Finite-time Blowup of Semilinear PDEs via the Feynman-Kac - - PowerPoint PPT Presentation
Finite-time Blowup of Semilinear PDEs via the Feynman-Kac - - PowerPoint PPT Presentation
Finite-time Blowup of Semilinear PDEs via the Feynman-Kac Representation E A LFREDO L J OS OPEZ -M IMBELA C ENTRO DE I NVESTIGACI ON EN M ATEM ATICAS G UANAJUATO , M EXICO jalfredo@cimat.mx Introduction and backgrownd Consider a
Introduction and backgrownd
Consider a reaction-diffusion equation of the form ∂w ∂t = Lw + w1+β, w(0, x) = ϕ(x), x ∈ E, (1) where L is the generator of a strong Markov process in a locally compact space E, β > 0 is constant, ϕ ≥ 0 is bounded and measurable. Well-known facts:
- ∀ ϕ ≥ 0 ∃ Tϕ ∈ (0, ∞] such that (1) has a unique solution w on Rd × [0, Tϕ).
- w is bounded on Rd × [0, T] for any 0 < T < Tϕ.
- If Tϕ < ∞, then w(·, t)L∞(Rd) → ∞ as t ↑ Tϕ.
When Tϕ = ∞ we say that w is a global solution When Tϕ < ∞ we say that w blows up in finite time or that w is non-global.
1
The study of blow up properties of (1) goes back to the fundamental work of Fujita (1966): For E = Rd and L = ∆
- If d < 2/β, then any non-trivial positive solution blows up in finite time.
- If d > 2/β, then Equation (1) admits a global solution for all sufficiently small initial
values ϕ. Later on, Hayakawa (1973) and Aronson and Weinberger (1978) proved that the critical dimension d = 2 β also pertains to the finite-time blowup regime. The case of L = ∆α := −(−∆)α/2 in E = Rd was settled by Sugitani (1975), who showed that if d ≤ α/β, then for any non-vanishing initial condition the solution blows up in finite time.
2
An example with an integral power non-linearity
∂w ∂t = Lw + w2, w(0) = ϕ Blowup or stability of solutions? Recall ∂f ∂t = f 2, f = K has solution f(t) = 1
1 K − t
Thus: Blowup in the absence of motion For a (small) initial ϕ with bounded support, the motion tends to smear out u, hence counteract the blowup. Where is the border?
3
Probabilistic representation In case of integer exponents β ≥ 1 it was proved by McKean (1975) that w(t, x) = E
y∈Bx(t)
ϕ(y)
,
x ∈ E, t ≥ 0. solves the equation ∂w ∂t = Lw − w + w1+β, w(0) = ϕ Here (Bx(t))t≥0 is a branching particle system in E
- starting from an ancestor at x ∈ E,
- with exponential (mean–one) individual lifetimes,
- branching numbers 1 + β
- particle motions with generator L.
How to remove the “Feynman-Kac” term −w ?
4
FACTS:
- w is nonglobal provided that
T(t)ϕ(x) ≥
1
tβ
1/β
for some x ∈ E and t ≥ 0, where {T(t)}t≥0 is the semigroup with generator L.
- The condition
β
∞
sup
y∈E [T(s)ϕ(y)]β ds < 1
ensures sup
x∈E
w(t, x) < ∞ for all t ≥ 0, i.e. w is a global solution. (e.g. Nagasawa and Sirao (1969) and Weissler (1981))
5
Constructing Subsolutions by the Feynman-Kac Formula We now consider the equation ∂w(t) ∂t = ∆αw(t) + w(t)1+β, w(x, 0) = ϕ(x), x ∈ Rd. (2) Recall that the solution u of the IVP ∂u ∂t = ∆αu(t) + u(t)v(t), (3) u(0, x) = ϕ(x), (t, x) ∈ [0, T) × Rd with v : [0, T) × Rd → R+ locally bounded, has by the Feynman-Kac formula a proba- bilistic representation as the density of the measure
- Ex
- 1(Wt ∈ dy) exp
t
v(s)(Ws)
- ϕ(x) dx = u(t, y) dy
(4) where Ex denotes expectation with respect to the symmetric α-stable process (Wt) started at W0 = x. The representation (4) shows in particular that any solution u of (3) with v replaced by
- v ≤ v and
u0 ≤ u0 fulfills u ≤ u.
