Diffraction Theory
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Diffraction Theory 1 2 , 2 4 3 5 1 + 2 - - PowerPoint PPT Presentation
Diffraction Theory 1 2 , 2 4 3 5 1 + 2 , + 5 , , = 1 , + 3 , + 4 , + =
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2
3
π
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π 2 πΉ Τ¦ π , π’ = πΉ1 Τ¦ π , π’ πΉ Τ¦ π , π’
πΉ Τ¦ π , π’ =
πΉ0,1 π 1 ππ π π 1β π π’ + π1 + πΉ0,2
π 2 ππ π π 2β π π’ + π2
+ πΉ2 Τ¦ π , π’ π 3
+ πΉ0,3 π 3 ππ π π 3 β π π’ + π3
π
4
+ πΉ3 Τ¦ π , π’ + πΉ4 Τ¦ π , π’ π 5
+ πΉ0,4 π
4
ππ π π 4 β π π’ + π4
+ πΉ5 Τ¦ π , π’
+ πΉ0,5 π 5 ππ π π 5 β π π’ + π5
= ΰ·
π
πΉπ Τ¦ π , π’
+ β―
+ β¦
= ΰ·
π
πΉ0,π π π ππ π π π βπ π’ + ππ
4
5
πΉ π, π, π’ = ΰ·
π
πΉ0,π π
π
ππ π π π β π π’ + ππ = ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ π π§, π¨ ππ π π π§, π¨ β π π’ + π π§, π¨ ππ§ ππ¨
π π§, π¨ = π‘2 + π β π§ 2 + π β π¨ 2 π π‘ π π π¨ π§
π π§, π¨
ΰ·
π
ΰΆ΅
ππππ π’π£π π
ππ§ ππ¨
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π π§, π¨ β π‘ 1 + π2 2 Fresnel Approximation π π‘ πππ¦ π4 8 βͺ π = π‘ 1 + π2 2 β π4 8 + π6 16 β 5 π8 128 + β― π π§, π¨ = π‘2 + π β π§ 2 + π β π¨ 2 = π‘ 1 + π β π§ 2 π‘2 + π β π¨ 2 π‘2 = π‘ 1 + π2 π2 β‘ π β π§ 2 π‘2 + π β π¨ 2 π‘2
= π‘ + π2 + π2 2 π‘ β π π§ + π π¨ π‘ + π§2 + π¨2 2 π‘ = π‘ 1 + π β π§ 2 2 π‘2 + π β π¨ 2 2 π‘2
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π π§, π¨ β π‘ + π2 + π2 2 π‘ β π π§ + π π¨ π‘ + π§2 + π¨2 2 π‘ Fresnel Approximation π π‘ πππ¦ π4 8 βͺ π
πΉ π, π, π’ = ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ π π§, π¨ ππ π π π§, π¨ β π π’ + π π§, π¨ ππ§ ππ¨
β ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ π‘ ππ π
π‘ + π2+π2 2 π‘ β π π§+π π¨ π‘ + π§2+π¨2 2 π‘ β π π’ + π π§, π¨
ππ§ ππ¨
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π πππ¦ π§2 + π¨2 2 π‘ βͺ π πππ¦ π§2 + π¨2 π π‘ βͺ 1 Fraunhofer Approximation
also known as Far-Field Diffraction π π§, π¨ β π‘ + π2 + π2 2 π‘ β π π§ + π π¨ π‘ + π§2 + π¨2 2 π‘ Fresnel Approximation π π‘ πππ¦ π4 8 βͺ π In addition to Fresnel Approximation:
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πΉ π, π, π’ = ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ π π§, π¨ ππ π π π§, π¨ β π π’ + π π§, π¨ ππ§ ππ¨ β ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ π π
π π π β π π§ + π π¨ π β π π’ + π π§, π¨
ππ§ ππ¨ = ππ π π βπ π’ π ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ ππ π π§,π¨ πβ π π π π§ + π π¨
π
ππ§ ππ¨
