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Consequences of Solvability by Radicals Bernd Schr oder logo1 - - PowerPoint PPT Presentation

Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups Consequences of Solvability by Radicals Bernd Schr oder logo1 Bernd Schr oder Louisiana Tech University, College of Engineering and Science


slide-1
SLIDE 1

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Consequences of Solvability by Radicals

Bernd Schr¨

  • der

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 2

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Introduction

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-3
SLIDE 3

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Introduction

  • 1. Galois groups are isomorphic to subgroups of Sn

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-4
SLIDE 4

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Introduction

  • 1. Galois groups are isomorphic to subgroups of Sn and some
  • f them are equal to Sn.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-5
SLIDE 5

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Introduction

  • 1. Galois groups are isomorphic to subgroups of Sn and some
  • f them are equal to Sn.
  • 2. It does not look like Sn has many normal subgroups.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-6
SLIDE 6

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Introduction

  • 1. Galois groups are isomorphic to subgroups of Sn and some
  • f them are equal to Sn.
  • 2. It does not look like Sn has many normal subgroups. And

if An in an indication, there are not many ways for normal subgroups of Sn to have normal subgroups.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-7
SLIDE 7

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Introduction

  • 1. Galois groups are isomorphic to subgroups of Sn and some
  • f them are equal to Sn.
  • 2. It does not look like Sn has many normal subgroups. And

if An in an indication, there are not many ways for normal subgroups of Sn to have normal subgroups.

  • 3. So root towers for normal extensions cannot be terribly

tall.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-8
SLIDE 8

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Introduction

  • 1. Galois groups are isomorphic to subgroups of Sn and some
  • f them are equal to Sn.
  • 2. It does not look like Sn has many normal subgroups. And

if An in an indication, there are not many ways for normal subgroups of Sn to have normal subgroups.

  • 3. So root towers for normal extensions cannot be terribly

tall.

  • 4. But they need not be, because splitting fields can be

generated by adjoining a single element.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-9
SLIDE 9

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Introduction

  • 1. Galois groups are isomorphic to subgroups of Sn and some
  • f them are equal to Sn.
  • 2. It does not look like Sn has many normal subgroups. And

if An in an indication, there are not many ways for normal subgroups of Sn to have normal subgroups.

  • 3. So root towers for normal extensions cannot be terribly

tall.

  • 4. But they need not be, because splitting fields can be

generated by adjoining a single element.

  • 5. So we still need some more ideas.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-10
SLIDE 10

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Definition.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 11

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. An nth root of unity r is called a primitive nth root
  • f unity iff every other nth root of unity is a power of r.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-12
SLIDE 12

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. An nth root of unity r is called a primitive nth root
  • f unity iff every other nth root of unity is a power of r.

Roots of unity can be adjoined before we start, if necessary.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-13
SLIDE 13

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. An nth root of unity r is called a primitive nth root
  • f unity iff every other nth root of unity is a power of r.

Roots of unity can be adjoined before we start, if necessary. From here on, demanding characteristic 0 is quite common.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-14
SLIDE 14

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. An nth root of unity r is called a primitive nth root
  • f unity iff every other nth root of unity is a power of r.

Roots of unity can be adjoined before we start, if necessary. From here on, demanding characteristic 0 is quite common. Theorem.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-15
SLIDE 15

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. An nth root of unity r is called a primitive nth root
  • f unity iff every other nth root of unity is a power of r.

Roots of unity can be adjoined before we start, if necessary. From here on, demanding characteristic 0 is quite common.

  • Theorem. Let F be a field of characteristic 0 that contains all

nth roots of unity, let f ∈ F and let w be a root of xn −f = 0.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-16
SLIDE 16

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. An nth root of unity r is called a primitive nth root
  • f unity iff every other nth root of unity is a power of r.

Roots of unity can be adjoined before we start, if necessary. From here on, demanding characteristic 0 is quite common.

  • Theorem. Let F be a field of characteristic 0 that contains all

nth roots of unity, let f ∈ F and let w be a root of xn −f = 0. Then F(w) is the splitting field of the polynomial xn −f.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-17
SLIDE 17

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. An nth root of unity r is called a primitive nth root
  • f unity iff every other nth root of unity is a power of r.

