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Hilbert Function and Betti Numbers of Algebras with Lefschetz Property of Order m ALEXANDRU CONSTANTINESCU Dipartimento di Matematica, Universit` a di Genova 8-9 May 2008 Barcellona-Genova Workshop on Commutative Algebra and Applications 1


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Hilbert Function and Betti Numbers of Algebras with Lefschetz Property of Order m

ALEXANDRU CONSTANTINESCU

Dipartimento di Matematica, Universit` a di Genova

8-9 May 2008 Barcellona-Genova Workshop on Commutative Algebra and Applications

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Main Goal:

◮ Characterize the Hilbert function of algebras with the

Lefschetz property m times.

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Main Goal:

◮ Characterize the Hilbert function of algebras with the

Lefschetz property m times.

◮ Give upper bounds for the Betti numbers of Artinian algebras

with a given Hilbert Function and with the Lefschetz property m times

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Main Goal:

◮ Characterize the Hilbert function of algebras with the

Lefschetz property m times.

◮ Give upper bounds for the Betti numbers of Artinian algebras

with a given Hilbert Function and with the Lefschetz property m times and describe the cases in which these bounds are reached.

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Some results in this direction

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Some results in this direction

  • T. Harima, J.C. Migliore, U. Nagel, J. Watanabe

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Some results in this direction

  • T. Harima, J.C. Migliore, U. Nagel, J. Watanabe

The Weak and Strong Lefschetz Properties for Artinian K-algebras, Journal of Algebra 262 (2003), 99–126

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Some results in this direction

  • T. Harima, J.C. Migliore, U. Nagel, J. Watanabe

The Weak and Strong Lefschetz Properties for Artinian K-algebras, Journal of Algebra 262 (2003), 99–126

  • T. Harima, A. Wachi

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Some results in this direction

  • T. Harima, J.C. Migliore, U. Nagel, J. Watanabe

The Weak and Strong Lefschetz Properties for Artinian K-algebras, Journal of Algebra 262 (2003), 99–126

  • T. Harima, A. Wachi

Generic initial ideals, graded Betti numbers and k-Lefschetz properties, arXiv:0707.2247 (2007)

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Notations and Definitions

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Notations and Definitions

  • Let K be an infinite field, char(K) = 0.

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Notations and Definitions

  • Let K be an infinite field, char(K) = 0.
  • A =

d≥0 Ad be a homogeneous, Artinian K-algebra,

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Notations and Definitions

  • Let K be an infinite field, char(K) = 0.
  • A =

d≥0 Ad be a homogeneous, Artinian K-algebra, i.e.

A = R/I, where R = K[x1, . . . , xn] and I is a homogeneous ideal.

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Notations and Definitions

  • Let K be an infinite field, char(K) = 0.
  • A =

d≥0 Ad be a homogeneous, Artinian K-algebra, i.e.

A = R/I, where R = K[x1, . . . , xn] and I is a homogeneous ideal.

  • hA - the Hilbert function of A

hd(A) = dimK(Ad).

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Notations and Definitions

Definition (WLP)

A has the weak Lefschetz Property (WLP)

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Notations and Definitions

Definition (WLP)

A has the weak Lefschetz Property (WLP) if ∃ ℓ ∈ A1 s. t.

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Notations and Definitions

Definition (WLP)

A has the weak Lefschetz Property (WLP) if ∃ ℓ ∈ A1 s. t. ×ℓ : Ad− → Ad+1 has maximal rank ∀ d ≥ 1.

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Notations and Definitions

Definition (WLP)

A has the weak Lefschetz Property (WLP) if ∃ ℓ ∈ A1 s. t. ×ℓ : Ad− → Ad+1 has maximal rank ∀ d ≥ 1. ℓ is called a weak Lefschetz Element (WLE) for A.

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Notations and Definitions

Definition (WLP)

A has the weak Lefschetz Property (WLP) if ∃ ℓ ∈ A1 s. t. ×ℓ : Ad− → Ad+1 has maximal rank ∀ d ≥ 1. ℓ is called a weak Lefschetz Element (WLE) for A. A has m-times the weak Lefschetz Property (m ∈ N)

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Notations and Definitions

Definition (WLP)

A has the weak Lefschetz Property (WLP) if ∃ ℓ ∈ A1 s. t. ×ℓ : Ad− → Ad+1 has maximal rank ∀ d ≥ 1. ℓ is called a weak Lefschetz Element (WLE) for A. A has m-times the weak Lefschetz Property (m ∈ N) if ∃ ℓ1, . . . , ℓm ∈ A1 s. t.

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Notations and Definitions

Definition (WLP)

A has the weak Lefschetz Property (WLP) if ∃ ℓ ∈ A1 s. t. ×ℓ : Ad− → Ad+1 has maximal rank ∀ d ≥ 1. ℓ is called a weak Lefschetz Element (WLE) for A. A has m-times the weak Lefschetz Property (m ∈ N) if ∃ ℓ1, . . . , ℓm ∈ A1 s. t. ℓi is a WLE for A/(ℓ1, . . . , ℓi−1), ∀ i ∈ 1, . . . , m.

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Notations and Definitions

Let h : 1 = h0, h1, . . . , hs be a finite O-sequence.

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Notations and Definitions

Let h : 1 = h0, h1, . . . , hs be a finite O-sequence.

Definition (WL O-sequence)

h is a weak Lefschetz O − sequence if :

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Notations and Definitions

Let h : 1 = h0, h1, . . . , hs be a finite O-sequence.

Definition (WL O-sequence)

h is a weak Lefschetz O − sequence if :

  • h is unimodal∗

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Notations and Definitions

Let h : 1 = h0, h1, . . . , hs be a finite O-sequence.