π π§, π¨ = π‘2 + π β π§ 2 + π β π¨ 2 π2 β‘ π‘2 + π2 + π2 = π2 β 2 π π§ β 2 π π¨ + π§2 + π¨2 = π 1 + β2 π π§ β 2 π π¨ + π§2 + π¨2 π2 β π β π π§ + π π¨ π
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πΉ π, π, π’ = ππ π π βπ π’ π ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ ππ π π§, π¨ πβ π π π π§ + π π¨
π
ππ§ ππ¨
π π‘ π π π¨ π§ π
π2 β‘ π‘2 + π2 + π2
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In the examples to follow, we will consider a flat wavefront at normal incidence on the aperture
πΉ0 π§, π¨ ππ π π§, π¨ = πΉ0
πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π ΰΆ΅
ππππ π’π£π π
πβ π π π π§ + π π¨
π
ππ§ ππ¨
Inside the aperture Outside the aperture
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π π‘ π π π¨ π§ π π β‘ π2 + π‘2 π
πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π ΰΆ±
β ΰ΅ π 2 + ΰ΅ π 2
πβ π π π
π π§ππ§
π π‘ππ π = π π π§ π¨
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πΉ π, π, π’ = πΉ0 ππ π π β π π’ π π π‘πππ π π π 2 π
π½ β‘ πΉ
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π½ π, π = π½0 π‘πππ2 π π π 2 π π½0 β‘ πΉ0 2 2 π2 π2
π = 50 Β΅π π = 0.6 Β΅π π‘ = 1 π
π π
π π
2 π = π π
π = Β±1, Β±2, Β±3 π β 1 π
π
π = π π π
π π‘ππ ππ = π
π
π = π π π π(ππ) π
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ΰ΅ π½ π½0 zeros at
geometrical shadow
π
β1
with π π
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π π π π§
ΰ΅ π 2 β ΰ΅ π 2 ΰ΅ π 2 + ΰ΅ π 2 ΰ΅ βπ 2 β ΰ΅ π 2 ΰ΅ βπ 2 + ΰ΅ π 2
π¨
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π π‘ π π π¨ π§ π π β‘ π2 + π‘2
πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π ΰΆ±
ΰ΅ βπ 2β ΰ΅ π 2 ΰ΅ βπ 2+ ΰ΅ π 2
πβ π π π
π π§ππ§ +
ΰΆ±
ΰ΅ π 2β ΰ΅ π 2 ΰ΅ π 2+ ΰ΅ π 2
πβ π π π
π π§ππ§
π π‘ππ π = π π
= πΉ0 ππ π π βπ π’ π π π‘πππ π π π 2 π 2 πππ‘ π π π 2 π
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πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π π π‘πππ π π π 2 π 2 πππ‘ π π π 2 π π½ π, π = 4 π½0 π‘πππ2 π π π 2 π πππ‘2 π π π 2 π
π½0 β‘ πΉ0 2 2 π2 π2
Mathematica
π π
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π π π§ π¨
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πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π ΰΆ΅
ππππ π’π£π π
πβ π π π π§ + π π¨
π
ππ§ ππ¨ = πΉ0 ππ π π βπ π’ π ΰΆ±
ΰ΅ βπ 2 ΰ΅ π 2
πβ π π π
π π§ππ§
ΰΆ±
ΰ΅ βπ 2 ΰ΅ π 2
πβ π π π
π π¨ππ¨
= πΉ0 ππ π π βπ π’ π π π‘πππ π π π 2 π π π‘πππ π π π 2 π
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π π
π½ π, π = π½0 π‘πππ2 π π π 2 π π‘πππ2 π π π 2 π
π½0 β‘ πΉ0 2 2 π2 π2 π2
