies furthermore ζ0 ≥ 0, ζ0(u′′

0 + u0) = 0

The second order optimality condition is necessary Example: Consider G(u, p) = −1

2

p

u

2. = −

  • {u′′

0 +u0>0}

u′ u0 v u0 ′ =

  • {u′′

0 +u0>0}

u′ u0 ′ v u0 u0 = AeBθ

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-91
SLIDE 91

Proofs: Theorem 0.1 (inclusion in A(a, b))

By contradiction Case a < u0(θ0 = 0) < b (Fig. 1)

∃ǫn → 0, Su0 ∩ (0, ǫn) = ∅ To find vn: (v ′′

n + vn) ≥ λ(u′′ 0 + u0) 1 a 1 b

ǫn Ωu0 ǫi

n

θ0 A(a, b)

  • Fig. 1

We consider vn,i ∈ H1(❚) solving v ′′

n,i + vn,i

= χ(ǫi

n,ǫi+1 n

)(u′′ 0 + u0),

(0, ǫn), vn,i = 0, (0, ǫn)c. Look for vn =

i=1,3 λn,ivn,i such that

v ′

n(0+) = v ′ n(ǫ− n ) = 0, which implies (v ′′ n + vn) ≥ λ(u′′ 0 + u0)

  • ❚ vn(ζ0 + ζ′′

0 ) =

  • ❚ vndµa =
  • ❚ vndµb = 0, and

≤ j′′(u0)(vn, vn) =

Guuv 2

n + 2Gupvnv ′ n + Gppv ′ n 2

(o(1) − Kpp)|v ′

n|2 < 0

(!) (vnL2(❚) ≤ √ǫnv ′

nL2(❚))

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-92
SLIDE 92

Proofs: Theorem 0.1 (inclusion in A(a, b))

By contradiction Case a < u0(θ0 = 0) < b (Fig. 1)

∃ǫn → 0, Su0 ∩ (0, ǫn) = ∅ To find vn: (v ′′

n + vn) ≥ λ(u′′ 0 + u0) 1 a 1 b

ǫn Ωu0 ǫi

n

θ0 A(a, b)

  • Fig. 1

We consider vn,i ∈ H1(❚) solving v ′′

n,i + vn,i

= χ(ǫi

n,ǫi+1 n

)(u′′ 0 + u0),

(0, ǫn), vn,i = 0, (0, ǫn)c. Look for vn =

i=1,3 λn,ivn,i such that

v ′

n(0+) = v ′ n(ǫ− n ) = 0, which implies (v ′′ n + vn) ≥ λ(u′′ 0 + u0)

  • ❚ vn(ζ0 + ζ′′

0 ) =

  • ❚ vndµa =
  • ❚ vndµb = 0, and

≤ j′′(u0)(vn, vn) =

Guuv 2

n + 2Gupvnv ′ n + Gppv ′ n 2

(o(1) − Kpp)|v ′

n|2 < 0

(!) (vnL2(❚) ≤ √ǫnv ′

nL2(❚))

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-93
SLIDE 93

Proofs: Theorem 0.1 (inclusion in A(a, b))

By contradiction Case a < u0(θ0 = 0) < b (Fig. 1)

∃ǫn → 0, Su0 ∩ (0, ǫn) = ∅ To find vn: (v ′′

n + vn) ≥ λ(u′′ 0 + u0) 1 a 1 b

ǫn Ωu0 ǫi

n

θ0 A(a, b)

  • Fig. 1

We consider vn,i ∈ H1(❚) solving v ′′

n,i + vn,i

= χ(ǫi

n,ǫi+1 n

)(u′′ 0 + u0),

(0, ǫn), vn,i = 0, (0, ǫn)c. Look for vn =

i=1,3 λn,ivn,i such that

v ′

n(0+) = v ′ n(ǫ− n ) = 0, which implies (v ′′ n + vn) ≥ λ(u′′ 0 + u0)

  • ❚ vn(ζ0 + ζ′′

0 ) =

  • ❚ vndµa =
  • ❚ vndµb = 0, and

≤ j′′(u0)(vn, vn) =

Guuv 2

n + 2Gupvnv ′ n + Gppv ′ n 2

(o(1) − Kpp)|v ′

n|2 < 0

(!) (vnL2(❚) ≤ √ǫnv ′

nL2(❚))

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-94
SLIDE 94

Proofs: Theorem 0.1 (inclusion in A(a, b))

By contradiction Case a < u0(θ0 = 0) < b (Fig. 1)

∃ǫn → 0, Su0 ∩ (0, ǫn) = ∅ To find vn: (v ′′

n + vn) ≥ λ(u′′ 0 + u0) 1 a 1 b

ǫn Ωu0 ǫi

n

θ0 A(a, b)

  • Fig. 1

We consider vn,i ∈ H1(❚) solving v ′′

n,i + vn,i

= χ(ǫi

n,ǫi+1 n

)(u′′ 0 + u0),

(0, ǫn), vn,i = 0, (0, ǫn)c. Look for vn =

i=1,3 λn,ivn,i such that

v ′

n(0+) = v ′ n(ǫ− n ) = 0, which implies (v ′′ n + vn) ≥ λ(u′′ 0 + u0)

  • ❚ vn(ζ0 + ζ′′

0 ) =

  • ❚ vndµa =
  • ❚ vndµb = 0, and

≤ j′′(u0)(vn, vn) =

Guuv 2

n + 2Gupvnv ′ n + Gppv ′ n 2

(o(1) − Kpp)|v ′

n|2 < 0

(!) (vnL2(❚) ≤ √ǫnv ′

nL2(❚))

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-95
SLIDE 95

Proofs: Theorem 0.1 (inclusion in A(a, b))

By contradiction Case a < u0(θ0 = 0) < b (Fig. 1)

∃ǫn → 0, Su0 ∩ (0, ǫn) = ∅ To find vn: (v ′′

n + vn) ≥ λ(u′′ 0 + u0) 1 a 1 b

ǫn Ωu0 ǫi

n

θ0 A(a, b)

  • Fig. 1

We consider vn,i ∈ H1(❚) solving v ′′

n,i + vn,i

= χ(ǫi

n,ǫi+1 n

)(u′′ 0 + u0),

(0, ǫn), vn,i = 0, (0, ǫn)c. Look for vn =

i=1,3 λn,ivn,i such that

v ′

n(0+) = v ′ n(ǫ− n ) = 0, which implies (v ′′ n + vn) ≥ λ(u′′ 0 + u0)

