Linear independence of zeros of Dirichlet L -functions Greg Martin - - PowerPoint PPT Presentation

linear independence of zeros of dirichlet l functions
SMART_READER_LITE
LIVE PREVIEW

Linear independence of zeros of Dirichlet L -functions Greg Martin - - PowerPoint PPT Presentation

Linear independence conjectures Vertical arithmetic progressions Other work in progress Linear independence of zeros of Dirichlet L -functions Greg Martin University of British Columbia joint work with Nathan Ng University of Lethbridge 3rd


slide-1
SLIDE 1

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence of zeros of Dirichlet L-functions

Greg Martin

University of British Columbia joint work with Nathan Ng University of Lethbridge 3rd Montreal–Toronto Workshop in Number Theory University of Toronto October 7, 2011 in honour of John Friedlander’s 70th birthday

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-2
SLIDE 2

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence of zeros of Dirichlet L-functions

Greg Martin

University of British Columbia joint work with Nathan Ng University of Lethbridge 3rd Montreal–Toronto Workshop in Number Theory University of Toronto October 7, 2011 in honour of John Friedlander’s 70th birthday

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-3
SLIDE 3

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Outline

1

Linear independence conjectures

2

Vertical arithmetic progressions

3

Other work in progress

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-4
SLIDE 4

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Zeros of Dirichlet L-functions: horizontal distribution

Classical fact: every Dirichlet L-function L(s, χ) = ∞

n=1 χ(n)n−s

has infinitely many zeros ρ = β + iγ whose real parts satisfy 0 < β < 1 (“nontrivial zeros”).

Conjecture GRH

Generalized Riemann hypothesis: every nontrivial zero actually satisfies β = 1

2.

Notice that this conjecture actually addresses both: the analytic nature of the zeros’ abscissae (the distribution function of β is a Dirac delta function at 1

2);

the algebraic nature of the zeros’ abscissae (the β are all rational, for example).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-5
SLIDE 5

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Zeros of Dirichlet L-functions: horizontal distribution

Classical fact: every Dirichlet L-function L(s, χ) = ∞

n=1 χ(n)n−s

has infinitely many zeros ρ = β + iγ whose real parts satisfy 0 < β < 1 (“nontrivial zeros”).

Conjecture GRH

Generalized Riemann hypothesis: every nontrivial zero actually satisfies β = 1

2.

Notice that this conjecture actually addresses both: the analytic nature of the zeros’ abscissae (the distribution function of β is a Dirac delta function at 1

2);

the algebraic nature of the zeros’ abscissae (the β are all rational, for example).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-6
SLIDE 6

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Zeros of Dirichlet L-functions: horizontal distribution

Classical fact: every Dirichlet L-function L(s, χ) = ∞

n=1 χ(n)n−s

has infinitely many zeros ρ = β + iγ whose real parts satisfy 0 < β < 1 (“nontrivial zeros”).

Conjecture GRH

Generalized Riemann hypothesis: every nontrivial zero actually satisfies β = 1

2.

Notice that this conjecture actually addresses both: the analytic nature of the zeros’ abscissae (the distribution function of β is a Dirac delta function at 1

2);

the algebraic nature of the zeros’ abscissae (the β are all rational, for example).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-7
SLIDE 7

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Zeros of Dirichlet L-functions: horizontal distribution

Classical fact: every Dirichlet L-function L(s, χ) = ∞

n=1 χ(n)n−s

has infinitely many zeros ρ = β + iγ whose real parts satisfy 0 < β < 1 (“nontrivial zeros”).

Conjecture GRH

Generalized Riemann hypothesis: every nontrivial zero actually satisfies β = 1

2.

Notice that this conjecture actually addresses both: the analytic nature of the zeros’ abscissae (the distribution function of β is a Dirac delta function at 1

2);

the algebraic nature of the zeros’ abscissae (the β are all rational, for example).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-8
SLIDE 8

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Zeros of Dirichlet L-functions: vertical distribution

We have some good ideas about the distribution of the imaginary parts as well: The number of zeros β + iγ with 0 ≤ γ ≤ T is asymptotic to

T 2π log qT 2π; in fact we have an asymptotic formula for the

number of zeros with T ≤ γ ≤ T + y when y is almost bounded. We have conjectures for the distribution of gaps between

  • rdinates and, more generally, for the n-level correlations of

the sequence γ. Note that these statements all concern the analytic nature of the zeros’ ordinates.

Question

What about the algebraic nature of the zeros’ ordinates γ?

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-9
SLIDE 9

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Zeros of Dirichlet L-functions: vertical distribution

We have some good ideas about the distribution of the imaginary parts as well: The number of zeros β + iγ with 0 ≤ γ ≤ T is asymptotic to

T 2π log qT 2π; in fact we have an asymptotic formula for the

number of zeros with T ≤ γ ≤ T + y when y is almost bounded. We have conjectures for the distribution of gaps between

  • rdinates and, more generally, for the n-level correlations of

the sequence γ. Note that these statements all concern the analytic nature of the zeros’ ordinates.

Question

What about the algebraic nature of the zeros’ ordinates γ?

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-10
SLIDE 10

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Zeros of Dirichlet L-functions: vertical distribution

We have some good ideas about the distribution of the imaginary parts as well: The number of zeros β + iγ with 0 ≤ γ ≤ T is asymptotic to

T 2π log qT 2π; in fact we have an asymptotic formula for the

number of zeros with T ≤ γ ≤ T + y when y is almost bounded. We have conjectures for the distribution of gaps between

  • rdinates and, more generally, for the n-level correlations of

the sequence γ. Note that these statements all concern the analytic nature of the zeros’ ordinates.

Question

What about the algebraic nature of the zeros’ ordinates γ?

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-11
SLIDE 11

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Zeros of Dirichlet L-functions: vertical distribution

We have some good ideas about the distribution of the imaginary parts as well: The number of zeros β + iγ with 0 ≤ γ ≤ T is asymptotic to

T 2π log qT 2π; in fact we have an asymptotic formula for the

number of zeros with T ≤ γ ≤ T + y when y is almost bounded. We have conjectures for the distribution of gaps between

  • rdinates and, more generally, for the n-level correlations of

the sequence γ. Note that these statements all concern the analytic nature of the zeros’ ordinates.

Question

What about the algebraic nature of the zeros’ ordinates γ?

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-12
SLIDE 12

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Zeros of Dirichlet L-functions: vertical distribution

We have some good ideas about the distribution of the imaginary parts as well: The number of zeros β + iγ with 0 ≤ γ ≤ T is asymptotic to

T 2π log qT 2π; in fact we have an asymptotic formula for the

number of zeros with T ≤ γ ≤ T + y when y is almost bounded. We have conjectures for the distribution of gaps between

  • rdinates and, more generally, for the n-level correlations of

the sequence γ. Note that these statements all concern the analytic nature of the zeros’ ordinates.