Roots of unity can be adjoined before we start, if necessary. From here on, demanding characteristic 0 is quite common.

  • Theorem. Let F be a field of characteristic 0 that contains all

nth roots of unity, let f ∈ F and let w be a root of xn −f = 0. Then F(w) is the splitting field of the polynomial xn −f. Moreover, the Galois group G

  • F(w)/F
  • is isomorphic to a

subgroup of Zn.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-18
SLIDE 18

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. An nth root of unity r is called a primitive nth root
  • f unity iff every other nth root of unity is a power of r.

Roots of unity can be adjoined before we start, if necessary. From here on, demanding characteristic 0 is quite common.

  • Theorem. Let F be a field of characteristic 0 that contains all

nth roots of unity, let f ∈ F and let w be a root of xn −f = 0. Then F(w) is the splitting field of the polynomial xn −f. Moreover, the Galois group G

  • F(w)/F
  • is isomorphic to a

subgroup of Zn. In particular, the Galois group G

  • F(w)/F
  • is

commutative.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 19

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 20

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-21
SLIDE 21

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-22
SLIDE 22

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-23
SLIDE 23

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-24
SLIDE 24

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • .

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-25
SLIDE 25

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-26
SLIDE 26

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-27
SLIDE 27

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-28
SLIDE 28

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-29
SLIDE 29

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • Bernd Schr¨
  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-30
SLIDE 30

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-31
SLIDE 31

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w)

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-32
SLIDE 32

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-33
SLIDE 33

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-34
SLIDE 34

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-35
SLIDE 35

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-36
SLIDE 36

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-37
SLIDE 37

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ)

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-38
SLIDE 38

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ) = [j+k]n

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-39
SLIDE 39

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ) = [j+k]n = [j]n +[k]n

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-40
SLIDE 40

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ) = [j+k]n = [j]n +[k]n = Φ(µ)+Φ(σ).

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-41
SLIDE 41

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ) = [j+k]n = [j]n +[k]n = Φ(µ)+Φ(σ). Moreover, Φ is injective

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-42
SLIDE 42

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ) = [j+k]n = [j]n +[k]n = Φ(µ)+Φ(σ). Moreover, Φ is injective, because Φ(σ) = [0]n implies σ(w) = w

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-43
SLIDE 43

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ) = [j+k]n = [j]n +[k]n = Φ(µ)+Φ(σ). Moreover, Φ is injective, because Φ(σ) = [0]n implies σ(w) = w, and hence σ = id

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-44
SLIDE 44

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ) = [j+k]n = [j]n +[k]n = Φ(µ)+Φ(σ). Moreover, Φ is injective, because Φ(σ) = [0]n implies σ(w) = w, and hence σ = id (rest: good exercise).

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-45
SLIDE 45

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ) = [j+k]n = [j]n +[k]n = Φ(µ)+Φ(σ). Moreover, Φ is injective, because Φ(σ) = [0]n implies σ(w) = w, and hence σ = id (rest: good exercise). Hence G

  • F(w)/F
  • is isomorphic to a subgroup of Zn

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-46
SLIDE 46

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ) = [j+k]n = [j]n +[k]n = Φ(µ)+Φ(σ). Moreover, Φ is injective, because Φ(σ) = [0]n implies σ(w) = w, and hence σ = id (rest: good exercise). Hence G

  • F(w)/F
  • is isomorphic to a subgroup of Zn, and

because Zn is commutative, so are its subgroups.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-47
SLIDE 47

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let r be a primitive nth root of unity. Then

1,r,r2,...,rn−1 are the n distinct nth roots of unity and w,rw,r2w,...,rn−1w are the n distinct roots of xn −f. Therefore F(w) is the splitting field of the polynomial xn −f. Let σ ∈ G

  • F(w)/F
  • . Then σ(w) = wrk for some k ∈ Z, which

is unique modulo n. Define Φ : G

  • F(w)/F
  • → Zn by

Φ(σ) := [k]n, where k is the unique element of {0,...,n−1} so that σ(w) = wrk. Let σ,µ ∈ G

  • F(w)/F
  • and let µ(w) = wrj, σ(w) = wrk. Then

µ ◦σ(w) = µ

  • wrk

= µ(w)µ

  • rk

= µ(w)rk = wrjrk = wrj+k and hence Φ(µ ◦σ) = [j+k]n = [j]n +[k]n = Φ(µ)+Φ(σ). Moreover, Φ is injective, because Φ(σ) = [0]n implies σ(w) = w, and hence σ = id (rest: good exercise). Hence G

