Dilatons and Fine Tuning
John Terning, UC Davis with Csaba Csáki, Brando Bellazzini, Jay Hubisz, Javi Serra hep-ph/1209.3299 and 1305.3919
Dilatons and Fine Tuning John Terning, UC Davis with Csaba Cski, - - PowerPoint PPT Presentation
Dilatons and Fine Tuning John Terning, UC Davis with Csaba Cski, Brando Bellazzini, Jay Hubisz, Javi Serra hep-ph/1209.3299 and 1305.3919 dilaton potential f = 0 a > 0 Review of broken CFT s f = a < 0 A k 5 f =? New 5D
John Terning, UC Davis with Csaba Csáki, Brando Bellazzini, Jay Hubisz, Javi Serra hep-ph/1209.3299 and 1305.3919
a > 0
a < 0
a = 0 f = 0
f = ∞
f =?
Review of broken CFT’ s Reducing the cosmological constant New 5D Dual of a Spontaneously Broken CFT
16.0 16.5 17.0 17.5 18.0With a consistent effective theory up to scale µ, without tuning coefficients go like:
µ4 µ2 ln µ 1 µn g2 16π2 ✓ ◆ , , ,
O(1) < 1 (10 TeV)n (126 GeV)2 (10−12 GeV)4 L = Λ + m2H†H + Ld=4 + Ld=4+n
LHC understand the weak scale string theory unique vacuum ?
LHC understand the weak scale string theory unique vacuum ? find a bunch of new particles
LHC understand the weak scale string theory unique vacuum ? find a bunch of new particles a miracle occurs
LHC we don’ t understand the weak scale string theory
unusual vacuum
The Universe must be such that life can be advanced enough to contemplate the Universe and primitive enough to contemplate the anthropic principle.
terms can be forbidden to leading order Pseudo-Nambu-Goldstone bosons can have suppressed masses
supersymmetry
m2H†H Λ
little Higgs
X
extra dim. gauge
X
conformal
X X X X
we’ll explore spontaneously broken CFTs
Goldstone boson
σ(x) → σ(eαx) + αf hOi = f n f → f χ ≡ f eσ/f Leff = X
n,m>0
an,m (4π)2(n−1) f 2(n−2) ∂2nχm χ2n+m−4 = −a0,0 (4π)2f 4χ4 + f 2 2 (∂µχ)2 + a2,4 (4π)2 (∂χ)4 χ4 + . . .
non-linear realization a la Callan, Coleman, Wess, and Zumino
quartic coupling
a > 0
a < 0
a = 0 f = 0
f = ∞
f =? for exact conformal symmetry need a flat direction to have spontaneous breaking
Leff = −a0,0 (4π)2f 4χ4 + f 2 2 (∂µχ)2 + . . .
still need approximate flat direction QCD-like theories don’ t have light dilatons, Phys.Lett. B200 (1988) 338
f δL = λ(µ)O V = a f 4 → V = a(λ(f)) f 4 V 0 = f 3 [4a(λ(f)) + βa0(λ(f))] = 0 ' 4f 2βa0(λ(f)) = 16f 2a(λ(f)) m2
dil = f 2β [βa00 + 4a0 + β0a0]
= O(16π2)f 2
() = d d ln µ = ✏ + b1 4⇡ 2 + O3 a(λ) = (4π)2 " c0 + X
n
cn ✓ λ 4π ◆n# f ≈ µ0 ✓−16πc0 λ(µ0)c1 ◆1/✏ V 0 = f 3 [4a + βa0] ≈ (4π)2 f 3 4c0 + c1 4π λ0 ✓ f µ0 ◆✏
need a marginal operator, small function, and a tuned flat direction
β
Turn to the AdS/CFT correspondence
h e
R d4x φ0(x)O(x)iCFT ⇡ e−S5Dgrav[φ(x,z)|z=0=φ0(x)]
O ⊂ CFT ↔ φ AdS5 field, φ0(x) is boundary value ds2 = R2 z2
source
∆ = 2 + r 4 + m2 k2 φ = φ0 z4−∆ + c z∆
condensate
O has dimension ∆
CFT operator
how do we spontaneously break the CFT?
why is there a flat direction without SUSY?
IR UV W,Z e t
brane tensions
Veff = V0 + V1 ✓ R R0 ◆4 + Λ(5)R 1 − ✓ R R0 ◆4!
