INC 342 Lecture 2: Root Locus (cont.) Dr. Benjamas Panomruttanarug - - PowerPoint PPT Presentation

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INC 342 Lecture 2: Root Locus (cont.) Dr. Benjamas Panomruttanarug - - PowerPoint PPT Presentation

INC 342 Lecture 2: Root Locus (cont.) Dr. Benjamas Panomruttanarug Benjamas.pan@kmutt.ac.th Sketching Root Locus (review) 1. Number of branches 2. Symmetry 3. Real axis segment 4. Starting and ending points 5. Behavior at infinity BP INC 342


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SLIDE 1

INC 342

Lecture 2: Root Locus (cont.)

  • Dr. Benjamas Panomruttanarug

Benjamas.pan@kmutt.ac.th

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SLIDE 2

Sketching Root Locus (review)

  • 1. Number of branches
  • 2. Symmetry
  • 3. Real‐axis segment
  • 4. Starting and ending points
  • 5. Behavior at infinity

BP 2 INC 342

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SLIDE 3

BP 3 INC 342

Example

) 2 )( 1 ( ) 5 )( 3 ( ) ( ) (      s s s s K s H s KG

Find breakaway, break‐in points

15 8 61 26 11 ) 15 8 ( ) 2 3 ( ) 2 3 ( ) 15 8 ( 1 ) ( ) (

2 2 2 2 2 2

                   s s s s ds dK s s s s K s s s s K s H s KG

Condition of poles then solve for s s = ‐1.45, 3.82 is breakaway and break‐in points

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SLIDE 4

BP 4 INC 342

Example

sketch root locus and find angel of departure

  • f complex poles

x x x

  • ‐3

‐2 ‐1 1

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SLIDE 5

Using MATLAB with Root Locus

  • tf
  • pole
  • zero
  • rlocus
  • pzmap
  • sisotool

BP INC 342 5

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SLIDE 6

6

2 objectives for desired response

  • 1. Improving transient response
  • Percent overshoot, damping ratio, settling

time, peak time

  • 2. Improving steady‐state error
  • Steady state error

BP INC 342

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SLIDE 7

7

Gain adjustment

  • Higher gain, smaller steady stead error,

larger percent overshoot

  • Reducing gain, smaller percent overshoot,

higher steady state error

BP INC 342

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SLIDE 8

8

Improving transient response

  • Point A and B have the

same damping ratio.

  • Starting from point A,

cannot reach a faster response at point B by adjusting K.

  • Compensator is

preferred.

BP INC 342

Y=‐mx m = tan(acos(damping ratio)) θ

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SLIDE 9

BP 9 INC 342

Transient Response Design via Gain Adjustment

Find K that gives a desired peak time, settling time, %OS (find K at the intersection) Use 2 order approx. and consider only dominant pole

100 %

2

1 /

 

         

e OS

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SLIDE 10

BP 10 INC 342

Example

Find K that yields 1.52% overshoot. Also estimate settling time, peak time, steady‐state error corresponding to the K Step I: 1.52% overshoot  ζ=0.8 Step II: draw a root locus

100 %

2

1 /

 

         

e OS

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SLIDE 11

BP 11 INC 342

Step III: draw a straight line of 0.8 damping ratio Step IV: find intersection points where the net angle is added up to 180*n, n=1,2,3,…

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SLIDE 12

BP 12 INC 342

Step V: find the corresponding K at each point Step VI: find peak time, settling time corresponding to the pole locations (assume 2nd order approx.) Step VII: calculate Kv and ss error Note: case 1 and 2 cannot use 2nd order approx. cause the third pole and closed loop zero are far away. In case 3, the approx. is valid.