  • F(w)/F
  • is isomorphic to a subgroup of Zn, and

because Zn is commutative, so are its subgroups.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-48
SLIDE 48

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Definition.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-49
SLIDE 49

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. Let G be a finite group.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-50
SLIDE 50

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. Let G be a finite group. Then G is called solvable iff

there is a chain of subgroups {e} = G0 ⊳G1 ⊳···⊳Gm = G so that Gj/Gj−1 is commutative for j = 1,...,m.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-51
SLIDE 51

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. Let G be a finite group. Then G is called solvable iff

there is a chain of subgroups {e} = G0 ⊳G1 ⊳···⊳Gm = G so that Gj/Gj−1 is commutative for j = 1,...,m. Lemma.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-52
SLIDE 52

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. Let G be a finite group. Then G is called solvable iff

there is a chain of subgroups {e} = G0 ⊳G1 ⊳···⊳Gm = G so that Gj/Gj−1 is commutative for j = 1,...,m.

  • Lemma. Let G be a finite group and let N ⊳G.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-53
SLIDE 53

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Definition. Let G be a finite group. Then G is called solvable iff

there is a chain of subgroups {e} = G0 ⊳G1 ⊳···⊳Gm = G so that Gj/Gj−1 is commutative for j = 1,...,m.

  • Lemma. Let G be a finite group and let N ⊳G. If G is solvable,

then G/N is solvable.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-54
SLIDE 54

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-55
SLIDE 55

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-56
SLIDE 56

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G:

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-57
SLIDE 57

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-58
SLIDE 58

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = / 0.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-59
SLIDE 59

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-60
SLIDE 60

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-61
SLIDE 61

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-62
SLIDE 62

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny)

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-63
SLIDE 63

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-64
SLIDE 64

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-65
SLIDE 65

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny)

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-66
SLIDE 66

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-67
SLIDE 67

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-68
SLIDE 68

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-69
SLIDE 69

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-70
SLIDE 70

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-71
SLIDE 71

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-72
SLIDE 72

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-73
SLIDE 73

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-74
SLIDE 74

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-75
SLIDE 75

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-76
SLIDE 76

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N:

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-77
SLIDE 77

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N: Gj−1N/N is a subgroup of GjN/N.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-78
SLIDE 78

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N: Gj−1N/N is a subgroup of GjN/N. Let gjN ∈ GjN/N and let gj−1N ∈ Gj−1N/N.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-79
SLIDE 79

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N: Gj−1N/N is a subgroup of GjN/N. Let gjN ∈ GjN/N and let gj−1N ∈ Gj−1N/N. Then (gjN)(gj−1N)

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-80
SLIDE 80

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N: Gj−1N/N is a subgroup of GjN/N. Let gjN ∈ GjN/N and let gj−1N ∈ Gj−1N/N. Then (gjN)(gj−1N) = Ngjgj−1N

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-81
SLIDE 81

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N: Gj−1N/N is a subgroup of GjN/N. Let gjN ∈ GjN/N and let gj−1N ∈ Gj−1N/N. Then (gjN)(gj−1N) = Ngjgj−1N = Ng′

j−1gjN

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-82
SLIDE 82

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N: Gj−1N/N is a subgroup of GjN/N. Let gjN ∈ GjN/N and let gj−1N ∈ Gj−1N/N. Then (gjN)(gj−1N) = Ngjgj−1N = Ng′

j−1gjN =

  • g′

j−1N

  • (gjN)

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-83
SLIDE 83

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N: Gj−1N/N is a subgroup of GjN/N. Let gjN ∈ GjN/N and let gj−1N ∈ Gj−1N/N. Then (gjN)(gj−1N) = Ngjgj−1N = Ng′

j−1gjN =

  • g′

j−1N

  • (gjN),

which proves that (gjN)(Gj−1N/N) ⊆ (Gj−1N/N)(gjN).