  • ❚ vn(ζ0 + ζ′′

0 ) =

  • ❚ vndµa =
  • ❚ vndµb = 0, and

≤ j′′(u0)(vn, vn) =

Guuv 2

n + 2Gupvnv ′ n + Gppv ′ n 2

(o(1) − Kpp)|v ′

n|2 < 0

(!) (vnL2(❚) ≤ √ǫnv ′

nL2(❚))

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-96
SLIDE 96

Proofs: Theorem 0.1 (inclusion in A(a, b))

By contradiction Case a < u0(θ0 = 0) < b (Fig. 1)

∃ǫn → 0, Su0 ∩ (0, ǫn) = ∅ To find vn: (v ′′

n + vn) ≥ λ(u′′ 0 + u0) 1 a 1 b

ǫn Ωu0 ǫi

n

θ0 A(a, b)

  • Fig. 1

We consider vn,i ∈ H1(❚) solving v ′′

n,i + vn,i

= χ(ǫi

n,ǫi+1 n

)(u′′ 0 + u0),

(0, ǫn), vn,i = 0, (0, ǫn)c. Look for vn =

i=1,3 λn,ivn,i such that

v ′

n(0+) = v ′ n(ǫ− n ) = 0, which implies (v ′′ n + vn) ≥ λ(u′′ 0 + u0)

  • ❚ vn(ζ0 + ζ′′

0 ) =

  • ❚ vndµa =
  • ❚ vndµb = 0, and

≤ j′′(u0)(vn, vn) =

Guuv 2

n + 2Gupvnv ′ n + Gppv ′ n 2

(o(1) − Kpp)|v ′

n|2 < 0

(!) (vnL2(❚) ≤ √ǫnv ′

nL2(❚))

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-97
SLIDE 97

Proofs: Theorem 0.1 (inclusion in A(a, b))

By contradiction Case a < u0(θ0 = 0) < b (Fig. 1)

∃ǫn → 0, Su0 ∩ (0, ǫn) = ∅ To find vn: (v ′′

n + vn) ≥ λ(u′′ 0 + u0) 1 a 1 b

ǫn Ωu0 ǫi

n

θ0 A(a, b)

  • Fig. 1

We consider vn,i ∈ H1(❚) solving v ′′

n,i + vn,i

= χ(ǫi

n,ǫi+1 n

)(u′′ 0 + u0),

(0, ǫn), vn,i = 0, (0, ǫn)c. Look for vn =

i=1,3 λn,ivn,i such that

v ′

n(0+) = v ′ n(ǫ− n ) = 0, which implies (v ′′ n + vn) ≥ λ(u′′ 0 + u0)

  • ❚ vn(ζ0 + ζ′′

0 ) =

  • ❚ vndµa =
  • ❚ vndµb = 0, and

≤ j′′(u0)(vn, vn) =

Guuv 2

n + 2Gupvnv ′ n + Gppv ′ n 2

(o(1) − Kpp)|v ′

n|2 < 0

(!) (vnL2(❚) ≤ √ǫnv ′

nL2(❚))

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-98
SLIDE 98

Proofs: Theorem 0.1 (inclusion in A(a, b))

By contradiction Case a < u0(θ0 = 0) < b (Fig. 1)

∃ǫn → 0, Su0 ∩ (0, ǫn) = ∅ To find vn: (v ′′

n + vn) ≥ λ(u′′ 0 + u0) 1 a 1 b

ǫn Ωu0 ǫi

n

θ0 A(a, b)

  • Fig. 1

We consider vn,i ∈ H1(❚) solving v ′′

n,i + vn,i

= χ(ǫi

n,ǫi+1 n

)(u′′ 0 + u0),

(0, ǫn), vn,i = 0, (0, ǫn)c. Look for vn =

i=1,3 λn,ivn,i such that

v ′

n(0+) = v ′ n(ǫ− n ) = 0, which implies (v ′′ n + vn) ≥ λ(u′′ 0 + u0)

  • ❚ vn(ζ0 + ζ′′

0 ) =

  • ❚ vndµa =
  • ❚ vndµb = 0, and

≤ j′′(u0)(vn, vn) =

Guuv 2

n + 2Gupvnv ′ n + Gppv ′ n 2

(o(1) − Kpp)|v ′

n|2 < 0

(!) (vnL2(❚) ≤ √ǫnv ′

nL2(❚))

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-99
SLIDE 99

Proofs: Theorem 0.1 (inclusion in A(a, b))

By contradiction Case a < u0(θ0 = 0) < b (Fig. 1)

∃ǫn → 0, Su0 ∩ (0, ǫn) = ∅ To find vn: (v ′′

n + vn) ≥ λ(u′′ 0 + u0) 1 a 1 b

ǫn Ωu0 ǫi

n

θ0 A(a, b)

  • Fig. 1

We consider vn,i ∈ H1(❚) solving v ′′

n,i + vn,i

= χ(ǫi

n,ǫi+1 n

)(u′′ 0 + u0),

(0, ǫn), vn,i = 0, (0, ǫn)c. Look for vn =

i=1,3 λn,ivn,i such that

v ′

n(0+) = v ′ n(ǫ− n ) = 0, which implies (v ′′ n + vn) ≥ λ(u′′ 0 + u0)

  • ❚ vn(ζ0 + ζ′′

0 ) =

  • ❚ vndµa =
  • ❚ vndµb = 0, and

≤ j′′(u0)(vn, vn) =

Guuv 2

n + 2Gupvnv ′ n + Gppv ′ n 2

(o(1) − Kpp)|v ′

n|2 < 0

(!) (vnL2(❚) ≤ √ǫnv ′

nL2(❚))

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-100
SLIDE 100

Proofs: Theorem 0.1 (inclusion in A(a, b))

By contradiction Case a < u0(θ0 = 0) < b (Fig. 1)

∃ǫn → 0, Su0 ∩ (0, ǫn) = ∅ To find vn: (v ′′

n + vn) ≥ λ(u′′ 0 + u0) 1 a 1 b

ǫn Ωu0 ǫi

n

θ0 A(a, b)

  • Fig. 1

We consider vn,i ∈ H1(❚) solving v ′′

n,i + vn,i

= χ(ǫi

n,ǫi+1 n

)(u′′ 0 + u0),

(0, ǫn), vn,i = 0, (0, ǫn)c. Look for vn =

i=1,3 λn,ivn,i such that

v ′

n(0+) = v ′ n(ǫ− n ) = 0, which implies (v ′′ n + vn) ≥ λ(u′′ 0 + u0)

  • ❚ vn(ζ0 + ζ′′

0 ) =

  • ❚ vndµa =
  • ❚ vndµb = 0, and

≤ j′′(u0)(vn, vn) =

Guuv 2

n + 2Gupvnv ′ n + Gppv ′ n 2

(o(1) − Kpp)|v ′

n|2 < 0

(!) (vnL2(❚) ≤ √ǫnv ′

nL2(❚))

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-101
SLIDE 101

Proofs: Theorem 0.1 (inclusion in A(a, b))

Case u0(θ0 = 0) = a (Fig. 2)

Near θ0: u′′

0 + u0 = n∈◆∗ αnδθn near θ0 .

