On calculation of Blaker’s binomial confidence limits
Jan Klaschka
klaschka@cs.cas.cz
- Inst. of Computer Science, Academy of Sciences,
On calculation of Blakers binomial confidence limits Jan Klaschka - - PowerPoint PPT Presentation
On calculation of Blakers binomial confidence limits Jan Klaschka klaschka@cs.cas.cz Inst. of Computer Science, Academy of Sciences, Prague, Czech Republic COMPSTAT 2010, Paris, August 22-27, 2010 Summary Blaker (2000) proposed - a
0.0 0.2 0.4 0.6 0.8 1.0 0.0 0.2 0.4 0.6 0.8 1.0
Blaker’s confidence curve n = 10, k= 4
p confidence
0.0 0.2 0.4 0.6 0.8 1.0 0.0 0.2 0.4 0.6 0.8 1.0
Blaker’s confidence curve n = 10, k= 4
p confidence
0.0 0.2 0.4 0.6 0.8 1.0 0.0 0.2 0.4 0.6 0.8 1.0
Blaker’s confidence curve n = 10, k= 4
p confidence
1 Start in Clopper-Pearson limit pCP
L
2 Iterate p := p + ∆p
3 Once β(p) ≥ α, set pL := p − ∆p, finish
0.90 0.92 0.94 0.96 0.98 1.00 0.0 0.2 0.4 0.6 0.8 1.0
Original Blaker’s algorithm, step = 1e−04 n = 134, k = 131, alpha = 0.05
p confidence
0.90 0.92 0.94 0.96 0.98 1.00 0.0 0.2 0.4 0.6 0.8 1.0
Original Blaker’s algorithm, step = 1e−04 n = 134, k = 131, alpha = 0.05
p confidence
0.934 0.936 0.938 0.940 0.942 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.10
Original Blaker’s algorithm, step = 1e−04 n = 134, k = 131, alpha = 0.05
p confidence
0.934 0.936 0.938 0.940 0.942 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.10
Original Blaker’s algorithm, step = 1e−04 n = 134, k = 131, alpha = 0.05
p confidence
0.9360 0.9365 0.9370 0.9375 0.9380 0.9385 0.0497 0.0498 0.0499 0.0500 0.0501 0.0502
Original Blaker’s algorithm, step = 1e−04 n = 134, k = 131, alpha = 0.05
p confidence
0.9360 0.9365 0.9370 0.9375 0.9380 0.9385 0.0497 0.0498 0.0499 0.0500 0.0501 0.0502
Original Blaker’s algorithm, step = 1e−04 n = 134, k = 131, alpha = 0.05
p confidence
0.93600 0.93605 0.93610 0.93615 0.93620 0.04999 0.05000 0.05001 0.05002 0.05003 0.05004
Original Blaker’s algorithm, step = 1e−04 n = 134, k = 131, alpha = 0.05
p confidence
200 400 600 800 1000 −7 −6 −5 −4
Original Blaker’s algorithm − coverage deficit step = 1e−4, alpha = 0.05
n log(deficit)
200 400 600 800 1000 −7 −6 −5 −4
Original Blaker’s algorithm − coverage deficit step = 1e−5, alpha = 0.05
n log(deficit)
200 400 600 800 1000 −7 −6 −5 −4
Original Blaker’s algorithm − coverage deficit step = 1e−6, alpha = 0.05
n log(deficit)
L
L
L , p∗]
1 Modify β(·):
2 Apply interval halving to β∗(·) between pCP
L
L , p∗],