IDEALS AND THEIR INTEGRAL CLOSURE ALBERTO CORSO (joint work with C. - - PowerPoint PPT Presentation

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IDEALS AND THEIR INTEGRAL CLOSURE ALBERTO CORSO (joint work with C. - - PowerPoint PPT Presentation

IDEALS AND THEIR INTEGRAL CLOSURE ALBERTO CORSO (joint work with C. Huneke and W.V. Vasconcelos) Department of Mathematics Purdue University West Lafayette, 47907 San Diego January 8, 1997 1 SETTING Let R be


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IDEALS AND THEIR INTEGRAL CLOSURE

ALBERTO CORSO (joint work with C. Huneke and W.V. Vasconcelos) Department of Mathematics Purdue University West Lafayette, 47907 San Diego — January 8, 1997

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SETTING

Let R be a Noetherian ringa and I one of its ideals.

  • The integral closure of I is the ideal I of all elements of R

that satisfy an equation of the form Xn + a1Xn−1 + · · · + an−1X + an = 0, ai ∈ Ii.

  • The radical √I consists of all the solutions in R of equations
  • f the form

Xm − b = 0, b ∈ I.

  • In particular:

I ⊆ I ⊆ √I.

  • I is integrally closed (resp. normal) if I = I (resp. I n = In

for all n).

aLater we may even want to assume the ring to have other additional prop-

erties (such as: Cohen–Macaulay, with infinite residue field, etc.

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PROBLEMS

For an ideal I of R we would like to give an answer to questions of the following kind:

  • Find ‘efficient’ and ‘global’ criteria to test whether or not I is

integrally closed.

Comment: The criteria should involve natural objects associated with I: e.g. the powers of I, the radical of I, modules of syzygies, etc.

  • If I fails the ‘above’ tests, find a procedure to compute (part
  • f) the integral closure of I.

Comment: It is not an easy task. For example, if R is a polynomial ring

  • ver a field and I is a monomial ideal, I is then the monomial ideal defined

by the integral convex hull of the exponent vectors of I. However, if I is binomial then I need not be binomial.

  • When I integrally closed implies I normal.

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POSSIBLE APPROACHES

  • A consequence of the determinant trick is that for every finitely

generated faithful R-module M then I ⊆ IM: M ⊆ I. In particular if I is integrally closed, for any such M, IM: M = I. We then need appropriate ‘test modules’ for a given ideal I.

  • An alternative approach is through the Rees algebra

R[It] = R + It + I2t2 + · · · + Intn + · · · of I;

  • ne then looks for its integral closure inside R[t]:

R + It + I2t2 + · · · ⊂ R[t]. This is obviously wasteful of resources since the integral closure

  • f all powers of I will be computed. Of course this could be

profitably taken if it turns out that I is normal.

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CRITERION

Let I be a height unmixed ideal in a Cohen–Macaulay ring R. Suppose that I is generically a complete intersection. Then the following conditions are equivalent:

  • I is integrally closed;
  • I = IL: L, where L = I: √I.

Remarks:

  • An earlier version of this criterion had the condition I = IL: L

replaced by √I = IL: L2.

  • The proof in both cases is essentially the same, and it is based
  • n the following two ‘local criteria.’

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A ‘LOCAL’ RESULT OF GOTO Theorema:

Let I be an ideal in a Noetherian ring R and assume that µR(I) = heightR(I) = g. Then the following conditions are equivalent:

  • I = I, i.e. I is integrally closed;
  • In = In, i.e. I is normal;
  • for each p ∈ AssR(R/I), the local ring Rp is regular and

λRp IRp + p2Rp p2Rp

  • ≥ g − 1.

When this is the case, AssR(R/I) = MinR(R/I) and I is generated by an R-regular sequence.

  • aS. Goto: Integral closedness of complete-intersection ideals, J. Alge-

bra 108 (1987), 151–160.

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LINKAGE AND REDUCTION NUMBER Theorema+b:

Let (R, m) be a Cohen–Macaulay local ring and let I = (z1, . . . , zg) be an ideal generated by a regular sequence inside a prime ideal p

  • f height g. If we set L = I: p then L2 = IL if one of the following

two conditions holds: (l1) Rp is not a regular local ring; (l2) Rp is a regular local ring with dimension at least 2 and two of the zi’s in p(2).

  • aA. Corso, C. Polini and W. V. Vasconcelos: Links of prime ideals, Math.
  • Proc. Camb. Phil. Soc. 115 (1994), 431–436.
  • bA. Corso and C. Polini: Links of prime ideals and their Rees algebras,
  • J. Algebra 178 (1995), 224–238.

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ANOTHER USEFUL CRITERION

Let R be a Gorenstein ring and let I be a Gorenstein ideal of codimension 3. Then the following conditions are equivalent:

  • I is generically a complete intersection;
  • I2: I = I.

Remarks:

  • In particular, if I is integrally closed then it is generically a

complete intersection.