Consider vn ∈ H1

0(θn+1, θn−1):

v ′′

n + vn = δθn in (θn+1, θn−1). 1 a 1 b

θn θ0

  • Fig. 2

We can choose λ ≪ 0 (depending on n) such that       

  • ❚ vd(ζ0 + ζ′′

0 + µa − µb)

= 0, v ′′

n + vn

≥ λ(u′′

0 + u0)

vn ≥ λ(u0 − a), vn ≤ λ(u0 − b). Proceeding as in (a) above, we find a contradiction! Case u0(θ0 = 0) = b Proceed as in u0(θ0) = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-102
SLIDE 102

Proofs: Theorem 0.1 (inclusion in A(a, b))

Case u0(θ0 = 0) = a (Fig. 2)

Near θ0: u′′

0 + u0 = n∈◆∗ αnδθn near θ0 .

Consider vn ∈ H1

0(θn+1, θn−1):

v ′′

n + vn = δθn in (θn+1, θn−1). 1 a 1 b

θn θ0

  • Fig. 2

We can choose λ ≪ 0 (depending on n) such that       

  • ❚ vd(ζ0 + ζ′′

0 + µa − µb)

= 0, v ′′

n + vn

≥ λ(u′′

0 + u0)

vn ≥ λ(u0 − a), vn ≤ λ(u0 − b). Proceeding as in (a) above, we find a contradiction! Case u0(θ0 = 0) = b Proceed as in u0(θ0) = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-103
SLIDE 103

Proofs: Theorem 0.1 (inclusion in A(a, b))

Case u0(θ0 = 0) = a (Fig. 2)

Near θ0: u′′

0 + u0 = n∈◆∗ αnδθn near θ0 .

Consider vn ∈ H1

0(θn+1, θn−1):

v ′′

n + vn = δθn in (θn+1, θn−1). 1 a 1 b

θn θ0

  • Fig. 2

We can choose λ ≪ 0 (depending on n) such that       

  • ❚ vd(ζ0 + ζ′′

0 + µa − µb)

= 0, v ′′

n + vn

≥ λ(u′′

0 + u0)

vn ≥ λ(u0 − a), vn ≤ λ(u0 − b). Proceeding as in (a) above, we find a contradiction! Case u0(θ0 = 0) = b Proceed as in u0(θ0) = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-104
SLIDE 104

Proofs: Theorem 0.1 (inclusion in A(a, b))

Case u0(θ0 = 0) = a (Fig. 2)

Near θ0: u′′

0 + u0 = n∈◆∗ αnδθn near θ0 .

Consider vn ∈ H1

0(θn+1, θn−1):

v ′′

n + vn = δθn in (θn+1, θn−1). 1 a 1 b

θn θ0

  • Fig. 2

We can choose λ ≪ 0 (depending on n) such that       

  • ❚ vd(ζ0 + ζ′′

0 + µa − µb)

= 0, v ′′

n + vn

≥ λ(u′′

0 + u0)

vn ≥ λ(u0 − a), vn ≤ λ(u0 − b). Proceeding as in (a) above, we find a contradiction! Case u0(θ0 = 0) = b Proceed as in u0(θ0) = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-105
SLIDE 105

Proofs: Theorem 0.1 (inclusion in A(a, b))

Case u0(θ0 = 0) = a (Fig. 2)

Near θ0: u′′

0 + u0 = n∈◆∗ αnδθn near θ0 .

Consider vn ∈ H1

0(θn+1, θn−1):

v ′′

n + vn = δθn in (θn+1, θn−1). 1 a 1 b

θn θ0

  • Fig. 2

We can choose λ ≪ 0 (depending on n) such that       

  • ❚ vd(ζ0 + ζ′′

0 + µa − µb)

= 0, v ′′

n + vn

≥ λ(u′′

0 + u0)

vn ≥ λ(u0 − a), vn ≤ λ(u0 − b). Proceeding as in (a) above, we find a contradiction! Case u0(θ0 = 0) = b Proceed as in u0(θ0) = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-106
SLIDE 106

Proofs: Theorem 0.1 (inclusion in A(a, b))

Case u0(θ0 = 0) = a (Fig. 2)

Near θ0: u′′

0 + u0 = n∈◆∗ αnδθn near θ0 .

Consider vn ∈ H1

0(θn+1, θn−1):

v ′′

n + vn = δθn in (θn+1, θn−1). 1 a 1 b

θn θ0

  • Fig. 2

We can choose λ ≪ 0 (depending on n) such that       

  • ❚ vd(ζ0 + ζ′′

0 + µa − µb)

= 0, v ′′

n + vn

≥ λ(u′′

0 + u0)

vn ≥ λ(u0 − a), vn ≤ λ(u0 − b). Proceeding as in (a) above, we find a contradiction! Case u0(θ0 = 0) = b Proceed as in u0(θ0) = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-107
SLIDE 107

Proofs: Theorem 0.1 (inclusion in A(a, b))

Case u0(θ0 = 0) = a (Fig. 2)

Near θ0: u′′

0 + u0 = n∈◆∗ αnδθn near θ0 .

Consider vn ∈ H1

0(θn+1, θn−1):

v ′′

n + vn = δθn in (θn+1, θn−1). 1 a 1 b

θn θ0

  • Fig. 2

We can choose λ ≪ 0 (depending on n) such that       

  • ❚ vd(ζ0 + ζ′′

0 + µa − µb)

= 0, v ′′

n + vn

≥ λ(u′′

0 + u0)

vn ≥ λ(u0 − a), vn ≤ λ(u0 − b). Proceeding as in (a) above, we find a contradiction! Case u0(θ0 = 0) = b Proceed as in u0(θ0) = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-108
SLIDE 108

Proofs: Theorem 0.1 (inclusion in A(a, b))

Case u0(θ0 = 0) = a (Fig. 2)

Near θ0: u′′

0 + u0 = n∈◆∗ αnδθn near θ0 .

