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Dynamics of Disjoint Hypercyclic Operators: Hypercyclicity vs. - - PowerPoint PPT Presentation

Introduction Dynamics of Hypercyclic Operators Results Dynamics of Disjoint Hypercyclic Operators: Hypercyclicity vs. Disjoint Hypercyclicity Rebecca Sanders Department of Mathematics, Statistics, and Computer Sci. Marquette University April


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Introduction Dynamics of Hypercyclic Operators Results

Dynamics of Disjoint Hypercyclic Operators: Hypercyclicity vs. Disjoint Hypercyclicity

Rebecca Sanders Department of Mathematics, Statistics, and Computer Sci. Marquette University April 11-13, 2014

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Throughout this talk, let

  • X = separable,∞-dimensional Banach space
  • B(X) = algebra of operators T : X −

→ X

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Throughout this talk, let

  • X = separable,∞-dimensional Banach space
  • B(X) = algebra of operators T : X −

→ X Definition. An operator T ∈ B(X) is hypercyclic if there is a vector x ∈ X for which its orbit Orb(T, x) = {T nx : n ≥ 0} is dense in X.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Throughout this talk, let

  • X = separable,∞-dimensional Banach space
  • B(X) = algebra of operators T : X −

→ X Definition. An operator T ∈ B(X) is hypercyclic if there is a vector x ∈ X for which its orbit Orb(T, x) = {T nx : n ≥ 0} is dense in X. HC(T) = set of hypercyclic vectors for T

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Definition. Operators T1, T2, . . . , TN ∈ B(X) with N ≥ 2 are disjoint hypercyclic or d-hypercyclic if there is a vector x ∈ X for which (x, x, . . . , x) ∈ HC(T1 ⊕ T2 ⊕ · · · ⊕ TN)

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Definition. Operators T1, T2, . . . , TN ∈ B(X) with N ≥ 2 are disjoint hypercyclic or d-hypercyclic if there is a vector x ∈ X for which (x, x, . . . , x) ∈ HC(T1 ⊕ T2 ⊕ · · · ⊕ TN) d-HC(T1, T2, . . . , TN) = set d-hypercyclic vectors for T1, . . . , TN

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Definition. Operators T1, T2, . . . , TN ∈ B(X) with N ≥ 2 are disjoint hypercyclic or d-hypercyclic if there is a vector x ∈ X for which (x, x, . . . , x) ∈ HC(T1 ⊕ T2 ⊕ · · · ⊕ TN) d-HC(T1, T2, . . . , TN) = set d-hypercyclic vectors for T1, . . . , TN Definition. The operators T1, T2, . . . , TN are densely d-hypercyclic if the set d-HC(T1, T2, . . . , TN) is dense in X.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Goal Show several of the standard dynamical properties of hypercyclic operators fail to hold true for disjoint hypercyclic

  • perators.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Goal Show several of the standard dynamical properties of hypercyclic operators fail to hold true for disjoint hypercyclic

  • perators.
  • Remark. Restrict our attention for d-hypercyclicity to two
  • perators T1, T2.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Dynamics of Hypercyclic Operators

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Dynamics of Hypercyclic Operators Fact 1. The following statements are equivalent: (1) T is hypercyclic. (2) HC(T) is a dense Gδ set. (3) T is topologically transitive; that is, for any nonempty, open sets U, V , there is n ≥ 1 such that U ∩ T −n(V ) = ∅.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Fact 2. The following statements are equivalent: (1) T satisfies the Hypercyclicity Criterion. (2) T is weakly mixing; that is, T ⊕ T is topologically transitive. (3) M

i=1 T is topologically transitive for each M ≥ 1.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Fact 2. The following statements are equivalent: (1) T satisfies the Hypercyclicity Criterion. (2) T is weakly mixing; that is, T ⊕ T is topologically transitive. (3) M

i=1 T is topologically transitive for each M ≥ 1.

(4) T satisfies the Blow-up/Collapse Property; that is, for any nonempty, open sets U, V, W with 0 ∈ W, there is n ≥ 1 such that U ∩ T −n(W) = ∅ and W ∩ T −n(V ) = ∅.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Fact 2. The following statements are equivalent: (1) T satisfies the Hypercyclicity Criterion. (2) T is weakly mixing; that is, T ⊕ T is topologically transitive. (3) M

i=1 T is topologically transitive for each M ≥ 1.