Definition (WL O-sequence)

h is a weak Lefschetz O − sequence if :

  • h is unimodal∗ i.e. h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs for

some k ∈ 0, . . . , s.

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Notations and Definitions

Let h : 1 = h0, h1, . . . , hs be a finite O-sequence.

Definition (WL O-sequence)

h is a weak Lefschetz O − sequence if :

  • h is unimodal∗ i.e. h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs for

some k ∈ 0, . . . , s.

  • the sequence 1, h1 − h0, . . . , hk − hk−1 is again an O-sequence.

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Notations and Definitions

Let h : 1 = h0, h1, . . . , hs be a finite O-sequence.

Definition (WL O-sequence)

h is a weak Lefschetz O − sequence if :

  • h is unimodal∗ i.e. h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs for

some k ∈ 0, . . . , s.

  • the sequence 1, h1 − h0, . . . , hk − hk−1 is again an O-sequence.

h is a m-times weak Lefschetz O − sequence if:

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Notations and Definitions

Let h : 1 = h0, h1, . . . , hs be a finite O-sequence.

Definition (WL O-sequence)

h is a weak Lefschetz O − sequence if :

  • h is unimodal∗ i.e. h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs for

some k ∈ 0, . . . , s.

  • the sequence 1, h1 − h0, . . . , hk − hk−1 is again an O-sequence.

h is a m-times weak Lefschetz O − sequence if:

  • h is unimodal∗ .

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Notations and Definitions

Let h : 1 = h0, h1, . . . , hs be a finite O-sequence.

Definition (WL O-sequence)

h is a weak Lefschetz O − sequence if :

  • h is unimodal∗ i.e. h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs for

some k ∈ 0, . . . , s.

  • the sequence 1, h1 − h0, . . . , hk − hk−1 is again an O-sequence.

h is a m-times weak Lefschetz O − sequence if:

  • h is unimodal∗ .
  • the sequence 1, h1 − h0, . . . , hk − hk−1 is a (m − 1)-times

weak Lefschetz O-sequence.

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Main result

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Main result

Theorem

  • 1. If A is an Artinian homogeneous K-algebra with m-times the

WLP, then hA is a m-times weak Lefschetz O-sequence.

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Main result

Theorem

  • 1. If A is an Artinian homogeneous K-algebra with m-times the

WLP, then hA is a m-times weak Lefschetz O-sequence.

  • 2. For every m-times weak Lefschetz O-sequence h, there exists

an Artinian homogeneous K-algebra with hA = h.

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Main result

Theorem

  • 1. If A is an Artinian homogeneous K-algebra with m-times the

WLP, then hA is a m-times weak Lefschetz O-sequence.

  • 2. For every m-times weak Lefschetz O-sequence h, there exists

an Artinian homogeneous K-algebra with hA = h.

  • 1. is easy:

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Main result

Theorem

  • 1. If A is an Artinian homogeneous K-algebra with m-times the

WLP, then hA is a m-times weak Lefschetz O-sequence.

  • 2. For every m-times weak Lefschetz O-sequence h, there exists

an Artinian homogeneous K-algebra with hA = h.

  • 1. is easy:

◮ The unimodality follows from the natural grading of the

algebra:

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Main result

Theorem

  • 1. If A is an Artinian homogeneous K-algebra with m-times the

WLP, then hA is a m-times weak Lefschetz O-sequence.

  • 2. For every m-times weak Lefschetz O-sequence h, there exists

an Artinian homogeneous K-algebra with hA = h.

  • 1. is easy:

◮ The unimodality follows from the natural grading of the

algebra: if ×ℓ1 : Aj − → Aj+1 is surjective,

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Main result

Theorem

  • 1. If A is an Artinian homogeneous K-algebra with m-times the

WLP, then hA is a m-times weak Lefschetz O-sequence.

  • 2. For every m-times weak Lefschetz O-sequence h, there exists

an Artinian homogeneous K-algebra with hA = h.

  • 1. is easy:

◮ The unimodality follows from the natural grading of the

algebra: if ×ℓ1 : Aj − → Aj+1 is surjective, then ×ℓ1 : Ad − → Ad+1 is surjective ∀ d ≥ j.

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Main result

Theorem

  • 1. If A is an Artinian homogeneous K-algebra with m-times the

WLP, then hA is a m-times weak Lefschetz O-sequence.

  • 2. For every m-times weak Lefschetz O-sequence h, there exists

an Artinian homogeneous K-algebra with hA = h.

  • 1. is easy:

◮ The unimodality follows from the natural grading of the

algebra: if ×ℓ1 : Aj − → Aj+1 is surjective, then ×ℓ1 : Ad − → Ad+1 is surjective ∀ d ≥ j.

◮ A/(ℓ1) in an algebra with (m − 1)-times the WLP and

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Main result

Theorem

  • 1. If A is an Artinian homogeneous K-algebra with m-times the

WLP, then hA is a m-times weak Lefschetz O-sequence.

  • 2. For every m-times weak Lefschetz O-sequence h, there exists

an Artinian homogeneous K-algebra with hA = h.

  • 1. is easy:

◮ The unimodality follows from the natural grading of the

algebra: if ×ℓ1 : Aj − → Aj+1 is surjective, then ×ℓ1 : Ad − → Ad+1 is surjective ∀ d ≥ j.

◮ A/(ℓ1) in an algebra with (m − 1)-times the WLP and

hA/(ℓ1) : 1, h1 − h0, . . . , hk − hk−1.

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  • 2. is not so easy....

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Plan

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Plan

Fix h a m-times weak Lefschetz O-sequence.

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Plan

Fix h a m-times weak Lefschetz O-sequence.