Question

What about the algebraic nature of the zeros’ ordinates γ?

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-13
SLIDE 13

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence conjecture for zeros of ζ(s)

Let Z1 = {ρ: ζ(ρ) = 0, Re ρ ≥ 1

2, Im ρ ≥ 0} (where non-simple

zeros are listed several times according to their multiplicity, so that Z1 is a multiset). We restrict to Re ρ ≥ 1

2 and Im ρ ≥ 0 to avoid the zeros

caused by the symmetry and functional equation of ζ. Let S1 be the multiset of imaginary parts of the elements of Z1.

Conjecture LI1

The ordinates of the zeros of ζ(s) are linearly independent over the rational numbers. More precisely, S1 is linearly independent over Q.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-14
SLIDE 14

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence conjecture for zeros of ζ(s)

Let Z1 = {ρ: ζ(ρ) = 0, Re ρ ≥ 1

2, Im ρ ≥ 0} (where non-simple

zeros are listed several times according to their multiplicity, so that Z1 is a multiset). We restrict to Re ρ ≥ 1

2 and Im ρ ≥ 0 to avoid the zeros

caused by the symmetry and functional equation of ζ. Let S1 be the multiset of imaginary parts of the elements of Z1.

Conjecture LI1

The ordinates of the zeros of ζ(s) are linearly independent over the rational numbers. More precisely, S1 is linearly independent over Q.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-15
SLIDE 15

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence conjecture for zeros of ζ(s)

Let Z1 = {ρ: ζ(ρ) = 0, Re ρ ≥ 1

2, Im ρ ≥ 0} (where non-simple

zeros are listed several times according to their multiplicity, so that Z1 is a multiset). We restrict to Re ρ ≥ 1

2 and Im ρ ≥ 0 to avoid the zeros

caused by the symmetry and functional equation of ζ. Let S1 be the multiset of imaginary parts of the elements of Z1.

Conjecture LI1

The ordinates of the zeros of ζ(s) are linearly independent over the rational numbers. More precisely, S1 is linearly independent over Q.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-16
SLIDE 16

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence conjecture for zeros of ζ(s)

Let Z1 = {ρ: ζ(ρ) = 0, Re ρ ≥ 1

2, Im ρ ≥ 0} (where non-simple

zeros are listed several times according to their multiplicity, so that Z1 is a multiset). We restrict to Re ρ ≥ 1

2 and Im ρ ≥ 0 to avoid the zeros

caused by the symmetry and functional equation of ζ. Let S1 be the multiset of imaginary parts of the elements of Z1.

Conjecture LI1

The ordinates of the zeros of ζ(s) are linearly independent over the rational numbers. More precisely, S1 is linearly independent over Q.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-17
SLIDE 17

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Some history of LI1

Wintner used LI1 to study the limiting (logarithmic) distribution of log x

√x (π(x) − li(x)), as did Montgomery (1979)

and Monach (1980). Ingham (1942) showed that LI1 implies: lim sup

x→∞

  • x−1/2

n≤x

µ(n)

  • = +∞.

In particular, LI1 implies that the Mertens conjecture |M(x)| < √x is false. Odlyzko and te Riele (1986) unconditionally disproved the Mertens conjecture. Proof follows Ingham and makes use

  • f numerical calculations where k

j=1 ajγj is small (γj ∈ S1).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-18
SLIDE 18

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Some history of LI1

Wintner used LI1 to study the limiting (logarithmic) distribution of log x

√x (π(x) − li(x)), as did Montgomery (1979)

and Monach (1980). Ingham (1942) showed that LI1 implies: lim sup

x→∞

  • x−1/2

n≤x

µ(n)

  • = +∞.

In particular, LI1 implies that the Mertens conjecture |M(x)| < √x is false. Odlyzko and te Riele (1986) unconditionally disproved the Mertens conjecture. Proof follows Ingham and makes use

  • f numerical calculations where k

j=1 ajγj is small (γj ∈ S1).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-19
SLIDE 19

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Some history of LI1

Wintner used LI1 to study the limiting (logarithmic) distribution of log x

√x (π(x) − li(x)), as did Montgomery (1979)

and Monach (1980). Ingham (1942) showed that LI1 implies: lim sup

x→∞

  • x−1/2

n≤x

µ(n)

  • = +∞.

In particular, LI1 implies that the Mertens conjecture |M(x)| < √x is false. Odlyzko and te Riele (1986) unconditionally disproved the Mertens conjecture. Proof follows Ingham and makes use

  • f numerical calculations where k

j=1 ajγj is small (γj ∈ S1).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-20
SLIDE 20

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Some history of LI1

Wintner used LI1 to study the limiting (logarithmic) distribution of log x

√x (π(x) − li(x)), as did Montgomery (1979)

and Monach (1980). Ingham (1942) showed that LI1 implies: lim sup

x→∞

  • x−1/2

n≤x

µ(n)

  • = +∞.

In particular, LI1 implies that the Mertens conjecture |M(x)| < √x is false. Odlyzko and te Riele (1986) unconditionally disproved the Mertens conjecture. Proof follows Ingham and makes use

  • f numerical calculations where k

j=1 ajγj is small (γj ∈ S1).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-21
SLIDE 21

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence conjecture for zeros of L(s, χ)

Analogously, for every Dirichlet character χ, define Zχ = {ρ: L(ρ, χ) = 0, Re ρ ≥ 1

2, Im ρ ≥ 0}

and let Sχ be the multiset of the imaginary parts of the elements

  • f Zχ. Further, define

Sq =

  • primitive χ (mod q)

Sχ and S =

  • q=1

Sq.

Conjecture LI

S is linearly independent over Q. Conjecture LI appears in an article of Hooley (1977). Rubinstein and Sarnak (1994) and others used LI to study prime number races.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-22
SLIDE 22

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence conjecture for zeros of L(s, χ)

Analogously, for every Dirichlet character χ, define Zχ = {ρ: L(ρ, χ) = 0, Re ρ ≥ 1

2, Im ρ ≥ 0}

and let Sχ be the multiset of the imaginary parts of the elements

  • f Zχ. Further, define

Sq =

  • primitive χ (mod q)

Sχ and S =

  • q=1

Sq.