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-84
SLIDE 84

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N: Gj−1N/N is a subgroup of GjN/N. Let gjN ∈ GjN/N and let gj−1N ∈ Gj−1N/N. Then (gjN)(gj−1N) = Ngjgj−1N = Ng′

j−1gjN =

  • g′

j−1N

  • (gjN),

which proves that (gjN)(Gj−1N/N) ⊆ (Gj−1N/N)(gjN). Thus for all x ∈ GjN/N we have x(Gj−1N/N) ⊆ (Gj−1N/N)x

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-85
SLIDE 85

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N: Gj−1N/N is a subgroup of GjN/N. Let gjN ∈ GjN/N and let gj−1N ∈ Gj−1N/N. Then (gjN)(gj−1N) = Ngjgj−1N = Ng′

j−1gjN =

  • g′

j−1N

  • (gjN),

which proves that (gjN)(Gj−1N/N) ⊆ (Gj−1N/N)(gjN). Thus for all x ∈ GjN/N we have x(Gj−1N/N) ⊆ (Gj−1N/N)x, that is, x(Gj−1N/N)x−1 ⊆ (Gj−1N/N)

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-86
SLIDE 86

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Proof. Let {e} = G0 ⊳G1 ⊳···⊳Gm = G be a chain of

subgroups so that Gj/Gj−1 is commutative for j = 1,...,m. Each GjN is a subgroup of G: e ∈ GjN = /

  • 0. Let x,y ∈ GjN.

Then there are gx,gy ∈ Gj and nx,ny ∈ N so that x = gxnx and y = gyny. Now xy = (gxnx)(gyny) = gx(nxgy)ny = gx(gyn)ny = (gxgy)(nny) ∈ GjN and x−1 = n−1

x g−1 x

= g−1

x ˜

n ∈ GjN. N ⊳G, so N ⊳GjN. If xN ∈ GjN/N, then there are a gj ∈ Gj and an n ∈ N so that xN = gjnN = gjN. So each element of GjN/N is of the form gjN for some gj ∈ Gj. Gj−1N/N is normal in GjN/N: Gj−1N/N is a subgroup of GjN/N. Let gjN ∈ GjN/N and let gj−1N ∈ Gj−1N/N. Then (gjN)(gj−1N) = Ngjgj−1N = Ng′

j−1gjN =

  • g′

j−1N

  • (gjN),

which proves that (gjN)(Gj−1N/N) ⊆ (Gj−1N/N)(gjN). Thus for all x ∈ GjN/N we have x(Gj−1N/N) ⊆ (Gj−1N/N)x, that is, x(Gj−1N/N)x−1 ⊆ (Gj−1N/N) and Gj−1N/N ⊳GjN/N.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-87
SLIDE 87

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.).

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-88
SLIDE 88

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative:

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-89
SLIDE 89

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-90
SLIDE 90

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-91
SLIDE 91

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-92
SLIDE 92

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-93
SLIDE 93

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-94
SLIDE 94

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj. Now let gjGj−1N,hjGj−1N ∈ (GjN/N)/(Gj−1N/N).

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-95
SLIDE 95

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj. Now let gjGj−1N,hjGj−1N ∈ (GjN/N)/(Gj−1N/N). Then (gjGj−1N)(hjGj−1N)

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-96
SLIDE 96

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj. Now let gjGj−1N,hjGj−1N ∈ (GjN/N)/(Gj−1N/N). Then (gjGj−1N)(hjGj−1N) = gjGj−1hjNGj−1N

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-97
SLIDE 97

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj. Now let gjGj−1N,hjGj−1N ∈ (GjN/N)/(Gj−1N/N). Then (gjGj−1N)(hjGj−1N) = gjGj−1hjNGj−1N = gjGj−1hjGj−1NN

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-98
SLIDE 98

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj. Now let gjGj−1N,hjGj−1N ∈ (GjN/N)/(Gj−1N/N). Then (gjGj−1N)(hjGj−1N) = gjGj−1hjNGj−1N = gjGj−1hjGj−1NN = hjGj−1gjGj−1NN

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-99
SLIDE 99

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj. Now let gjGj−1N,hjGj−1N ∈ (GjN/N)/(Gj−1N/N). Then (gjGj−1N)(hjGj−1N) = gjGj−1hjNGj−1N = gjGj−1hjGj−1NN = hjGj−1gjGj−1NN = hjGj−1gjNGj−1N