6
Consider the initial value problems ∂ft ∂t = ∆αft, f0 = ϕ (vt ≡ 0) ∂gt ∂t = ∆αgt + ftgt, g0 = ϕ (vt ≡ ft) ∂ht ∂t = ∆αht + gtht, h0 = ϕ (vt ≡ gt). Then, by the previous remark ft ≤ gt ≤ ht ≤ wt, i.e., ft, gt and ht are subsolutions of ∂wt ∂t = ∆αwt + w1+β, w0 = ϕ.
7
Basic Estimates We denote by Br the ball in Rd with radius r centered at the origin, and write pt(x) for the transition density of (Wt). Let ft(y) :=
- pt(y − x)ϕ(x) dx = Ey [ϕ(Wt)] .
Lemma 1. For all t ≥ 1 we have the inequality ft(y) ≥ c0t−d/α1B1(t−1/αy)
- B1
ϕ(x) dx for some c0 > 0. Indeed, let y ∈ Bt1/α. Then, by the scaling property of Wt ft(y) =
Ey [ϕ(Wt)] = E0 [ϕ(Wt + y)]
=
E0
- ϕ
- t1/α(W1 + t−1/αy)
- ≥
- B1
p1(x − t−1/αy)ϕ(t1/αx) dx ≥ c0
- B1
ϕ(t1/αx) dx = c0t−d/α
- Bt1/α
ϕ(x) dx ≥ c0t−d/α1B1(t−1/αy)
- B1
ϕ(x) dx
8
This argument also shows that, for sufficiently large t, ft(y) ≥ c′
0t−d/α1B1(t−1/αy).
for some c′
0 > 0.
In the same way one can prove the following Lemma 2. There exists a c > 0 such that for all t ≥ 2, y ∈ Bt1/α, x ∈ B1 and s ∈ [1, t/2],
Px {Ws ∈ Bs1/α| Wt = y} ≥ c.
- Proof. Using self-similarity, continuity and strict positivity of stable densities, we have that
for all s ∈ [1, t/2],
- Bs1/α
ps(z − x)pt−s(y − z) pt(y − x) dz =
- Bs1/α
s−d/αp1(s−1/α(z − x))(t − s)−d/αp1((t − s)−1/α(y − z)) t−d/αp1(t−1/α(y − x)) dz ≥ s−d/α(t − s)−d/α t−d/α · (infw∈B2 p1(w))2 p1(0)
- Bs1/α
dz ≥ s−d/αVol(Bs1/α)(infw∈B2 p1(w))2 2p1(0) . 9
Let gt solve ∂gt ∂t = ∆αgt + gtf β
t ,
g0 = ϕ, (5) where ft is defined in Lemma 1. Proposition 1 Let d < α/β. Then gt grows to ∞ uniformly on the unit ball as t → ∞, i.e., lim
t→∞ inf x∈B1 gt(x) = ∞.
- Proof. From the Feynman-Kac representation we know that gt is given by
gt(y) =
- ϕ(x) pt(y − x)E x
- exp
t
fs(Ws)β ds
- Wt = y
- dx.
Using Lemma 1 and Jensen’s inequality, it follows that for y ∈ Bt1/α,
gt(y) ≥
- ϕ(x) pt(y − x)E x
- exp
t/2
1
c1s−βd/α1Bs1/α(Ws) ds
- Wt = y
- dx
≥
- ϕ(x) pt(y − x) exp
- c2
t/2
1
s−βd/αPx{Ws ∈ Bs1/α| Wt = y} ds
- dx
≥ c3t−d/α exp
- c4
t/2
1
s−βd/αds
- ,
(6)
where we have used Lemma 2 to obtain the last inequality, and where ci, i = 1, 2, 3, 4, are positive constants. The result follows from the condition d < α/β.
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Completion of the proof of blowup
Since wt ≥ gt, from Proposition 1 it follows that K(t) := inf
x∈B1
wt(x) → ∞ as t → ∞. (7) We re-start (2) with the initial condition wt0, with a suitable choice of t0 given below. Writing ut = wt0+t, the equation becomes ∂ut ∂t = ∆αut + u1+β
t
, u0(x) = wt0(x), x ∈ Rd. Its integral form is ut(x) =
- pt(y − x)u0(y) dy +
t
ds
- pt−s(y − x)us(y)1+β dy.