Conjecture LI

S is linearly independent over Q. Conjecture LI appears in an article of Hooley (1977). Rubinstein and Sarnak (1994) and others used LI to study prime number races.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-23
SLIDE 23

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence conjecture for zeros of L(s, χ)

Analogously, for every Dirichlet character χ, define Zχ = {ρ: L(ρ, χ) = 0, Re ρ ≥ 1

2, Im ρ ≥ 0}

and let Sχ be the multiset of the imaginary parts of the elements

  • f Zχ. Further, define

Sq =

  • primitive χ (mod q)

Sχ and S =

  • q=1

Sq.

Conjecture LI

S is linearly independent over Q. Conjecture LI appears in an article of Hooley (1977). Rubinstein and Sarnak (1994) and others used LI to study prime number races.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-24
SLIDE 24

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence conjecture for zeros of L(s, χ)

Analogously, for every Dirichlet character χ, define Zχ = {ρ: L(ρ, χ) = 0, Re ρ ≥ 1

2, Im ρ ≥ 0}

and let Sχ be the multiset of the imaginary parts of the elements

  • f Zχ. Further, define

Sq =

  • primitive χ (mod q)

Sχ and S =

  • q=1

Sq.

Conjecture LI

S is linearly independent over Q. Conjecture LI appears in an article of Hooley (1977). Rubinstein and Sarnak (1994) and others used LI to study prime number races.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-25
SLIDE 25

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Linear independence conjecture for zeros of L(s, χ)

Analogously, for every Dirichlet character χ, define Zχ = {ρ: L(ρ, χ) = 0, Re ρ ≥ 1

2, Im ρ ≥ 0}

and let Sχ be the multiset of the imaginary parts of the elements

  • f Zχ. Further, define

Sq =

  • primitive χ (mod q)

Sχ and S =

  • q=1

Sq.

Conjecture LI

S is linearly independent over Q. Conjecture LI appears in an article of Hooley (1977). Rubinstein and Sarnak (1994) and others used LI to study prime number races.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-26
SLIDE 26

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Consequences of LI: Non-vanishing of L(1

2, χ)

No linearly independent set can contain 0, so LI implies:

Conjecture

L( 1

2, χ) = 0 for all Dirichlet L-functions.

For real characters, this is a conjecture of Chowla (1965). The proportion of real Dirichlet characters χ with L( 1

2, χ) = 0 is greater than 7 8 (Soundararajan, 2000).

At least 34% of all even primitive Dirichlet characters χ with prime conductor satisfy L( 1

2, χ) = 0 (Bui, 2010).

Builds on work of Iwaniec and Sarnak (1999) and Balasubramanian and V.K. Murty (1992).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-27
SLIDE 27

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Consequences of LI: Non-vanishing of L(1

2, χ)

No linearly independent set can contain 0, so LI implies:

Conjecture

L( 1

2, χ) = 0 for all Dirichlet L-functions.

For real characters, this is a conjecture of Chowla (1965). The proportion of real Dirichlet characters χ with L( 1

2, χ) = 0 is greater than 7 8 (Soundararajan, 2000).

At least 34% of all even primitive Dirichlet characters χ with prime conductor satisfy L( 1

2, χ) = 0 (Bui, 2010).

Builds on work of Iwaniec and Sarnak (1999) and Balasubramanian and V.K. Murty (1992).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-28
SLIDE 28

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Consequences of LI: Non-vanishing of L(1

2, χ)

No linearly independent set can contain 0, so LI implies:

Conjecture

L( 1

2, χ) = 0 for all Dirichlet L-functions.

For real characters, this is a conjecture of Chowla (1965). The proportion of real Dirichlet characters χ with L( 1

2, χ) = 0 is greater than 7 8 (Soundararajan, 2000).

At least 34% of all even primitive Dirichlet characters χ with prime conductor satisfy L( 1

2, χ) = 0 (Bui, 2010).

Builds on work of Iwaniec and Sarnak (1999) and Balasubramanian and V.K. Murty (1992).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-29
SLIDE 29

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Consequences of LI: Non-vanishing of L(1

2, χ)

No linearly independent set can contain 0, so LI implies:

Conjecture

L( 1

2, χ) = 0 for all Dirichlet L-functions.

For real characters, this is a conjecture of Chowla (1965). The proportion of real Dirichlet characters χ with L( 1

2, χ) = 0 is greater than 7 8 (Soundararajan, 2000).

At least 34% of all even primitive Dirichlet characters χ with prime conductor satisfy L( 1

2, χ) = 0 (Bui, 2010).

Builds on work of Iwaniec and Sarnak (1999) and Balasubramanian and V.K. Murty (1992).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-30
SLIDE 30

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Consequences of LI: Simple zeros of L(s, χ)

A linearly independent multiset can’t in fact contain repeated elements, so LI implies:

Conjecture

All zeros of Dirichlet L-functions are simple, and no two Dirichlet L-functions share a zero. For any L(s, χ), at least 1

3 of the zeros are simple and on

the critical line (Bauer, 2000). For ζ(s), at least 41% are simple and critical (Bui, Conrey, and Young, 2010). Assuming GRH, at least 11

12 of the zeros are simple (Ozluk,

1996). When all characters to all moduli are considered together, at least 1

2 of the zeros of the L(s, χ) are simple (Conrey,

Iwaniec, and Soundararajan, 2011).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-31
SLIDE 31

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Consequences of LI: Simple zeros of L(s, χ)

A linearly independent multiset can’t in fact contain repeated elements, so LI implies:

Conjecture

All zeros of Dirichlet L-functions are simple, and no two Dirichlet L-functions share a zero. For any L(s, χ), at least 1

3 of the zeros are simple and on

the critical line (Bauer, 2000). For ζ(s), at least 41% are simple and critical (Bui, Conrey, and Young, 2010). Assuming GRH, at least 11

12 of the zeros are simple (Ozluk,

1996). When all characters to all moduli are considered together, at least 1

2 of the zeros of the L(s, χ) are simple (Conrey,

Iwaniec, and Soundararajan, 2011).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-32
SLIDE 32

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Consequences of LI: Simple zeros of L(s, χ)

A linearly independent multiset can’t in fact contain repeated elements, so LI implies:

Conjecture

All zeros of Dirichlet L-functions are simple, and no two Dirichlet L-functions share a zero. For any L(s, χ), at least 1

3 of the zeros are simple and on

the critical line (Bauer, 2000). For ζ(s), at least 41% are simple and critical (Bui, Conrey, and Young, 2010). Assuming GRH, at least 11

12 of the zeros are simple (Ozluk,

1996). When all characters to all moduli are considered together, at least 1

2 of the zeros of the L(s, χ) are simple (Conrey,

Iwaniec, and Soundararajan, 2011).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-33
SLIDE 33

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Consequences of LI: Simple zeros of L(s, χ)

A linearly independent multiset can’t in fact contain repeated elements, so LI implies:

Conjecture

All zeros of Dirichlet L-functions are simple, and no two Dirichlet L-functions share a zero. For any L(s, χ), at least 1

3 of the zeros are simple and on

the critical line (Bauer, 2000). For ζ(s), at least 41% are simple and critical (Bui, Conrey, and Young, 2010). Assuming GRH, at least 11

12 of the zeros are simple (Ozluk,

1996). When all characters to all moduli are considered together, at least 1

2 of the zeros of the L(s, χ) are simple (Conrey,

Iwaniec, and Soundararajan, 2011).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-34
SLIDE 34

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Vertical arithmetic progressions

Fix real numbers a, b and consider the arithmetic progression

1 2 + i(a + kb) (k = 1, 2, . . . ) on the critical line.