(4) T satisfies the Blow-up/Collapse Property; that is, for any nonempty, open sets U, V, W with 0 ∈ W, there is n ≥ 1 such that U ∩ T −n(W) = ∅ and W ∩ T −n(V ) = ∅.

  • Remark. If M

i=1 T with M ≥ 2 is hypercyclic, then M+1 i=1 T is

also hypercyclic.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Defintion. Operators T1, T2 ∈ B(X) are d-topologically transitive if for any nonempty, open sets U, V1, V2, there is n ≥ 1 such that U ∩ T −n

1

(V1) ∩ T −n

2

(V2) = ∅.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Defintion. Operators T1, T2 ∈ B(X) are d-topologically transitive if for any nonempty, open sets U, V1, V2, there is n ≥ 1 such that U ∩ T −n

1

(V1) ∩ T −n

2

(V2) = ∅. Theorem A. (B` es, Peris) The following statements are equivalent: (1) T1, T2 are densely d-hypercyclic. (2) d-HC(T1, T2) is a dense Gδ set. (3) T1, T2 are d-topologically transitive.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Questions

  • 1. Does d-hypercyclicity imply dense d-hypercyclicity?

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Definition. Operators T1, T2 ∈ B(X) are d-weakly mixing if T1 ⊕ T1, T2 ⊕ T2 are d-topologically transitive.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Definition. Operators T1, T2 ∈ B(X) are d-weakly mixing if T1 ⊕ T1, T2 ⊕ T2 are d-topologically transitive. Disjoint Hypercyclicity Criterion. Operators T1, T2 ∈ B(X) satisfy the d-Hypercyclicity Criterion if there exist sequence (nk)∞

k=1, dense sets X0, X1, X2 of X, and

maps Sm,k : Xm − → X (m = 1, 2) such that T nk

m −

→ 0 pointwise on X0 for m = 1, 2, Sm,k − → 0 pointwise on Xm for m = 1, 2, T nk

m Si,k −

→ δi,mI pointwise on Xi for i, m = 1, 2.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Disjoint Blow-up/Collapse Property. Operators T1, T2 ∈ B(X) satisfy the Disjoint Blow-up/Collapse Property if for any nonempty, open sets U, V1, V2, W with 0 ∈ W, there is n ≥ 1 for which U ∩ T −n

1

(W) ∩ T −n

2

(W) = ∅ and W ∩ T −n

1

(V1) ∩ T −n

2

(V2) = ∅.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Theorem B. (B` es, Peris)

  • The two statements are equivalent:

(1) T1, T2 satisfy d-Hypercyclicity Criterion (2) M

i=1 T1, M i=1 T2 are d-topologically transitive for each

M ≥ 1.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Theorem B. (B` es, Peris)

  • The two statements are equivalent:

(1) T1, T2 satisfy d-Hypercyclicity Criterion (2) M

i=1 T1, M i=1 T2 are d-topologically transitive for each

M ≥ 1.

  • If T1, T2 satisfy the Disjoint Blow-up/Collapse Property,

then T1, T2 are d-topologically transitive and so densely d-hypercyclic.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Theorem B. (B` es, Peris)

  • The two statements are equivalent:

(1) T1, T2 satisfy d-Hypercyclicity Criterion (2) M

i=1 T1, M i=1 T2 are d-topologically transitive for each

M ≥ 1.

  • If T1, T2 satisfy the Disjoint Blow-up/Collapse Property,

then T1, T2 are d-topologically transitive and so densely d-hypercyclic.

  • If T1, T2 are d-weakly mixing, then T1, T2 satisfy the Disjoint

Blow-up/Collapse Property. Hence, d-Hypercyclicity Criterion implies the Disjoint Blow-up/Collapse Property.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Questions

  • 1. Does d-hypercyclicity imply dense d-hypercyclicity?

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Questions

  • 1. Does d-hypercyclicity imply dense d-hypercyclicity?
  • 2. Can we add “T1, T2 are d-weakly mixing” to the first

statement in Theorem B as in Fact 2?

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Questions

  • 1. Does d-hypercyclicity imply dense d-hypercyclicity?
  • 2. Can we add “T1, T2 are d-weakly mixing” to the first

statement in Theorem B as in Fact 2?

  • 3. Are the d-Hypercyclicity Criterion and the Disjoint

Blow-up/Collapse Property equivalent as in Fact 2?

