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Content Mixing of neutral B mesons. Gilberto Tetlalmatzi (IPPP - - PowerPoint PPT Presentation

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New Physics in d Gilberto Tetlalmatzi IPPP Durham University gilberto.tetlalmatzi-xolocotz@durham.ac.uk October 31, 2014 Gilberto Tetlalmatzi (IPPP Durham) New Physics in d October 31, 2014 1 / 23 Content Mixing of neutral B

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SLIDE 1

New Physics in ∆Γd

Gilberto Tetlalmatzi

IPPP Durham University gilberto.tetlalmatzi-xolocotz@durham.ac.uk

October 31, 2014

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 1 / 23

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SLIDE 2

Content

Mixing of neutral B mesons.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 2 / 23

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SLIDE 3

Content

Mixing of neutral B mesons. The observables ∆Γd,s.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 2 / 23

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SLIDE 4

Content

Mixing of neutral B mesons. The observables ∆Γd,s. How big can ∆Γd be?.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 2 / 23

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SLIDE 5

Content

Mixing of neutral B mesons. The observables ∆Γd,s. How big can ∆Γd be?. CKM unitarity violations.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 2 / 23

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SLIDE 6

Content

Mixing of neutral B mesons. The observables ∆Γd,s. How big can ∆Γd be?. CKM unitarity violations. Current-current operators.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 2 / 23

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SLIDE 7

Content

Mixing of neutral B mesons. The observables ∆Γd,s. How big can ∆Γd be?. CKM unitarity violations. Current-current operators. (b¯ d)(ττ)operators

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 2 / 23

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SLIDE 8

Content

Mixing of neutral B mesons. The observables ∆Γd,s. How big can ∆Γd be?. CKM unitarity violations. Current-current operators. (b¯ d)(ττ)operators Like-sign dimuon asymmetry.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 2 / 23

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SLIDE 9

Content

Mixing of neutral B mesons. The observables ∆Γd,s. How big can ∆Γd be?. CKM unitarity violations. Current-current operators. (b¯ d)(ττ)operators Like-sign dimuon asymmetry. Conclusions

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 2 / 23

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SLIDE 10

Mixing of neutral B mesons

Bd = {¯ b, d}

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 3 / 23

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SLIDE 11

Mixing of neutral B mesons

Bd = {¯ b, d} ¯ Bd = {b, ¯ d}

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 3 / 23

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SLIDE 12

Mixing of neutral B mesons

Bd = {¯ b, d} ¯ Bd = {b, ¯ d} i d dt

  • |Bd
  • ¯

Bd

  • = Σd
  • |Bd
  • ¯

Bd

  • Gilberto Tetlalmatzi (IPPP Durham)

New Physics in ∆Γd October 31, 2014 3 / 23

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SLIDE 13

Mixing of neutral B mesons

Bd = {¯ b, d} ¯ Bd = {b, ¯ d} i d dt

  • |Bd
  • ¯

Bd

  • = Σd
  • |Bd
  • ¯

Bd

  • Σq = Mq − i

2Γq; Mq and Γq are hermitian matrices. Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 3 / 23

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SLIDE 14

Mixing of neutral B mesons

Bd = {¯ b, d} ¯ Bd = {b, ¯ d} i d dt

  • |Bd
  • ¯

Bd

  • = Σd
  • |Bd
  • ¯

Bd

  • Σq = Mq − i

2Γq; Mq and Γq are hermitian matrices. Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 3 / 23

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SLIDE 15

Mixing of neutral B mesons

Bd = {¯ b, d} ¯ Bd = {b, ¯ d} i d dt

  • |Bd
  • ¯

Bd

  • = Σd
  • |Bd
  • ¯

Bd

  • Σq = Mq − i

2Γq; Mq and Γq are hermitian matrices.

Bd ⇐ ⇒ ¯ Bd

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 3 / 23

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SLIDE 16

Mixing of neutral B mesons

Bd = {¯ b, d} ¯ Bd = {b, ¯ d} i d dt

  • |Bd
  • ¯

Bd

  • = Σd
  • |Bd
  • ¯

Bd

  • Σq = Mq − i

2Γq; Mq and Γq are hermitian matrices.

Bd ⇐ ⇒ ¯ Bd (Bs ⇐ ⇒ ¯ Bs)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 3 / 23

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SLIDE 17

Mixing of neutral B mesons

Bd = {¯ b, d} ¯ Bd = {b, ¯ d} i d dt

  • |Bd
  • ¯

Bd

  • = Σd
  • |Bd
  • ¯

Bd

  • Σq = Mq − i

2Γq; Mq and Γq are hermitian matrices.

Bd ⇐ ⇒ ¯ Bd (Bs ⇐ ⇒ ¯ Bs) Σ =

  • M11 − iΓ11

2

M12 − iΓ12

2

M∗

12 − iΓ∗

12

2

M11 − iΓ11

2

  • Gilberto Tetlalmatzi (IPPP Durham)

New Physics in ∆Γd October 31, 2014 3 / 23

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SLIDE 18

Mixing of neutral B mesons

Bd = {¯ b, d} ¯ Bd = {b, ¯ d} i d dt

  • |Bd
  • ¯

Bd

  • = Σd
  • |Bd
  • ¯

Bd

  • Σq = Mq − i

2Γq; Mq and Γq are hermitian matrices.