Consequence of LI

Three terms in an arithmetic progression a + kb are linearly dependent over Q, so we expect to find at most two zeros of L(s, χ) in this arithmetic progression (and at most one zero if a = 0). Putnam (1954) proved that ζ( 1

2 + ikb, χ) = 0 for infinitely

many values of k. Lapidus and van Frankenhuysen (2000) proved that ≫ T5/6 of the first T values L( 1

2 + ikb, χ) are nonzero;

assuming GRH, they proved ≫ε T1−ε.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-35
SLIDE 35

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Vertical arithmetic progressions

Fix real numbers a, b and consider the arithmetic progression

1 2 + i(a + kb) (k = 1, 2, . . . ) on the critical line.

Consequence of LI

Three terms in an arithmetic progression a + kb are linearly dependent over Q, so we expect to find at most two zeros of L(s, χ) in this arithmetic progression (and at most one zero if a = 0). Putnam (1954) proved that ζ( 1

2 + ikb, χ) = 0 for infinitely

many values of k. Lapidus and van Frankenhuysen (2000) proved that ≫ T5/6 of the first T values L( 1

2 + ikb, χ) are nonzero;

assuming GRH, they proved ≫ε T1−ε.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-36
SLIDE 36

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Vertical arithmetic progressions

Fix real numbers a, b and consider the arithmetic progression

1 2 + i(a + kb) (k = 1, 2, . . . ) on the critical line.

Consequence of LI

Three terms in an arithmetic progression a + kb are linearly dependent over Q, so we expect to find at most two zeros of L(s, χ) in this arithmetic progression (and at most one zero if a = 0). Putnam (1954) proved that ζ( 1

2 + ikb, χ) = 0 for infinitely

many values of k. Lapidus and van Frankenhuysen (2000) proved that ≫ T5/6 of the first T values L( 1

2 + ikb, χ) are nonzero;

assuming GRH, they proved ≫ε T1−ε.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-37
SLIDE 37

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Vertical arithmetic progressions

Fix real numbers a, b and consider the arithmetic progression

1 2 + i(a + kb) (k = 1, 2, . . . ) on the critical line.

Consequence of LI

Three terms in an arithmetic progression a + kb are linearly dependent over Q, so we expect to find at most two zeros of L(s, χ) in this arithmetic progression (and at most one zero if a = 0). Putnam (1954) proved that ζ( 1

2 + ikb, χ) = 0 for infinitely

many values of k. Lapidus and van Frankenhuysen (2000) proved that ≫ T5/6 of the first T values L( 1

2 + ikb, χ) are nonzero;

assuming GRH, they proved ≫ε T1−ε.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-38
SLIDE 38

Linear independence conjectures Vertical arithmetic progressions Other work in progress

More nonzero values

Theorem (M.–Ng, 2011)

Let χ be a Dirichlet character, and let a and b be real numbers with b = 0. Then #

  • 1 ≤ k ≤ T : L

1

2 + i(a + kb), χ

  • = 0
  • ≫χ,a,b

T log T . Our theorem strengthens Lapidus and van Frankenhuysen without requiring GRH, as well as extending the result to nonhomogeneous arithmetic progressions (a = 0). Our methods apply also to other vertical lines; however, zero-density results (Linnik, 1946) already show that L(σ + i(a + kb), χ) = 0 for almost all 1 ≤ k ≤ T when σ = 1

2.

We would like to have shown that a positive proportion of points in the arithmetic progression weren’t zeros of L(s, χ), but for now this stronger statement remains open.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-39
SLIDE 39

Linear independence conjectures Vertical arithmetic progressions Other work in progress

More nonzero values

Theorem (M.–Ng, 2011)

Let χ be a Dirichlet character, and let a and b be real numbers with b = 0. Then #

  • 1 ≤ k ≤ T : L

1

2 + i(a + kb), χ

  • = 0
  • ≫χ,a,b

T log T . Our theorem strengthens Lapidus and van Frankenhuysen without requiring GRH, as well as extending the result to nonhomogeneous arithmetic progressions (a = 0). Our methods apply also to other vertical lines; however, zero-density results (Linnik, 1946) already show that L(σ + i(a + kb), χ) = 0 for almost all 1 ≤ k ≤ T when σ = 1

2.

We would like to have shown that a positive proportion of points in the arithmetic progression weren’t zeros of L(s, χ), but for now this stronger statement remains open.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-40
SLIDE 40

Linear independence conjectures Vertical arithmetic progressions Other work in progress

More nonzero values

Theorem (M.–Ng, 2011)

Let χ be a Dirichlet character, and let a and b be real numbers with b = 0. Then #

  • 1 ≤ k ≤ T : L

1

2 + i(a + kb), χ

  • = 0
  • ≫χ,a,b

T log T . Our theorem strengthens Lapidus and van Frankenhuysen without requiring GRH, as well as extending the result to nonhomogeneous arithmetic progressions (a = 0). Our methods apply also to other vertical lines; however, zero-density results (Linnik, 1946) already show that L(σ + i(a + kb), χ) = 0 for almost all 1 ≤ k ≤ T when σ = 1

2.

We would like to have shown that a positive proportion of points in the arithmetic progression weren’t zeros of L(s, χ), but for now this stronger statement remains open.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-41
SLIDE 41

Linear independence conjectures Vertical arithmetic progressions Other work in progress

More nonzero values

Theorem (M.–Ng, 2011)

Let χ be a Dirichlet character, and let a and b be real numbers with b = 0. Then #

  • 1 ≤ k ≤ T : L

1

2 + i(a + kb), χ

  • = 0
  • ≫χ,a,b

T log T . Our theorem strengthens Lapidus and van Frankenhuysen without requiring GRH, as well as extending the result to nonhomogeneous arithmetic progressions (a = 0). Our methods apply also to other vertical lines; however, zero-density results (Linnik, 1946) already show that L(σ + i(a + kb), χ) = 0 for almost all 1 ≤ k ≤ T when σ = 1

2.