Consider vn ∈ H1

0(θn+1, θn−1):

v ′′

n + vn = δθn in (θn+1, θn−1). 1 a 1 b

θn θ0

  • Fig. 2

We can choose λ ≪ 0 (depending on n) such that       

  • ❚ vd(ζ0 + ζ′′

0 + µa − µb)

= 0, v ′′

n + vn

≥ λ(u′′

0 + u0)

vn ≥ λ(u0 − a), vn ≤ λ(u0 − b). Proceeding as in (a) above, we find a contradiction! Case u0(θ0 = 0) = b Proceed as in u0(θ0) = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-109
SLIDE 109

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points in {a < u0 < b}:

follows from Theorem 0.1

No accumulation points on {u0 = a}:

θ1

n

θ1

n−1

θ2

n−1

θ0 ǫn

1 a

ωn−1 ωn

  • Fig. 3

θn θ0 ǫn

1 a

Fa Fa ωi−1 ωi

  • Fig. 4
  • Fig. 3: v ′′

n + vn = u′′ 0 + u0 = Ni i=1 αiδθi

n in ωn, vn = 0 in ωc

n.

  • Fig. 4: v ′′

n + vn = −(u′′ 0 + u0) in (0, ǫn), vn = 0 in (0, ǫn)c.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-110
SLIDE 110

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points in {a < u0 < b}:

follows from Theorem 0.1

No accumulation points on {u0 = a}:

θ1

n

θ1

n−1

θ2

n−1

θ0 ǫn

1 a

ωn−1 ωn

  • Fig. 3

θn θ0 ǫn

1 a

Fa Fa ωi−1 ωi

  • Fig. 4
  • Fig. 3: v ′′

n + vn = u′′ 0 + u0 = Ni i=1 αiδθi

n in ωn, vn = 0 in ωc

n.

  • Fig. 4: v ′′

n + vn = −(u′′ 0 + u0) in (0, ǫn), vn = 0 in (0, ǫn)c.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-111
SLIDE 111

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points in {a < u0 < b}:

follows from Theorem 0.1

No accumulation points on {u0 = a}:

θ1

n

θ1

n−1

θ2

n−1

θ0 ǫn

1 a

ωn−1 ωn

  • Fig. 3

θn θ0 ǫn

1 a

Fa Fa ωi−1 ωi

  • Fig. 4
  • Fig. 3: v ′′

n + vn = u′′ 0 + u0 = Ni i=1 αiδθi

n in ωn, vn = 0 in ωc

n.

  • Fig. 4: v ′′

n + vn = −(u′′ 0 + u0) in (0, ǫn), vn = 0 in (0, ǫn)c.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-112
SLIDE 112

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points in {a < u0 < b}:

follows from Theorem 0.1

No accumulation points on {u0 = a}:

θ1

n

θ1

n−1

θ2

n−1

θ0 ǫn

1 a

ωn−1 ωn

  • Fig. 3

θn θ0 ǫn

1 a

Fa Fa ωi−1 ωi

  • Fig. 4
  • Fig. 3: v ′′

n + vn = u′′ 0 + u0 = Ni i=1 αiδθi

n in ωn, vn = 0 in ωc

n.

  • Fig. 4: v ′′

n + vn = −(u′′ 0 + u0) in (0, ǫn), vn = 0 in (0, ǫn)c.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-113
SLIDE 113

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points in {a < u0 < b}:

follows from Theorem 0.1

No accumulation points on {u0 = a}:

θ1

n

θ1

n−1

θ2

n−1

θ0 ǫn

1 a

ωn−1 ωn

  • Fig. 3

θn θ0 ǫn

1 a

Fa Fa ωi−1 ωi

  • Fig. 4
  • Fig. 3: v ′′

n + vn = u′′ 0 + u0 = Ni i=1 αiδθi

n in ωn, vn = 0 in ωc

n.

  • Fig. 4: v ′′

n + vn = −(u′′ 0 + u0) in (0, ǫn), vn = 0 in (0, ǫn)c.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-114
SLIDE 114

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points in {a < u0 < b}:

follows from Theorem 0.1

No accumulation points on {u0 = a}:

θ1

n

θ1

n−1

θ2

n−1

θ0 ǫn

1 a

ωn−1 ωn

  • Fig. 3

θn θ0 ǫn

1 a

Fa Fa ωi−1 ωi

  • Fig. 4
  • Fig. 3: v ′′

n + vn = u′′ 0 + u0 = Ni i=1 αiδθi

n in ωn, vn = 0 in ωc

n.

  • Fig. 4: v ′′

n + vn = −(u′′ 0 + u0) in (0, ǫn), vn = 0 in (0, ǫn)c.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-115
SLIDE 115

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points in {a < u0 < b}:

follows from Theorem 0.1

No accumulation points on {u0 = a}:

θ1

n

θ1

n−1

θ2

n−1

θ0 ǫn

1 a

ωn−1 ωn

  • Fig. 3

θn θ0 ǫn

1 a

Fa Fa ωi−1 ωi

  • Fig. 4
  • Fig. 3: v ′′

n + vn = u′′ 0 + u0 = Ni i=1 αiδθi

n in ωn, vn = 0 in ωc

n.

  • Fig. 4: v ′′

n + vn = −(u′′ 0 + u0) in (0, ǫn), vn = 0 in (0, ǫn)c.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-116
SLIDE 116

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points on {u0 = b}:

σn0

1 b

Fb ǫn θi

n

τn 2ǫn ωi

n

  • Fig. 5

   un = u0, (0, 2ǫn)c, un = b cos θ, (0, ǫn), un = b cos(θ − 2ǫn), (ǫn, 2ǫn),

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-117
SLIDE 117

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points on {u0 = b}:

σn0

1 b

Fb ǫn θi

n

τn 2ǫn ωi

n

  • Fig. 5

   un = u0, (0, 2ǫn)c, un = b cos θ, (0, ǫn), un = b cos(θ − 2ǫn), (ǫn, 2ǫn),

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-118
SLIDE 118

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points on {u0 = b}:

σn0

1 b

Fb ǫn θi

n

τn 2ǫn ωi

n

  • Fig. 5

   un = u0, (0, 2ǫn)c, un = b cos θ, (0, ǫn), un = b cos(θ − 2ǫn), (ǫn, 2ǫn),

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-119
SLIDE 119

Proofs: Theorem 0.2 (inclusion in A(a, b))

No accumulation points on {u0 = b}:

σn0

1 b

Fb ǫn θi

n

τn 2ǫn ωi

n

  • Fig. 5

   un = u0, (0, 2ǫn)c, un = b cos θ, (0, ǫn), un = b cos(θ − 2ǫn), (ǫn, 2ǫn),

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-120
SLIDE 120

Remarks: sharpness of conditions

Theorem 0.5 (inclusion in A(a, b))

1

Let j(u) =

  • ❚ G(u, u′), u0 be a solution of (1). Assume that

2

(i) G is a C2 function and Gpp < 0 on {(u0(θ), u′

0(θ)), θ ∈ ❚},

3

(ii) The function p → G(a, p) is even and one of the followings holds

(ii.1): Gu(a, 0) < 0, or (ii.2): Gu(a, 0) = 0 and Gu(u0, u′

0)u0 + Gp(u0, u′ 0)u′ 0 ≤ 0, 4

(iii) The function p → G(·, p) is even and Gu ≥ 0 near (b, 0).

