Exam Format and Notes: Electrodynamics PHYS30441 Time: 1 hours - - PowerPoint PPT Presentation
Exam Format and Notes: Electrodynamics PHYS30441 Time: 1 hours - - PowerPoint PPT Presentation
Exam Format and Notes: Electrodynamics PHYS30441 Time: 1 hours Paper consists of 4 questions Answer question 1 and 2 others Question 1 is multi-part and covers the whole course Question 2 is on Statics . Question 3 is on
Exam Format and Notes: Electrodynamics PHYS30441
- Time: 1 ½ hours
- Paper consists of 4 questions
- Answer question 1 and 2 others
- Question 1 is multi-part and covers the whole course
- Question 2 is on Statics.
- Question 3 is on Radiation from moving charges or Hertzian Dipole
- Question 4 is on Relativity
- There will be a formula sheet in the exam paper.
This will include: Legendre polynomials (if needed); Differential operators (i.e. grad, curl, divergence) for different coordinate systems (if needed); L.W. fields and potentials (if needed); EM field tensor and Lorentz transformation matrix (if needed). Difficult integrals (if needed).
Summary of Essential E.M. Formulae
Gauss' law and Poisson's equation: R ~ D d2~ r = R d3r = q; r2V = ="; and solution: V =
1 4"
R
(r0) j~ r~ r0jd3r0
Also, r2 ~ A = 0 ~ J; with a solution: ~ A = 0
4
R
~ J(r0) j~ r~ r0jd3r0
Biot-Savart law: ~ B = 0
4
R dl0(~
r~ r0) j~ r~ r0j3
d ! l 0 = 0I
4
R dl0(~
r~ r0) j~ r~ r0j3
(dl' lies along the current source) Maxwell's equations (ME): r ~ E = @
@t ~
H; r ~ H = ~ J + @
@t ~
D In media: ~ D = " ~ E = "0(1 + e) ~ E; ~ B = 0 (1 + m) ~ H From ME: r ~ E = ="; r ~ B = 0; r ~ J = @
@t (continuity equation)
Lorentz force: ~ F = q
- ~
E + ~ v ~ B
- Scalar and vector potentials:
~ B = r ~ A; ~ E = rV @
@t ~
A Coulomb gauge: r: ~ A = 0 Lorentz gauge: r:A = 1
c2 @ @tV
Inhomogeneous wave equation:
- r2 1
c2 @2 @t2
- V = =";
- r2 1
c2 @2 @t2
- ~
A = ~ J Vector relations: r:
- r ~
A
- = 0; If r ~
E = 0 ) ~ E = rV; r r ~ A = r
- r: ~
A
- r2 ~
A; r ^ r = 2
r; r ~
r = 3; rrn = nrn2~ r;
- for example: rr = ^
r; r 1
r = ~ r r3 = ^ r r2
- Dirac delta:
(f (x)) = P
i 1 jd f=dxj x=xi (x xi) ; e.g. (ax) = 1 jaj (x) ;
r2
r 1
j~
r~ r0j = 1 4 (~
r ~ r0) ; r ^
r r2
- = 43 (r)
Multipole expansion: V (~ r) =
1 4"
P1
n=0 1 rn+1
R (r0)n Pn
- cos 0
(~ r0) d3r0 =
1 4"
h
1 r
R (~ r0) d3r0 + 1
r2
R r0 cos 0 (~ r0) d3r0 + 1
r3
R (r0)2 3
2 cos2 0 1 2
- (~
r0) d3r0 + :: i 1
- rm
- lar
- rdinates:
V (r, θ) =
∞
- l=0
- Alrl + Bl
rl+1
- Pl(cos θ)
P = µ0q2a2 6πc
1