Bd ⇐ ⇒ ¯ Bd (Bs ⇐ ⇒ ¯ Bs) Σ =

  • M11 − iΓ11

2

M12 − iΓ12

2

M∗

12 − iΓ∗

12

2

M11 − iΓ11

2

  • Γ12

On-shell M12 Off-shell

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 3 / 23

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SLIDE 19

Mixing of neutral B mesons

Eigenvalues of Σ: λL = ML − i

2 ΓL

λH = MH − i

2ΓH Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 4 / 23

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SLIDE 20

Mixing of neutral B mesons

Eigenvalues of Σ: λL = ML − i

2 ΓL

λH = MH − i

2ΓH

∆M = MH − ML ∆Γ = ΓH − ΓL φ ≡ arg

  • − M12

Γ12

  • Gilberto Tetlalmatzi (IPPP Durham)

New Physics in ∆Γd October 31, 2014 4 / 23

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SLIDE 21

Mixing of neutral B mesons

Eigenvalues of Σ: λL = ML − i

2 ΓL

λH = MH − i

2ΓH

∆M = MH − ML ∆Γ = ΓH − ΓL φ ≡ arg

  • − M12

Γ12

  • ∆M

≈ 2|M12| asl =

  • Γ12

M12

  • sin(φ)

∆Γ ≈ 2|Γ12|cos(φ)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 4 / 23

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SLIDE 22

The observables ∆Γd,s

Experimental results vs theoretical prediction for ∆Γs:

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 5 / 23

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SLIDE 23

The observables ∆Γd,s

Experimental results vs theoretical prediction for ∆Γs: ∆ΓHFAG

s

= (0.081 ± 0.011) ps−1(LHCb(2013), ATLAS(2012), CDF (2012) and D0 (2012)).

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 5 / 23

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SLIDE 24

The observables ∆Γd,s

Experimental results vs theoretical prediction for ∆Γs: ∆ΓHFAG

s

= (0.081 ± 0.011) ps−1(LHCb(2013), ATLAS(2012), CDF (2012) and D0 (2012)). ∆ΓTheo

s

= (0.087 ± 0.021) ps−1(A. Lenz and U. Nierste, arXiv:1102.4274).

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 5 / 23

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SLIDE 25

The observables ∆Γd,s

Experimental results vs theoretical prediction for ∆Γs: ∆ΓHFAG

s

= (0.081 ± 0.011) ps−1(LHCb(2013), ATLAS(2012), CDF (2012) and D0 (2012)). ∆ΓTheo

s

= (0.087 ± 0.021) ps−1(A. Lenz and U. Nierste, arXiv:1102.4274). Experimental results vs theoretical prediction for ∆Γd:

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 5 / 23

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SLIDE 26

The observables ∆Γd,s

Experimental results vs theoretical prediction for ∆Γs: ∆ΓHFAG

s

= (0.081 ± 0.011) ps−1(LHCb(2013), ATLAS(2012), CDF (2012) and D0 (2012)). ∆ΓTheo

s

= (0.087 ± 0.021) ps−1(A. Lenz and U. Nierste, arXiv:1102.4274). Experimental results vs theoretical prediction for ∆Γd: ∆ΓHFAG

d

Γd = (1.5 ± 1.8)%(BABAR(2006) and Belle(2012)). ∆ΓD0

d

Γd = (0.50 ± 1.38)%(2014). ∆ΓLHCb

d

Γd = (−4.4 ± 2.7)%(2014).

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 5 / 23

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SLIDE 27

The observables ∆Γd,s

Experimental results vs theoretical prediction for ∆Γs: ∆ΓHFAG

s

= (0.081 ± 0.011) ps−1(LHCb(2013), ATLAS(2012), CDF (2012) and D0 (2012)). ∆ΓTheo

s

= (0.087 ± 0.021) ps−1(A. Lenz and U. Nierste, arXiv:1102.4274). Experimental results vs theoretical prediction for ∆Γd: ∆ΓHFAG

d

Γd = (1.5 ± 1.8)%(BABAR(2006) and Belle(2012)). ∆ΓD0

d

Γd = (0.50 ± 1.38)%(2014). ∆ΓLHCb

d

Γd = (−4.4 ± 2.7)%(2014). ∆ΓTheo

d

Γd = (0.42 ± 0.08)%(A. Lenz and U. Nierste, arXiv:1102.4274).

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 5 / 23

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SLIDE 28

How big can ∆Γd be?

Enhancements in ∆Γd arise from:

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 6 / 23

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SLIDE 29

How big can ∆Γd be?

Enhancements in ∆Γd arise from:

1

CKM Unitarity violations.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 6 / 23

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SLIDE 30

How big can ∆Γd be?

Enhancements in ∆Γd arise from:

1

CKM Unitarity violations.

2

New Physics at tree level decays.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 6 / 23

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SLIDE 31

How big can ∆Γd be?

Enhancements in ∆Γd arise from:

1

CKM Unitarity violations.

2

New Physics at tree level decays.

3

(¯ db)(¯ ττ) operators.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 6 / 23

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SLIDE 32

CKM Unitarity Violations

NP contributions on ∆Γd can be introduced through unitarity violations of the CKM matrix

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 7 / 23

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SLIDE 33

CKM Unitarity Violations

NP contributions on ∆Γd can be introduced through unitarity violations of the CKM matrix let λu = V ∗

udVub, λc = V ∗ cdVcb, λt = V ∗ tdVtb. Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 7 / 23

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SLIDE 34

CKM Unitarity Violations

NP contributions on ∆Γd can be introduced through unitarity violations of the CKM matrix let λu = V ∗

udVub, λc = V ∗ cdVcb, λt = V ∗ tdVtb.

In the SM: λu + λc + λt = 0

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 7 / 23

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SLIDE 35

CKM Unitarity Violations

NP contributions on ∆Γd can be introduced through unitarity violations of the CKM matrix let λu = V ∗

udVub, λc = V ∗ cdVcb, λt = V ∗ tdVtb.

In the SM: λu + λc + λt = 0 λu + λc + λt + δCKM = 0

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 7 / 23

slide-36
SLIDE 36

CKM Unitarity Violations

NP contributions on ∆Γd can be introduced through unitarity violations of the CKM matrix let λu = V ∗

udVub, λc = V ∗ cdVcb, λt = V ∗ tdVtb.