  • 1. We will construct inductively an ideal Wm(h) of R

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Plan

Fix h a m-times weak Lefschetz O-sequence.

  • 1. We will construct inductively an ideal Wm(h) of R such that

R/Wm(h) will be the algebra we are looking for.

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Plan

Fix h a m-times weak Lefschetz O-sequence.

  • 1. We will construct inductively an ideal Wm(h) of R such that

R/Wm(h) will be the algebra we are looking for.

  • 2. If R/I is an Artinian K-algebra with Hilbert function h and

m-times the WLP then:

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Plan

Fix h a m-times weak Lefschetz O-sequence.

  • 1. We will construct inductively an ideal Wm(h) of R such that

R/Wm(h) will be the algebra we are looking for.

  • 2. If R/I is an Artinian K-algebra with Hilbert function h and

m-times the WLP then: βij(R/I) ≤ βij(R/Wm(h)) , ∀i, j ≥ 0.

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Plan

  • 3. Let I ⊂ R be an ideal such that R/I has Hilbert function h

and m-times the weak Lefschetz property (m ∈ N).

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Plan

  • 3. Let I ⊂ R be an ideal such that R/I has Hilbert function h

and m-times the weak Lefschetz property (m ∈ N). T.F.A.E.:

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Plan

  • 3. Let I ⊂ R be an ideal such that R/I has Hilbert function h

and m-times the weak Lefschetz property (m ∈ N). T.F.A.E.:

(a) R/I has maximal Betti numbers among K-algebras with the above properties.

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Plan

  • 3. Let I ⊂ R be an ideal such that R/I has Hilbert function h

and m-times the weak Lefschetz property (m ∈ N). T.F.A.E.:

(a) R/I has maximal Betti numbers among K-algebras with the above properties. (b) I is componentwise linear and the ideal ρn−m(Gin(I)) is Gotzmann in K[x1, . . . , xn−m].

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Plan

  • 3. Let I ⊂ R be an ideal such that R/I has Hilbert function h

and m-times the weak Lefschetz property (m ∈ N). T.F.A.E.:

(a) R/I has maximal Betti numbers among K-algebras with the above properties. (b) I is componentwise linear and the ideal ρn−m(Gin(I)) is Gotzmann in K[x1, . . . , xn−m].

where: ρi : K[x1, . . . , xn] − → K[x1, . . . , xi], with: ρi(xj) = xj if j ≤ i if j > i.

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Plan

  • 4. Let R/I be as above.

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Plan

  • 4. Let R/I be as above. If ∃ q ∈ N such that:

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Plan

  • 4. Let R/I be as above. If ∃ q ∈ N such that:

βq(R/I) = βq(R/Wm(h))

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Plan

  • 4. Let R/I be as above. If ∃ q ∈ N such that:

βq(R/I) = βq(R/Wm(h)) then: βi(R/I) = βi(R/Wm(h)) for all i ≥ q.

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Plan

  • 4. Let R/I be as above. If ∃ q ∈ N such that:

βq(R/I) = βq(R/Wm(h)) then: βi(R/I) = βi(R/Wm(h)) for all i ≥ q.

  • 5. Construct, starting from Wm(h) and using a distraction

matrix, another ideal I with :

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Plan

  • 4. Let R/I be as above. If ∃ q ∈ N such that:

βq(R/I) = βq(R/Wm(h)) then: βi(R/I) = βi(R/Wm(h)) for all i ≥ q.

  • 5. Construct, starting from Wm(h) and using a distraction

matrix, another ideal I with :

  • the same Hilbert function

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Plan

  • 4. Let R/I be as above. If ∃ q ∈ N such that:

βq(R/I) = βq(R/Wm(h)) then: βi(R/I) = βi(R/Wm(h)) for all i ≥ q.

  • 5. Construct, starting from Wm(h) and using a distraction

matrix, another ideal I with :

  • the same Hilbert function
  • the same Betti numbers

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Plan

  • 4. Let R/I be as above. If ∃ q ∈ N such that:

βq(R/I) = βq(R/Wm(h)) then: βi(R/I) = βi(R/Wm(h)) for all i ≥ q.

  • 5. Construct, starting from Wm(h) and using a distraction

matrix, another ideal I with :

  • the same Hilbert function
  • the same Betti numbers
  • such that R/I still has m-times the WLP

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Plan

  • 4. Let R/I be as above. If ∃ q ∈ N such that:

βq(R/I) = βq(R/Wm(h)) then: βi(R/I) = βi(R/Wm(h)) for all i ≥ q.

  • 5. Construct, starting from Wm(h) and using a distraction

matrix, another ideal I with :

  • the same Hilbert function
  • the same Betti numbers
  • such that R/I still has m-times the WLP
  • I≤k1 is the ideal of finite set of rational points in Pn−1

K

.

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The construction of Wm(h)

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The construction of Wm(h)

For h : 1 = h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs a m-times weak Lefschetz O-sequence, denote:

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The construction of Wm(h)

For h : 1 = h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs a m-times weak Lefschetz O-sequence, denote: ∆h := 1, h1 − h0, . . . , hk − hk−1.

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The construction of Wm(h)

For h : 1 = h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs a m-times weak Lefschetz O-sequence, denote: ∆h := 1, h1 − h0, . . . , hk − hk−1. Inductively, ∆1h = ∆h,

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The construction of Wm(h)

For h : 1 = h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs a m-times weak Lefschetz O-sequence, denote: ∆h := 1, h1 − h0, . . . , hk − hk−1. Inductively, ∆1h = ∆h, ∆ih := ∆(∆i−1h) for i = 2, . . . , m

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The construction of Wm(h)

For h : 1 = h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs a m-times weak Lefschetz O-sequence, denote: ∆h := 1, h1 − h0, . . . , hk − hk−1. Inductively, ∆1h = ∆h, ∆ih := ∆(∆i−1h) for i = 2, . . . , m ∆ih is a (m − i)-times weak Lefschetz O-sequence.