We would like to have shown that a positive proportion of points in the arithmetic progression weren’t zeros of L(s, χ), but for now this stronger statement remains open.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-42
SLIDE 42

Linear independence conjectures Vertical arithmetic progressions Other work in progress

The lowest nonzero value

Watkins (1998, unpublished) had determined a bound for the least k such that L( 1

2 + ikb, χ) = 0. We can improve his bound:

Theorem (M.–Ng, 2011)

Let χ be a Dirichlet character modulo q, and let 0 ≤ a < b be real numbers. Then there exists a positive integer k ≪ε

  • q max{b3, b−1})1+ε

such that L( 1

2 + i(a + kb), χ) = 0.

We obtain something a little more precise. For example, with q = 1, there exists a positive integer k ≪ 1 + b3 exp

  • 17 log b/ log log b
  • for which ζ( 1

2 + i(a + kb)) = 0.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-43
SLIDE 43

Linear independence conjectures Vertical arithmetic progressions Other work in progress

The lowest nonzero value

Watkins (1998, unpublished) had determined a bound for the least k such that L( 1

2 + ikb, χ) = 0. We can improve his bound:

Theorem (M.–Ng, 2011)

Let χ be a Dirichlet character modulo q, and let 0 ≤ a < b be real numbers. Then there exists a positive integer k ≪ε

  • q max{b3, b−1})1+ε

such that L( 1

2 + i(a + kb), χ) = 0.

We obtain something a little more precise. For example, with q = 1, there exists a positive integer k ≪ 1 + b3 exp

  • 17 log b/ log log b
  • for which ζ( 1

2 + i(a + kb)) = 0.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-44
SLIDE 44

Linear independence conjectures Vertical arithmetic progressions Other work in progress

The lowest nonzero value

Watkins (1998, unpublished) had determined a bound for the least k such that L( 1

2 + ikb, χ) = 0. We can improve his bound:

Theorem (M.–Ng, 2011)

Let χ be a Dirichlet character modulo q, and let 0 ≤ a < b be real numbers. Then there exists a positive integer k ≪ε

  • q max{b3, b−1})1+ε

such that L( 1

2 + i(a + kb), χ) = 0.

We obtain something a little more precise. For example, with q = 1, there exists a positive integer k ≪ 1 + b3 exp

  • 17 log b/ log log b
  • for which ζ( 1

2 + i(a + kb)) = 0.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-45
SLIDE 45

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Outline of proof

Let a = 2πα and b = 2πβ, and set sk = 1

2 + 2πi(α + kβ) for k = 1, 2, . . . .

First and second mollified moments

Define S1(T) =

T

  • k=1

L(sk, χ)M(sk) and S2(T) =

T

  • k=1

|L(sk, χ)M(sk)|2, where the mollifier is M(s) = MX(s) =

  • 1≤n≤X

µ(n)χ(n) ns

  • 1 − log n

log X

  • .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-46
SLIDE 46

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Outline of proof

Let a = 2πα and b = 2πβ, and set sk = 1

2 + 2πi(α + kβ) for k = 1, 2, . . . .

First and second mollified moments

Define S1(T) =

T

  • k=1

L(sk, χ)M(sk) and S2(T) =

T

  • k=1

|L(sk, χ)M(sk)|2, where the mollifier is M(s) = MX(s) =

  • 1≤n≤X

µ(n)χ(n) ns

  • 1 − log n

log X

  • .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-47
SLIDE 47

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Outline of proof

Let a = 2πα and b = 2πβ, and set sk = 1

2 + 2πi(α + kβ) for k = 1, 2, . . . .

First and second mollified moments

Define S1(T) =

T

  • k=1

L(sk, χ)M(sk) and S2(T) =

T

  • k=1

|L(sk, χ)M(sk)|2, where the mollifier is M(s) = MX(s) =

  • 1≤n≤X

µ(n)χ(n) ns

  • 1 − log n

log X

  • .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-48
SLIDE 48

Linear independence conjectures Vertical arithmetic progressions Other work in progress

We love Cauchy–Schwarz

Note that S1(T) =

T

  • k=1

L(sk, χ)M(sk) =

  • 1≤k≤T

L(sk,χ)=0

L(sk, χ)M(sk) Applying Cauchy–Schwarz: S1(T)2 ≤

  • 1≤k≤T

L(sk,χ)=0

1

  • 1≤k≤T

L(sk,χ)=0

|L(sk, χ)M(sk)|2

  • After rearranging:

#

  • 1 ≤ k ≤ T : L(sk, χ) = 0} ≥ S1(T)2

S2(T) .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-49
SLIDE 49

Linear independence conjectures Vertical arithmetic progressions Other work in progress

We love Cauchy–Schwarz

Note that S1(T) =

T

  • k=1

L(sk, χ)M(sk) =

  • 1≤k≤T

L(sk,χ)=0

L(sk, χ)M(sk) Applying Cauchy–Schwarz: S1(T)2 ≤

  • 1≤k≤T

L(sk,χ)=0

1

  • 1≤k≤T

L(sk,χ)=0

|L(sk, χ)M(sk)|2

  • After rearranging:

#

  • 1 ≤ k ≤ T : L(sk, χ) = 0} ≥ S1(T)2

S2(T) .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-50
SLIDE 50

Linear independence conjectures Vertical arithmetic progressions Other work in progress

We love Cauchy–Schwarz

Note that S1(T) =

T

  • k=1

L(sk, χ)M(sk) =

  • 1≤k≤T

L(sk,χ)=0

L(sk, χ)M(sk) Applying Cauchy–Schwarz: S1(T)2 ≤

  • 1≤k≤T

L(sk,χ)=0

1

  • 1≤k≤T

L(sk,χ)=0

|L(sk, χ)M(sk)|2

  • After rearranging:

#

  • 1 ≤ k ≤ T : L(sk, χ) = 0} ≥ S1(T)2

S2(T) .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-51
SLIDE 51

Linear independence conjectures Vertical arithmetic progressions Other work in progress

We love Cauchy–Schwarz

Note that S1(T) =

T

  • k=1

L(sk, χ)M(sk) =

  • 1≤k≤T

L(sk,χ)=0

L(sk, χ)M(sk) Applying Cauchy–Schwarz: S1(T)2 ≤

  • 1≤k≤T

L(sk,χ)=0

1

  • 1≤k≤T

L(sk,χ)=0

|L(sk, χ)M(sk)|2

  • After rearranging:

