Jia Xu et al. Cell 2013 14 J23100 J23101 J23105 J23110 12 10 - PowerPoint PPT Presentation

Jia Xu et al. Cell 2013

14 J23100 J23101 J23105 J23110 12 10 RFU (A.U.) 8 6 4 2 0 -7 -6 -5 -4 -3 log10 Kana (umol/L)

Mut-3 Mut-8 1.42 1.34 1.40 1.32 1.38 1.30 RFU (A.U.) RFU (A.U.) 1.36 1.28 1.34 1.26 1.32 1.24 -6.0 -5.5 -5.0 -4.5 -4.0 -3.5 -6.0 -5.5 -5.0 -4.5 -4.0 -3.5 log10 [Kana] (umol/L) log10 [Kana] (umol/L) Mut-11 Mut-10 1.40 1.40 1.38 1.38 1.36 1.36 RFU (A.U.) RFU (A.U.) 1.34 1.34 1.32 1.32 1.30 1.30 1.28 -6.0 -5.5 -5.0 -4.5 -4.0 -3.5 -6.0 -5.5 -5.0 -4.5 -4.0 -3.5 log10 [Kana] (umol/L) log10 [Kana] (umol/L)

• – – • –

14 12 J23100 J23100 J23101 J23101 J23105 J23104 J23110 J23110 12 10 R1051 R0010 10 Expression level (A.U.) 8 RFU (A.U.) 8 6 6 4 4 2 2 0 0 -7 -6 -5 -4 -3 -6.0 -5.5 -5.0 -4.5 -4.0 log10 Kana (umol/L) log10 Kana (umol/L) ALeader (w.t.) ALeaderT

pSB1C3-J23100-loci-X-mRFP1 Aleader 12 AleaderT AleaderT-BCD 10 Expression level 8 6 4 2 -6.0 -5.5 -5.0 -4.5 -4.0 log10 Kana (umol/L)

• • Aleader Aleader AleaderT AleaderT 15 15 10 10 RFU (A.U.) RFU (A.U.) 5 5 0 0 -6.0 -5.5 -5.0 -4.5 -4.0 -3.5 -6.0 -5.5 -5.0 -4.5 -4.0 -3.5 log10[Kana] (mol/L) log10[Kana] (mol/L)

• •

•

Conformati ∆G˚ on B -7.8 (Binding) A -4.3 (Free) SPR signal Data Calculated by RNA fold Model Fits Experiment

• • • • J S Paige et al. Science 2012

• –  –  –

B0015 Terminator Efficiency 1.0 Interacted Normal 0.8 Terminator Efficiency 0.6 Test Input 0.4 0.2 Test Output 0.0 Interacted CC JK

• –

• • • ， • • • • • • •

dA Conformation ∆G˚ dt =k fA -(k 1 +k 3 +k m )A+k 1 'B+k 3 'C dB B -7.8 =k fB +k 1 A-(k 1 '+k 4 '+k 2 L+k m )B+k 2 'B L +k 4 C dt (Natural Binding) dB L dt =k 2 LB-(k 2 '+k m )B L A -4.3 dC =k fC +k 3 A+k 4 'B-(k 3 '+k 4 +k m )C (Natural Free) dt dA m C -11.80 =k MA A-(k 1 +k 3 +k dMA )A m +k 1 'B m +k 3 'C m dt (Artificial Free) dB m dt =k MB B+k 1 A m -(k 1 '+k 4 '+k 2 L+k dMB )B m +k 2 'B Lm +k 4 C m Partitioning No ribosome dB Lm =k MB B L +k 2 LB m -(k 2 '+k dMB )B Lm dt Parameter Influence dCm dt =k MC C+k 3 A m +k 4 'B m -(k 3 '+k 4 +k dMC )C m K1 1.5234 dT dt =k tA A+k tB (B+B L )+k tC C-k dT T K3 0.4309 dP dt =k pA A m +k pB (B m + B Lm )+k pC C m -k dP P K4 0.6564