5

Then Su0 is finite, i.e. Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-121
SLIDE 121

Remarks: sharpness of conditions

Theorem 0.5 (inclusion in A(a, b))

1

Let j(u) =

  • ❚ G(u, u′), u0 be a solution of (1). Assume that

2

(i) G is a C2 function and Gpp < 0 on {(u0(θ), u′

0(θ)), θ ∈ ❚},

3

(ii) The function p → G(a, p) is even and one of the followings holds

(ii.1): Gu(a, 0) < 0, or (ii.2): Gu(a, 0) = 0 and Gu(u0, u′

0)u0 + Gp(u0, u′ 0)u′ 0 ≤ 0, 4

(iii) The function p → G(·, p) is even and Gu ≥ 0 near (b, 0).

5

Then Su0 is finite, i.e. Ωu0 is a polygon.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-122
SLIDE 122

Remarks: sharpness of conditions - counterexamples

Concavity condition Gpp < 0 Set c = a+b

2

and consider G(u, p) = 1

2

  • (u − c)2 + p2

.

G satisfies (ii.1) because Gu(a, 0) = a − c < 0, G satisfies (iii) because Gu(b, 0) = b − c > 0.

G does not satisfy (i) because Gpp = 1. It is obvious that the corresponding solution of (1) is not a polygon, but rather (the circle) {u0 = c}.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-123
SLIDE 123

Remarks: sharpness of conditions - counterexamples

Concavity condition Gpp < 0 Set c = a+b

2

and consider G(u, p) = 1

2

  • (u − c)2 + p2

.

G satisfies (ii.1) because Gu(a, 0) = a − c < 0, G satisfies (iii) because Gu(b, 0) = b − c > 0.

G does not satisfy (i) because Gpp = 1. It is obvious that the corresponding solution of (1) is not a polygon, but rather (the circle) {u0 = c}.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-124
SLIDE 124

Remarks: sharpness of conditions - counterexamples

Concavity condition Gpp < 0 Set c = a+b

2

and consider G(u, p) = 1

2

  • (u − c)2 + p2

.

G satisfies (ii.1) because Gu(a, 0) = a − c < 0, G satisfies (iii) because Gu(b, 0) = b − c > 0.

G does not satisfy (i) because Gpp = 1. It is obvious that the corresponding solution of (1) is not a polygon, but rather (the circle) {u0 = c}.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-125
SLIDE 125

Remarks: sharpness of conditions - counterexamples

Concavity condition Gpp < 0 Set c = a+b

2

and consider G(u, p) = 1

2

  • (u − c)2 + p2

.

G satisfies (ii.1) because Gu(a, 0) = a − c < 0, G satisfies (iii) because Gu(b, 0) = b − c > 0.

G does not satisfy (i) because Gpp = 1. It is obvious that the corresponding solution of (1) is not a polygon, but rather (the circle) {u0 = c}.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-126
SLIDE 126

Remarks: sharpness of conditions - counterexamples

Concavity condition Gpp < 0 Set c = a+b

2

and consider G(u, p) = 1

2

  • (u − c)2 + p2

.

G satisfies (ii.1) because Gu(a, 0) = a − c < 0, G satisfies (iii) because Gu(b, 0) = b − c > 0.

G does not satisfy (i) because Gpp = 1. It is obvious that the corresponding solution of (1) is not a polygon, but rather (the circle) {u0 = c}.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-127
SLIDE 127

Remarks: sharpness of conditions - counterexamples

Concavity condition Gpp < 0 Set c = a+b

2

and consider G(u, p) = 1

2

  • (u − c)2 + p2

.

G satisfies (ii.1) because Gu(a, 0) = a − c < 0, G satisfies (iii) because Gu(b, 0) = b − c > 0.

G does not satisfy (i) because Gpp = 1. It is obvious that the corresponding solution of (1) is not a polygon, but rather (the circle) {u0 = c}.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-128
SLIDE 128

Remarks: sharpness of conditions - counterexamples

Concavity condition Gpp < 0 Set c = a+b

2

and consider G(u, p) = 1

2

  • (u − c)2 + p2

.

G satisfies (ii.1) because Gu(a, 0) = a − c < 0, G satisfies (iii) because Gu(b, 0) = b − c > 0.

G does not satisfy (i) because Gpp = 1. It is obvious that the corresponding solution of (1) is not a polygon, but rather (the circle) {u0 = c}.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-129
SLIDE 129

Remarks: sharpness of conditions - counterexamples

Condition at u = a: Gu(a, 0) < 0 Consider the function G(u, p) = 1

2(u2 − p2).

G(u, p) satisfies (i) because Gpp(u, p) = −2 G(u, p) satisfies (iii) because Gu(b, 0) = b G does not satisfy (ii.1), neither (ii.2).

The solution of (1) for this G(u, p) is (the circle) u0 = a. Indeed, for admissible u we have j(u) = 1 2

(u+u′′)u ≥ a 2

(u+u′′) = a 2

u ≥ πa2 = j(u0), which proves that u0 ≡ a is the minimizer of j(u). Another example: Take G(u, p) = −(u2+p2)1/2

u2

, so j(u) = −P(Ωu). Then u0 = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-130
SLIDE 130

Remarks: sharpness of conditions - counterexamples

Condition at u = a: Gu(a, 0) < 0 Consider the function G(u, p) = 1

2(u2 − p2).

G(u, p) satisfies (i) because Gpp(u, p) = −2 G(u, p) satisfies (iii) because Gu(b, 0) = b G does not satisfy (ii.1), neither (ii.2).