#

  • 1 ≤ k ≤ T : L(sk, χ) = 0} ≥ S1(T)2

S2(T) .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-52
SLIDE 52

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Here’s where the technical stuff gets hidden

S1(T) =

T

  • k=1

L(sk, χ)M(sk) and S2(T) =

T

  • k=1

|L(sk, χ)M(sk)|2

Proposition

Taking X = T1/4 in the definition of M(s), we have S1(T) = T + O

  • T(log T)−1/2

and S2(T) ≪ T log T. Consequently, #

  • 1 ≤ k ≤ T : L(sk, χ) = 0} ≥ S1(T)2

S2(T) ≫ T2 T log T = T log T .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-53
SLIDE 53

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Here’s where the technical stuff gets hidden

S1(T) =

T

  • k=1

L(sk, χ)M(sk) and S2(T) =

T

  • k=1

|L(sk, χ)M(sk)|2

Proposition

Taking X = T1/4 in the definition of M(s), we have S1(T) = T + O

  • T(log T)−1/2

and S2(T) ≪ T log T. Consequently, #

  • 1 ≤ k ≤ T : L(sk, χ) = 0} ≥ S1(T)2

S2(T) ≫ T2 T log T = T log T .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-54
SLIDE 54

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Here’s where the technical stuff gets hidden

S1(T) =

T

  • k=1

L(sk, χ)M(sk) and S2(T) =

T

  • k=1

|L(sk, χ)M(sk)|2

Proposition

Taking X = T1/4 in the definition of M(s), we have S1(T) = T + O

  • T(log T)−1/2

and S2(T) ≪ T log T. Consequently, #

  • 1 ≤ k ≤ T : L(sk, χ) = 0} ≥ S1(T)2

S2(T) ≫ T2 T log T = T log T .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-55
SLIDE 55

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Here’s where the technical stuff gets hidden

S1(T) =

T

  • k=1

L(sk, χ)M(sk) and S2(T) =

T

  • k=1

|L(sk, χ)M(sk)|2

Proposition

Taking X = T1/4 in the definition of M(s), we have S1(T) = T + O

  • T(log T)−1/2

and S2(T) ≪ T log T. Consequently, #

  • 1 ≤ k ≤ T : L(sk, χ) = 0} ≥ S1(T)2

S2(T) ≫ T2 T log T = T log T .

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-56
SLIDE 56

Linear independence conjectures Vertical arithmetic progressions Other work in progress

A linear form evaluated at zeros

Consequence of LI

Let a1, . . . , ak be positive rational numbers. Whenever γ1, · · · , γk are positive ordinates of zeros of L(s, χ), then L 1

2 + i(a1γ1 + · · · + akγk), χ

  • = 0

unless a1 + · · · + ak = 1 and γ1 = · · · = γk. Examples: When a ∈ Q \ {±1}, we expect L( 1

2 + iaγ, χ) = 0. (In 2005,

van Frankenhuysen verified that ζ( 1

2 + 2iγ) = 0 for all

|γ| < 1.13 × 106). The average of distinct zeros shouldn’t be another zero: L 1

2 + i(γ1 + · · · + γk)/k

  • = 0.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-57
SLIDE 57

Linear independence conjectures Vertical arithmetic progressions Other work in progress

A linear form evaluated at zeros

Consequence of LI

Let a1, . . . , ak be positive rational numbers. Whenever γ1, · · · , γk are positive ordinates of zeros of L(s, χ), then L 1

2 + i(a1γ1 + · · · + akγk), χ

  • = 0

unless a1 + · · · + ak = 1 and γ1 = · · · = γk. Examples: When a ∈ Q \ {±1}, we expect L( 1

2 + iaγ, χ) = 0. (In 2005,

van Frankenhuysen verified that ζ( 1

2 + 2iγ) = 0 for all

|γ| < 1.13 × 106). The average of distinct zeros shouldn’t be another zero: L 1

2 + i(γ1 + · · · + γk)/k

  • = 0.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-58
SLIDE 58

Linear independence conjectures Vertical arithmetic progressions Other work in progress

A linear form evaluated at zeros

Consequence of LI

Let a1, . . . , ak be positive rational numbers. Whenever γ1, · · · , γk are positive ordinates of zeros of L(s, χ), then L 1

2 + i(a1γ1 + · · · + akγk), χ

  • = 0

unless a1 + · · · + ak = 1 and γ1 = · · · = γk. Examples: When a ∈ Q \ {±1}, we expect L( 1

2 + iaγ, χ) = 0. (In 2005,

van Frankenhuysen verified that ζ( 1

2 + 2iγ) = 0 for all

|γ| < 1.13 × 106). The average of distinct zeros shouldn’t be another zero: L 1

2 + i(γ1 + · · · + γk)/k

  • = 0.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-59
SLIDE 59

Linear independence conjectures Vertical arithmetic progressions Other work in progress

A linear form evaluated at zeros

Consequence of LI

Let a1, . . . , ak be positive rational numbers. Whenever γ1, · · · , γk are positive ordinates of zeros of L(s, χ), then L 1

2 + i(a1γ1 + · · · + akγk), χ

  • = 0

unless a1 + · · · + ak = 1 and γ1 = · · · = γk. Examples: When a ∈ Q \ {±1}, we expect L( 1

2 + iaγ, χ) = 0. (In 2005,

van Frankenhuysen verified that ζ( 1

2 + 2iγ) = 0 for all

|γ| < 1.13 × 106). The average of distinct zeros shouldn’t be another zero: L 1

2 + i(γ1 + · · · + γk)/k

  • = 0.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-60
SLIDE 60

Linear independence conjectures Vertical arithmetic progressions Other work in progress

This will take a moment or two

An approach to this problem is to average L(s, χ) over copies of Iχ(T) =

  • 0 ≤ γ ≤ T : L( 1

2 + iγ, χ) = 0

  • .

(As before, #Iχ(T) ∼ T

2π log qT 2π.)

Try the same strategy again

If we can evaluate S1(T) =

  • γ1,...,γk∈Iχ(T)

L 1

2 + i(a1γ1 + · · · + akγk), χ

  • and

S2(T) =

  • γ1,...,γk∈Iχ(T)
  • L

1

2 + i(a1γ1 + · · · + akγk), χ

  • 2,

then we can use Cauchy–Schwarz to understand the number of (γ1, . . . , γk) such that L 1

2 + i(a1γ1 + · · · + akγk), χ

  • = 0.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-61
SLIDE 61

Linear independence conjectures Vertical arithmetic progressions Other work in progress

This will take a moment or two

An approach to this problem is to average L(s, χ) over copies of Iχ(T) =

  • 0 ≤ γ ≤ T : L( 1

2 + iγ, χ) = 0

  • .