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The construction of Wm(h)

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The construction of Wm(h)

The case m = 1

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The construction of Wm(h)

The case m = 1 Set n = h1

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The construction of Wm(h)

The case m = 1 Set n = h1 and define: I0 :=Lex(∆h) ⊂ R′ = K[x1, . . . , xn−1] .

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The construction of Wm(h)

The case m = 1 Set n = h1 and define: I0 :=Lex(∆h) ⊂ R′ = K[x1, . . . , xn−1] . I1 := I0 · R ⊂ R.

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The construction of Wm(h)

The case m = 1 Set n = h1 and define: I0 :=Lex(∆h) ⊂ R′ = K[x1, . . . , xn−1] . I1 := I0 · R ⊂ R. It is easy to see that:

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The construction of Wm(h)

The case m = 1 Set n = h1 and define: I0 :=Lex(∆h) ⊂ R′ = K[x1, . . . , xn−1] . I1 := I0 · R ⊂ R. It is easy to see that:

  • the Hilbert function of R/I1 is:

1 = h0, h1, . . . , hk−1, hk, hk, . . . , hk, . . .

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The construction of Wm(h)

The case m = 1 Set n = h1 and define: I0 :=Lex(∆h) ⊂ R′ = K[x1, . . . , xn−1] . I1 := I0 · R ⊂ R. It is easy to see that:

  • the Hilbert function of R/I1 is:

1 = h0, h1, . . . , hk−1, hk, hk, . . . , hk, . . .

  • (x1, . . . , xn−1)k+1 ⊆ I1

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The construction of Wm(h)

Let d0 > k be the smallest degree for which hk > hd0.

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The construction of Wm(h)

Let d0 > k be the smallest degree for which hk > hd0. Let r0 := hk − hd0.

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The construction of Wm(h)

Let d0 > k be the smallest degree for which hk > hd0. Let r0 := hk − hd0. Take M1 , . . . , Mr0 ∈ R, the largest (in rev-lex order) r0 monomials of degree d0 NOT in I1.

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The construction of Wm(h)

Let d0 > k be the smallest degree for which hk > hd0. Let r0 := hk − hd0. Take M1 , . . . , Mr0 ∈ R, the largest (in rev-lex order) r0 monomials of degree d0 NOT in I1. We define: I2 := I1 + (M1 , . . . , Mr0).

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The construction of Wm(h)

Let d0 > k be the smallest degree for which hk > hd0. Let r0 := hk − hd0. Take M1 , . . . , Mr0 ∈ R, the largest (in rev-lex order) r0 monomials of degree d0 NOT in I1. We define: I2 := I1 + (M1 , . . . , Mr0). The Hilbert function of R/I2 will be: 1 = h0, h1, . . . , hd0−1, hd0, hd0, . . . , hd0, . . .

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The construction of Wm(h)

Let d0 > k be the smallest degree for which hk > hd0. Let r0 := hk − hd0. Take M1 , . . . , Mr0 ∈ R, the largest (in rev-lex order) r0 monomials of degree d0 NOT in I1. We define: I2 := I1 + (M1 , . . . , Mr0). The Hilbert function of R/I2 will be: 1 = h0, h1, . . . , hd0−1, hd0, hd0, . . . , hd0, . . . Technical proof...

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The construction of Wm(h)

This ensures that we can proceed in the same way, that is by adding in each degree where it is needed the largest in rev-lex order monomials.

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The construction of Wm(h)

This ensures that we can proceed in the same way, that is by adding in each degree where it is needed the largest in rev-lex order monomials. After at most s − k steps we will obtain an ideal W1(h) such that: hR/W1(h) = h.

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Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1.

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Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1. R = K[x, y, z, t].

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Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1. R = K[x, y, z, t]. I0 := Lex(∆h) = (x2, xy, xz, y3, y2z, yz2, z4) ⊂ K[x, y, z].

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Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1. R = K[x, y, z, t]. I0 := Lex(∆h) = (x2, xy, xz, y3, y2z, yz2, z4) ⊂ K[x, y, z]. I1 = I0 · R

85

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SLIDE 86

Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1. R = K[x, y, z, t]. I0 := Lex(∆h) = (x2, xy, xz, y3, y2z, yz2, z4) ⊂ K[x, y, z]. I1 = I0 · R For d ≥ 4, the monomials in R \ I1 are: z3td−3, y2td−2, yztd−2, z2td−2, xtd−1, ytd−1, ztd−1, td

86

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SLIDE 87

Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1. R = K[x, y, z, t]. I0 := Lex(∆h) = (x2, xy, xz, y3, y2z, yz2, z4) ⊂ K[x, y, z]. I1 = I0 · R For d ≥ 4, the monomials in R \ I1 are: z3td−3, y2td−2, yztd−2, z2td−2, xtd−1, ytd−1, ztd−1, td Add to I1:

87

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SLIDE 88

Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1. R = K[x, y, z, t]. I0 := Lex(∆h) = (x2, xy, xz, y3, y2z, yz2, z4) ⊂ K[x, y, z]. I1 = I0 · R For d ≥ 4, the monomials in R \ I1 are: z3td−3, y2td−2, yztd−2, z2td−2, xtd−1, ytd−1, ztd−1, td Add to I1: d = 4 : z3t, y2t2, yzt2, z2t2, xt3, yt3, zt3, t4