In the SM: λu + λc + λt = 0 λu + λc + λt + δCKM = 0 As a very rough estimate (4th family studies) δd

CKM

= λ3 δs

CKM

= λ3 λ ≈ 0.23

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 7 / 23

slide-37
SLIDE 37

CKM Unitarity Violations

NP contributions on ∆Γd can be introduced through unitarity violations of the CKM matrix let λu = V ∗

udVub, λc = V ∗ cdVcb, λt = V ∗ tdVtb.

In the SM: λu + λc + λt = 0 λu + λc + λt + δCKM = 0 As a very rough estimate (4th family studies) δd

CKM

= λ3 δs

CKM

= λ3 λ ≈ 0.23 = ⇒ enhancement by a factor of 4 in ∆Γd = ⇒ enhancement by a factor of 1.4 in ∆Γs.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 7 / 23

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SLIDE 38

How big can ∆Γd be?

Enhancements in ∆Γd arise from:

1

CKM Unitarity violations.

2

New Physics at tree level decays.

3

(¯ db)(¯ ττ) operators.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 8 / 23

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SLIDE 39

New Physics at tree level decays.

The effective Hamiltonian approach g2 2 √ 2 2 1 k2 − M2

W

≈ − g2 2 √ 2 2 1 M2

W

≡ GF √ 2

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 9 / 23

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SLIDE 40

New Physics at tree level decays.

The effective Hamiltonian approach g2 2 √ 2 2 1 k2 − M2

W

≈ − g2 2 √ 2 2 1 M2

W

≡ GF √ 2

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 9 / 23

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SLIDE 41

New Physics at tree level decays.

The effective Hamiltonian approach g2 2 √ 2 2 1 k2 − M2

W

≈ − g2 2 √ 2 2 1 M2

W

≡ GF √ 2 Qqq′

2

= ¯ diγµPLqi ¯ q′

j γµPLbj

  • Gilberto Tetlalmatzi (IPPP Durham)

New Physics in ∆Γd October 31, 2014 9 / 23

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SLIDE 42

New Physics at tree level decays.

The effective Hamiltonian approach g2 2 √ 2 2 1 k2 − M2

W

≈ − g2 2 √ 2 2 1 M2

W

≡ GF √ 2 Qqq′

2

= ¯ diγµPLqi ¯ q′

j γµPLbj

  • QCD corrections

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 9 / 23

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SLIDE 43

New Physics at tree level decays.

The effective Hamiltonian approach g2 2 √ 2 2 1 k2 − M2

W

≈ − g2 2 √ 2 2 1 M2

W

≡ GF √ 2 Qqq′

2

= ¯ diγµPLqi ¯ q′

j γµPLbj

  • QCD corrections

After integrating out the W boson we get: Qqq′

1

= ¯ djγµPLqi ¯ q′

i γµPLbj

  • Gilberto Tetlalmatzi (IPPP Durham)

New Physics in ∆Γd October 31, 2014 9 / 23

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SLIDE 44

New Physics at tree level decays.

Heff = 4GF √ 2

  • q,q′=u,c

λqq′

  • i=1,2

C q,q′

i

(MW , µ)Qqq′

i

+ h.c.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 10 / 23

slide-45
SLIDE 45

New Physics at tree level decays.

Heff = 4GF √ 2

  • q,q′=u,c

λqq′

  • i=1,2

C q,q′

i

(MW , µ)Qqq′

i

+ h.c. with λqq′ = V ∗

qdVq′b. Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 10 / 23

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SLIDE 46

New Physics at tree level decays.

Heff = 4GF √ 2

  • q,q′=u,c

λqq′

  • i=1,2

C q,q′

i

(MW , µ)Qqq′

i

+ h.c. with λqq′ = V ∗

qdVq′b.

Wilson Coefficients C1(µ) = − 3αs(µ) 4π Ln M2

W

µ2

  • C2(µ)

= 1 + 3 Nc αs(µ) 4π Ln M2

W

µ2

  • Gilberto Tetlalmatzi (IPPP Durham)

New Physics in ∆Γd October 31, 2014 10 / 23

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SLIDE 47

Analysis strategy

We investigated how constrained by New Physics C1 and C2 are.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 11 / 23

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SLIDE 48

Analysis strategy

We investigated how constrained by New Physics C1 and C2 are. To analyze the effects of new physics the theoretical result O(C SM

1

, C SM

2

) ± σSM

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 11 / 23

slide-49
SLIDE 49

Analysis strategy

We investigated how constrained by New Physics C1 and C2 are. To analyze the effects of new physics the theoretical result O(C SM

1

, C SM

2

) ± σSM is compared against the experimental one Oexp ± σexp

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 11 / 23

slide-50
SLIDE 50

Analysis strategy

We investigated how constrained by New Physics C1 and C2 are. To analyze the effects of new physics the theoretical result O(C SM

1

, C SM

2

) ± σSM is compared against the experimental one Oexp ± σexp taking into account a shift in C1,2 O(C SM

1

, C SM

2

) − → O(C SM

1

+ ∆C1, C SM

2

+ ∆C2)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 11 / 23

slide-51
SLIDE 51

Analysis strategy

We investigated how constrained by New Physics C1 and C2 are. To analyze the effects of new physics the theoretical result O(C SM

1

, C SM

2

) ± σSM is compared against the experimental one Oexp ± σexp taking into account a shift in C1,2 O(C SM