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-100
SLIDE 100

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj. Now let gjGj−1N,hjGj−1N ∈ (GjN/N)/(Gj−1N/N). Then (gjGj−1N)(hjGj−1N) = gjGj−1hjNGj−1N = gjGj−1hjGj−1NN = hjGj−1gjGj−1NN = hjGj−1gjNGj−1N = (hjGj−1N)(gjGj−1N)

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-101
SLIDE 101

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj. Now let gjGj−1N,hjGj−1N ∈ (GjN/N)/(Gj−1N/N). Then (gjGj−1N)(hjGj−1N) = gjGj−1hjNGj−1N = gjGj−1hjGj−1NN = hjGj−1gjGj−1NN = hjGj−1gjNGj−1N = (hjGj−1N)(gjGj−1N), which means that (GjN/N)/(Gj−1N/N) is commutative.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-102
SLIDE 102

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj. Now let gjGj−1N,hjGj−1N ∈ (GjN/N)/(Gj−1N/N). Then (gjGj−1N)(hjGj−1N) = gjGj−1hjNGj−1N = gjGj−1hjGj−1NN = hjGj−1gjGj−1NN = hjGj−1gjNGj−1N = (hjGj−1N)(gjGj−1N), which means that (GjN/N)/(Gj−1N/N) is commutative. Therefore, {eN} = G0N/N ⊳G1N/N ⊳···⊳GmN/N = G/N is a chain of subgroups as in the definition of solvability.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 103

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (concl.). (GjN/N)/(Gj−1N/N) is commutative: The elements of (GjN/N)/(Gj−1N/N) are of the form gjNGj−1N with gj ∈ Gj. Hence each element of (GjN/N)/(Gj−1N/N) is of the form gjNGj−1N = gjGj−1NN = gjGj−1N with gj ∈ Gj. Now let gjGj−1N,hjGj−1N ∈ (GjN/N)/(Gj−1N/N). Then (gjGj−1N)(hjGj−1N) = gjGj−1hjNGj−1N = gjGj−1hjGj−1NN = hjGj−1gjGj−1NN = hjGj−1gjNGj−1N = (hjGj−1N)(gjGj−1N), which means that (GjN/N)/(Gj−1N/N) is commutative. Therefore, {eN} = G0N/N ⊳G1N/N ⊳···⊳GmN/N = G/N is a chain of subgroups as in the definition of solvability.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 104

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Theorem.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 105

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 106

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 107

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 108

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F. Proof (q ≤ 2).

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 109

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F. Proof (q ≤ 2). Because q = [Fq : F]

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 110

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F. Proof (q ≤ 2). Because q = [Fq : F], the case q = 1 is trivial

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 111

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F. Proof (q ≤ 2). Because q = [Fq : F], the case q = 1 is trivial (F is the splitting field of x−1).

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 112

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F. Proof (q ≤ 2). Because q = [Fq : F], the case q = 1 is trivial (F is the splitting field of x−1). In case q = 2, F2 = F(w2) for some w2 ∈ F2 with wn1

2 ∈ F.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 113

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F. Proof (q ≤ 2). Because q = [Fq : F], the case q = 1 is trivial (F is the splitting field of x−1). In case q = 2, F2 = F(w2) for some w2 ∈ F2 with wn1

2 ∈ F. If w2

is a primitive nst

1 root of unity, let E := F2.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 114

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F. Proof (q ≤ 2). Because q = [Fq : F], the case q = 1 is trivial (F is the splitting field of x−1). In case q = 2, F2 = F(w2) for some w2 ∈ F2 with wn1

2 ∈ F. If w2

is a primitive nst

1 root of unity, let E := F2. Otherwise, let θ be a

primitive nst

1 root of unity and let E := F2(θ).