88

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SLIDE 89

Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1. R = K[x, y, z, t]. I0 := Lex(∆h) = (x2, xy, xz, y3, y2z, yz2, z4) ⊂ K[x, y, z]. I1 = I0 · R For d ≥ 4, the monomials in R \ I1 are: z3td−3, y2td−2, yztd−2, z2td−2, xtd−1, ytd−1, ztd−1, td Add to I1: d = 4 : z3t, y2t2, yzt2, z2t2, xt3, yt3, zt3, t4 d = 5 : z3t2, y2t3, yzt3, z2t3, xt4, yt4, zt4, t5

89

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SLIDE 90

Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1. R = K[x, y, z, t]. I0 := Lex(∆h) = (x2, xy, xz, y3, y2z, yz2, z4) ⊂ K[x, y, z]. I1 = I0 · R For d ≥ 4, the monomials in R \ I1 are: z3td−3, y2td−2, yztd−2, z2td−2, xtd−1, ytd−1, ztd−1, td Add to I1: d = 4 : z3t, y2t2, yzt2, z2t2, xt3, yt3, zt3, t4 d = 5 : z3t2, y2t3, yzt3, z2t3, xt4, yt4, zt4, t5 d = 6 : z3t3, y2t4, yzt4, z2t4, xt5, yt5, zt5, t6

90

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SLIDE 91

Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1. R = K[x, y, z, t]. I0 := Lex(∆h) = (x2, xy, xz, y3, y2z, yz2, z4) ⊂ K[x, y, z]. I1 = I0 · R For d ≥ 4, the monomials in R \ I1 are: z3td−3, y2td−2, yztd−2, z2td−2, xtd−1, ytd−1, ztd−1, td Add to I1: d = 4 : z3t, y2t2, yzt2, z2t2, xt3, yt3, zt3, t4 d = 5 : z3t2, y2t3, yzt3, z2t3, xt4, yt4, zt4, t5 d = 6 : z3t3, y2t4, yzt4, z2t4, xt5, yt5, zt5, t6 d = 7 : z3t4, y2t5, yzt5, z2t5, xt6, yt6, zt6, t7

91

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SLIDE 92

Example

Let h : 1, 4, 7, 8, 6, 3, 1. Then we have ∆h : 1, 3, 3, 1. R = K[x, y, z, t]. I0 := Lex(∆h) = (x2, xy, xz, y3, y2z, yz2, z4) ⊂ K[x, y, z]. I1 = I0 · R For d ≥ 4, the monomials in R \ I1 are: z3td−3, y2td−2, yztd−2, z2td−2, xtd−1, ytd−1, ztd−1, td Add to I1: d = 4 : z3t, y2t2, yzt2, z2t2, xt3, yt3, zt3, t4 d = 5 : z3t2, y2t3, yzt3, z2t3, xt4, yt4, zt4, t5 d = 6 : z3t3, y2t4, yzt4, z2t4, xt5, yt5, zt5, t6 d = 7 : z3t4, y2t5, yzt5, z2t5, xt6, yt6, zt6, t7 W1(h) = I1 + (z3t, y2t2, yzt3, z2t3, xt4, yt5, zt5, t7).

92

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SLIDE 93

The construction of Wm(h)

In order to apply induction we also need to show that W1(h) is strongly stable.

93

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SLIDE 94

The construction of Wm(h)

In order to apply induction we also need to show that W1(h) is strongly stable. This is not difficult:

94

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SLIDE 95

The construction of Wm(h)

In order to apply induction we also need to show that W1(h) is strongly stable. This is not difficult:

  • For the monomial generators in the first n − 1 variables

95

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SLIDE 96

The construction of Wm(h)

In order to apply induction we also need to show that W1(h) is strongly stable. This is not difficult:

  • For the monomial generators in the first n − 1 variables it

follows from the fact that Lex(∆h) is strongly stable.

96

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SLIDE 97

The construction of Wm(h)

In order to apply induction we also need to show that W1(h) is strongly stable. This is not difficult:

  • For the monomial generators in the first n − 1 variables it

follows from the fact that Lex(∆h) is strongly stable.

  • For the monomial generators divisible by xn

97

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SLIDE 98

The construction of Wm(h)

In order to apply induction we also need to show that W1(h) is strongly stable. This is not difficult:

  • For the monomial generators in the first n − 1 variables it

follows from the fact that Lex(∆h) is strongly stable.

  • For the monomial generators divisible by xn it follows from

the fact that we chose the largest monomilas in rev-lex order as generators.

98

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SLIDE 99

The construction of Wm(h)

The general case

99

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SLIDE 100

The construction of Wm(h)

The general case Let m ∈ N, m≥ 2.

100

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The construction of Wm(h)

The general case Let m ∈ N, m≥ 2. Assume we can construct an algebra R′/Wm−1(∆h), with:

101

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SLIDE 102

The construction of Wm(h)

The general case Let m ∈ N, m≥ 2. Assume we can construct an algebra R′/Wm−1(∆h), with:

  • Hilbert function ∆h,

102

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SLIDE 103

The construction of Wm(h)

The general case Let m ∈ N, m≥ 2. Assume we can construct an algebra R′/Wm−1(∆h), with:

  • Hilbert function ∆h,
  • Wm−1(∆h) is a strongly stable ideal of R′ = K[x1, . . . , xn−1].