1

, C SM

2

) − → O(C SM

1

+ ∆C1, C SM

2

+ ∆C2) |O(C SM

1

+ ∆C1, C SM

2

+ ∆C2) − Oexp| < 1.64

  • (σexp)2 + (σSM)2

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 11 / 23

slide-52
SLIDE 52

Analysis strategy

We investigated how constrained by New Physics C1 and C2 are. To analyze the effects of new physics the theoretical result O(C SM

1

, C SM

2

) ± σSM is compared against the experimental one Oexp ± σexp taking into account a shift in C1,2 O(C SM

1

, C SM

2

) − → O(C SM

1

+ ∆C1, C SM

2

+ ∆C2) |O(C SM

1

+ ∆C1, C SM

2

+ ∆C2) − Oexp| < 1.64

  • (σexp)2 + (σSM)2

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 11 / 23

slide-53
SLIDE 53

Constraints over the Wilson coefficients

C cc

1

and C cc

2

Q = (¯ dγµPLc)(¯ cγµPLb)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 12 / 23

slide-54
SLIDE 54

Constraints over the Wilson coefficients

C cc

1

and C cc

2

Q = (¯ dγµPLc)(¯ cγµPLb) Channels and Observables

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 12 / 23

slide-55
SLIDE 55

Constraints over the Wilson coefficients

C cc

1

and C cc

2

Q = (¯ dγµPLc)(¯ cγµPLb) Channels and Observables B → Xdγ = ⇒ Operator Mixing

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 12 / 23

slide-56
SLIDE 56

Constraints over the Wilson coefficients

C cc

1

and C cc

2

Q = (¯ dγµPLc)(¯ cγµPLb) Channels and Observables B → Xdγ = ⇒ Operator Mixing Sin

  • 2βd
  • = Im

Md

12

|Md

12|

  • =

⇒ Double insertion of ∆B = 1 operators.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 12 / 23

slide-57
SLIDE 57

Constraints over the Wilson coefficients

C cc

1

and C cc

2

Q = (¯ dγµPLc)(¯ cγµPLb) Channels and Observables B → Xdγ = ⇒ Operator Mixing Sin

  • 2βd
  • = Im

Md

12

|Md

12|

  • =

⇒ Double insertion of ∆B = 1 operators. ad

sl = Im

Γd

12

Md

12

  • Gilberto Tetlalmatzi (IPPP Durham)

New Physics in ∆Γd October 31, 2014 12 / 23

slide-58
SLIDE 58

Constraints over the Wilson coefficients

C cc

1

and C cc

2

Q = (¯ dγµPLc)(¯ cγµPLb) Channels and Observables B → Xdγ = ⇒ Operator Mixing Sin

  • 2βd
  • = Im

Md

12

|Md

12|

  • =

⇒ Double insertion of ∆B = 1 operators. ad

sl = Im

Γd

12

Md

12

  • SM

4 2 2 4 2 2 4 Re C2

cc

Im C2

cc

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 12 / 23

slide-59
SLIDE 59

New Physics at tree level decays.

Calculation of ∆Γd,s

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 13 / 23

slide-60
SLIDE 60

New Physics at tree level decays.

Calculation of ∆Γd,s H∆B=1

eff

= 4GF √ 2

  • q,q′=u,c

λqq′

  • i=1,2

C q,q′

i

(MW , µ)Qqq′

i

+ h.c.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 13 / 23

slide-61
SLIDE 61

New Physics at tree level decays.

Calculation of ∆Γd,s H∆B=1

eff

= 4GF √ 2

  • q,q′=u,c

λqq′

  • i=1,2

C q,q′

i

(MW , µ)Qqq′

i

+ h.c. Γd

12

= 1 2MBd < ¯ Bd|Im

  • i
  • d4x ˆ

T H∆B=1

eff

(x)H∆B=1

eff

(0) |Bd > = −

  • λ2

cΓcc,d 12

(C cc

1 , C cc 2 ) + 2λcλuΓuc,d 12

(C uc

1 , C uc 2 ) + λ2 uΓuu,d 12

(C uu

1 , C uu 2 )

  • ,

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 13 / 23

slide-62
SLIDE 62

New Physics at tree level decays.

Calculation of ∆Γd,s H∆B=1

eff

= 4GF √ 2

  • q,q′=u,c

λqq′

  • i=1,2

C q,q′

i

(MW , µ)Qqq′

i

+ h.c. Γd

12

= 1 2MBd < ¯ Bd|Im

  • i
  • d4x ˆ

T H∆B=1

eff

(x)H∆B=1

eff

(0) |Bd > = −

  • λ2

cΓcc,d 12

(C cc

1 , C cc 2 ) + 2λcλuΓuc,d 12

(C uc

1 , C uc 2 ) + λ2 uΓuu,d 12

(C uu

1 , C uu 2 )

  • ,

∆Γd ≈ 2|Γd

12|cos(φd) Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 13 / 23

slide-63
SLIDE 63

Effect of C1, C2 on ∆Γ

Up to an enhancement of 1.5 possible.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 14 / 23

slide-64
SLIDE 64

Effect of C1, C2 on ∆Γ

Up to an enhancement of 1.5 possible. Up to an enhancement of 1.6 possible.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 14 / 23

slide-65
SLIDE 65

Effect of C1, C2 on ∆Γ

Up to an enhancement of 1.5 possible. Up to an enhancement of 1.6 possible. Up to an enhancement of 16 posssible

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 14 / 23

slide-66
SLIDE 66

How big can ∆Γd be?

Enhancements in ∆Γd arise from:

1

CKM Unitarity violations.

2

New Physics at tree level decays.

3

(¯ db)(¯ ττ) operators.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 15 / 23

slide-67
SLIDE 67
  • b¯

d

  • (¯

ττ) Operators

The contributions from NP on ∆Γd can be estimated by analyzing effective operators well suppressed in the SM.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 16 / 23

slide-68
SLIDE 68
  • b¯

d

  • (¯

ττ) Operators

The contributions from NP on ∆Γd can be estimated by analyzing effective operators well suppressed in the SM. The set of operators relevant to our study has the form (¯ db)(¯ ττ).