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π π
π§ = π π‘ππ π
π
π¨ = π πππ‘ π
π¨ π§
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Ξ¦
π = π π‘ππ Ξ¦
π
π = π πππ‘ Ξ¦
π π
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πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π ΰΆ΅
ππππ π’π£π π
πβ π π π π§ + π π¨
π
ππ§ ππ¨
π π§ + π π¨ = π π‘ππ Ξ¦ π π‘ππ π + π πππ‘ Ξ¦ π πππ‘ π
= π π πππ‘ π β Ξ¦ ππ§ ππ¨ = π ππ ππ
πΉ π, Ξ¦, π’ = πΉ0 ππ π π βπ π’ π ΰΆ±
π
π ππ ΰΆ±
2π
ππ π β π π π π πππ‘ π β Ξ¦
π Ξ¦ = 0 Due to axial symmetry, we can choose:
= π π πππ‘ Ξ¦ πππ‘ π + π‘ππ Ξ¦ π‘ππ π
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πΉ π, Ξ¦, π’ = πΉ0 ππ π π βπ π’ π ΰΆ±
π
π ππ ΰΆ±
2π
ππ π β π π π π πππ‘ π
π
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1 2 π ΰΆ±
2π
ππ ππ π£ πππ‘ π β‘ πΎ0 π£
Bessel function
πΉ π, Ξ¦, π’ = πΉ0 ππ π π βπ π’ π ΰΆ±
π
π ππ ΰΆ±
2π
ππ π β π π π π πππ‘ π
π
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πΉ π, Ξ¦, π’ = πΉ0 ππ π π β π π’ π 2 π ΰΆ±
π
π ππ πΎ0 β π π π π π£ β‘ β π π π π = πΉ0 ππ π π β π π’ π 2 π π π π
2
ΰΆ±
βπ π π π
Ξ± πΞ± πΎ0 Ξ±
π½ β‘ βπ π π π π ππ = π π π
2
Ξ± πΞ±
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ΰΆ±
π½
π½ πΎ0 π½ ππ½ β‘ π½ πΎ1 π½
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πΉ π, Ξ¦, π’ = πΉ0 ππ π π β π π’ π 2 π π π π
2
ΰΆ±
βπ π π π
Ξ± πΞ± πΎ0 Ξ± = πΉ0 ππ π π β π π’ π 2 π π π π
2 βπ π π
π πΎ1 βπ π π π = πΉ0 ππ π π β π π’ π π π2 2 πΎ1 π π π π π π π π
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π½ π, Ξ¦ = π½0 2 πΎ1 π π π π π π π π
2
π½0 β‘ πΉ0 2 2 π2 π π2 2
π π π π ΰ΅ π½ π½0
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zeros at
π π π π = 3.832, 7.016, 10.173, β¦
π π π1 π = 3.832 π1 π = π‘ππ π1 = 3.832 π 2 π π = 1.22 π 2 π first zero at Light is essentially confined inside the cone: πππ π1 < π. ππ π
π π
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π¨ π§ π‘ π§ π π π π‘ππ π1 = π1 π = 1.22 π 2 π π 2π
Airyβs pattern
π π1 π1 π1
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π¨ π§ 2π π‘ π π1
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π§ 2π π1 π1 π‘ππ π1 = 1.22 π 2 π tan π1 = π1 π π1 π1 β 1.22 π π 2 π π
Smallest spot size:
π1 β 1.22 π π πΈππππ‘ πΈππππ‘ = 1.22 ππ π π πΈππππ‘ π
Smallest angular width:
π1 π = 1.22 ππ π πΈππππ‘
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Diameter of primary mirror 2.4 m Wavelength 0.55 Β΅m Angular width 0.28 Γ 10-6 rad
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π’ππ ππππ¦ β‘ πΈππππ‘ 2 π πΈππππ‘ ππππ¦
