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Electric Current & DC Circuits
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Electric Current & DC Circuits www.njctl.org http://njc.tl/iq - - PowerPoint PPT Presentation
Slide 1 / 99 Electric Current & DC Circuits www.njctl.org http://njc.tl/iq Slide 2 / 99 New Jersey Center for Teaching and Learning Progressive Science Initiative This material is made freely available at www.njctl.org and is intended
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This material is made freely available at www.njctl.org and is intended for the non-commercial use of students and teachers. These materials may not be used for any commercial purpose without the written permission of the owners. NJCTL maintains its website for the convenience of teachers who wish to make their work available to other teachers, participate in a virtual professional learning community, and/or provide access to course materials to parents, students and others.
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Click on the topic to go to that section
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The current, has the units Coulombs per second. The units can be rewritten as Amperes (A). 1 A = 1 C/s Amperes are often called "amps". ΔQ Δt I =
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Positive Terminal Negative Terminal Each battery has two terminals which are conductors. The terminals are used to connect an external circuit allowing the movement of charge. Batteries convert chemical energy to electrical energy which maintains the potential difference. The chemical reaction acts like an escalator, carrying charge up to a higher voltage.
Click here for a Battery Voltage Simulation from PhET
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The circuit cannot have gaps. The bulb had to be between the wire and the terminal. A voltage difference is needed to make the bulb light. The bulb still lights regardless of which side of the battery you place it on.
As you watch the video,observations and the answers to the questions below. What is going on in the circuit? What is the role of the battery? How are the circuits similar? different?
Click here for video using the circuit simulator from PhET
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How will voltage affect current?
click here for a video from Veritasium's Derek on current
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Click here to run another PhET simulation
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V R I =
click here for a Veritasium music video on electricity
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How can we re-write electrical power by using Ohm's Law? P = IV
(electrical power)
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(electrical power)
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Resistance, R, is measured in Ohms (Ω). Ω is the Greek letter Omega. Cross-sectional area, A, is measured in m2 Length, L, is measured in m Resistivity, ρ, is measured in Ωm R = #L A How can we define A for a wire?
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L
Click here for a PhET simulation about Resistance
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Resistivity (10-8 Ωm) Material
Silver Copper Gold Aluminum Tungsten Iron Platinum Mercury Nichrome 1.59 1.68 2.44 2.65 5.60 9.71 10.6 98 100 http://njc.tl/nr
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Draw a simple circuit that has a 9 V battery with a 3 Ω resistor across its terminals. What is the magnitude and direction of the current? Conventional current flows from the positive terminal to the negative terminal.
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R1 R2
V
R1 R2 V
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eq).
R1 R2 V
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R1 R2 V
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R1 R2 V
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If V = V1 + V2 + V3 + ... IR = I1R1 + I2R2 + I3R3 IR = IR1 + IR2 + IR3 Req = R1 + R2 + R3 + ...
eq) of a series circuit,
substitute Ohm's Law solved for V is: V = IR but since current (I) is the same everywhere in a series circuit, I = I1 = I2 = I3
Now divide by I
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R1 = 5# R2 = 3# V = 9 V
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R1 = 5# R2 = 3# V = 9 V
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R1 = 5# R2 = 3# V = 9 V
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hint: A good way to check your work is to see if the voltage drop across all resistors equals the total voltage in the circuit.
R1 = 5# R2 = 3# V = 9 V
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R1 = 5# R2 = 3# V = 9 V
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R1 R2
V
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R1 R2
V
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If I = I
1 + I2 + I3
V1 R1 V R V3 R3 V2 R2 + + = V R1 V R V R3 V R2 + + = 1 R1 V R 1 R3 1 R2 + + = V(
1 R1 1 Req 1 R3 1 R2 + + =
If you add more resistors in parallel, what will happen to the resistance of the circuit?
Rewrite Ohm's Law for I and substitute for each resistor
Also, since V = V1 = V2 = V3 so we can substitute V for any other voltage Voltage is a common factor, so factor it
Divide by V to eliminate voltage from the equation.
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R1 = 3# R2 = 6# V = 18V
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R1 = 3# R2 = 6# V = 18V
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R1 = 3# R2 = 6# V = 18V
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R1 = 3# R2 = 6# V = 18V
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R1 = 3# R2 = 6# V = 18V
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R1 = 3# R2 = 6# V = 18V
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R1 = 3# R2 = 6# V = 18V R3 = 4#
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R1 = 3# R2 = 6# V = 18V R3 = 4#
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R1 = 3# R2 = 6# V = 18V R3 = 4#
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Since circuits in parallel have the same voltage, and a voltmeter has very high resistance, very little current passes through it. This means that it has little effect on the circuit.
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Click here for a PhET simulation on circuits
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Req E
_ +
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Req E
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If however a circuit is attached, the internal resistance will result in a voltage drop, and a smaller terminal voltage. (E - Ir)
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Req E
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We say that the terminal voltage is: VT = E - Ir Maximum current will occur when there is zero external current. When solving for equivalent resistance in a circuit, the internal resistance of the battery is considered a series resistor. REQ = Rint + Rext
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I1 I2 I3
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V V1 V2
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R1 = 5# R2 = 3#
V = 12 V
R3 = ? R4 = 2# V3 = 1.87 V I2 = 2.6 A
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R1 = 5# R2 = 3#
V = 12 V
R3 = ? R4 = 2# I2 = 2.6 A V3 = 1.87 V
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R1 = 5# R2 = 3#
V = 12 V
R3 = ? R4 = 2# I2 = 2.6 A V3 = 1.87 V
I3
I4
I I1
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R1 = 5# R2 = 3#
V = 12 V
R3 = ? R4 = 2# I2 = 2.6 A V3 = 1.87 V
I3
I4
I I1
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R1 = 5# R2 = 3#
V = 12 V
R3 = ? R4 = 2# I2 = 2.6 A V3 = 1.87 V
I3
I4 I1
I
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Current (Amps) Voltage (Volts) Resistance (Ohms) R1 5 R2 2.6 3 R3 1.87 R4 2 Total 12
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V = 120 V R1 = 10 # I1 = 7 A V1 = 70 V R3 = 2 # I3 = 10 A V3 = 20 V R4 = 3 # I4 = 10 A V4 = 30 V R2 = 23 # I2 = 3 A V2 = 70 V
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