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 16 / 23

slide-69
SLIDE 69
  • b¯

d

  • (¯

ττ) Operators

The contributions from NP on ∆Γd can be estimated by analyzing effective operators well suppressed in the SM. The set of operators relevant to our study has the form (¯ db)(¯ ττ). b ¯ d d ¯ b τ ¯ τ

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 16 / 23

slide-70
SLIDE 70
  • b¯

d

  • (¯

ττ) Operators

The contributions from NP on ∆Γd can be estimated by analyzing effective operators well suppressed in the SM. The set of operators relevant to our study has the form (¯ db)(¯ ττ). b ¯ d d ¯ b τ ¯ τ QS,AB = ¯ d PA b

  • (¯

τ PB τ) , QV ,AB = ¯ d γµPA b (¯ τ γµPB τ) , QT,A = ¯ d σµνPA b (¯ τ σµνPA τ) ,

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 16 / 23

slide-71
SLIDE 71
  • b¯

d

  • (¯

ττ) Operators

The contributions from NP on ∆Γd can be estimated by analyzing effective operators well suppressed in the SM. The set of operators relevant to our study has the form (¯ db)(¯ ττ). b ¯ d d ¯ b τ ¯ τ QS,AB = ¯ d PA b

  • (¯

τ PB τ) , QV ,AB = ¯ d γµPA b (¯ τ γµPB τ) , QT,A = ¯ d σµνPA b (¯ τ σµνPA τ) , The effective Hamiltonian involving these operators is Heff = − 4GF √ 2 λd

t

  • i,j

Ci,j(µ)Qi,j

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 16 / 23

slide-72
SLIDE 72
  • b¯

d

  • (¯

ττ) Operators

Example: Vector contribution QV ,AB = ¯ d γµPA b (¯ τ γµPB τ)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 17 / 23

slide-73
SLIDE 73
  • b¯

d

  • (¯

ττ) Operators

Example: Vector contribution QV ,AB = ¯ d γµPA b (¯ τ γµPB τ) Direct Bounds

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 17 / 23

slide-74
SLIDE 74
  • b¯

d

  • (¯

ττ) Operators

Example: Vector contribution QV ,AB = ¯ d γµPA b (¯ τ γµPB τ) Direct Bounds Bd → τ +τ − = ⇒ Br(Bd → τ +τ −) < 4.1 × 10−3

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 17 / 23

slide-75
SLIDE 75
  • b¯

d

  • (¯

ττ) Operators

Example: Vector contribution QV ,AB = ¯ d γµPA b (¯ τ γµPB τ) Direct Bounds Bd → τ +τ − = ⇒ Br(Bd → τ +τ −) < 4.1 × 10−3 B → Xdτ +τ − and B+ → π+τ +τ −

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 17 / 23

slide-76
SLIDE 76
  • b¯

d

  • (¯

ττ) Operators

Example: Vector contribution QV ,AB = ¯ d γµPA b (¯ τ γµPB τ) Direct Bounds Bd → τ +τ − = ⇒ Br(Bd → τ +τ −) < 4.1 × 10−3 B → Xdτ +τ − and B+ → π+τ +τ − τBs

τBd − 1

  • SM

vs τBs

τBd − 1

  • exp

= ⇒ Br(Bd → X) < 1.5%

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 17 / 23

slide-77
SLIDE 77
  • b¯

d

  • (¯

ττ) Operators

Example: Vector contribution QV ,AB = ¯ d γµPA b (¯ τ γµPB τ) Direct Bounds Bd → τ +τ − = ⇒ Br(Bd → τ +τ −) < 4.1 × 10−3 B → Xdτ +τ − and B+ → π+τ +τ − τBs

τBd − 1

  • SM

vs τBs

τBd − 1

  • exp

= ⇒ Br(Bd → X) < 1.5% Indirect Bounds

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 17 / 23

slide-78
SLIDE 78
  • b¯

d

  • (¯

ττ) Operators

Example: Vector contribution QV ,AB = ¯ d γµPA b (¯ τ γµPB τ) Direct Bounds Bd → τ +τ − = ⇒ Br(Bd → τ +τ −) < 4.1 × 10−3 B → Xdτ +τ − and B+ → π+τ +τ − τBs

τBd − 1

  • SM

vs τBs

τBd − 1

  • exp

= ⇒ Br(Bd → X) < 1.5% Indirect Bounds B+ → π+µ+µ− = ⇒ Br(B+ → π+µ+µ−)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 17 / 23

slide-79
SLIDE 79
  • b¯

d

  • (¯

ττ) Operators

Example: Vector contribution QV ,AB = ¯ d γµPA b (¯ τ γµPB τ) Direct Bounds Bd → τ +τ − = ⇒ Br(Bd → τ +τ −) < 4.1 × 10−3 B → Xdτ +τ − and B+ → π+τ +τ − τBs

τBd − 1

  • SM

vs τBs

τBd − 1

  • exp

= ⇒ Br(Bd → X) < 1.5% Indirect Bounds B+ → π+µ+µ− = ⇒ Br(B+ → π+µ+µ−) Q9 = e2 (4π)2 ¯ d γµPL b ¯ ℓ γµ ℓ ,

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 17 / 23

slide-80
SLIDE 80
  • b¯

d

  • (¯

ττ) Operators

Example: Vector contribution QV ,AB = ¯ d γµPA b (¯ τ γµPB τ) Direct Bounds Bd → τ +τ − = ⇒ Br(Bd → τ +τ −) < 4.1 × 10−3 B → Xdτ +τ − and B+ → π+τ +τ − τBs