ππ΅ β‘ π π‘ππ ππππ¦ β π πΈππππ‘ 2 π
π
π # = π πΈππππ‘
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ππ΅ β‘ π π‘ππ ππππ¦
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π1 = 1.22 ππ 2 ππ΅
π§ 2π = πΈππππ‘ π1 π1 π1 π πΈππππ‘ π π1 = 1.22 ππ π π πΈππππ‘ ππ΅ β‘ π π‘ππ ππππ¦ β π πΈππππ‘ 2 π
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Barely resolved Resolved Not resolved
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π1 = 1.22 ππ 2 ππ΅ ππ = 0.55 ππ 3.36 ππ 1.34 ππ 0.52 ππ 0.27 ππ
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πΉ π, π, π’ = ππ π π βπ π’ π ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ ππ π π§, π¨ πβ π π π π§ + π π¨
π
ππ§ ππ¨ π π‘ π π π¨ π§ π π β‘ π2 + π2 + π‘2
πππ¦ π§2 + π¨2 π π‘ βͺ 1 πππ¦ π β π§ 2 + π β π¨ 2 π π‘ βͺ 1
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πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π π π‘πππ π π π 2 π πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π π π‘πππ π π π 2 π 2 πππ‘ π π π 2 π πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π π π‘πππ π π π 2 π π π‘πππ π π π 2 π πΉ π, Ξ¦, π’ = πΉ0 ππ π π βπ π’ π π π2 2 πΎ1 π π π π π π π π
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πΉ π, π, π’ = ππ π π β π π’ π ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ ππ π π§, π¨ πβ π π π π§ + π π¨
π
ππ§ ππ¨ πΉ π, π, π’ = ππ π π β π π’ π ΰΆ΅
ββ +β
π π§, π¨ πβ π ππ§ π§ +ππ¨ π¨ ππ§ ππ¨ π π§, π¨ β‘ πΉ0 π§, π¨ ππ π π§, π¨ inside aperture
ππ§ β‘ π π π
ππ¨ β‘ π π π
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π π π§
π β π 2 π + π 2
π¨ πΆ (infinitely long) slits of width π separated by distance π
+ π 2 β π 2 π β 1 π β π 2 π β 1 π + π 2
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π π‘ π π π¨ π§ π π β‘ π2 + π‘2
πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π ΰΆ±
β π 2 + π 2
+ ΰΆ±
π β π 2 π + π 2
+ ΰΆ±
2 π β π 2 2 π + π 2
+ β― + ΰΆ±
πβ1 π β π 2 πβ1 π + π 2
πβ π π π
π π§ ππ§
π π‘ππ π = π π
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πΉ π, π, π’ = πΉ0 ππ π π βπ π’ π π π‘πππ π π π 2 π ΰ·
π = 0 πβ1
πβ π π π π
π π
= πΉ0 ππ π π βπ π’ π π π‘πππ π π π 2 π 1 β πβπ π π π π
π
1 β πβπ π π π
π
= πΉ0 ππ π π βπ π’ π π π‘πππ π π π 2 π πβπ π π π π
2 π
πβπ π π π
2 π
π+π π π π π
2 π β πβπ π π π π 2 π
π+π π π π
2 π β πβπ π π π 2 π
= πΉ0 ππ π π βπ π’ π π π‘πππ π π π 2 π πβπ π π π π
2 π
πβπ π π π
2 π
sin π π π π 2 π sin π π π 2 π