103

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SLIDE 104

The construction of Wm(h)

The general case Let m ∈ N, m≥ 2. Assume we can construct an algebra R′/Wm−1(∆h), with:

  • Hilbert function ∆h,
  • Wm−1(∆h) is a strongly stable ideal of R′ = K[x1, . . . , xn−1].
  • (x1, . . . , xn−i)ki+1 ⊆ Wm−1(∆h) for all i = 2, . . . , m − 1,

104

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SLIDE 105

The construction of Wm(h)

The general case Let m ∈ N, m≥ 2. Assume we can construct an algebra R′/Wm−1(∆h), with:

  • Hilbert function ∆h,
  • Wm−1(∆h) is a strongly stable ideal of R′ = K[x1, . . . , xn−1].
  • (x1, . . . , xn−i)ki+1 ⊆ Wm−1(∆h) for all i = 2, . . . , m − 1,

where ki is the length of ∆ih.

105

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SLIDE 106

The construction of Wm(h)

The general case Let m ∈ N, m≥ 2. Assume we can construct an algebra R′/Wm−1(∆h), with:

  • Hilbert function ∆h,
  • Wm−1(∆h) is a strongly stable ideal of R′ = K[x1, . . . , xn−1].
  • (x1, . . . , xn−i)ki+1 ⊆ Wm−1(∆h) for all i = 2, . . . , m − 1,

where ki is the length of ∆ih. To construct Wm(h)

106

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SLIDE 107

The construction of Wm(h)

The general case Let m ∈ N, m≥ 2. Assume we can construct an algebra R′/Wm−1(∆h), with:

  • Hilbert function ∆h,
  • Wm−1(∆h) is a strongly stable ideal of R′ = K[x1, . . . , xn−1].
  • (x1, . . . , xn−i)ki+1 ⊆ Wm−1(∆h) for all i = 2, . . . , m − 1,

where ki is the length of ∆ih. To construct Wm(h) take I1 := Wm−1(∆h) · R and

107

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SLIDE 108

The construction of Wm(h)

The general case Let m ∈ N, m≥ 2. Assume we can construct an algebra R′/Wm−1(∆h), with:

  • Hilbert function ∆h,
  • Wm−1(∆h) is a strongly stable ideal of R′ = K[x1, . . . , xn−1].
  • (x1, . . . , xn−i)ki+1 ⊆ Wm−1(∆h) for all i = 2, . . . , m − 1,

where ki is the length of ∆ih. To construct Wm(h) take I1 := Wm−1(∆h) · R and follow the same steps as in the case m = 1.

108

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SLIDE 109

The construction of Wm(h)

The general case Let m ∈ N, m≥ 2. Assume we can construct an algebra R′/Wm−1(∆h), with:

  • Hilbert function ∆h,
  • Wm−1(∆h) is a strongly stable ideal of R′ = K[x1, . . . , xn−1].
  • (x1, . . . , xn−i)ki+1 ⊆ Wm−1(∆h) for all i = 2, . . . , m − 1,

where ki is the length of ∆ih. To construct Wm(h) take I1 := Wm−1(∆h) · R and follow the same steps as in the case m = 1. Everything works because we only used the fact that Lex(∆h) is strongly stable.

109

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SLIDE 110

The construction of Wm(h)

The general case Let m ∈ N, m≥ 2. Assume we can construct an algebra R′/Wm−1(∆h), with:

  • Hilbert function ∆h,
  • Wm−1(∆h) is a strongly stable ideal of R′ = K[x1, . . . , xn−1].
  • (x1, . . . , xn−i)ki+1 ⊆ Wm−1(∆h) for all i = 2, . . . , m − 1,

where ki is the length of ∆ih. To construct Wm(h) take I1 := Wm−1(∆h) · R and follow the same steps as in the case m = 1. Everything works because we only used the fact that Lex(∆h) is strongly stable. The choice of Lex(∆h) as a starting point is useful for obtaining maximal Betti numbers.

110

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R/Wm(h) has the WLP m times

111

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R/Wm(h) has the WLP m times

Lemma

If I is a strongly stable ideal of R = K[x1, . . . , xn], then T.F.A.E:

112

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SLIDE 113

R/Wm(h) has the WLP m times

Lemma

If I is a strongly stable ideal of R = K[x1, . . . , xn], then T.F.A.E:

  • 1. R/I has the WLP.

113

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SLIDE 114

R/Wm(h) has the WLP m times

Lemma

If I is a strongly stable ideal of R = K[x1, . . . , xn], then T.F.A.E:

  • 1. R/I has the WLP.
  • 2. The following three conditions hold:

114

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R/Wm(h) has the WLP m times

Lemma

If I is a strongly stable ideal of R = K[x1, . . . , xn], then T.F.A.E:

  • 1. R/I has the WLP.
  • 2. The following three conditions hold:

(a) hR/I is unimodal∗ : h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs,

115

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SLIDE 116

R/Wm(h) has the WLP m times

Lemma

If I is a strongly stable ideal of R = K[x1, . . . , xn], then T.F.A.E:

  • 1. R/I has the WLP.
  • 2. The following three conditions hold:

(a) hR/I is unimodal∗ : h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs, (b) (x1, . . . , xn−1)k+1 ⊆ I,

116

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SLIDE 117

R/Wm(h) has the WLP m times

Lemma

If I is a strongly stable ideal of R = K[x1, . . . , xn], then T.F.A.E:

  • 1. R/I has the WLP.
  • 2. The following three conditions hold:

(a) hR/I is unimodal∗ : h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs, (b) (x1, . . . , xn−1)k+1 ⊆ I, (c) If M ∈ Gens(I) is divisible by xn, then deg(M) ≥ k + 1.

117

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SLIDE 118

R/Wm(h) has the WLP m times

Lemma

If I is a strongly stable ideal of R = K[x1, . . . , xn], then T.F.A.E:

  • 1. R/I has the WLP.
  • 2. The following three conditions hold:

(a) hR/I is unimodal∗ : h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs, (b) (x1, . . . , xn−1)k+1 ⊆ I, (c) If M ∈ Gens(I) is divisible by xn, then deg(M) ≥ k + 1.