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 115

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F. Proof (q ≤ 2). Because q = [Fq : F], the case q = 1 is trivial (F is the splitting field of x−1). In case q = 2, F2 = F(w2) for some w2 ∈ F2 with wn1

2 ∈ F. If w2

is a primitive nst

1 root of unity, let E := F2. Otherwise, let θ be a

primitive nst

1 root of unity and let E := F2(θ). In either case, E

is a normal extension of F2

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 116

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F. Proof (q ≤ 2). Because q = [Fq : F], the case q = 1 is trivial (F is the splitting field of x−1). In case q = 2, F2 = F(w2) for some w2 ∈ F2 with wn1

2 ∈ F. If w2

is a primitive nst

1 root of unity, let E := F2. Otherwise, let θ be a

primitive nst

1 root of unity and let E := F2(θ). In either case, E

is a normal extension of F2 (because E is the splitting field of xn1 −1)

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 117

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

F = F1 ⊆ F2 ⊆ ··· ⊆ Fq be a root tower for Fq over F. Then there is normal extension E of Fq that has a root tower over F. Proof (q ≤ 2). Because q = [Fq : F], the case q = 1 is trivial (F is the splitting field of x−1). In case q = 2, F2 = F(w2) for some w2 ∈ F2 with wn1

2 ∈ F. If w2

is a primitive nst

1 root of unity, let E := F2. Otherwise, let θ be a

primitive nst

1 root of unity and let E := F2(θ). In either case, E

is a normal extension of F2 (because E is the splitting field of xn1 −1) that has the root tower F ⊆ F2 ⊆ E over F.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 118

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction).

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 119

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction). Let F′

q−1 be a normal extension of

Fq−1 that has a root tower over F.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 120

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction). Let F′

q−1 be a normal extension of

Fq−1 that has a root tower over F. By assumption, Fq = Fq−1(wq) for some wq with w

nq−1 q

∈ Fq−1.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 121

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction). Let F′

q−1 be a normal extension of

Fq−1 that has a root tower over F. By assumption, Fq = Fq−1(wq) for some wq with w

nq−1 q

∈ Fq−1. Let f(x) :=

σ∈G(F′

q−1/F)

  • xnq−1 −σ
  • w

nq−1 q

  • .

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 122

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction). Let F′

q−1 be a normal extension of

Fq−1 that has a root tower over F. By assumption, Fq = Fq−1(wq) for some wq with w

nq−1 q

∈ Fq−1. Let f(x) :=

σ∈G(F′

q−1/F)

  • xnq−1 −σ
  • w

nq−1 q

  • . For all

ϕ ∈ G(F′

q−1/F) we have

˜ ϕ(f)

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 123

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction). Let F′

q−1 be a normal extension of

Fq−1 that has a root tower over F. By assumption, Fq = Fq−1(wq) for some wq with w

nq−1 q

∈ Fq−1. Let f(x) :=

σ∈G(F′

q−1/F)

  • xnq−1 −σ
  • w

nq−1 q

  • . For all

ϕ ∈ G(F′

q−1/F) we have

˜ ϕ(f) =

σ∈G(F′

q−1/F)

  • xnq−1 −ϕσ
  • w

nq−1 q

  • Bernd Schr¨
  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 124

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction). Let F′

q−1 be a normal extension of

Fq−1 that has a root tower over F. By assumption, Fq = Fq−1(wq) for some wq with w

nq−1 q

∈ Fq−1. Let f(x) :=

σ∈G(F′

q−1/F)

  • xnq−1 −σ
  • w

nq−1 q

  • . For all

ϕ ∈ G(F′

q−1/F) we have

˜ ϕ(f) =

σ∈G(F′

q−1/F)

  • xnq−1 −ϕσ
  • w

nq−1 q

  • =

γ∈G(F′

q−1/F)

  • xnq−1 −γ
  • w

nq−1 q

  • Bernd Schr¨
  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 125

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction). Let F′

q−1 be a normal extension of

Fq−1 that has a root tower over F. By assumption, Fq = Fq−1(wq) for some wq with w

nq−1 q

∈ Fq−1. Let f(x) :=

σ∈G(F′

q−1/F)

  • xnq−1 −σ
  • w

nq−1 q

  • . For all

ϕ ∈ G(F′

q−1/F) we have

˜ ϕ(f) =

σ∈G(F′

q−1/F)

  • xnq−1 −ϕσ
  • w

nq−1 q

  • =

γ∈G(F′

q−1/F)

  • xnq−1 −γ
  • w

nq−1 q

  • = f

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 126

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction). Let F′

q−1 be a normal extension of

Fq−1 that has a root tower over F. By assumption, Fq = Fq−1(wq) for some wq with w

nq−1 q

∈ Fq−1. Let f(x) :=

σ∈G(F′

q−1/F)

  • xnq−1 −σ
  • w

nq−1 q

  • . For all

ϕ ∈ G(F′

q−1/F) we have

˜ ϕ(f) =

σ∈G(F′

q−1/F)

  • xnq−1 −ϕσ
  • w

nq−1 q

  • =

γ∈G(F′

q−1/F)

  • xnq−1 −γ
  • w

nq−1 q

  • = f,

so the coefficients of f are in the fixed field F of G(F′

q−1/F).