τBd − 1

  • SM

vs τBs

τBd − 1

  • exp

= ⇒ Br(Bd → X) < 1.5% Indirect Bounds B+ → π+µ+µ− = ⇒ Br(B+ → π+µ+µ−) Q9 = e2 (4π)2 ¯ d γµPL b ¯ ℓ γµ ℓ , C9,A(mb) =

  • 0.1 − 0.2 η−1

6

CV ,AL(Λ) + CV ,AR(Λ)

  • Gilberto Tetlalmatzi (IPPP Durham)

New Physics in ∆Γd October 31, 2014 17 / 23

slide-81
SLIDE 81
  • b¯

d

  • (¯

ττ) Operators

Γd

12

= Γd,SM

12

˜ ∆d ∆Γd ∆ΓSM

d

≤ | ˜ ∆d|

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 18 / 23

slide-82
SLIDE 82
  • b¯

d

  • (¯

ττ) Operators

Γd

12

= Γd,SM

12

˜ ∆d ∆Γd ∆ΓSM

d

≤ | ˜ ∆d| Dependence of ˜ ∆d on the Wilson coefficients | ˜ ∆d|S,AB < 1 + (0.41+0.13

−0.08)|CS,AB(mb)|2 ≤ 1.6

| ˜ ∆d|V ,AB < 1 + (0.42+0.13

−0.08)|CV ,AB(mb)|2 ≤ 3.7

| ˜ ∆d|T,AB < 1 + (3.81+1.21

−0.74)|CT,A(mb)|2 ≤ 1.2 Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 18 / 23

slide-83
SLIDE 83
  • b¯

d

  • (¯

ττ) Operators

Γd

12

= Γd,SM

12

˜ ∆d ∆Γd ∆ΓSM

d

≤ | ˜ ∆d| Dependence of ˜ ∆d on the Wilson coefficients | ˜ ∆d|S,AB < 1 + (0.41+0.13

−0.08)|CS,AB(mb)|2 ≤ 1.6

| ˜ ∆d|V ,AB < 1 + (0.42+0.13

−0.08)|CV ,AB(mb)|2 ≤ 3.7

| ˜ ∆d|T,AB < 1 + (3.81+1.21

−0.74)|CT,A(mb)|2 ≤ 1.2 Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 18 / 23

slide-84
SLIDE 84
  • b¯

d

  • (¯

ττ) operators

Expected values for Br

  • B → π+τ +τ −

and Br

  • B → Xdτ +τ −

in order to compete against Br

  • Bd → τ +τ −

Bd ΤΤ B XdΤΤ B ΠΤΤ

  • 2. 106

0.00001 0.0001 0.001 0.01 1 2 3 4 5 7 10 Br d d

SM V

Allowed region from Bd ΤΤ

| ˜ ∆d|V ,AB ≤ 3.7 = ⇒ Br(B → Xdτ +τ −) ≤ 2.6 × 10−3

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 19 / 23

slide-85
SLIDE 85

Like-sign dimuon asymmetry

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-86
SLIDE 86

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−−

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-87
SLIDE 87

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-88
SLIDE 88

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays A = ACP + Abkg

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-89
SLIDE 89

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays A = ACP + Abkg Standard interpretation: CP violation in mixing ACP ∝ Ab

sl = Cdad sl + Csas sl Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-90
SLIDE 90

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays A = ACP + Abkg Standard interpretation: CP violation in mixing ACP ∝ Ab

sl = Cdad sl + Csas sl

Ab,D0

sl

= (−0.787 ± 0.172 ± 0.093)%(2011) 3.9 σ deviation from the SM

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-91
SLIDE 91

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays A = ACP + Abkg Standard interpretation: CP violation in mixing ACP ∝ Ab

sl = Cdad sl + Csas sl

Ab,D0

sl

= (−0.787 ± 0.172 ± 0.093)%(2011) 3.9 σ deviation from the SM Borissov and Hoeneisen ACP ∝ Cdad

sl + Csas sl + CΓd ∆Γd Γd

+ CΓs

∆Γs Γs Phys. Rev. D 87, 074020 Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-92
SLIDE 92

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays A = ACP + Abkg Standard interpretation: CP violation in mixing ACP ∝ Ab

sl = Cdad sl + Csas sl

Ab,D0

sl

= (−0.787 ± 0.172 ± 0.093)%(2011) 3.9 σ deviation from the SM Borissov and Hoeneisen ACP ∝ Cdad

sl + Csas sl + CΓd ∆Γd Γd

+ CΓs

∆Γs Γs Phys. Rev. D 87, 074020

CP violation in mixing

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-93
SLIDE 93

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays A = ACP + Abkg Standard interpretation: CP violation in mixing ACP ∝ Ab

sl = Cdad sl + Csas sl

Ab,D0

sl

= (−0.787 ± 0.172 ± 0.093)%(2011) 3.9 σ deviation from the SM Borissov and Hoeneisen ACP ∝ Cdad

sl + Csas sl + CΓd ∆Γd Γd

+ CΓs

∆Γs Γs Phys. Rev. D 87, 074020

CP violation in mixing+

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-94
SLIDE 94

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays A = ACP + Abkg Standard interpretation: CP violation in mixing ACP ∝ Ab

sl = Cdad sl + Csas sl

Ab,D0

sl

= (−0.787 ± 0.172 ± 0.093)%(2011) 3.9 σ deviation from the SM Borissov and Hoeneisen ACP ∝ Cdad

sl + Csas sl + CΓd ∆Γd Γd

+ CΓs

∆Γs Γs Phys. Rev. D 87, 074020

CP violation in mixing+CP violation in interference between mixing and decay.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-95
SLIDE 95

