Lecture 2.2: Linear independence and the Wronskian Matthew Macauley - - PowerPoint PPT Presentation

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Lecture 2.2: Linear independence and the Wronskian Matthew Macauley - - PowerPoint PPT Presentation

Lecture 2.2: Linear independence and the Wronskian Matthew Macauley Department of Mathematical Sciences Clemson University http://www.math.clemson.edu/~macaule/ Math 4340, Advanced Engineering Mathematics M. Macauley (Clemson) Lecture 2.2:


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Lecture 2.2: Linear independence and the Wronskian

Matthew Macauley Department of Mathematical Sciences Clemson University http://www.math.clemson.edu/~macaule/ Math 4340, Advanced Engineering Mathematics

  • M. Macauley (Clemson)

Lecture 2.2: Linear independence and the Wronskian Advanced Engineering Mathematics 1 / 8

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Motivation

Question

To solve an nth order linear homogeneous ODE, we need to (somehow) find n linearly independent solutions, i.e., a basis for the solution space. Given n functions y1, . . . , yn, how can we determine if they are linearly independent? The case n = 1 is easy: {y1} is independent iff y1 ≡ 0. The case n = 2 isn’t difficult, but we have to be careful: {y1, y2} is independent iff y1 = cy2.

Example

Are the functions y1(t) = sin 2t and y2(t) = sin t cos t linearly independent? Things can get much more complicated if n > 2.

Example

Are the functions y1(t) = e2t, y2(t) = e−2t, and y3(t) = cosh 2t linearly independent? What about y1(t) = e2t − 5e−2t, y2(t) = 3e−2t − cosh 2t, and y3(t) = e2t + e−2t + cosh 2t?

  • M. Macauley (Clemson)

Lecture 2.2: Linear independence and the Wronskian Advanced Engineering Mathematics 2 / 8

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The Wronskian

Definition

Let f1, . . . , fn be functions defined on an interval [α, β]. Their Wronskian is defined by W (f1, . . . , fn)(x) =

  • f1(x)

f2(x) · · · fn(x) f ′

1 (x)

f ′

2 (x)

· · · f ′

n(x)

. . . . . . ... . . . f (n−1)

1

(x) f (n−1)

2

(x) · · · f (n−1)

n

(x)

  • Example

Compute the Wronskian of y1(t) = cos t and y2(t) = sin t.

Theorem

If W (f1, . . . , fn) ≡ 0, then {f1, . . . , fn} is linearly independent.

Remark

Unfortunately, W (f1, . . . , fn) ≡ 0 does not necessarily imply that {f1, . . . , fn} is linearly independent. Example: f1(x) = x2 and f2(x) = |x| · x.

  • M. Macauley (Clemson)

Lecture 2.2: Linear independence and the Wronskian Advanced Engineering Mathematics 3 / 8

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Key property of the Wronskian

Abel’s theorem

Let y1, y2 be solutions to y′′ + a(t)y′ + b(t)y = 0, where a, b are continuous in [α, β]. Then the Wronskian is W (y1, y2)(t) = Ce−

  • a(t) dt,

for some constant C. Moreover, W (t) is either identically 0, or never zero, on [α, β].

Proof

Claim: The Wronskian W (y1, y2) is a solution to the first order ODE W ′ + a(t)W = 0.

  • M. Macauley (Clemson)

Lecture 2.2: Linear independence and the Wronskian Advanced Engineering Mathematics 4 / 8

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Reduction of order

Abel’s theorem

Let y1, y2 be solutions to y′′ + a(t)y′ + b(t)y = 0, where a, b are continuous in [α, β]. Then the Wronskian is W (y1, y2)(t) = Ce−

  • a(t) dt,

for some constant C. Moreover, W (t) is either identically 0, or never zero, on [α, β].

Corollary

If we only know one solution y1(t) of an 2nd order ODE, then we can solve for the other: y′

2 + a(t)y2 = g(t) :

y′

2 − y′ 1

y1 y2 = W (y1, y2)/y1 = e−

  • a(t) dt/y1.

Proof

  • M. Macauley (Clemson)

Lecture 2.2: Linear independence and the Wronskian Advanced Engineering Mathematics 5 / 8

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Reduction of order

Example

Solve y′′ + 4y′ + 4y = 0.

  • M. Macauley (Clemson)

Lecture 2.2: Linear independence and the Wronskian Advanced Engineering Mathematics 6 / 8

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More applications of Abel’s theorem

Abel’s theorem

Let y1, y2 be solutions to y′′ + a(t)y′ + b(t)y = 0, where a, b are continuous in [α, β]. Then the Wronskian is W (y1, y2)(t) = Ce−

  • a(t) dt,

for some constant C. Moreover, W (t) is either identically 0, or never zero, on [α, β].

Example

Compute the Wronskian of y1(t) = sin 2t and y2(t) = sin t cos t.

  • M. Macauley (Clemson)

Lecture 2.2: Linear independence and the Wronskian Advanced Engineering Mathematics 7 / 8

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More applications of Abel’s theorem

Abel’s theorem

Let y1, y2 be solutions to y′′ + a(t)y′ + b(t)y = 0, where a, b are continuous in [α, β]. Then the Wronskian is W (y1, y2)(t) = Ce−

  • a(t) dt,

for some constant C. Moreover, W (t) is either identically 0, or never zero, on [α, β].

Example

There is no ODE of the form y′′ + a(t)y′ + b(t)y = 0 that has both y1(t) = t2 and y2(t) = t + 1 as solutions.

  • M. Macauley (Clemson)

Lecture 2.2: Linear independence and the Wronskian Advanced Engineering Mathematics 8 / 8