5D cosmo. constant UV cosmo. constant quartic coupling
Veff = V0 + Λ(5)R + f 4χ4 V1R4 − Λ(5)R5
this solution is not stable to perturbations
Csaki, Graesser, Kolda, JT hep-ph/9906513, hep-ph/9911406
brane potentials
m2 = −4 ✏ k2 ∆ ≈ 4 − ✏ φ = φ0 e✏ky V0 = λ0(φ − v0)2 V1 = λ1(φ − v1)2 λ0, λ1 → ∞ Veff = V0 + Λ(5)R + f 4χ4 V1R4 − Λ(5)R5
two fine tunings
ds2 = e−2A(y)dx2 − dy2
hep-ph/9907447
brane potentials
V0 = λ0(φ − v0)2 V1 = λ1(φ − v1)2
1 2 3 4 5 1 2 3 4 5 0.5 1 1.5 2 2.5 3
brane potentials
V0 = λ0(φ − v0)2 V1 = λ1(φ − v1)2
1 2 3 4 5 1 2 3 4 5 0.5 1 1.5 2 2.5 3
brane potentials
V0 = λ0(φ − v0)2 V1 = λ1(φ − v1)2
1 2 3 4 5 1 2 3 4 5 0.5 1 1.5 2 2.5 3
now we can parameterize a broken CFT
Riccardo Rattazzi perturbing the CFT and allowing sufficient running allows the IR brane to sit at a location with a vanishing c.c. Planck conference 2010
You can’ t have your cake and eat it too! Exact conformal symmetry can remove the c.c. but to have a unique vacuum it must be broken.
assuming we have fine-tuned the UV contributions
ds2 = e−2A(y)dx2 − dy2 A02 = κ2φ02 12 − κ2 6 V (φ) φ00 = 4A0φ0 + ∂V ∂φ Veff(y1) = e4A(y1) V1 (φ(y1)) + 6 κ2 A0(y1)
φ = φ0 e✏ky A = ky − κ2φ2 12
dominant balance
perturbative RG evolution
00 − 4A00 + 4✏k2 = 0 dominant balance
0.0 0.2 0.4 0.6 0.8 1.0 y y_c 2 4 6 8singularity at yc
A0(y) = −k coth (4k(y − yc)) φ(y) = c κ − √ 3 2κ log (tanh (2k(yc − y)))
Csaki, Erlich, Grojean, Hollowood hep-th/0004133
yc = 1 ✏k log c 0 − √ 3 20 log 1 − (0)4 1 + (0)4 ! φ(y) = φ0e✏ky − √ 3 2κ log [tanh (2k(yc − y))] − φ0e✏kyc + c κ
5 10 15 20 0.5 1.0 1.5 2.0A0(y) = k coth (4k(yc − y)) φ(y) = φ0 e✏ky − √ 3 2κ log (tanh (2k(yc − y))) Veff = e4A(y1) Λ1 + 6 κ2 A0(y1, yc)
V 0
eff = e4A(y1)
−4A0Vb + d dy1 Vb + dyc dy1 d dyc Vb
φ
potentially 24 orders of magnitude better than SUSY
V ∼ ✏ (TeV)4 m2
dil ∼ ✏ (TeV)2
A0(y) = k coth (4k(yc − y)) φ(y) = φ0 e✏ky − √ 3 2κ log (tanh (2k(yc − y)))
16.0 16.5 17.0 17.5 18.0
0.01 0.02 16.0 16.5 17.0 17.5 18.0
0.001 0.002
✏ = 0.01 ✏ = 0.001 Λ1 = 2ΛRS
You can’ t have your cake and eat it too! can remove the c.c. but to have a unique vacuum
✏ = 0 ✏ 6= 0 ✏ = 10−12 ?
we have a new 5D dual of a spontaneously broken CFT conformal symmetry is better than SUSY for reducing the cosmological constant but not nearly a solution by itself
is a massless Nambu-Goldstone boson
L = 1 2 ∂νφ ∂νφ hφi = v φ
SU(3) SU(2) U(1) U(1)R Q 1/3 1 L 1 1 3 U 1 4/3 8 D 1 2/3 4
W =
Λ7
3
det(QQ) + λ Q ¯
DL
⌧ V = | ∂W
∂Q |2 + | ∂W ∂U |2 + | ∂W ∂D |2 + | ∂W ∂L |2
⇡
Λ14
3
φ10 + λ Λ7
3
φ3 + λ2φ4
hφi = Λ3 λ1/7
SU(3) SU(2) U(1) U(1)R Q 1/3 1 L 1 1 3 U 1 4/3 8 D 1 2/3 4
mdil = λhφi = λ6/7Λ3 hφi = Λ3 λ1/7 Vmin ≈ λ2 < φ >4
invariance requires
x → x0 = eαx O(x) → O0(x) = eα∆O(eαx) S = X
i
Z d4x giOi(x) − → S0 = X
i
Z d4xeα(∆i4)giOi(x) ∆i = 4
Sydney Coleman, “Aspects of Symmetry” see also Ian Low, hep-th/0110285
Mµν = −i(xµ∂ν − xν∂µ) Pµ = −i∂µ Kµ = −i(x2∂µ − 2xµxα∂α) D = ixα∂α