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays A = ACP + Abkg Standard interpretation: CP violation in mixing ACP ∝ Ab

sl = Cdad sl + Csas sl

Ab,D0

sl

= (−0.787 ± 0.172 ± 0.093)%(2011) 3.9 σ deviation from the SM Borissov and Hoeneisen ACP ∝ Cdad

sl + Csas sl + CΓd ∆Γd Γd

+ CΓs

∆Γs Γs Phys. Rev. D 87, 074020

CP violation in mixing+CP violation in interference between mixing and decay. ad

sl = (−0.62 ± 0.43)% as sl = (−0.82 ± 0.99)%

∆Γd Γd = (0.50 ± 1.38)%D0 (2014)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-96
SLIDE 96

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays A = ACP + Abkg Standard interpretation: CP violation in mixing ACP ∝ Ab

sl = Cdad sl + Csas sl

Ab,D0

sl

= (−0.787 ± 0.172 ± 0.093)%(2011) 3.9 σ deviation from the SM Borissov and Hoeneisen ACP ∝ Cdad

sl + Csas sl + CΓd ∆Γd Γd

+ CΓs

∆Γs Γs Phys. Rev. D 87, 074020

CP violation in mixing+CP violation in interference between mixing and decay. ad

sl = (−0.62 ± 0.43)% as sl = (−0.82 ± 0.99)%

∆Γd Γd = (0.50 ± 1.38)%D0 (2014)

  • Phys. Rev. D 89, 012002 (2014)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-97
SLIDE 97

Like-sign dimuon asymmetry

A = N++ − N−− N++ + N−− N++/−− : # of events with two +/- muons from B hadron decays A = ACP + Abkg Standard interpretation: CP violation in mixing ACP ∝ Ab

sl = Cdad sl + Csas sl

Ab,D0

sl

= (−0.787 ± 0.172 ± 0.093)%(2011) 3.9 σ deviation from the SM Borissov and Hoeneisen ACP ∝ Cdad

sl + Csas sl + CΓd ∆Γd Γd

+ CΓs

∆Γs Γs Phys. Rev. D 87, 074020

CP violation in mixing+CP violation in interference between mixing and decay. ad

sl = (−0.62 ± 0.43)% as sl = (−0.82 ± 0.99)%

∆Γd Γd = (0.50 ± 1.38)%D0 (2014)

  • Phys. Rev. D 89, 012002 (2014)

3.0 σ deviation from the SM

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 20 / 23

slide-98
SLIDE 98

Conclusions

We have investigated the room for New Physics in ∆Γd

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 21 / 23

slide-99
SLIDE 99

Conclusions

We have investigated the room for New Physics in ∆Γd A priori a large enhancement in ∆Γd in contrast for ∆Γs BSM effects cannot exceed the size of the hadronic uncertainties.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 21 / 23

slide-100
SLIDE 100

Conclusions

We have investigated the room for New Physics in ∆Γd A priori a large enhancement in ∆Γd in contrast for ∆Γs BSM effects cannot exceed the size of the hadronic uncertainties. ∆Γ ∆ΓSM ≤      4 CKM unitarity violations. 16 Current-current operators. 3.7 (bd)(ττ) operators.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 21 / 23

slide-101
SLIDE 101

Conclusions

We have investigated the room for New Physics in ∆Γd A priori a large enhancement in ∆Γd in contrast for ∆Γs BSM effects cannot exceed the size of the hadronic uncertainties. ∆Γ ∆ΓSM ≤      4 CKM unitarity violations. 16 Current-current operators. 3.7 (bd)(ττ) operators. The interference contribution to the like sign dimuon asymmetry comes from Γcc

12 rather

than from ∆Γd.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 21 / 23

slide-102
SLIDE 102

Conclusions

We have investigated the room for New Physics in ∆Γd A priori a large enhancement in ∆Γd in contrast for ∆Γs BSM effects cannot exceed the size of the hadronic uncertainties. ∆Γ ∆ΓSM ≤      4 CKM unitarity violations. 16 Current-current operators. 3.7 (bd)(ττ) operators. The interference contribution to the like sign dimuon asymmetry comes from Γcc

12 rather

than from ∆Γd. Main differences:

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 21 / 23

slide-103
SLIDE 103

Conclusions

We have investigated the room for New Physics in ∆Γd A priori a large enhancement in ∆Γd in contrast for ∆Γs BSM effects cannot exceed the size of the hadronic uncertainties. ∆Γ ∆ΓSM ≤      4 CKM unitarity violations. 16 Current-current operators. 3.7 (bd)(ττ) operators. The interference contribution to the like sign dimuon asymmetry comes from Γcc

12 rather

than from ∆Γd. Main differences: 2|λ2

cΓcc 12| is a bit bigger than ∆Γd in the SM Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 21 / 23

slide-104
SLIDE 104

Conclusions

We have investigated the room for New Physics in ∆Γd A priori a large enhancement in ∆Γd in contrast for ∆Γs BSM effects cannot exceed the size of the hadronic uncertainties. ∆Γ ∆ΓSM ≤      4 CKM unitarity violations. 16 Current-current operators. 3.7 (bd)(ττ) operators. The interference contribution to the like sign dimuon asymmetry comes from Γcc

12 rather

than from ∆Γd. Main differences: 2|λ2

cΓcc 12| is a bit bigger than ∆Γd in the SM

There are different phases Sin(2β + 2θλc ) attached with the components of ∆Γd.