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π½ π, π = π½0 π‘πππ2 π π π 2 π π‘ππ2 π π π π 2 π π‘ππ2 π π π 2 π π½0 β‘ πΉ0 2 2 π2 π2
π = 1 π = 4 π = 1 π = 1
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π‘πππ2 π π π 2 π β 1
π½ π, π β π½0 π‘ππ2 π π π π 2 π π‘ππ2 π π π 2 π
π = 0.1 π = 4 π = 1 π = 1
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π π π 2 π = π π π½ π, π, π’ = π2 π½0
π = 0, Β±1, Β±2, β¦ π π‘ππ ππ = π π grating equation grating
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π π π π 2 π = π π π = 1, 2, 3, β¦ , (π β 1)
π π π 2 π = π π π
π = 0.1 π = 4 π = 1 π = 1 0 < π π π 2 π < π π = 0 π = 1 1 β1 π 2 β2 π½ π, π β π½0 π‘ππ2 π π π π 2 π π‘ππ2 π π π 2 π
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π π π‘ππ ππ + βπ 2 2 = π π + 1 π π π π π 2 π = π π π‘ππ π 2 βπ = 2 π π π πππ‘ ππ π π πππ‘ ππ π‘ππ βπ 2 2 β 1 π π
π
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π π‘ππ ππ = π π π πππ‘ ππ ππ = π ππ βππ ππ‘ = π π π ππ β‘ βπ 2 = π π π πππ‘ ππ ππ β‘ βππ ππ‘
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π π‘ππ π = π + 1 π = π π + βππΊππ βππΊππ = π π
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π π‘ππ π β π π‘ππ ππππ = π π π π‘ππ ππ β π‘ππ ππππ = π π π π‘ππ ππ = π π
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Going beyond the Fraunhofer (far-field) approximation
getting closer to the aperture
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π π§, π¨ = π‘2 + π β π§ 2 + π β π¨ 2 π π‘ π π π¨ π§ π π§, π¨ β π‘ + 1 2 π‘ π β π§ 2 + 1 2 π‘ π β π¨ 2
πΉ π, π, π’ = ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ π π§, π¨ ππ π π π§, π¨ β π π’ + π π§, π¨ ππ§ ππ¨
= π‘ 1 + π β π§ 2 π‘2 + π β π¨ 2 π‘2 π π‘ πππ¦ π β π§ 2 + π β π¨ 2 2 π‘4 βͺ π
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πΉ π, π, π’ = ππ π π‘ β π π’ π‘ ΰΆ΅
ππππ π’π£π π
πΉ0 π§, π¨ ππ π π§, π¨ ππ π
2 π‘ πβπ§ 2+ πβπ¨ 2 ππ§ ππ¨
πΉ π, π, π’ = πΉ0 ππ π π‘ β π π’ π‘ ΰΆ΅
ππππ π’π£π π
ππ π
π π‘ πβπ§ 2+ πβπ¨ 2 ππ§ ππ¨
πΉ0 π§, π¨ ππ π π§, π¨ = πΉ0 Inside the aperture Outside the aperture
Flat Wavefront Illumination
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πΏ β‘ 2 π π‘ π β π§ ππ§ = β π π‘ 2 ππΏ π β‘ 2 π π‘ π β π¨ ππ¨ = β π π‘ 2 ππ πΉ π, π, π’ = πΉ0 ππ π π‘ β π π’ π‘ ΰΆ΅
ππππ π’π£π π
ππ π
π π‘ πβπ§ 2+ πβπ¨ 2 ππ§ ππ¨
= πΉ0 ππ π π‘ β π π’ π‘ π π‘ 2 ΰΆ΅
ππππ π’π£π π
ππ π
2 πΏ2+ π2 ππΏ ππ
= π πΉ0 ππ π π‘ β π π’ 2 ΰΆ±
πΏ1 πΏ2
ππ π
2 πΏ2 ππΏ ΰΆ± π1 π2
ππ π
2 π2 ππ
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ΰΆ±
πΏ1 πΏ2
ππ π
2 πΏ2 ππΏ = ΰΆ± πΏ1 πΏ2
cos π 2 πΏ2 ππΏ + π ΰΆ±
