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Overview of Mixing and Transport. William Young Scripps Institution of Oceanography June 2004 1 Prehistory of Stirring, Mixing and Transport Einstein, 1905 diffusion by discontinuous jumps. Taylor 1921 diffusion by continuous


  1. Overview of Mixing and Transport. William Young Scripps Institution of Oceanography June 2004 1

  2. Prehistory of Stirring, Mixing and Transport ♦ Einstein, 1905 — diffusion by discontinuous jumps. ♦ Taylor 1921 — diffusion by continuous movements. ♦ The renovating wave model — Zeldovich 19?? ♦ Eckart, 1948 — stirring versus mixing. ♦ Batchelor, 1952 — exponential stretching of line elements. ♦ Welander, 1955 — visualization of advective distortion. ♦ Molecular diffusivity and eddy diffusivity, correlation functions, enhanced transport, single realizations versus ensemble averages. Turbulent flame propagation, mixing of reactants, the geometry of turbulence. 2

  3. PART I: Eddy Diffusion 3

  4. Diffusion by discontinuous movements ♦ In 1905 Einstein explained Brown’s 1828 observation that sus- pended pollen grains (and also inorganic particles) are in “unin- terrupted and irregular swarming motion”. ♦ Einstein’s assumptions: (i) Particles move independently of one another. (ii) We observe particle positions at time intervals, τ , which are much greater than the interval between molecular collisions. So the motion in one interval is independent of the previous interval. 4

  5. The random walk: D ≡ � ∆ 2 � and � x 2 � = 2 Dt 2 τ A random walk with 200 steps N ( t ) � x ( t ) = ∆ k k =1 � x 2 � = N ( t ) � ∆ 2 � = � ∆ 2 � × 2 t 2 τ 5

  6. Einstein’s derivation of the diffusion equation ♦ In each interval τ each particle has a random displacement ∆ with a PDF, φ (∆; τ ): � ∞ � ∞ � ∆ 2 � ≡ ∆ 2 φ (∆) d∆ < ∞ . φ (∆) d∆ = 1 , −∞ −∞ ♦ If c ( x, t ) is particles per unit length at time t then � ∞ c ( x, t + τ ) = c ( x − ∆ , t ) φ (∆)d∆ . −∞ ♦ Taking τ, ∆ → 0, and Taylor expanding: D ≡ � ∆ 2 � U ≡ � ∆ � c t + Uc x ≈ Dc xx , , 2 τ τ where U and D are independent of τ . (OK provided τ is not too small, or too large.) 6

  7. Einstein’s formula D = k B T 6 πµa 7

  8. Eddy diffusion in a (turbulent) fluid ♦ In a fluid we observe continuous motion of particles. ♦ Example: ocean SOFAR floats. ♦ What is the analog of Einstein’s τ in a moving fluid? ♦ How to quantify the “diffusing power” of a flow? ♦ It is certainly not just KE ∝ �| u | 2 � ! ♦ Certainly changing direction is important e.g., perhaps �| u t | 2 � ? ♦ But the nondiffusing example u = U cos ωt confounds us.... 8

  9. Diffusion by continuous movements — Taylor (1921) A time series of Lagrangian velocity 2 u(t), 0 -2 0 0.5 1 1.5 2 2.5 3 3.5 4 t ♦ For a stationary time-series, u ( t ), � u 2 � , � u 2 � u 2 et cetera t � , tt � , are all constants. ♦ This implies � uu t � = 0 and � uu tt � = −� u 2 t � and so on. 9

  10. The correlation function ♦ The Lagrangian velocity correlation function C ( t ) = � u ( t 0 + t ) u ( t 0 ) � is key in understanding “diffusing power”. ♦ Note C ( t ) = � u 2 � − t 2 t � + t 4 2 � u 2 4! � u 2 tt � + · · · 10

