How many mice and how many arrays? Replication in cDNA microarray - - PowerPoint PPT Presentation

how many mice and how many arrays replication in cdna
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How many mice and how many arrays? Replication in cDNA microarray - - PowerPoint PPT Presentation

How many mice and how many arrays? Replication in cDNA microarray experiment Xiangqin Cui The Jackson Laboratory Data preprocess: Download data Trim to 5507 clones in all organs Extract foreground only log 2 transformation Intensity-Lowess


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How many mice and how many arrays? Replication in cDNA microarray experiment

Xiangqin Cui The Jackson Laboratory

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Data preprocess:

Download data Trim to 5507 clones in all organs Extract foreground only log2 transformation Intensity-Lowess transformation Channel-mean center each channel

ijk

Y

Not log ratio

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Mixed linear model for each gene:

2 m

σ

ijk k j i ijk

R A D M u y ε + + + + + =

Log2(signal) Gene mean (fixed) Mouse effect (random ) Dye effect (fixed) Array effect (random ) Reference mean (fixed)

  • Meas. error

(random )

2 a

σ

2 e

σ

) , ( ~

2 m i

N M σ

) , ( ~

2 e ijk

N σ ε

) , ( ~

2 a k

N A σ

Assumptions:

lijk k j i l lijk

R A D M O u y ε + + + + + + =

Organ (fixed effect) Combined data: Individual organ:

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Estimated variance components from kidney

Significant gene

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Estimated variance components from all organs

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Gallstone Brain cortex

Variance components from two other data sets:

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MSE for treatment effects:

mnr mnr mn m MSE

e s a m 2 2 2 2

σ σ σ σ + + + =

m : number of mice per treatment n : number of arrays per mouse r: number of spots for each clone on array

Reference Design

Trt A Trt B m1 m2 m3 m4 ( m = 2 ) R R R R ( n = 2 )

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4 mice / trt, 2 arrays / mouse 4 mice / trt, 4 arrays / mouse 2 mice / trt, 2 arrays / mouse 2 mice / trt, 4 arrays / mouse 2 mice / trt, 6 arrays / mouse 4 mice / trt, 6 arrays / mouse

Power at different fold changes

1.5 fold change kidney

Log2(fold change)

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Power to detect 1.5 fold change in kidney

2 mice / trt 4 mice / trt 6 mice / trt 8 mice / trt 8 12 16 24 32

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Power to detect 1.5 fold change

2 mice / trt 4 mice / trt 6 mice / trt 8 mice / trt

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Resource allocation:

a m

nC m mC Cost ⋅ + =

m mice / trt n arrays / mouse r spot replicates on array Cm cost / mouse Ca cost / array

The optimum number of arrays per mouse:

a m m e s a

C C r r n ⋅ + + =

2 2 2 2

σ σ σ σ

spot variation

2 s

σ

mnr mnr mn m MSE

e s a m 2 2 2 2

σ σ σ σ + + + =

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Examples for resource allocation

Mouse price Array price # of arrays per mouse $15 $300 2 $300 $300 7 $1500 $300 16

  • Based on the variance components estimated from Project Normal data.
  • r = 1 ( no replicated spots on array )
  • Reference design

More efficient array level designs, such as direct comparisons and loop designs, can reduce the optimum number of arrays per mouse.

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Pooling mice

2 2

1

m pool

k σ σ

α

=

k : pool size α : constant for the effect of pooling. 0 < α < 1 α = 0, pooling has no effect. α = 1, pooling has maximum effect. Pooling can reduce the mouse variance but not the technical variances

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Power increase to detect 1.5 fold change by pooling

2 mice / trt 4 mice / trt 6 mice / trt 8 mice / trt 2 pools / trt 4 pools / trt 6 pools / trt 8 pools / trt

( Pool size k = 3, α = 1 )

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2 mice / trt 4 mice / trt 6 mice / trt 8 mice / trt 2 pools / trt 4 pools / trt 6 pools / trt 8 pools / trt

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Conclusions

* Technical variation is larger than biological variation for

most genes.

* Increase of technical replication can improve the power of

the experiment effectively.

* Biological replication is essential for making broad-sense

  • inferences. Increase of it is more effective in improving the

power of the experiment.

* Pooling can reduce biological variation. However, the

effect can be small due to relative small biological variation.

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Acknowledgements:

The Jackson Laboratory : Gary A. Churchill Hao Wu Qian Li Microarray facility Beverly J. Paigen TIGR: John Quackenbush