The solution of (1) for this G(u, p) is (the circle) u0 = a. Indeed, for admissible u we have j(u) = 1 2

(u+u′′)u ≥ a 2

(u+u′′) = a 2

u ≥ πa2 = j(u0), which proves that u0 ≡ a is the minimizer of j(u). Another example: Take G(u, p) = −(u2+p2)1/2

u2

, so j(u) = −P(Ωu). Then u0 = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-131
SLIDE 131

Remarks: sharpness of conditions - counterexamples

Condition at u = a: Gu(a, 0) < 0 Consider the function G(u, p) = 1

2(u2 − p2).

G(u, p) satisfies (i) because Gpp(u, p) = −2 G(u, p) satisfies (iii) because Gu(b, 0) = b G does not satisfy (ii.1), neither (ii.2).

The solution of (1) for this G(u, p) is (the circle) u0 = a. Indeed, for admissible u we have j(u) = 1 2

(u+u′′)u ≥ a 2

(u+u′′) = a 2

u ≥ πa2 = j(u0), which proves that u0 ≡ a is the minimizer of j(u). Another example: Take G(u, p) = −(u2+p2)1/2

u2

, so j(u) = −P(Ωu). Then u0 = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-132
SLIDE 132

Remarks: sharpness of conditions - counterexamples

Condition at u = a: Gu(a, 0) < 0 Consider the function G(u, p) = 1

2(u2 − p2).

G(u, p) satisfies (i) because Gpp(u, p) = −2 G(u, p) satisfies (iii) because Gu(b, 0) = b G does not satisfy (ii.1), neither (ii.2).

The solution of (1) for this G(u, p) is (the circle) u0 = a. Indeed, for admissible u we have j(u) = 1 2

(u+u′′)u ≥ a 2

(u+u′′) = a 2

u ≥ πa2 = j(u0), which proves that u0 ≡ a is the minimizer of j(u). Another example: Take G(u, p) = −(u2+p2)1/2

u2

, so j(u) = −P(Ωu). Then u0 = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-133
SLIDE 133

Remarks: sharpness of conditions - counterexamples

Condition at u = a: Gu(a, 0) < 0 Consider the function G(u, p) = 1

2(u2 − p2).

G(u, p) satisfies (i) because Gpp(u, p) = −2 G(u, p) satisfies (iii) because Gu(b, 0) = b G does not satisfy (ii.1), neither (ii.2).

The solution of (1) for this G(u, p) is (the circle) u0 = a. Indeed, for admissible u we have j(u) = 1 2

(u+u′′)u ≥ a 2

(u+u′′) = a 2

u ≥ πa2 = j(u0), which proves that u0 ≡ a is the minimizer of j(u). Another example: Take G(u, p) = −(u2+p2)1/2

u2

, so j(u) = −P(Ωu). Then u0 = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-134
SLIDE 134

Remarks: sharpness of conditions - counterexamples

Condition at u = a: Gu(a, 0) < 0 Consider the function G(u, p) = 1

2(u2 − p2).

G(u, p) satisfies (i) because Gpp(u, p) = −2 G(u, p) satisfies (iii) because Gu(b, 0) = b G does not satisfy (ii.1), neither (ii.2).

The solution of (1) for this G(u, p) is (the circle) u0 = a. Indeed, for admissible u we have j(u) = 1 2

(u+u′′)u ≥ a 2

(u+u′′) = a 2

u ≥ πa2 = j(u0), which proves that u0 ≡ a is the minimizer of j(u). Another example: Take G(u, p) = −(u2+p2)1/2

u2

, so j(u) = −P(Ωu). Then u0 = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-135
SLIDE 135

Remarks: sharpness of conditions - counterexamples

Condition at u = a: Gu(a, 0) < 0 Consider the function G(u, p) = 1

2(u2 − p2).

G(u, p) satisfies (i) because Gpp(u, p) = −2 G(u, p) satisfies (iii) because Gu(b, 0) = b G does not satisfy (ii.1), neither (ii.2).

The solution of (1) for this G(u, p) is (the circle) u0 = a. Indeed, for admissible u we have j(u) = 1 2

(u+u′′)u ≥ a 2

(u+u′′) = a 2

u ≥ πa2 = j(u0), which proves that u0 ≡ a is the minimizer of j(u). Another example: Take G(u, p) = −(u2+p2)1/2

u2

, so j(u) = −P(Ωu). Then u0 = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-136
SLIDE 136

Remarks: sharpness of conditions - counterexamples

Condition at u = a: Gu(a, 0) < 0 Consider the function G(u, p) = 1

2(u2 − p2).

G(u, p) satisfies (i) because Gpp(u, p) = −2 G(u, p) satisfies (iii) because Gu(b, 0) = b G does not satisfy (ii.1), neither (ii.2).

The solution of (1) for this G(u, p) is (the circle) u0 = a. Indeed, for admissible u we have j(u) = 1 2

(u+u′′)u ≥ a 2

(u+u′′) = a 2

u ≥ πa2 = j(u0), which proves that u0 ≡ a is the minimizer of j(u). Another example: Take G(u, p) = −(u2+p2)1/2

u2

, so j(u) = −P(Ωu). Then u0 = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-137
SLIDE 137

Remarks: sharpness of conditions - counterexamples

Condition at u = a: Gu(a, 0) < 0 Consider the function G(u, p) = 1

2(u2 − p2).

G(u, p) satisfies (i) because Gpp(u, p) = −2 G(u, p) satisfies (iii) because Gu(b, 0) = b G does not satisfy (ii.1), neither (ii.2).

The solution of (1) for this G(u, p) is (the circle) u0 = a. Indeed, for admissible u we have j(u) = 1 2

(u+u′′)u ≥ a 2

(u+u′′) = a 2

u ≥ πa2 = j(u0), which proves that u0 ≡ a is the minimizer of j(u). Another example: Take G(u, p) = −(u2+p2)1/2

u2

, so j(u) = −P(Ωu). Then u0 = a.

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-138
SLIDE 138

Remarks: sharpness of conditions - counterexamples

Condition at u = b: Gu(b, 0) ≥ 0 Consider G(u, p) = −1

2(u2 + p2).

G(u, p) satisfies (i), (ii.1) since Gpp = −2 and Gu(a, 0) = −a. G(u, p) does not satisfy (iii). A solution of the corresponding minimization problem is u0 ≡ b. In fact, any u0 representing a convex polygon with edges tangent to the circle {u0 = b} is a solution! Indeed: j(u) = lim

n→∞ j(un) = −1

2 lim

n→∞

(u2

n + |u′ n|)2 ≥ −πb2

= j(u0).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-139
SLIDE 139

Remarks: sharpness of conditions - counterexamples

Condition at u = b: Gu(b, 0) ≥ 0 Consider G(u, p) = −1

2(u2 + p2).