(As before, #Iχ(T) ∼ T

2π log qT 2π.)

Try the same strategy again

If we can evaluate S1(T) =

  • γ1,...,γk∈Iχ(T)

L 1

2 + i(a1γ1 + · · · + akγk), χ

  • and

S2(T) =

  • γ1,...,γk∈Iχ(T)
  • L

1

2 + i(a1γ1 + · · · + akγk), χ

  • 2,

then we can use Cauchy–Schwarz to understand the number of (γ1, . . . , γk) such that L 1

2 + i(a1γ1 + · · · + akγk), χ

  • = 0.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-62
SLIDE 62

Linear independence conjectures Vertical arithmetic progressions Other work in progress

LI holds a lot of the time

Theorem (M.–Ng, 2011+)

Assume GRH. For fixed 0 < a1, . . . , ak < 1, we have S1(T) ∼ #Iχ(T)k and S2(T) ∼ #Iχ(T)k log T.

Corollary

Assume GRH. For fixed 0 < a1, . . . , ak < 1, we have #

  • (γ1, . . . , γk) ∈ Iχ(T)k : L

1

2 + i(a1γ1 + · · · akγk), χ

  • = 0
  • ≫ S1(T)2

S2(T) ∼ #Iχ(T)k log T . We could also let the variables γ1, . . . , γk run over ordinates

  • f different Dirichlet L-functions.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-63
SLIDE 63

Linear independence conjectures Vertical arithmetic progressions Other work in progress

LI holds a lot of the time

Theorem (M.–Ng, 2011+)

Assume GRH. For fixed 0 < a1, . . . , ak < 1, we have S1(T) ∼ #Iχ(T)k and S2(T) ∼ #Iχ(T)k log T.

Corollary

Assume GRH. For fixed 0 < a1, . . . , ak < 1, we have #

  • (γ1, . . . , γk) ∈ Iχ(T)k : L

1

2 + i(a1γ1 + · · · akγk), χ

  • = 0
  • ≫ S1(T)2

S2(T) ∼ #Iχ(T)k log T . We could also let the variables γ1, . . . , γk run over ordinates

  • f different Dirichlet L-functions.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-64
SLIDE 64

Linear independence conjectures Vertical arithmetic progressions Other work in progress

LI holds a lot of the time

Theorem (M.–Ng, 2011+)

Assume GRH. For fixed 0 < a1, . . . , ak < 1, we have S1(T) ∼ #Iχ(T)k and S2(T) ∼ #Iχ(T)k log T.

Corollary

Assume GRH. For fixed 0 < a1, . . . , ak < 1, we have #

  • (γ1, . . . , γk) ∈ Iχ(T)k : L

1

2 + i(a1γ1 + · · · akγk), χ

  • = 0
  • ≫ S1(T)2

S2(T) ∼ #Iχ(T)k log T . We could also let the variables γ1, . . . , γk run over ordinates

  • f different Dirichlet L-functions.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-65
SLIDE 65

Linear independence conjectures Vertical arithmetic progressions Other work in progress

LI holds a lot of the time

Theorem (M.–Ng, 2011+)

Assume GRH. For fixed 0 < a1, . . . , ak < 1, we have S1(T) ∼ #Iχ(T)k and S2(T) ∼ #Iχ(T)k log T.

Corollary

Assume GRH. For fixed 0 < a1, . . . , ak < 1, we have #

  • (γ1, . . . , γk) ∈ Iχ(T)k : L

1

2 + i(a1γ1 + · · · akγk), χ

  • = 0
  • ≫ S1(T)2

S2(T) ∼ #Iχ(T)k log T . We could also let the variables γ1, . . . , γk run over ordinates

  • f different Dirichlet L-functions.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-66
SLIDE 66

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Prime number races

Definition

Let a1, . . . , ar be distinct reduced residues (mod q). We say that the prime number race among a1, . . . , ar (mod q) is inclusive if, for every permutation (σ1, . . . , σr) of (a1, . . . , ar), there are arbitrarily large real numbers x for which π(x; q, σ1) > · · · > π(x; q, σr). Rubinstein and Sarnak (1994) proved that all prime number races are inclusive—conditionally on GRH and LI.

Notation

I(χ) = {γ ≥ 0 : L( 1

2 + iγ, χ) = 0} and I(q) =

  • χ (mod q)

I(χ) are multisets of ordinates of zeros of Dirichlet L-functions.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-67
SLIDE 67

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Prime number races

Definition

Let a1, . . . , ar be distinct reduced residues (mod q). We say that the prime number race among a1, . . . , ar (mod q) is inclusive if, for every permutation (σ1, . . . , σr) of (a1, . . . , ar), there are arbitrarily large real numbers x for which π(x; q, σ1) > · · · > π(x; q, σr). Rubinstein and Sarnak (1994) proved that all prime number races are inclusive—conditionally on GRH and LI.

Notation

I(χ) = {γ ≥ 0 : L( 1

2 + iγ, χ) = 0} and I(q) =

  • χ (mod q)

I(χ) are multisets of ordinates of zeros of Dirichlet L-functions.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-68
SLIDE 68

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Prime number races

Definition

Let a1, . . . , ar be distinct reduced residues (mod q). We say that the prime number race among a1, . . . , ar (mod q) is inclusive if, for every permutation (σ1, . . . , σr) of (a1, . . . , ar), there are arbitrarily large real numbers x for which π(x; q, σ1) > · · · > π(x; q, σr). Rubinstein and Sarnak (1994) proved that all prime number races are inclusive—conditionally on GRH and LI.

Notation

I(χ) = {γ ≥ 0 : L( 1

2 + iγ, χ) = 0} and I(q) =

  • χ (mod q)

I(χ) are multisets of ordinates of zeros of Dirichlet L-functions.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-69
SLIDE 69

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Prime number races

Definition

Let a1, . . . , ar be distinct reduced residues (mod q). We say that the prime number race among a1, . . . , ar (mod q) is inclusive if, for every permutation (σ1, . . . , σr) of (a1, . . . , ar), there are arbitrarily large real numbers x for which π(x; q, σ1) > · · · > π(x; q, σr). Rubinstein and Sarnak (1994) proved that all prime number races are inclusive—conditionally on GRH and LI.

Notation

I(χ) = {γ ≥ 0 : L( 1

2 + iγ, χ) = 0} and I(q) =

  • χ (mod q)

I(χ) are multisets of ordinates of zeros of Dirichlet L-functions.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-70
SLIDE 70

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Self-sufficient ordinates

Definition

We say that γ ∈ I(q) is self-sufficient if γ cannot be written as a nontrivial finite Q-linear combination of elements of I(q) \ {γ}.