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Results

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Results Theorem 1. (Sanders, Shkarin) Let X be a separable, infinite dimensional Banach space. For each M ≥ 1, there are T1, T2 ∈ B(X) such that

M

  • i=1

T1,

M

  • i=1

T2 are densely d-hypercyclic and hence d-topologically transitive, but

M+1

  • i=1

T1,

M+1

  • i=1

T2 fail to be d-hypercyclic.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Take M = 2 in Theorem 1.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Take M = 2 in Theorem 1.

  • T1, T2 satisfy the d-Hypercyclicity Criterion ⇐

⇒ M

i=1 T1, M i=1 T2 are d-topologically transitive for each M ≥ 1.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Take M = 2 in Theorem 1.

  • T1, T2 satisfy the d-Hypercyclicity Criterion ⇐

⇒ M

i=1 T1, M i=1 T2 are d-topologically transitive for each M ≥ 1.

Corollary 1. There are d-weakly mixing operators T1, T2 ∈ B(X) which fail to satisfy the d-Hypercyclicity Criterion.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

  • If T1, T2 are d-weakly mixing, then T1, T2 ∈ B(X) satisfy the

Disjoint Blow-up/Collapse Property.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

  • If T1, T2 are d-weakly mixing, then T1, T2 ∈ B(X) satisfy the

Disjoint Blow-up/Collapse Property. Corollary 2. There are operators T1, T2 ∈ B(X) which satisfy the Blow-up/Collapse Property but fail to satisfy the d-Hypercyclicity Criterion.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

  • If T1, T2 are d-weakly mixing, then T1, T2 ∈ B(X) satisfy the

Disjoint Blow-up/Collapse Property. Corollary 2. There are operators T1, T2 ∈ B(X) which satisfy the Blow-up/Collapse Property but fail to satisfy the d-Hypercyclicity Criterion. Take M = 1 in Theorem 1.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

  • If T1, T2 are d-weakly mixing, then T1, T2 ∈ B(X) satisfy the

Disjoint Blow-up/Collapse Property. Corollary 2. There are operators T1, T2 ∈ B(X) which satisfy the Blow-up/Collapse Property but fail to satisfy the d-Hypercyclicity Criterion. Take M = 1 in Theorem 1. Corollary 3. There are densely d-hypercyclic operators T1, T2 ∈ B(X) which fail to be d-weakly mixing.

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Hypercyclicity vs d-Hypercyclicity T1, T2 satisfy d-Hypercyclicity ⇒ T1, T2 satisfy Disjoint Blow-up Criterion

  • /Collapse Property
  • M

i=1 T1, M i=1 T2 d-top. trans.

⇓ ⇑ ր ւ? T1, T2 d-weakly mixing

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Hypercyclicity vs d-Hypercyclicity T1, T2 satisfy d-Hypercyclicity ⇒ T1, T2 satisfy Disjoint Blow-up Criterion

  • /Collapse Property
  • M

i=1 T1, M i=1 T2 d-top. trans.

⇓ ⇑ ր ւ? T1, T2 d-weakly mixing Open Question. Does every separable, infinite dimensional Banach space X admit operators T1, T2 which satisfy the Disjoint Blow-up/Collapse Property but fail to be d-weakly mixing?

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Outline of Proof for Theorem 1

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Outline of Proof for Theorem 1 Step 1. Construct T1, T2 ∈ B(X).

Sanders Disjoint Hypercyclic Operators

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Outline of Proof for Theorem 1 Step 1. Construct T1, T2 ∈ B(X). Let T1 ∈ B(X) which satisfies the Hypercyclicity Criterion. Select any vector (f1, . . . , fM, g1 . . . , gM) ∈ HC 2M

  • i=1

T1

  • Sanders

Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Outline of Proof for Theorem 1 Step 1. Construct T1, T2 ∈ B(X). Let T1 ∈ B(X) which satisfies the Hypercyclicity Criterion. Select any vector (f1, . . . , fM, g1 . . . , gM) ∈ HC 2M

  • i=1

T1

  • By Hahn-Banach Theorem, there are λ1, . . . , λM ∈ X∗ such

that λi(fj) =

  • 1,

if i = j 0, if i = j and λi(gj) = 0.

Sanders Disjoint Hypercyclic Operators

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Define L : X − → X by Lx = x + M

i=1 λi(x)gi. One can show

this operator is invertible, and so we let T2 = L−1T1L.

