SLIDE 54 Comparison of 64Ge and 66Ge
Assuming complete similarity between the nuclear wave functions in 64Ge and
66Ge (with 2 particles or 2 holes difference), we can write:
𝐵 = 64, 𝐾, 𝑈, 𝑈
3 = 0 = (𝐵 = 66, 𝐾, 𝑈 + 1) ⊗ (ℎ2, 𝐾 = 0, 𝑈 = 1) 𝐾, 𝑈,𝑈 3 = 0
Considering the mixing between states with different isospin in 64Ge, one finds:
𝑗, 𝐾 = 𝛾𝑗 𝐾, 𝑈 = 0 + 𝛽𝑗 𝐾, 𝑈 = 1 𝑔, 𝐾′ = 𝛾𝑔 𝐾′, 𝑈 = 0 + 𝛽𝑔 𝐾′, 𝑈 = 1
With standard angular momentum coupling techniques and exploiting the fact that for small values of 𝛽𝑗, 𝛽𝑔 one can approximate 𝛾𝑗=𝛾𝑔=1:
(𝑗, 𝐾 ℳ 1 (𝐹1) 𝑔, 𝐾′)(64𝐻𝑓) = (𝛽𝑗 − 𝛽𝑔) ∙ 2 3 (𝑗, 𝐾 ℳ 1 (𝐹1) 𝑔, 𝐾′)(66𝐻𝑓)
Therefore, the minimum value of isospin mixing in 64Ge is such that:
𝐶(𝐹1, 𝐾 → 𝐾′, 64Ge)= 8 3 𝛽2𝐶(𝐹1, 𝐾 → 𝐾′, 66Ge)
𝜷𝟑 = 𝟑. 𝟔%+𝟐. 𝟏% −𝟏. 𝟖%