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 127

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction). Let F′

q−1 be a normal extension of

Fq−1 that has a root tower over F. By assumption, Fq = Fq−1(wq) for some wq with w

nq−1 q

∈ Fq−1. Let f(x) :=

σ∈G(F′

q−1/F)

  • xnq−1 −σ
  • w

nq−1 q

  • . For all

ϕ ∈ G(F′

q−1/F) we have

˜ ϕ(f) =

σ∈G(F′

q−1/F)

  • xnq−1 −ϕσ
  • w

nq−1 q

  • =

γ∈G(F′

q−1/F)

  • xnq−1 −γ
  • w

nq−1 q

  • = f,

so the coefficients of f are in the fixed field F of G(F′

q−1/F).

Hence f ∈ F[x].

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 128

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.).

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 129

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 130

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 131

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x].

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 132

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 133

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E and any field in which fg splits must contain F′

q−1

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 134

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E and any field in which fg splits must contain F′

q−1 as well as the elements that must be adjoined to it to

  • btain E.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 135

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E and any field in which fg splits must contain F′

q−1 as well as the elements that must be adjoined to it to

  • btain E. Hence E is the splitting field of fg

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 136

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E and any field in which fg splits must contain F′

q−1 as well as the elements that must be adjoined to it to

  • btain E. Hence E is the splitting field of fg and thus E is a

normal extension of F.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 137

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E and any field in which fg splits must contain F′

q−1 as well as the elements that must be adjoined to it to

  • btain E. Hence E is the splitting field of fg and thus E is a

normal extension of F. By definition of f, E is obtained from F′

q−1 by adjoining nst q−1

roots.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 138

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E and any field in which fg splits must contain F′

q−1 as well as the elements that must be adjoined to it to

  • btain E. Hence E is the splitting field of fg and thus E is a

normal extension of F. By definition of f, E is obtained from F′

q−1 by adjoining nst q−1

  • roots. Hence E has a root tower over F′

q−1.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 139

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E and any field in which fg splits must contain F′

q−1 as well as the elements that must be adjoined to it to

  • btain E. Hence E is the splitting field of fg and thus E is a

normal extension of F. By definition of f, E is obtained from F′

q−1 by adjoining nst q−1

  • roots. Hence E has a root tower over F′

q−1. Appending this root

tower to the root tower for F′

q−1 over F produces a root tower

for E over F.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 140

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E and any field in which fg splits must contain F′

q−1 as well as the elements that must be adjoined to it to

  • btain E. Hence E is the splitting field of fg and thus E is a

normal extension of F. By definition of f, E is obtained from F′

q−1 by adjoining nst q−1

  • roots. Hence E has a root tower over F′

q−1. Appending this root

tower to the root tower for F′

q−1 over F produces a root tower

for E over F. Finally, wq is a root of f.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 141

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E and any field in which fg splits must contain F′

q−1 as well as the elements that must be adjoined to it to

  • btain E. Hence E is the splitting field of fg and thus E is a

normal extension of F. By definition of f, E is obtained from F′

q−1 by adjoining nst q−1

  • roots. Hence E has a root tower over F′

q−1. Appending this root

tower to the root tower for F′

q−1 over F produces a root tower

for E over F. Finally, wq is a root of f. Hence E must contain the field Fq = Fq−1(wq).

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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SLIDE 142

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

Proof (q > 2, induction, concl.). Let E be the splitting field of f over F′

q−1. Because F′ q−1 is a normal extension of F, it is the

splitting field of a polynomial g ∈ F[x]. The polynomial fg ∈ F[x] splits in E and any field in which fg splits must contain F′

q−1 as well as the elements that must be adjoined to it to

  • btain E. Hence E is the splitting field of fg and thus E is a

normal extension of F. By definition of f, E is obtained from F′

q−1 by adjoining nst q−1

  • roots. Hence E has a root tower over F′

q−1. Appending this root

tower to the root tower for F′

q−1 over F produces a root tower

for E over F. Finally, wq is a root of f. Hence E must contain the field Fq = Fq−1(wq).