Sanders Disjoint Hypercyclic Operators

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Define L : X − → X by Lx = x + M

i=1 λi(x)gi. One can show

this operator is invertible, and so we let T2 = L−1T1L. Step 2. Show M

i=1 T1, M i=1 T2 are densely d-hypercyclic.

Sanders Disjoint Hypercyclic Operators

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Define L : X − → X by Lx = x + M

i=1 λi(x)gi. One can show

this operator is invertible, and so we let T2 = L−1T1L. Step 2. Show M

i=1 T1, M i=1 T2 are densely d-hypercyclic.

  • Claim. Let A1 = L−1

1 AL1, A2 = L−1 2 AL2. Then (x1, . . . , xM) ∈

d-HC(M

i=1 A1, M i=1 A2) if and only if

(L1x1, . . . , L1xM, L2x1, . . . , L2xM) ∈ HC 2M

  • i=1

A

  • .

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Define L : X − → X by Lx = x + M

i=1 λi(x)gi. One can show

this operator is invertible, and so we let T2 = L−1T1L. Step 2. Show M

i=1 T1, M i=1 T2 are densely d-hypercyclic.

  • Claim. Let A1 = L−1

1 AL1, A2 = L−1 2 AL2. Then (x1, . . . , xM) ∈

d-HC(M

i=1 A1, M i=1 A2) if and only if

(L1x1, . . . , L1xM, L2x1, . . . , L2xM) ∈ HC 2M

  • i=1

A

  • .

Proof of Claim. Follow directly from definitions of hypercyclic and d-hypercyclic vectors.

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Let U1 ⊕ · · · ⊕ UM be a basic open in M

i=1 X. Define

A : M

i=1 X −

→ B(FM) by A(x1, . . . , xM) = [λi(xj)]i,j=1,...,M.

Sanders Disjoint Hypercyclic Operators

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Let U1 ⊕ · · · ⊕ UM be a basic open in M

i=1 X. Define

A : M

i=1 X −

→ B(FM) by A(x1, . . . , xM) = [λi(xj)]i,j=1,...,M. Observe that (U1 ⊕ · · · ⊕ UM) ∩ A−1(O) = ∅ where O is the set

  • f all invertible M × M matrices.

Sanders Disjoint Hypercyclic Operators

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Let U1 ⊕ · · · ⊕ UM be a basic open in M

i=1 X. Define

A : M

i=1 X −

→ B(FM) by A(x1, . . . , xM) = [λi(xj)]i,j=1,...,M. Observe that (U1 ⊕ · · · ⊕ UM) ∩ A−1(O) = ∅ where O is the set

  • f all invertible M × M matrices. Moreover, since this set is
  • pen and (f1, . . . , fM) ∈ HC(M

i=1 T1), there is r ≥ 1 with

(T r

1 f1, . . . , T r 1 fM) ∈ (U1 ⊕ · · · ⊕ UM) ∩ A−1(O)

Sanders Disjoint Hypercyclic Operators

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Introduction Dynamics of Hypercyclic Operators Results

Let U1 ⊕ · · · ⊕ UM be a basic open in M

i=1 X. Define

A : M

i=1 X −

→ B(FM) by A(x1, . . . , xM) = [λi(xj)]i,j=1,...,M. Observe that (U1 ⊕ · · · ⊕ UM) ∩ A−1(O) = ∅ where O is the set

  • f all invertible M × M matrices. Moreover, since this set is
  • pen and (f1, . . . , fM) ∈ HC(M

i=1 T1), there is r ≥ 1 with

(T r

1 f1, . . . , T r 1 fM) ∈ (U1 ⊕ · · · ⊕ UM) ∩ A−1(O)

It remains to show (T r

1 f1, . . . , T r 1 fM) ∈ d-HC

M

  • i=1

T1,

M

  • i=1

T2

  • .