Our construction satisfies (a), (b) and (c), so it has the WLP.

118

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SLIDE 119

R/Wm(h) has the WLP m times

Lemma

If I is a strongly stable ideal of R = K[x1, . . . , xn], then T.F.A.E:

  • 1. R/I has the WLP.
  • 2. The following three conditions hold:

(a) hR/I is unimodal∗ : h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs, (b) (x1, . . . , xn−1)k+1 ⊆ I, (c) If M ∈ Gens(I) is divisible by xn, then deg(M) ≥ k + 1.

Our construction satisfies (a), (b) and (c), so it has the WLP. It is also easy to check that xn is a WLE for R/Wm(h).

119

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SLIDE 120

R/Wm(h) has the WLP m times

Lemma

If I is a strongly stable ideal of R = K[x1, . . . , xn], then T.F.A.E:

  • 1. R/I has the WLP.
  • 2. The following three conditions hold:

(a) hR/I is unimodal∗ : h0 < h1 < . . . < hk ≥ hk+1 ≥ . . . ≥ hs, (b) (x1, . . . , xn−1)k+1 ⊆ I, (c) If M ∈ Gens(I) is divisible by xn, then deg(M) ≥ k + 1.

Our construction satisfies (a), (b) and (c), so it has the WLP. It is also easy to check that xn is a WLE for R/Wm(h). As R/Wm(h) + (xn) = R′/Wm−1(∆h), which by induction has the WLP (m −1) times, we have that R/Wm(h) has m-times the WLP.

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R/Wm(h) has the WLP m times

The proof of the Lemma is based on tahe following result:

121

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R/Wm(h) has the WLP m times

The proof of the Lemma is based on tahe following result:

Lemma (A. Wiebe)

If I is a strongly stable ideal of R = K[x1, . . . , xn] then:

122

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SLIDE 123

R/Wm(h) has the WLP m times

The proof of the Lemma is based on tahe following result:

Lemma (A. Wiebe)

If I is a strongly stable ideal of R = K[x1, . . . , xn] then: R/I has the WLP ⇐ ⇒ xn is a WLE for R/I.

123

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SLIDE 124

R/Wm(h) has maximal Betti numbers

124

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SLIDE 125

R/Wm(h) has maximal Betti numbers

Proposition

If R/I is an Artinian K-algebra with Hilbert function h and m-times the WLP then:

125

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SLIDE 126

R/Wm(h) has maximal Betti numbers

Proposition

If R/I is an Artinian K-algebra with Hilbert function h and m-times the WLP then: βij(R/I) ≤ βij(R/Wm(h)) , ∀i, j ≥ 0.

126

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SLIDE 127

R/Wm(h) has maximal Betti numbers

Proposition

If R/I is an Artinian K-algebra with Hilbert function h and m-times the WLP then: βij(R/I) ≤ βij(R/Wm(h)) , ∀i, j ≥ 0. To prove this we mainly use three facts:

127

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R/Wm(h) has maximal Betti numbers

Proposition

If R/I is an Artinian K-algebra with Hilbert function h and m-times the WLP then: βij(R/I) ≤ βij(R/Wm(h)) , ∀i, j ≥ 0. To prove this we mainly use three facts: 1. ρn−m(Wm(h)) = Lex(∆m(h)).

128

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R/Wm(h) has maximal Betti numbers

Proposition

If R/I is an Artinian K-algebra with Hilbert function h and m-times the WLP then: βij(R/I) ≤ βij(R/Wm(h)) , ∀i, j ≥ 0. To prove this we mainly use three facts: 1. ρn−m(Wm(h)) = Lex(∆m(h)).

  • 2. Because
  • βij(R/I) ≤ βij(R/Gin(I)),

∀i, j ≥ 0,

129

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R/Wm(h) has maximal Betti numbers

Proposition

If R/I is an Artinian K-algebra with Hilbert function h and m-times the WLP then: βij(R/I) ≤ βij(R/Wm(h)) , ∀i, j ≥ 0. To prove this we mainly use three facts: 1. ρn−m(Wm(h)) = Lex(∆m(h)).

  • 2. Because
  • βij(R/I) ≤ βij(R/Gin(I)),

∀i, j ≥ 0,

  • Gin(I) is a strongly stable ideal in characteristic 0,

130

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R/Wm(h) has maximal Betti numbers

Proposition

If R/I is an Artinian K-algebra with Hilbert function h and m-times the WLP then: βij(R/I) ≤ βij(R/Wm(h)) , ∀i, j ≥ 0. To prove this we mainly use three facts: 1. ρn−m(Wm(h)) = Lex(∆m(h)).

  • 2. Because
  • βij(R/I) ≤ βij(R/Gin(I)),

∀i, j ≥ 0,

  • Gin(I) is a strongly stable ideal in characteristic 0,
  • R/I has the m-WLP ⇔ R/Gin(I) has the m-WLP,

131

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SLIDE 132

R/Wm(h) has maximal Betti numbers

Proposition

If R/I is an Artinian K-algebra with Hilbert function h and m-times the WLP then: βij(R/I) ≤ βij(R/Wm(h)) , ∀i, j ≥ 0. To prove this we mainly use three facts: 1. ρn−m(Wm(h)) = Lex(∆m(h)).

  • 2. Because
  • βij(R/I) ≤ βij(R/Gin(I)),

∀i, j ≥ 0,

  • Gin(I) is a strongly stable ideal in characteristic 0,
  • R/I has the m-WLP ⇔ R/Gin(I) has the m-WLP,

we can restrict to the case when I is strongly stable.