Noting that ζ := min
x∈B1
min
0≤s≤1 Px {Ws ∈ B1} > 0,
we deduce that, for every t ∈ [0, 1], min
x∈B1
ut(x) ≥ ζK(t0) + ζ
t
- min
y∈B1
us(y)
1+β
ds. Moreover, min
x∈B1
ut(x) ≥ v(t), where v(t) = ζK(t0) + ζ
t
v(s)1+β ds, and v(t) blows up at time τ = 1 βζ1+βK(t0)β . Due to (7), we can choose t0 so big that τ < 1. This yields min
x∈B1
u1(x) = ∞, which shows blowup of wt0+1. 11
Remark By a second application of the Feynman-Kac formula, one can easily prove that the subsolution ht ∂ht ∂t = ∆αht + gβ
t ht,
h0 = ϕ, (where gt is the subsolution obtained above), is such that inf
x∈B1 ht(x) → ∞
as t → ∞ even if d = α/β. Hence, our equation has no positive global solutions if d ≤ α/β.
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Other Generators Consider the one-dimensional semilinear equation ∂wt ∂t = Γwt + νtσw1+β
t
, w0(x) = ϕ(x), x ∈ R+, (8) where ν, σ, β ≥ 0, ϕ ≥ 0 and
Γf(x) =
∞
- [f(x + y) − f(x)] e−y
y dy, i.e. Γ is the generator of the standard Gamma process.
- The Γ-process enjoys no self-similarity or symmetry, nor dimensional-dependent
behavior.
- The transition densities of the Γ-motion process are explicitly given,
- The bridges of the Γ-process are beta distributed.
13
In this case, we need to impose conditions on the decay of the initial value ϕ(x) as x → ∞. By adapting the Feynman-Kac approach one can prove [LM, N. Privault]:
- Every bounded, measurable initial condition ϕ ≥ 0 satisfying
c1x−a1 ≤ ϕ(x), x > x0 for some positive constants x0, c1, a1, where a1β < 1 + σ, produces a non-global solution.
- On the other side, if ϕ fulfils
ϕ(x) ≤ c2x−a2, x > x0, where x0, c2, a2 are positive numbers and a2β > 1 + σ, then the solution wt to (8) is global and, moreover, 0 ≤ wt(x) ≤ Ct−a2, x ≥ 0, for some constant C > 0.
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- In case of σ = 0 with
ϕ(x) ∼ cx−a as x → ∞ for some constants c > 0 and a > 0, we have – explosion in finite time if aβ < 1, – existence of global solutions if aβ > 1.
- If σ = 0 and
lim inf
x→∞ x−ε+1/βϕ(x) > 0,
for some ε > 0, then the solution of (8) blows up in finite time, whereas it is global provided that lim inf
x→∞ xε+1/βϕ(x) = 0.
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A generator with a bounded potential We consider now the semilinear equation ∂wt ∂t (x) = ∆wt(x) − V (x)wt(x) + tζw1+β
t
(x), (9) w0(x) = ϕ(x), x ∈ Rd where β > 0, ζ > 0 ϕ ≥ 0 and V is a bounded potential. The case ζ = 0 has been studied by Souplet and Zhang. Notice that V > 0 is constant and ϕ∞ ≤ 1 ⇒ w is a global solution. This is so because, in case of a constant V , L = ∆ − V generates the semigroup T V
t
:= e−V tTt where (Tt)t≥0 is the Brownian semigroup, and therefore T V
t ϕ ≤ e−V tϕ∞
which implies β
∞
sup
x∈Rd
- T V
t ϕ(x)
β dt < 1
for all sufficiently small ϕ and any β > 0.
16
Using the Feynman-Kac approach, one can prove [P . Souplet and Q.S. Zhang], [LM, N. Privault] that
- If d ≥ 3 and
0 ≤ V (x) ≤ a 1 + |x|b, x ∈ Rd, (10) for some a > 0 and b ∈ [2, ∞), then b > 2 implies finite time blow-up of (9) for all 0 < β < 2/d.
- If b = 2, then there exists β∗(a) < 2/d such that blow-up occurs if 0 < β < β∗(a).
Moreover,
- If for some a > 0 and 0 ≤ b < 2,
V (x) ≥ a 1 + |x|b, x ∈ Rd, (11) then (9) admits a global solution for all β > 0 and all non-negative initial values satisfying ϕ(x) ≤ c/(1 + |x|σ) for a sufficiently small constant c > 0 and all σ obeying σ ≥ b/β.
- Two critical exponents β∗(a), β∗(a) were found for the quadratic decay case
V (x) ∼+∞ a(1 + |x|2)−1, a > 0, with 0 < β∗(a) ≤ β∗(a) < 2/d and such that – any nontrivial positive solution is nonglobal provided 0 < β < β∗(a), – if β∗(a) < β, then nontrivial positive global solutions may exist. 17
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