Sanders Disjoint Hypercyclic Operators

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Note that (T r

1 f1, . . . , T r 1 fM, LT1f1, . . . , LT r 1 fM) is the same as

  • T r

1 f1, . . . , T r 1 fM, T r 1 f1 + M

  • i=1

λi(T r

1 f1)gi, . . . , T r 1 fM + M

  • i=1

λi(T r

1 fM)gi

  • Sanders

Disjoint Hypercyclic Operators

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Note that (T r

1 f1, . . . , T r 1 fM, LT1f1, . . . , LT r 1 fM) is the same as

  • T r

1 f1, . . . , T r 1 fM, T r 1 f1 + M

  • i=1

λi(T r

1 f1)gi, . . . , T r 1 fM + M

  • i=1

λi(T r

1 fM)gi

  • Since (f1, . . . , fM, g1, . . . , gM) ∈ HC(2M

i=1 T1) and the matrix

A(T r

1 f1, . . . , T r 1 fM) = [λi(T r 1 fj)]i,j=1,...,M is invertible, we get

this vector is in HC(2M

i=1 T1).

Sanders Disjoint Hypercyclic Operators

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Note that (T r

1 f1, . . . , T r 1 fM, LT1f1, . . . , LT r 1 fM) is the same as

  • T r

1 f1, . . . , T r 1 fM, T r 1 f1 + M

  • i=1

λi(T r

1 f1)gi, . . . , T r 1 fM + M

  • i=1

λi(T r

1 fM)gi

  • Since (f1, . . . , fM, g1, . . . , gM) ∈ HC(2M

i=1 T1) and the matrix

A(T r

1 f1, . . . , T r 1 fM) = [λi(T r 1 fj)]i,j=1,...,M is invertible, we get

this vector is in HC(2M

i=1 T1). By our Claim, it follows that

(T r

1 f1, . . . , T r 1 fM) ∈ d-HC

M

  • i=1

T1,

M

  • i=1

T2

  • .

Sanders Disjoint Hypercyclic Operators

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Step 3. Show M+1

i=1 T1, M+1 i=1 T2 fail to be d-hypercyclic.

Sanders Disjoint Hypercyclic Operators

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Step 3. Show M+1

i=1 T1, M+1 i=1 T2 fail to be d-hypercyclic.

Suppose (x1, . . . , xM+1) ∈ d-HC(M+1

i=1 T1, M+1 i=1 T2). Let

y1, . . . , yM+1 ∈ X be linearly independent.

Sanders Disjoint Hypercyclic Operators

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Step 3. Show M+1

i=1 T1, M+1 i=1 T2 fail to be d-hypercyclic.

Suppose (x1, . . . , xM+1) ∈ d-HC(M+1

i=1 T1, M+1 i=1 T2). Let

y1, . . . , yM+1 ∈ X be linearly independent. Select (nk)∞

k=1 such

that T nk

1 xj −

→ 0 as k → ∞ and T nk

2 xj −

→ yj as k → ∞ for j = 1, . . . M + 1.

Sanders Disjoint Hypercyclic Operators

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Using the definition of L, T2, we have T nk

2 xj = L−1T nk 1 xj + M

  • i=1

λi(xj)L−1T nk

1 gi

Sanders Disjoint Hypercyclic Operators

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Using the definition of L, T2, we have T nk

2 xj = L−1T nk 1 xj + M

  • i=1

λi(xj)L−1T nk

1 gi

Using linear algebra, we can show there exists h1, . . . , hM in span{y1, . . . , yM} such that L−1T nk

1 gi −

→ hi as k → ∞ for 1 = 1, . . . , M.

Sanders Disjoint Hypercyclic Operators

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Using the definition of L, T2, we have T nk

2 xj = L−1T nk 1 xj + M

  • i=1

λi(xj)L−1T nk

1 gi

Using linear algebra, we can show there exists h1, . . . , hM in span{y1, . . . , yM} such that L−1T nk

1 gi −

→ hi as k → ∞ for 1 = 1, . . . , M. Now, T nk

2 xM+1 −

→ yM+1 as k → ∞, and

Sanders Disjoint Hypercyclic Operators

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T nk

2 xM+1 = L−1T nk 1 xM+1 + M

  • i=1

λi(xM+1)L−1T nk

1 gi

− → L−10 +

M

  • i=1

λi(xM+1)hi =

M

  • i=1

λi(xM+1)hi ∈ span{y1, . . . , yM}.

Sanders Disjoint Hypercyclic Operators

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T nk

2 xM+1 = L−1T nk 1 xM+1 + M

  • i=1

λi(xM+1)L−1T nk

1 gi

− → L−10 +

M

  • i=1

λi(xM+1)hi =

M

  • i=1

λi(xM+1)hi ∈ span{y1, . . . , yM}. Therefore, yM+1 =

M

  • i=1

λi(xM+1)hi ∈ span{y1, . . . , yM} which gives us a contradiction.