G(u, p) satisfies (i), (ii.1) since Gpp = −2 and Gu(a, 0) = −a. G(u, p) does not satisfy (iii). A solution of the corresponding minimization problem is u0 ≡ b. In fact, any u0 representing a convex polygon with edges tangent to the circle {u0 = b} is a solution! Indeed: j(u) = lim

n→∞ j(un) = −1

2 lim

n→∞

(u2

n + |u′ n|)2 ≥ −πb2

= j(u0).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-140
SLIDE 140

Remarks: sharpness of conditions - counterexamples

Condition at u = b: Gu(b, 0) ≥ 0 Consider G(u, p) = −1

2(u2 + p2).

G(u, p) satisfies (i), (ii.1) since Gpp = −2 and Gu(a, 0) = −a. G(u, p) does not satisfy (iii). A solution of the corresponding minimization problem is u0 ≡ b. In fact, any u0 representing a convex polygon with edges tangent to the circle {u0 = b} is a solution! Indeed: j(u) = lim

n→∞ j(un) = −1

2 lim

n→∞

(u2

n + |u′ n|)2 ≥ −πb2

= j(u0).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-141
SLIDE 141

Remarks: sharpness of conditions - counterexamples

Condition at u = b: Gu(b, 0) ≥ 0 Consider G(u, p) = −1

2(u2 + p2).

G(u, p) satisfies (i), (ii.1) since Gpp = −2 and Gu(a, 0) = −a. G(u, p) does not satisfy (iii). A solution of the corresponding minimization problem is u0 ≡ b. In fact, any u0 representing a convex polygon with edges tangent to the circle {u0 = b} is a solution! Indeed: j(u) = lim

n→∞ j(un) = −1

2 lim

n→∞

(u2

n + |u′ n|)2 ≥ −πb2

= j(u0).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-142
SLIDE 142

Remarks: sharpness of conditions - counterexamples

Condition at u = b: Gu(b, 0) ≥ 0 Consider G(u, p) = −1

2(u2 + p2).

G(u, p) satisfies (i), (ii.1) since Gpp = −2 and Gu(a, 0) = −a. G(u, p) does not satisfy (iii). A solution of the corresponding minimization problem is u0 ≡ b. In fact, any u0 representing a convex polygon with edges tangent to the circle {u0 = b} is a solution! Indeed: j(u) = lim

n→∞ j(un) = −1

2 lim

n→∞

(u2

n + |u′ n|)2 ≥ −πb2

= j(u0).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-143
SLIDE 143

Remarks: sharpness of conditions - counterexamples

Condition at u = b: Gu(b, 0) ≥ 0 Consider G(u, p) = −1

2(u2 + p2).

G(u, p) satisfies (i), (ii.1) since Gpp = −2 and Gu(a, 0) = −a. G(u, p) does not satisfy (iii). A solution of the corresponding minimization problem is u0 ≡ b. In fact, any u0 representing a convex polygon with edges tangent to the circle {u0 = b} is a solution! Indeed: j(u) = lim

n→∞ j(un) = −1

2 lim

n→∞

(u2

n + |u′ n|)2 ≥ −πb2

= j(u0).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-144
SLIDE 144

Remarks: sharpness of conditions - counterexamples

Condition at u = b: Gu(b, 0) ≥ 0 Consider G(u, p) = −1

2(u2 + p2).

G(u, p) satisfies (i), (ii.1) since Gpp = −2 and Gu(a, 0) = −a. G(u, p) does not satisfy (iii). A solution of the corresponding minimization problem is u0 ≡ b. In fact, any u0 representing a convex polygon with edges tangent to the circle {u0 = b} is a solution! Indeed: j(u) = lim

n→∞ j(un) = −1

2 lim

n→∞

(u2

n + |u′ n|)2 ≥ −πb2

= j(u0).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-145
SLIDE 145

Remarks: generality of approach

j(u) =

  • ❚ G(θ, u, u′)dθ is a geometric shape functionnal.

The method works even for non-geometric shape functionnals. Namely, Theorem 0.1 is valid for

j : u ∈ W 1,∞(❚) → j(u) ∈ ❘, of class C2 and satisfying juu(u0)(v, v) ≤ −αv2

H1(❚) + βv2 L2(❚),

for some α > 0, β ∈ ❘, because vL∞(0,ǫ) ≤ √ǫv ′L2(0,ǫ), v ∈ H1

0(0, ǫ),

is used

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-146
SLIDE 146

Remarks: generality of approach

j(u) =

  • ❚ G(θ, u, u′)dθ is a geometric shape functionnal.

The method works even for non-geometric shape functionnals. Namely, Theorem 0.1 is valid for

j : u ∈ W 1,∞(❚) → j(u) ∈ ❘, of class C2 and satisfying juu(u0)(v, v) ≤ −αv2

H1(❚) + βv2 L2(❚),

for some α > 0, β ∈ ❘, because vL∞(0,ǫ) ≤ √ǫv ′L2(0,ǫ), v ∈ H1

0(0, ǫ),

is used

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-147
SLIDE 147

Remarks: generality of approach

j(u) =

  • ❚ G(θ, u, u′)dθ is a geometric shape functionnal.

The method works even for non-geometric shape functionnals. Namely, Theorem 0.1 is valid for

j : u ∈ W 1,∞(❚) → j(u) ∈ ❘, of class C2 and satisfying juu(u0)(v, v) ≤ −αv2

H1(❚) + βv2 L2(❚),

for some α > 0, β ∈ ❘, because vL∞(0,ǫ) ≤ √ǫv ′L2(0,ǫ), v ∈ H1

0(0, ǫ),

is used

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-148
SLIDE 148

Remarks: generality of approach

j(u) =

  • ❚ G(θ, u, u′)dθ is a geometric shape functionnal.

The method works even for non-geometric shape functionnals. Namely, Theorem 0.1 is valid for

j : u ∈ W 1,∞(❚) → j(u) ∈ ❘, of class C2 and satisfying juu(u0)(v, v) ≤ −αv2

H1(❚) + βv2 L2(❚),

for some α > 0, β ∈ ❘, because vL∞(0,ǫ) ≤ √ǫv ′L2(0,ǫ), v ∈ H1

0(0, ǫ),

is used

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-149
SLIDE 149

Remarks: generality of approach

j(u) =

  • ❚ G(θ, u, u′)dθ is a geometric shape functionnal.