Notation

We use the notation I♠(χ) = {γ ∈ I(χ): γ is self-sufficient} and I♠(q) =

  • χ (mod q)

I♠(χ). “Every γ ∈ I♠(q) is self-sufficient” is stronger than “I♠(q) is linearly independent over Q”, since we also consider linear combinations using elements of I(q) \ I♠(q). I♠(q) is the intersection of all maximal linearly independent subsets of I(q).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-71
SLIDE 71

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Self-sufficient ordinates

Definition

We say that γ ∈ I(q) is self-sufficient if γ cannot be written as a nontrivial finite Q-linear combination of elements of I(q) \ {γ}.

Notation

We use the notation I♠(χ) = {γ ∈ I(χ): γ is self-sufficient} and I♠(q) =

  • χ (mod q)

I♠(χ). “Every γ ∈ I♠(q) is self-sufficient” is stronger than “I♠(q) is linearly independent over Q”, since we also consider linear combinations using elements of I(q) \ I♠(q). I♠(q) is the intersection of all maximal linearly independent subsets of I(q).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-72
SLIDE 72

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Self-sufficient ordinates

Definition

We say that γ ∈ I(q) is self-sufficient if γ cannot be written as a nontrivial finite Q-linear combination of elements of I(q) \ {γ}.

Notation

We use the notation I♠(χ) = {γ ∈ I(χ): γ is self-sufficient} and I♠(q) =

  • χ (mod q)

I♠(χ). “Every γ ∈ I♠(q) is self-sufficient” is stronger than “I♠(q) is linearly independent over Q”, since we also consider linear combinations using elements of I(q) \ I♠(q). I♠(q) is the intersection of all maximal linearly independent subsets of I(q).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-73
SLIDE 73

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Self-sufficient ordinates

Definition

We say that γ ∈ I(q) is self-sufficient if γ cannot be written as a nontrivial finite Q-linear combination of elements of I(q) \ {γ}.

Notation

We use the notation I♠(χ) = {γ ∈ I(χ): γ is self-sufficient} and I♠(q) =

  • χ (mod q)

I♠(χ). “Every γ ∈ I♠(q) is self-sufficient” is stronger than “I♠(q) is linearly independent over Q”, since we also consider linear combinations using elements of I(q) \ I♠(q). I♠(q) is the intersection of all maximal linearly independent subsets of I(q).

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-74
SLIDE 74

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Weakening the LI assumption: example theorems

Theorem (M.–Ng, 2011+)

Assume GRH. If for every nonprincipal character χ (mod q),

  • γ∈I♠(χ)

1 γ diverges, then every prime number race (mod q), including the full φ(q)-way race, is inclusive.

Theorem (M.–Ng, 2011+)

Assume GRH. Let a, b (mod q) be distinct reduced residues. If

  • χ (mod q)

χ(a)=χ(b)

  • γ∈I♠(χ)

1 γ diverges, then the two-way prime number race between a and b (mod q) is inclusive.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-75
SLIDE 75

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Weakening the LI assumption: example theorems

Theorem (M.–Ng, 2011+)

Assume GRH. If for every nonprincipal character χ (mod q),

  • γ∈I♠(χ)

1 γ diverges, then every prime number race (mod q), including the full φ(q)-way race, is inclusive.

Theorem (M.–Ng, 2011+)

Assume GRH. Let a, b (mod q) be distinct reduced residues. If

  • χ (mod q)

χ(a)=χ(b)

  • γ∈I♠(χ)

1 γ diverges, then the two-way prime number race between a and b (mod q) is inclusive.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-76
SLIDE 76

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Weakening the LI assumption: example theorems

Theorem (M.–Ng, 2011+)

Assume GRH. If for every nonprincipal character χ (mod q),

  • γ∈I♠(χ)

1 γ diverges, then every prime number race (mod q), including the full φ(q)-way race, is inclusive.

Theorem (M.–Ng, 2011+)

Assume GRH. Let a, b (mod q) be distinct reduced residues. If

  • χ (mod q)

χ(a)=χ(b)

  • γ∈I♠(χ)

1 γ diverges, then the two-way prime number race between a and b (mod q) is inclusive.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-77
SLIDE 77

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Weakening the LI assumption: example theorems

Theorem (M.–Ng, 2011+)

Assume GRH. If for every nonprincipal character χ (mod q),

  • γ∈I♠(χ)

1 γ diverges, then every prime number race (mod q), including the full φ(q)-way race, is inclusive.

Theorem (M.–Ng, 2011+)

Assume GRH. Let a, b (mod q) be distinct reduced residues. If

  • χ (mod q)

χ(a)=χ(b)

  • γ∈I♠(χ)

1 γ diverges, then the two-way prime number race between a and b (mod q) is inclusive.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-78
SLIDE 78

Linear independence conjectures Vertical arithmetic progressions Other work in progress

Weakening the LI assumption: example theorems

Theorem (M.–Ng, 2011+)

Assume GRH. If for every nonprincipal character χ (mod q),

  • γ∈I♠(χ)

1 γ diverges, then every prime number race (mod q), including the full φ(q)-way race, is inclusive.

Theorem (M.–Ng, 2011+)

Assume GRH. Let a, b (mod q) be distinct reduced residues. If

  • χ (mod q)

χ(a)=χ(b)

  • γ∈I♠(χ)

1 γ diverges, then the two-way prime number race between a and b (mod q) is inclusive.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-79
SLIDE 79

Linear independence conjectures Vertical arithmetic progressions Other work in progress

A simple challenge

To emphasize how little we know about the linear independence of zeros of Dirichlet L-functions, Silberman pointed out that the following problem is still open:

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-80
SLIDE 80

Linear independence conjectures Vertical arithmetic progressions Other work in progress

A simple challenge

To emphasize how little we know about the linear independence of zeros of Dirichlet L-functions, Silberman pointed out that the following problem is still open:

Prove that . . .

. . . there exists even one Dirichlet L-function (including the ζ-function) that has even one zero β + iγ with γ irrational.

Linear independence of zeros of Dirichlet L-functions Greg Martin

slide-81
SLIDE 81

Linear independence conjectures Vertical arithmetic progressions Other work in progress

The end

My paper with Nathan on vertical arithmetic progressions

www.math.ubc.ca/∼gerg/ index.shtml?abstract=NVDVAP

Papers with Nathan in preparation

Inclusive prime number races Nonzero values of Dirichlet L-functions at linear combinations of zeros

These slides

www.math.ubc.ca/∼gerg/index.shtml?slides

Linear independence of zeros of Dirichlet L-functions Greg Martin