  11. The diffusing power of a velocity field ♦ Taylor’s solution: � t d x d t = u ( t ) ⇒ x ( t ) = 0 u ( t 1 ) d t 1 . ♦ Multiply by u ( t ) and ensemble average, � t � t d x 2 d � x 2 � d t = 2 0 u ( t 1 ) u ( t ) d t, ⇒ = 2 0 � u ( t 1 ) u ( t ) � d t 1 . d t � �� � ≡C ( t − t 1 ) ♦ Our nondiffusing example is u ( t ) = U cos( ωt + φ ), and averag- ing over φ : 2 U 2 cos( ωt ) . C ( t ) = 1 11

  12. d � x 2 � � t Taylor’s formula: = 2 0 C ( t 1 ) d t 1 . d t 1.2 1 ∞ C(t) dt D= ∫ 0 0.8 C(t)/U 2 0.6 0.4 0.2 0 -0.2 0 0.5 1 1.5 2 2.5 3 t � ∞ ♦ If 0 C ( t )d t converges then the eddy diffusivity, D , is a well defined. ♦ But D might be zero (the sea surface) or infinite, (molecular diffusion in d = 2, where C ( t ) ∼ t − 1 ). 12

  13. Reconcile Einstein and Taylor? ♦ In a fluid we can still employ D = � ∆ 2 � / 2 τ E provided τ E ≥ τ T . ♦ The Taylor decorrelation time, τ T , is defined by � ∞ 0 C ( t ) d t = U 2 D = rms τ T . ♦ This implies � ∆ 2 � = 2 U 2 rms τ E τ T . 13

  14. Spatial correlations ♦ Fluid motion is also correlated spatially... ♦ D only provides single-particle information. ♦ To understand spatial correlations we must examine pairs of particles. ♦ To illustrate this, we construct a model that looks a little more like real fluid motion. ♦ We want a smoothly varying velocity field with a well defined D . ♦ We also want to be able to solve the model analytically, also and make efficient simulations. 14

  15. Eddy diffusion and stretching in a moving fluid ♦ Formulate the renovating wave model in d = 2. ♦ Advection with complete loss of memory at intervals of τ : ψ n = Uk − 1 cos[ k cos θ n x + k sin θ n y + ϕ n ] , I n = { ( n − 1) τ < t < nτ } : where θ n and ϕ n are random phases. ( u, v ) = ( − ψ y , ψ x ) Ukτ is a nondimensional parameter at left θ n = π/ 4 15

  16. Now solve ( ˙ x, ˙ y ) = ( − ψ y , ψ x ) explicitly in each I n ♦ The renovating wave model leads to a random map: � � � � x n +1 x n + Uτs n sin( kc n x n + ks n y n + ϕ n ) = , y n − Uτc n sin( kc n x n + ks n y n + ϕ n ) y n +1 where ( s n , c n ) ≡ (sin θ n , cos θ n ). t=20 τ D = τU 2 / 8 independent of k . t=0 ♦ Homework: C ( t ) =??? And evaluate ∂ ( x n +1 ,y n +1 ) · · · ∂ ( x n ,y n ) 16

  17. The advection-diffusion equation: c t + u ·∇ c = κ ∇ 2 c ♦ c ( x , t ) is the “concentration” and the velocity, u ( x , t ), is in- compressible, ∇· u = 0. ♦ Using the renovating wave model for u ( x, t ), we can exhibit single realizations with κ = 0. This is the “method of character- istics”. But really we just iterate the random map... ♦ Compute ensemble averages by integrating over { ϕ n , θ n } . 17

  18. Deformation of a medium sized blob kr ∼ 1 ♦ In a single realization the RW model produces spatially corre- lated deformation (not like molecular diffusion). t=1 τ t=2 τ t=3 τ The renovating wave model with Ukτ = 2 and kr = π . ♦ The IC is a circular blob and kr is a measure of scale separation . ♦ c ( x , t ) = 1 inside the blob and c ( x , t ) = − 1 outside. 18