πΏ1 πΏ2
sin π 2 πΏ2 ππΏ = π πΏ2 β π πΏ1 + π π― πΏ2 β π― πΏ1 ΰΆ±
π1 π2
ππ π
2 π2 ππ
= ΰΆ±
π1 π2
cos π 2 π2 ππ + π ΰΆ±
π1 π2
sin π 2 π2 ππ = π π2 β π π1 + π π― π2 β π― π1 π π¦ β‘ ΰΆ±
π¦
cos π 2 π¦2 ππ¦ π― π¦ β‘ ΰΆ±
π¦
sin π 2 π¦2 ππ¦
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Γ π πΏ2 β π πΏ1 + π π― πΏ2 β π― πΏ1 Γ π π2 β π π1 + π π― π2 β π― π1 πΉ π, π, π’ = π πΉ0 ππ π π‘ β π π’ 2 π½ π, π = π½0 4 Γ π πΏ2 β π πΏ1
2 + π― πΏ2 β π― πΏ1 2
Γ π π2 β π π1
2 + π― π2 β π― π1 2
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π π¦ β‘ ΰΆ±
π¦
cos π 2 π¦β²2 ππ¦β² π― π¦ β‘ ΰΆ±
π¦
sin π 2 π¦β²2 ππ¦β²
π π¦ π― π¦ π¦ π¦ π¦ π π¦ π― π¦
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π π¦ β‘ ΰΆ±
π¦
cos π 2 π¦2 ππ¦ π― π¦ β‘ ΰΆ±
π¦
sin π 2 π¦2 ππ¦ ππ π¦ = cos π 2 π¦2 ππ¦ ππ― π¦ = sin π 2 π¦2 ππ¦
π― π¦ π π¦
ππ 2 + ππ― 2 = ππ¦ 2
ππ ππ― ππ¦
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1.No obstruction 2.Straight edge
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π½ π, π = π½0 4 Γ π πΏ2 β π πΏ1
2 + π― πΏ2 β π― πΏ1 2
Γ π π2 β π π1
2 + π― π2 β π― π1 2
πΏ β‘ 2 π π‘ π β π§ π β‘ 2 π π‘ π β π¨
π§ π¨ πΏ2 = ββ πΏ1 = +β π2 = ββ π1 = +β
= π½0 4 Γ β0.5 β 0.5 2 + β0.5 β 0.5 2 Γ β0.5 β 0.5 2 + β0.5 β 0.5 2
= π½0
No surprises here, just the obvious result !!
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π½ π, π = π½0 4 Γ π πΏ2 β π πΏ1
2 + π― πΏ2 β π― πΏ1 2
Γ π π2 β π π1
2 + π― π2 β π― π1 2
πΏ β‘ 2 π π‘ π β π§ π β‘ 2 π π‘ π β π¨
π§ π¨ πΏ2 =
2 π π‘ π
πΏ1 = +β π2 = ββ π1 = +β
= π½0 4 Γ π 2 π π‘ π β 0.5
2
+ π― 2 π π‘ π β 0.5
2
Γ 2
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π― π¦ π π¦ π = 0 π > 0 π < 0 π½ π, π, π’ /π½0 π π π‘ = 2 π½ π, π = π½0 2
Γ π 2 π π‘ π β 0.5
2
+ π― 2 π π‘ π β 0.5
2
69
70
π½ π, π = π½0 4 Γ π πΏ2 β π πΏ1
2 + π― πΏ2 β π― πΏ1 2
Γ π π2 β π π1
2 + π― π2 β π― π1 2
πΏ β‘ 2 π π‘ π β π§ π β‘ 2 π π‘ π β π¨
π§ π¨ πΏ2 = 2 π π‘ π β π
2
πΏ1 = 2 π π‘ π + π
2
π2 = ββ π1 = +β
= π½0 4
Γ π 2 π π‘ π β π
2
β π 2 π π‘ π + π
2 2
+ π― 2 π π‘ π β π
2
β π― 2 π π‘ π + π
2 2
Γ 2
π
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π― π¦ π π¦ π = 0 π > 0 π < 0 π½ π, π = π½0 2
Γ π 2 π π‘ π β π
2
β π 2 π π‘ π + π
2 2
+ π― 2 π π‘ π β π
2
β π― 2 π π‘ π + π
2 2
πΏ1 β πΏ2 = 2 π π‘ π πΏ1 + πΏ2 2 = 2 π π‘ π
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π = 10 π π ππΊ β‘ π2 4 π π‘ ππΊ = 10 ππΊ = 1 ππΊ = 0.5 ππΊ = 0.1 π = 1 π‘ = 2.5 π π‘ = 25 π π‘ = 50 π π‘ = 250 π Near field Far field Fresnel number
73
74
75
Poisson (Arago) spot