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Results

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Results Theorem 2. (Sanders, Shkarin) Let X be a separable, infinite dimensional Banach space. For each M ≥ 1, there are T1, T2 ∈ B(X) and x1, x2, . . . , xM ∈ X such that the set d-HC M

i=1 T1, M i=1 T2

  • is exactly
  • (h1, . . . , hM) ∈

M

  • i=1

span{x1, . . . , xM} : h1, . . . , hM lin. ind.

  • Sanders

Disjoint Hypercyclic Operators

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Take M = 1 in Theorem 2.

  • d-HC(T1, T2) = span{x1} \ {0}

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Take M = 1 in Theorem 2.

  • d-HC(T1, T2) = span{x1} \ {0}

Corollary 1. There are d-hypercyclic operators T1, T2 ∈ B(X) for which d-HC(T1, T2) is nowhere dense, and so fail to be densely d-hypercyclic.

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Take M = 1 in Theorem 2.

  • d-HC(T1, T2) = span{x1} \ {0}

Corollary 1. There are d-hypercyclic operators T1, T2 ∈ B(X) for which d-HC(T1, T2) is nowhere dense, and so fail to be densely d-hypercyclic. Corollary 2. There are d-hypercyclic operators T1, T2 ∈ B(X) which fail to be d-topologically transitive.

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Corollary 3. There are d-hypercyclic operators T1, T2 ∈ B(X) and densely d-hypercyclic operators A1, A2 ∈ B(X) for which d-HC(T1, T2) ∩ d-HC(A1, A2) = ∅.

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Corollary 3. There are d-hypercyclic operators T1, T2 ∈ B(X) and densely d-hypercyclic operators A1, A2 ∈ B(X) for which d-HC(T1, T2) ∩ d-HC(A1, A2) = ∅. Take M = 2 in Theorem 2.

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Corollary 3. There are d-hypercyclic operators T1, T2 ∈ B(X) and densely d-hypercyclic operators A1, A2 ∈ B(X) for which d-HC(T1, T2) ∩ d-HC(A1, A2) = ∅. Take M = 2 in Theorem 2. Corollary 4. There are T1, T2 ∈ B(X) such that T1 ⊕ T1, T2 ⊕ T2 are d-hypercyclic, but T1, T2 fail to be d-weakly mixing.

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  • Remark. The operators T1, T2 in Theorem 2 satisfy the

property that M

i=1 T1, M i=1 T2 are d-hypercyclic, but

M+1

i=1 T1, M+1 i=1 T2 fail to be d-hypercylic.

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  • Remark. The operators T1, T2 in Theorem 2 satisfy the

property that M

i=1 T1, M i=1 T2 are d-hypercyclic, but

M+1

i=1 T1, M+1 i=1 T2 fail to be d-hypercylic.

  • Proof. Let (f1, . . . , fM+1) ∈ d-HC(M+1

i=1 T1, M+1 i=1 T2).

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  • Remark. The operators T1, T2 in Theorem 2 satisfy the

property that M

i=1 T1, M i=1 T2 are d-hypercyclic, but

M+1

i=1 T1, M+1 i=1 T2 fail to be d-hypercylic.

  • Proof. Let (f1, . . . , fM+1) ∈ d-HC(M+1

i=1 T1, M+1 i=1 T2). Then

(f1, . . . , fm), (f2, . . . fM+1) are both in d-HC(M

i=1 T1, M i=1 T2).

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  • Remark. The operators T1, T2 in Theorem 2 satisfy the

property that M

i=1 T1, M i=1 T2 are d-hypercyclic, but

M+1

i=1 T1, M+1 i=1 T2 fail to be d-hypercylic.

  • Proof. Let (f1, . . . , fM+1) ∈ d-HC(M+1

i=1 T1, M+1 i=1 T2). Then

(f1, . . . , fm), (f2, . . . fM+1) are both in d-HC(M

i=1 T1, M i=1 T2).

Thus, f1, . . . , fM+1 ∈ span{x1, . . . , xM} which is impossible.

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  • Remark. The operators T1, T2 in Theorem 2 satisfy the

property that M

i=1 T1, M i=1 T2 are d-hypercyclic, but

M+1

i=1 T1, M+1 i=1 T2 fail to be d-hypercylic.

