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IN3170/4170, Spring 2020 Philipp Hfliger hafliger@ifi.uio.no - - PowerPoint PPT Presentation
IN3170/4170, Spring 2020 Philipp Hfliger hafliger@ifi.uio.no - - PowerPoint PPT Presentation
IN3170/4170, Spring 2020 Philipp Hfliger hafliger@ifi.uio.no Excerpt of Sedra/Smith Chapter 7: Integrated CMOS Amplifier Basics Content Thevenin and Norton Equivalent (book 1.1) Small Signal Analysis and Transistor Model (book 6.2) CMOS
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Content
Thevenin and Norton Equivalent (book 1.1) Small Signal Analysis and Transistor Model (book 6.2) CMOS Common Source Amplifiers and FET Intrinsic Gain(book 7.3) Improved Current Mirrors/Sources (book 7.6)
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Thévenin and Norton (1/3)
Two equivalent models of signal sources (e.g. a sensor or other transducer): a) is called the The Thévenin form and b) the Norton
- form. Note: Outputresistance RS is the same in both models while
vS(t) = iS(t)RS. A more general model would consider an
- utputimpedance, i.e. including output capacitance/inductance
rather than just a resistance.
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Thévenin and Norton (2/3)
In general any circuit of linear components can be expressed as Thévenin or Norton equivalent circuit between two nodes of the circuit, with an equivalent resitance RS (or impedance ZS) and (optionally) a signal or DC source. One often talks about the ’impedance seen in this node’ where the second node implicitly is Gnd.
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Thévenin and Norton (3/3)
To get the resistance in this node supply a test current iX or test voltage vX between the nodes and measure/compute the voltage or current respectively. RS is then δvX
δiX .
To get the signal source, for the Thevenin equivalent, measure/compute the output voltage (voltage-signal) for open circuit between the two terminals and for the Norton form, measure/compute the current (or current-signal) for a short circuit between the terminals. The Thevenin can be transformed into the Norton form or vice versa by using vS(t) = RSiS(t).
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Content
Thevenin and Norton Equivalent (book 1.1) Small Signal Analysis and Transistor Model (book 6.2) CMOS Common Source Amplifiers and FET Intrinsic Gain(book 7.3) Improved Current Mirrors/Sources (book 7.6)
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Intermezzo: Signal Naming Convention in the Book
The book uses lower case letters with upper case indices to denominate large signal variables, i.e. with both DC (point of
- peration) and AC components. Upper case letters with upper case
indices are just the DC components (point of operation) and lower case letters with lower case indices are small signal components. The latter is equivalent to the AC component for completely linear (!) systems. So for example: iD ≈ ID + id
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Small Signal Analysis iD(vGS)
Equivalent to a 1st order Taylor expansion, the small signals only model a linear approximation around a point of operation. Thus: iD(vGS) ≈ iD(VGS)
ID
+ (vGS − VGS)
- vgs
∗ diD dvGS
did dvgs =gm
For strong inversion, active region: gm = diD dvGS = knVOV Note: The DC component (i.e. point of
- peration) ID is ignored for small signal
analysis, and simply defined to be zero.
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Small Signal Analysis iD(vDS)
0.5 1 1.5 2 2.5 3 3.5 −2 2 4 6 8 x 10
−4
ID VGS 0.5 1 1.5 2 2.5 3 3.5 1 2 3 x 10
−5
ID VDS
Again a 1st order Taylor expansion, i.e. a linear approximation around a point of
- peration:
iD(vDS) ≈ iD(VDS)
- ID
+ (vDS − VDS)
- vds
∗ diD dvDS
did dvgs = 1 ro
For strong inversion, active region: ro = dvDS diD = 1 λI ′
D
= VA I ′
D
(5.26/27) Note that VA is proportional to transistor length L and thus sometimes expressed as VA = V ′
AL.
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MOSFET Small Signal Circuit Model
low frequency variant, i.e. neglecting capacitors
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Applying the Small Signal Equivalent Circuits
- 1. Set all constant voltage sources (including DC biases) to Gnd
- 2. Set all constant current sources (including DC biases) to
zero/open circuit
- 3. Substitute transistors with small signal equivalent circuit
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Example: Common Source Amplifier
A = gm(RD||ro) RO = RD||ro
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Content
Thevenin and Norton Equivalent (book 1.1) Small Signal Analysis and Transistor Model (book 6.2) CMOS Common Source Amplifiers and FET Intrinsic Gain(book 7.3) Improved Current Mirrors/Sources (book 7.6)
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Intrinsic Gain from Small Signal
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Intrinsic Gain vs Bias Current
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CS Amplifier with Current-Source Load
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CS Amplifier Analysis
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CS with source degeneration no RL
Good as current source, e.g in current mirror, but not so good as amplifier. RO ≈ (1 + gmRS)ro gm → g′
m =
gm 1 + gmRs Much higher output resistance. Still no net-increase in gain!
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CS with source degeneration with RL
Av = g′
mRO
RL RL + RO ≈ gmro RL RL + (1 + gmRS)ro ... and more degradation to Av due to load RL!
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Cascode Amplifier
Can be looked upon as a CS and CG in series resulting in a intrinsic combined gain A = gm1ro1gm2ro2 (i.e. with a large load resistance),
- r a circuit where the CS serves as high quality voltage controlled
current source delivering id ≈ gm1vi and the CG buffers that current to a high output resistance ≈ gm2ro2ro1.
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Cascode Amplifier with Infinite Load Resistance
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Folded Cascode with Infinite Load Resistance
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Cascode Amplifier with Finite Load Resistance (1/2)
The load RL must be of equal magnitude as RO to get the benefit
- f the increased gain AV ! So here with a simple pFET we are back
to square one.
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Cascode Amplifier with Finite Load Resistance (2/2)
Better: employ a cascoded current source.
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Dependency of Gain on RL
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Content
Thevenin and Norton Equivalent (book 1.1) Small Signal Analysis and Transistor Model (book 6.2) CMOS Common Source Amplifiers and FET Intrinsic Gain(book 7.3) Improved Current Mirrors/Sources (book 7.6)
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Cascode Current Mirror
Increased output impedance, but quite a bit of output voltage headroom necessary ...
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Modified Wilson MOS Current Mirror
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