The method works even for non-geometric shape functionnals. Namely, Theorem 0.1 is valid for

j : u ∈ W 1,∞(❚) → j(u) ∈ ❘, of class C2 and satisfying juu(u0)(v, v) ≤ −αv2

H1(❚) + βv2 L2(❚),

for some α > 0, β ∈ ❘, because vL∞(0,ǫ) ≤ √ǫv ′L2(0,ǫ), v ∈ H1

0(0, ǫ),

is used

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-150
SLIDE 150

Remarks: generality of approach

j(u) =

  • ❚ G(θ, u, u′)dθ is a geometric shape functionnal.

The method works even for non-geometric shape functionnals. Namely, Theorem 0.1 is valid for

j : u ∈ W 1,∞(❚) → j(u) ∈ ❘, of class C2 and satisfying juu(u0)(v, v) ≤ −αv2

H1(❚) + βv2 L2(❚),

for some α > 0, β ∈ ❘, because vL∞(0,ǫ) ≤ √ǫv ′L2(0,ǫ), v ∈ H1

0(0, ǫ),

is used

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-151
SLIDE 151

Remarks: generality of approach

j(u) =

  • ❚ G(θ, u, u′)dθ is a geometric shape functionnal.

The method works even for non-geometric shape functionnals. Namely, Theorem 0.1 is valid for

j : u ∈ W 1,∞(❚) → j(u) ∈ ❘, of class C2 and satisfying juu(u0)(v, v) ≤ −αv2

H1(❚) + βv2 L2(❚),

for some α > 0, β ∈ ❘, because vL∞(0,ǫ) ≤ √ǫv ′L2(0,ǫ), v ∈ H1

0(0, ǫ),

is used

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-152
SLIDE 152

Remarks: generality of approach

Example Consider L2(❚) ∋ p → ψ := Ψ(p) ∈ H1(❚) given by −ψ′′ + ψ = 1 + 1 2p2 on ❚ and j(u) = −1

2

  • ❚(ψ′)2 + ψ2 for p = u′. Then

ψ ≥ 1, and juu(u0)(v, v) = −

  • ❚ Ψ′

ppψ′ + Ψppψ −

  • ❚(Ψ′

p)2 + Ψ2 p

≤ −

  • ❚ Ψ′

ppψ′ + Ψppψ

=

  • ❚ ψ|v ′|2

≤ −v2

H1 + v2 L2.

So, if u0 is a minimizer of j(u) then Ωu0 is a polygon inside A(a, b).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-153
SLIDE 153

Remarks: generality of approach

Example Consider L2(❚) ∋ p → ψ := Ψ(p) ∈ H1(❚) given by −ψ′′ + ψ = 1 + 1 2p2 on ❚ and j(u) = −1

2

  • ❚(ψ′)2 + ψ2 for p = u′. Then

ψ ≥ 1, and juu(u0)(v, v) = −

  • ❚ Ψ′

ppψ′ + Ψppψ −

  • ❚(Ψ′

p)2 + Ψ2 p

≤ −

  • ❚ Ψ′

ppψ′ + Ψppψ

=

  • ❚ ψ|v ′|2

≤ −v2

H1 + v2 L2.

So, if u0 is a minimizer of j(u) then Ωu0 is a polygon inside A(a, b).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-154
SLIDE 154

Remarks: generality of approach

Example Consider L2(❚) ∋ p → ψ := Ψ(p) ∈ H1(❚) given by −ψ′′ + ψ = 1 + 1 2p2 on ❚ and j(u) = −1

2

  • ❚(ψ′)2 + ψ2 for p = u′. Then

ψ ≥ 1, and juu(u0)(v, v) = −

  • ❚ Ψ′

ppψ′ + Ψppψ −

  • ❚(Ψ′

p)2 + Ψ2 p

≤ −

  • ❚ Ψ′

ppψ′ + Ψppψ

=

  • ❚ ψ|v ′|2

≤ −v2

H1 + v2 L2.

So, if u0 is a minimizer of j(u) then Ωu0 is a polygon inside A(a, b).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-155
SLIDE 155

Remarks: generality of approach

Example Consider L2(❚) ∋ p → ψ := Ψ(p) ∈ H1(❚) given by −ψ′′ + ψ = 1 + 1 2p2 on ❚ and j(u) = −1

2

  • ❚(ψ′)2 + ψ2 for p = u′. Then

ψ ≥ 1, and juu(u0)(v, v) = −

  • ❚ Ψ′

ppψ′ + Ψppψ −

  • ❚(Ψ′

p)2 + Ψ2 p

≤ −

  • ❚ Ψ′

ppψ′ + Ψppψ

=

  • ❚ ψ|v ′|2

≤ −v2

H1 + v2 L2.

So, if u0 is a minimizer of j(u) then Ωu0 is a polygon inside A(a, b).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-156
SLIDE 156

Remarks: generality of approach

Example Consider L2(❚) ∋ p → ψ := Ψ(p) ∈ H1(❚) given by −ψ′′ + ψ = 1 + 1 2p2 on ❚ and j(u) = −1

2

  • ❚(ψ′)2 + ψ2 for p = u′. Then

ψ ≥ 1, and juu(u0)(v, v) = −

  • ❚ Ψ′

ppψ′ + Ψppψ −

  • ❚(Ψ′

p)2 + Ψ2 p

≤ −

  • ❚ Ψ′

ppψ′ + Ψppψ

=

  • ❚ ψ|v ′|2

≤ −v2

H1 + v2 L2.

So, if u0 is a minimizer of j(u) then Ωu0 is a polygon inside A(a, b).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-157
SLIDE 157

Remarks: generality of approach

Example Consider L2(❚) ∋ p → ψ := Ψ(p) ∈ H1(❚) given by −ψ′′ + ψ = 1 + 1 2p2 on ❚ and j(u) = −1

2

  • ❚(ψ′)2 + ψ2 for p = u′. Then

ψ ≥ 1, and juu(u0)(v, v) = −

  • ❚ Ψ′

ppψ′ + Ψppψ −

  • ❚(Ψ′

p)2 + Ψ2 p

≤ −

  • ❚ Ψ′

ppψ′ + Ψppψ

=

  • ❚ ψ|v ′|2

≤ −v2

H1 + v2 L2.

So, if u0 is a minimizer of j(u) then Ωu0 is a polygon inside A(a, b).

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit

slide-158
SLIDE 158

Thank you!

  • J. Lamboley, A. Novruzi

Polygons as solutions to shape optimization problems with convexit