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 21 / 23

slide-105
SLIDE 105

Constraints over the Wilson coefficients

C uc

1

and C uc

2

Q = (¯ dγµPLu)(¯ cγµPLb)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 22 / 23

slide-106
SLIDE 106

Constraints over the Wilson coefficients

C uc

1

and C uc

2

Q = (¯ dγµPLu)(¯ cγµPLb) Channels and Observables

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 22 / 23

slide-107
SLIDE 107

Constraints over the Wilson coefficients

C uc

1

and C uc

2

Q = (¯ dγµPLu)(¯ cγµPLb) Channels and Observables ¯ B0 → D+π− = ⇒ R¯

B0→D∗+l− ¯ νl = Γ(¯ B0→D∗+π−) dΓ(¯ B0→π+l− ¯ νl )/dq2

  • q2=0

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 22 / 23

slide-108
SLIDE 108

Constraints over the Wilson coefficients

C uc

1

and C uc

2

Q = (¯ dγµPLu)(¯ cγµPLb) Channels and Observables ¯ B0 → D+π− = ⇒ R¯

B0→D∗+l− ¯ νl = Γ(¯ B0→D∗+π−) dΓ(¯ B0→π+l− ¯ νl )/dq2

  • q2=0

B0 → D(∗)0h0 = ⇒ SD(∗)0h0

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 22 / 23

slide-109
SLIDE 109

Constraints over the Wilson coefficients

C uc

1

and C uc

2

Q = (¯ dγµPLu)(¯ cγµPLb) Channels and Observables ¯ B0 → D+π− = ⇒ R¯

B0→D∗+l− ¯ νl = Γ(¯ B0→D∗+π−) dΓ(¯ B0→π+l− ¯ νl )/dq2

  • q2=0

B0 → D(∗)0h0 = ⇒ SD(∗)0h0 Γtot(Bd)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 22 / 23

slide-110
SLIDE 110

Constraints over the Wilson coefficients

C uc

1

and C uc

2

Q = (¯ dγµPLu)(¯ cγµPLb) Channels and Observables ¯ B0 → D+π− = ⇒ R¯

B0→D∗+l− ¯ νl = Γ(¯ B0→D∗+π−) dΓ(¯ B0→π+l− ¯ νl )/dq2

  • q2=0

B0 → D(∗)0h0 = ⇒ SD(∗)0h0 Γtot(Bd)

SM 2.5 2.0 1.5 1.0 0.5 0.0 0.5 1.5 1.0 0.5 0.0 0.5 1.0 1.5 Re C1

ucMW

Im C1

ucMW

SM SM 2.5 2.0 1.5 1.0 0.5 0.0 0.5 1.5 1.0 0.5 0.0 0.5 1.0 1.5 Re C2

ucMW

Im C2

ucMW

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 22 / 23

slide-111
SLIDE 111

Constraints over the Wilson coefficients

C uu

1

and C uu

2

Q = (¯ dγµPLu)(¯ uγµPLb)

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 23 / 23

slide-112
SLIDE 112

Constraints over the Wilson coefficients

C uu

1

and C uu

2

Q = (¯ dγµPLu)(¯ uγµPLb) Channels and Observables

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 23 / 23

slide-113
SLIDE 113

Constraints over the Wilson coefficients

C uu

1

and C uu

2

Q = (¯ dγµPLu)(¯ uγµPLb) Channels and Observables B− → π−π0 = ⇒ Rπ−π0 =

Γ(B−→π−π0) dΓ(¯ B0→π+l− ¯ νl )/dq2

  • q2=0

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 23 / 23

slide-114
SLIDE 114

Constraints over the Wilson coefficients

C uu

1

and C uu

2

Q = (¯ dγµPLu)(¯ uγµPLb) Channels and Observables B− → π−π0 = ⇒ Rπ−π0 =

Γ(B−→π−π0) dΓ(¯ B0→π+l− ¯ νl )/dq2

  • q2=0

B0 → π−π+ Indirect CP asymmetry

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 23 / 23

slide-115
SLIDE 115

Constraints over the Wilson coefficients

C uu

1

and C uu

2

Q = (¯ dγµPLu)(¯ uγµPLb) Channels and Observables B− → π−π0 = ⇒ Rπ−π0 =

Γ(B−→π−π0) dΓ(¯ B0→π+l− ¯ νl )/dq2

  • q2=0

B0 → π−π+ Indirect CP asymmetry B → ρπ Indirect CP Asymmetry

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 23 / 23

slide-116
SLIDE 116

Constraints over the Wilson coefficients

C uu

1

and C uu

2

Q = (¯ dγµPLu)(¯ uγµPLb) Channels and Observables B− → π−π0 = ⇒ Rπ−π0 =

Γ(B−→π−π0) dΓ(¯ B0→π+l− ¯ νl )/dq2

  • q2=0

B0 → π−π+ Indirect CP asymmetry B → ρπ Indirect CP Asymmetry B− → ρ−ρ0 and ¯ B0 → ρ+ρ− = ⇒ R(ρ−ρ0/ρ+ρ−) = Br(B−→ρ−ρ0)

Br(¯ B0→ρ+ρ−) Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 23 / 23

slide-117
SLIDE 117

Constraints over the Wilson coefficients

C uu

1

and C uu

2

Q = (¯ dγµPLu)(¯ uγµPLb) Channels and Observables B− → π−π0 = ⇒ Rπ−π0 =

Γ(B−→π−π0) dΓ(¯ B0→π+l− ¯ νl )/dq2

  • q2=0

B0 → π−π+ Indirect CP asymmetry B → ρπ Indirect CP Asymmetry B− → ρ−ρ0 and ¯ B0 → ρ+ρ− = ⇒ R(ρ−ρ0/ρ+ρ−) = Br(B−→ρ−ρ0)

Br(¯ B0→ρ+ρ−)

2.5 2.0 1.5 1.0 0.5 0.0 0.5 1.5 1.0 0.5 0.0 0.5 1.0 1.5 Re C1

uuMW

Im C1

uuMW

Gilberto Tetlalmatzi (IPPP Durham) New Physics in ∆Γd October 31, 2014 23 / 23