INC 342
Lecture 2: Root Locus (cont.)
- Dr. Benjamas Panomruttanarug
INC 342 Lecture 2: Root Locus (cont.) Dr. Benjamas Panomruttanarug - - PowerPoint PPT Presentation
INC 342 Lecture 2: Root Locus (cont.) Dr. Benjamas Panomruttanarug Benjamas.pan@kmutt.ac.th Sketching Root Locus (review) 1. Number of branches 2. Symmetry 3. Real axis segment 4. Starting and ending points 5. Behavior at infinity BP INC 342
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) 2 )( 1 ( ) 5 )( 3 ( ) ( ) ( s s s s K s H s KG
Find breakaway, break‐in points
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Condition of poles then solve for s s = ‐1.45, 3.82 is breakaway and break‐in points
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sketch root locus and find angel of departure
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‐2 ‐1 1
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Y=‐mx m = tan(acos(damping ratio)) θ
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Find K that gives a desired peak time, settling time, %OS (find K at the intersection) Use 2 order approx. and consider only dominant pole
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Find K that yields 1.52% overshoot. Also estimate settling time, peak time, steady‐state error corresponding to the K Step I: 1.52% overshoot ζ=0.8 Step II: draw a root locus
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Step III: draw a straight line of 0.8 damping ratio Step IV: find intersection points where the net angle is added up to 180*n, n=1,2,3,…
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Step V: find the corresponding K at each point Step VI: find peak time, settling time corresponding to the pole locations (assume 2nd order approx.) Step VII: calculate Kv and ss error Note: case 1 and 2 cannot use 2nd order approx. cause the third pole and closed loop zero are far away. In case 3, the approx. is valid.