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R/Wm(h) has maximal Betti numbers

  • 3. Proposition (A.M. Bigatti)

Let I, J be strongly stable ideals with the same Hilbert

  • function. Assume that m≤i(Ij) ≤ m≤i(Jj),

∀i, j ≥ 0. Then

  • ne has:

133

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R/Wm(h) has maximal Betti numbers

  • 3. Proposition (A.M. Bigatti)

Let I, J be strongly stable ideals with the same Hilbert

  • function. Assume that m≤i(Ij) ≤ m≤i(Jj),

∀i, j ≥ 0. Then

  • ne has:

(a) mi(J) ≤ mi(I), ∀ i > 0.

134

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R/Wm(h) has maximal Betti numbers

  • 3. Proposition (A.M. Bigatti)

Let I, J be strongly stable ideals with the same Hilbert

  • function. Assume that m≤i(Ij) ≤ m≤i(Jj),

∀i, j ≥ 0. Then

  • ne has:

(a) mi(J) ≤ mi(I), ∀ i > 0. (b) βij(R/J) ≤ βij(R/I), ∀ i, j ≥ 0.

135

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SLIDE 136

R/Wm(h) has maximal Betti numbers

  • 3. Proposition (A.M. Bigatti)

Let I, J be strongly stable ideals with the same Hilbert

  • function. Assume that m≤i(Ij) ≤ m≤i(Jj),

∀i, j ≥ 0. Then

  • ne has:

(a) mi(J) ≤ mi(I), ∀ i > 0. (b) βij(R/J) ≤ βij(R/I), ∀ i, j ≥ 0.

For a monomial M = xa1

1 . . . xan n in K[x1, . . . , xn] we define:

max(M) = max{i : ai > 0}.

136

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R/Wm(h) has maximal Betti numbers

  • 3. Proposition (A.M. Bigatti)

Let I, J be strongly stable ideals with the same Hilbert

  • function. Assume that m≤i(Ij) ≤ m≤i(Jj),

∀i, j ≥ 0. Then

  • ne has:

(a) mi(J) ≤ mi(I), ∀ i > 0. (b) βij(R/J) ≤ βij(R/I), ∀ i, j ≥ 0.

For a monomial M = xa1

1 . . . xan n in K[x1, . . . , xn] we define:

max(M) = max{i : ai > 0}. For a set of monomials A ⊂ K[x1, . . . , xn] and for i = 1, . . . , n we write: mi(A) = ♯{M ∈ A : max(M) = i}, m≤i(A) = ♯{M ∈ A : max(M) ≤ i}.

137

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All ideals with maximal Betti numbers

138

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All ideals with maximal Betti numbers

Proposition

Let I ⊂ R be an ideal such that R/I has Hilbert function h and m-times the weak Lefschetz property (m ∈ N). T.F.A.E.: (a) R/I has maximal Betti numbers among ideals with the above properties. (b) I is componentwise linear and the ideal ρn−m(Gin(I)) is Gotzmann in K[x1, . . . , xn−m].

139

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All ideals with maximal Betti numbers

Proposition

Let I ⊂ R be an ideal such that R/I has Hilbert function h and m-times the weak Lefschetz property (m ∈ N). T.F.A.E.: (a) R/I has maximal Betti numbers among ideals with the above properties. (b) I is componentwise linear and the ideal ρn−m(Gin(I)) is Gotzmann in K[x1, . . . , xn−m]. I is Componentwise linear ⇔ βij(R/I) = βij(R/Gin(I)), ∀i, j ≥ 0.

140

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All ideals with maximal Betti numbers

Proposition

Let I ⊂ R be an ideal such that R/I has Hilbert function h and m-times the weak Lefschetz property (m ∈ N). T.F.A.E.: (a) R/I has maximal Betti numbers among ideals with the above properties. (b) I is componentwise linear and the ideal ρn−m(Gin(I)) is Gotzmann in K[x1, . . . , xn−m]. I is Componentwise linear ⇔ βij(R/I) = βij(R/Gin(I)), ∀i, j ≥ 0. I is Gotzmann ⇔ βij(R/I) = βij(R/ Lex(I)), ∀i, j ≥ 0.

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SLIDE 142

Rigidity

Proposition

Let R/I be as above. If ∃ q ∈ N such that: βq(R/I) = βq(R/Wm(h)) , then: βi(R/I) = βi(R/Wm(h)) for all i ≥ q.

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Rigidity

Proposition

Let R/I be as above. If ∃ q ∈ N such that: βq(R/I) = βq(R/Wm(h)) , then: βi(R/I) = βi(R/Wm(h)) for all i ≥ q. In a general context, this true if we replace Wm(h) by Gin(I) or by Lex(I).

143

slide-144
SLIDE 144

Rigidity

Proposition

Let R/I be as above. If ∃ q ∈ N such that: βq(R/I) = βq(R/Wm(h)) , then: βi(R/I) = βi(R/Wm(h)) for all i ≥ q. In a general context, this true if we replace Wm(h) by Gin(I) or by Lex(I). The proposition follows from the Eliahou-Kervaire formula: βi(R/I) = n

s=i ms(I)

s−1

i−1

  • 144
slide-145
SLIDE 145

Rigidity

Proposition

Let R/I be as above. If ∃ q ∈ N such that: βq(R/I) = βq(R/Wm(h)) , then: βi(R/I) = βi(R/Wm(h)) for all i ≥ q. In a general context, this true if we replace Wm(h) by Gin(I) or by Lex(I). The proposition follows from the Eliahou-Kervaire formula: βi(R/I) = n

s=i ms(I)

s−1

i−1

  • and from: mj(I) ≤ mj(Wm(h)), ∀ j > 0 .

145