  • Proof. Let (f1, . . . , fM+1) ∈ d-HC(M+1

i=1 T1, M+1 i=1 T2). Then

(f1, . . . , fm), (f2, . . . fM+1) are both in d-HC(M

i=1 T1, M i=1 T2).

Thus, f1, . . . , fM+1 ∈ span{x1, . . . , xM} which is impossible. Open Question. Does there exist T1, T2 ∈ B(X) whose d-HC(T1, T2) is somewhere dense in X but not dense?

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Outline of Proof for Theorem 2

Sanders Disjoint Hypercyclic Operators

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Outline of Proof for Theorem 2 Step 1. Provide a sufficient condition for the conclusion of Theorem 2 to hold true.

Sanders Disjoint Hypercyclic Operators

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Outline of Proof for Theorem 2 Step 1. Provide a sufficient condition for the conclusion of Theorem 2 to hold true. Proposition. Let T1 ∈ B(X) and M ≥ 1. If there exist injective operator R ∈ B(X) and x1, . . . , xM, y1, . . . , yM ∈ X such that (i) (x1, . . . , xM, y1, . . . , yM) ∈ HC 2M

i=1 T

  • ,

(ii) Rxi = yj for i = 1, . . . M, (iii) R(X) ∩ HC(T1) ⊆ span{x1, . . . xM}, then there is T2 ∈ B(X) such that d-HC(M

i=1 T1, M i=1 T2) is

exactly

  • (h1, . . . , hM) ∈

M

  • i=1

span{x1, . . . , xM} : h1, . . . , hM lin. ind.

  • Sanders

Disjoint Hypercyclic Operators

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Proof of Proposition. Let A be this set. Select c > R, and set L1 = cI and L2 = cI + R.

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Proof of Proposition. Let A be this set. Select c > R, and set L1 = cI and L2 = cI + R. Note T1 = L−1

1 T1L1 and set

T2 = L−1

2 T1L2.

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Proof of Proposition. Let A be this set. Select c > R, and set L1 = cI and L2 = cI + R. Note T1 = L−1

1 T1L1 and set

T2 = L−1

2 T1L2.

To show A ⊆ d-HC(M

i=1 T1, M i=1 T2), let h1, . . . , hM in

span{x1, . . . , xM} be linearly independent.

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Proof of Proposition. Let A be this set. Select c > R, and set L1 = cI and L2 = cI + R. Note T1 = L−1

1 T1L1 and set

T2 = L−1

2 T1L2.

To show A ⊆ d-HC(M

i=1 T1, M i=1 T2), let h1, . . . , hM in

span{x1, . . . , xM} be linearly independent. By Claim from Theorem 1, it suffice to show (L1h1, . . . , L1hM, L2h1, . . . , L2hM) ∈ HC 2M

  • i=1

T1

  • .

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By definition of L1, L2, this vector is (ch1, . . . , chM, ch1 + Rh1, . . . , chM + RhM).

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By definition of L1, L2, this vector is (ch1, . . . , chM, ch1 + Rh1, . . . , chM + RhM). Moreover, this vector is in HC(2M

i=1 T1) if and only if

(h1, . . . , hM, Rh1, . . . , RhM) ∈ HC 2M

  • i=1

T1

  • .

Sanders Disjoint Hypercyclic Operators

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By definition of L1, L2, this vector is (ch1, . . . , chM, ch1 + Rh1, . . . , chM + RhM). Moreover, this vector is in HC(2M

i=1 T1) if and only if

(h1, . . . , hM, Rh1, . . . , RhM) ∈ HC 2M

  • i=1

T1

  • .

Now, h1, . . . , hM are linearly independent in span{x1, . . . , xM}. Since R is injective and Rxi = yi, we also have Rh1, . . . , RhM are linearly independent in span{y1, . . . , yM}.

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By definition of L1, L2, this vector is (ch1, . . . , chM, ch1 + Rh1, . . . , chM + RhM). Moreover, this vector is in HC(2M

i=1 T1) if and only if

(h1, . . . , hM, Rh1, . . . , RhM) ∈ HC 2M

  • i=1

T1

  • .

Now, h1, . . . , hM are linearly independent in span{x1, . . . , xM}. Since R is injective and Rxi = yi, we also have Rh1, . . . , RhM are linearly independent in span{y1, . . . , yM}. Since (x1, . . . , xM, y1, . . . , yM) ∈ HC(2M

i=1 T1), it follows that

(h1, . . . , hM, Rh1, . . . , RhM) ∈ HC 2M

  • i=1

T1

  • .