  19. Stretching of a small blob, kr = π/ 40 ≪ 1 & Ukτ = 1 t=1 τ t=2 τ t=3 τ t=4 τ t=5 τ t=6 τ t=7 τ t=8 τ t=9 τ t=10 τ t=11 τ t=12 τ ♦ Area ℓ 1 × ℓ 2 is conserved. But ℓ 1 ∝ e γt and ℓ 2 ∝ e − γt .... 19

  20. “Eddy Diffusion” of a big blob, kr = 20 π & Ukτ = 1 t=1 τ t=2 τ t=3 τ t=4 τ t=5 τ t=6 τ t=7 τ t=8 τ t=9 τ t=10 τ t=11 τ t=12 τ ♦ The eddy-diffusion limit: small eddies advecting a large-scale tracer distribution. 20

  21. The eddy-diffusion equation — slavishly follow E ♦ In a “decorrelation time”, τ , particles in different realizations have independent random displacements, r . ♦ Assume isotropy, so the displacement, r ≡ | r | , has a pdf g ( r ): � � g ( r ) d 2 r , � r 2 � = r 2 g ( r ) d 2 r , 1 = ( d = 2) . g ( r ) is the same in each time interval of length τ . ♦ If C ( x , t ) is the ensemble-average concentration at time ( x , t ) and � C ( x − r , t ) g ( r )d 2 r . C ( x , t + τ ) = Notice C ( x , t ) = � c ( x , t ) � — tired of all these �� ’s. 21

  22. � C ( x − r , t ) g ( r )d 2 r C ( x , t + τ ) = ♦ Taking τ and r to zero, and freely Taylor expanding: C t = D ∇ 2 C, D = � r 2 � / 4 τ . ♦ Restrictions: � r 2 g ( r ) d 2 r must converge. • The integral � r 2 � = • The decorrelation time, τ , must be finite. • Small r and τ requires scale separation. • Ensemble averages and single-particle descriptors? 22

  23. Details for the RW model? ♦ In the RW model, g ( r ) is the ensemble averaged Green’s func: g ( r ) = � G ( x , τ ) � , G t + u · ∇ G = 0 , G ( x , 0) = δ ( x ) . ♦ I found g ( r ) = 1 H ( τ ∗ − r ) τ 2 − r 2 . � π 2 r (Using nondimensional variables with length scaled by k − 1 and time with ( Uk ) − 1 .) 23

  24. Eddy diffusion of a front c ( x , t ) = ± 1 t=3 τ t=6 τ t=9 τ t=12 τ t=15 τ t=18 τ t=21 τ t=24 τ 24

  25. The ensemble average satisfies C t = D ∇ 2 C . √ ♦ Does the “erf” solution with η = x/ 2 Dt , describe the disper- sion of the front? Not really — in each realization c ( x , t ) = ± 1. ♦ But the ensemble average, C ( x , t ), might be a useful approxi- mation to spatial averages of a single realization e.g., � K ( x − x ′ ) c ( x ′ , t ) d 2 x ′ , ˆ c ( x , t ) ≡ K ( | x | ) is a filter. ♦ In the front problem we can use � L 1 ¯ c ( x, t ) ≡ lim c ( x, y, t )d y , 2 L L →∞ − L and avoid the ˆ ˆ c � = ˆ c issue. ♦ For estimating the rate of chemical reactions “coarse-graining” is definitely not good idea... 25

  26. Asymptotic success of eddy diffusivity, D = U 2 τ/ 8 t=1 t=2 t=3 t=4 150 150 400 100 100 100 200 50 50 50 0 0 0 0 -0.5 0 0.5 -2 0 2 -2 0 2 -2 0 2 t=5 t=10 t=20 t=25 200 150 100 100 150 100 100 50 50 50 50 0 0 0 0 -4 -2 0 2 -5 0 5 -5 0 5 -5 0 5 t=50 t=100 t=400 t=1600 150 150 150 150 100 100 100 100 50 50 50 50 0 0 0 0 -10 0 10 -10 0 10 -20 0 20 40 -50 0 50 The x -coordinates of particles initially at x = 0 in a single realization ( Ukτ = 1). 26

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