  • Furthermore, one could combine this and the previous criterion

to get a condition for a perfect Gorenstein ideal of codimension 3 to be integrally closed. However, this is not necessary as the next result shows.

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GORENSTEIN IDEALS

Let I be a Gorenstein ideal of codimension g ≥ 2 of a regular local ring R. Then the following conditions are equivalent:

  • I is an integrally closed ideal;
  • I = IL: L, where L = I: √I.

Comments:

  • As a consequence of the proof, I is generically a complete

intersection of the kind described in Goto’s paper.

  • Is it possible to find an easy, global criterion to characterize

integrally closed ideals with type 2 (3, etc...)?

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INTEGRAL CLOSEDNESS AND NORMALITY: ideals with linear presentation Theorem: Let k be a field of characteristic zero and let

I ⊂ R = k[x1, . . . , xd] be a Gorenstein ideal defined by the Pfaffians

  • f a n × n skew–symmetric matrix ϕ with linear forms as entries.

Suppose n = d + 1 (hence d is even) and that I is a complete intersection on the punctured spectrum. If I is integrally closed it is also normal.

Remark: The proof is based on the ‘Jacobian criterion.’ Corollary: Let k be a field of characteristic zero and let

I ⊂ R = k[x1, x2, x3, x4] be a Gorenstein ideal defined by the Pfaffians of a five by five skew–symmetric matrix ϕ with linear forms as entries. If I is integrally closed it is also normal.

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(COUNTER)EXAMPLE

Let R = k[a, b, c, d] with a, b, c, d be variables and char(k) = 0. The Pfaffians of the 5 × 5 matrix ϕ ϕ =           −a2 −b2 −c2 −d2 a2 −d2 −ab −c2 b2 d2 −a2 −ab c2 ab a2 −b2 d2 c2 ab b2           , define an height 3 Gorenstein ideal I such that I2: I = I and I = IL: L, where L = I: √I. Hence I is integrally closed BUT it is not normal. Note that I2 is integrally closed as well. Is I3 ‘BAD’?

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INTEGRAL CLOSEDNESS AND NORMALITY: complete intersections of codimension 2 Theorem:

Let R be a regular local ring and I = (a, b) a complete intersection

  • f codimension 2. Then I is normal, i.e.,

In = (I)n for all n ≥ 1.

Remark: For dimension 2 this is a very well known result of

Zariski.

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A METHOD TO COMPUTE THE INTEGRAL CLOSURE

If I = (a1, . . . , an) then one can represent its Rees algebra as R[It] = R[T1, . . . , Tn]/P, where P is the kernel of the map ϕ : R[T1, . . . , Tn] − → R[It] that sends Ti to ait. If R[It] is an affine domain over a field of characteristic zero and Jac denotes its Jacobian ideal, then the ring HomR[It](Jac−1, Jac−1) = · · · = (Jac Jac−1)−1, is guaranteed to be larger than R[It] if the ring is not already normal. Naturally, this process can be repeated several times until the integral closure of R[It] has been reached. The degree one component of the final output gives the desired integral closure of I.

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EXAMPLE

Let k be a field of characteristic zero and let I ⊆ R = k[x, y] be the codimension 2 complete intersection I = (x3 + y6, xy3 − y5). Iterating three times the method outlined before we can compute I. To be precise, the three outputs are: J1 = (x3 + y6, xy3 − y5, y8), J2 = (x3 + y6, xy3 − y5, x2y2 − y6, y7), J3 = I = (xy3 − y5, y6, x3, x2y2). Note that I is also a normal ideal. For the records, despite the fact that the original setting for the problem is a polynomial ring in 2 variables over a field of characteristic zero, overall we had to make use of 18 additional variables: quite a waste!

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FINAL COMMENT

If I is a complete intersection, several initial iterations of the process may be avoided (see [CP2] and [PU]). If I is an m-primary complete intersection of a Gorenstein local ring (R, m) and I ⊂ ms but I ⊂ ms+1 then one has an increasing sequence of ideals Ik = I: mk satisfying I2

k = IIk for k = 1, . . . , s if dim(R) ≥ 3 or for

k = 1, . . . s − 1 if R is a regular local ring and dim(R) = 2. This says that the Ik’s are contained in the integral closure of I. Hence, instead of computing the integral closure of R[It] one may start directly from R[Ist] (or R[Is−1t] if R is a regular local ring and dim(R) = 2).

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✬ ✫ ✩ ✪ If I is not primary to the maximal ideal one may use instead the sequence of ideals Ik = I: (√I)(k) = I: (√I)k, provided that at each localization at the associated primes of I the conditions in [CP2] and [PU] are satisfied so that I2

k = IIk for all

the k’s in the appropriate range. In the case of the example: R = k[x, y] and I = (x3 + y6, xy3 − y5)

  • ne has that I ⊂ (x, y)3. Since dim(R) = 2 one can consider only

the cases k = 1, 2 = s − 1. We can check that J1 = I: m J2 = I: m2.

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