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To show d-HC(M

i=1 T1, M i=1 T2) ⊆ A, let (h1, . . . , hM) be in

d-HC(M

i=1 T1, M i=1 T2).

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To show d-HC(M

i=1 T1, M i=1 T2) ⊆ A, let (h1, . . . , hM) be in

d-HC(M

i=1 T1, M i=1 T2). Note, h1, . . . , hM must be linearly

independent.

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To show d-HC(M

i=1 T1, M i=1 T2) ⊆ A, let (h1, . . . , hM) be in

d-HC(M

i=1 T1, M i=1 T2). Note, h1, . . . , hM must be linearly

  • independent. Also,

(h1, . . . , hM, Rh1, . . . , RhM) ∈ HC 2M

  • i=1

T1

  • .

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To show d-HC(M

i=1 T1, M i=1 T2) ⊆ A, let (h1, . . . , hM) be in

d-HC(M

i=1 T1, M i=1 T2). Note, h1, . . . , hM must be linearly

  • independent. Also,

(h1, . . . , hM, Rh1, . . . , RhM) ∈ HC 2M

  • i=1

T1

  • .

This implies Rh1, . . . , RhM ∈ R(X) ∩ HC(T1) ⊆ span{y1, . . . , yM}.

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Thus, we can write Rhi = α1,iy1 + · · · + αM,iyM.

Sanders Disjoint Hypercyclic Operators

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Thus, we can write Rhi = α1,iy1 + · · · + αM,iyM. Also R(α1,ix1 + · · · + αM,ixM) = α1,iy1 + · · · + αM,iyM.

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Thus, we can write Rhi = α1,iy1 + · · · + αM,iyM. Also R(α1,ix1 + · · · + αM,ixM) = α1,iy1 + · · · + αM,iyM. Since R is injective, we get hi = α1,ix1 + · · · + αM,ixM ∈ span{x1, . . . , xM}, and so (h1, . . . hM) ∈ A.

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Step 2. Construct the operator T1 ∈ B(X) for Proposition.

Sanders Disjoint Hypercyclic Operators

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Step 2. Construct the operator T1 ∈ B(X) for Proposition. Let (ek)∞

k=0 in X and (λk)∞ k=0 in X∗ such that

(a) span{ek : k ≥ 0} and ek = 1 (b) ∞

k=0 Ker(λk) = {0} and ∞ k=0 λk < ∞

(c) λk(ej) = 0 if j = k and λk(ek) = ck > 0.

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Step 2. Construct the operator T1 ∈ B(X) for Proposition. Let (ek)∞

k=0 in X and (λk)∞ k=0 in X∗ such that

(a) span{ek : k ≥ 0} and ek = 1 (b) ∞

k=0 Ker(λk) = {0} and ∞ k=0 λk < ∞

(c) λk(ej) = 0 if j = k and λk(ek) = ck > 0. Define T1 : X − → X by T1x = x +

  • k=0

λk+1(x)ek.

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Step 3. Based on T1, construct the injective operator R ∈ B(X) and the vectors x1, . . . , xM, y1, . . . , yM for Proposition.

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Step 3. Based on T1, construct the injective operator R ∈ B(X) and the vectors x1, . . . , xM, y1, . . . , yM for Proposition. Essentially (x1, . . . , xM, y1, . . . , yM) ∈ HC 2M

  • i=1

T1

  • and

R = nuclear operator +

M

  • i=1
  • λi(·)fi

Sanders Disjoint Hypercyclic Operators

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Thank you for listening.

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References

  • 1. L. Bernal-Gonz´

alez, Disjoint hypercyclic operators, Studia

  • Math. 182 (2) (2007), 113-130.
  • 2. J. B`

es and A. Peris, Disjointness in hypercyclicity, J. Math.

  • Anal. Appl. 336 (2007), 297-315.
  • 3. J. B`

es, ¨

  • O. Martin, and R. Sanders, Weighted shifts and

disjoint hypercyclicity, Journal of Operator Theory, to appear.

  • 4. R. Sanders and S. Shkarin, Existence of disjoint weakly

mixing operators that fail to satisfy the Disjoint Hypercyclicity Criterion, J. Math. Anal. App., to appear.

Sanders Disjoint Hypercyclic Operators