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Theorem.

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F.

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable. Proof.

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F, let n := n1 ···nq−1

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F, let n := n1 ···nq−1 and let θ be a primitive nth root of

unity.

Bernd Schr¨

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F, let n := n1 ···nq−1 and let θ be a primitive nth root of
  • unity. For all j ∈ {2,...,q} we have Fj(θ) = Fj−1(θ)(wj)

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F, let n := n1 ···nq−1 and let θ be a primitive nth root of
  • unity. For all j ∈ {2,...,q} we have Fj(θ) = Fj−1(θ)(wj) and

θ

n1···nq−1 nj−1

∈ Fj−1(θ) is a primitive nst

j−1 root of unity.

Bernd Schr¨

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F, let n := n1 ···nq−1 and let θ be a primitive nth root of
  • unity. For all j ∈ {2,...,q} we have Fj(θ) = Fj−1(θ)(wj) and

θ

n1···nq−1 nj−1

∈ Fj−1(θ) is a primitive nst

j−1 root of unity. Thus Fj(θ)

is a normal extension of Fj−1(θ)

Bernd Schr¨

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F, let n := n1 ···nq−1 and let θ be a primitive nth root of
  • unity. For all j ∈ {2,...,q} we have Fj(θ) = Fj−1(θ)(wj) and

θ

n1···nq−1 nj−1

∈ Fj−1(θ) is a primitive nst

j−1 root of unity. Thus Fj(θ)

is a normal extension of Fj−1(θ) and it has a commutative Galois group G

  • Fj(θ)/Fj−1(θ)
  • .

Bernd Schr¨

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F, let n := n1 ···nq−1 and let θ be a primitive nth root of
  • unity. For all j ∈ {2,...,q} we have Fj(θ) = Fj−1(θ)(wj) and

θ

n1···nq−1 nj−1

∈ Fj−1(θ) is a primitive nst

j−1 root of unity. Thus Fj(θ)

is a normal extension of Fj−1(θ) and it has a commutative Galois group G

  • Fj(θ)/Fj−1(θ)
  • .

E is the splitting field of a polynomial g ∈ F[x].

Bernd Schr¨

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F, let n := n1 ···nq−1 and let θ be a primitive nth root of
  • unity. For all j ∈ {2,...,q} we have Fj(θ) = Fj−1(θ)(wj) and

θ

n1···nq−1 nj−1

∈ Fj−1(θ) is a primitive nst

j−1 root of unity. Thus Fj(θ)

is a normal extension of Fj−1(θ) and it has a commutative Galois group G

  • Fj(θ)/Fj−1(θ)
  • .

E is the splitting field of a polynomial g ∈ F[x]. Then E(θ) is the splitting field of g(x)(xn −1).

Bernd Schr¨

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F, let n := n1 ···nq−1 and let θ be a primitive nth root of
  • unity. For all j ∈ {2,...,q} we have Fj(θ) = Fj−1(θ)(wj) and

θ

n1···nq−1 nj−1

∈ Fj−1(θ) is a primitive nst

j−1 root of unity. Thus Fj(θ)

is a normal extension of Fj−1(θ) and it has a commutative Galois group G

  • Fj(θ)/Fj−1(θ)
  • .

E is the splitting field of a polynomial g ∈ F[x]. Then E(θ) is the splitting field of g(x)(xn −1). Hence E(θ) is a normal extension of F

Bernd Schr¨

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  • Theorem. Let F be a field of characteristic 0 and let E be a

normal extension with a root tower over F. Then the Galois group G(E/F) is solvable.

  • Proof. Let F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E be a root tower for E
  • ver F, let n := n1 ···nq−1 and let θ be a primitive nth root of
  • unity. For all j ∈ {2,...,q} we have Fj(θ) = Fj−1(θ)(wj) and

θ

n1···nq−1 nj−1

∈ Fj−1(θ) is a primitive nst

j−1 root of unity. Thus Fj(θ)

is a normal extension of Fj−1(θ) and it has a commutative Galois group G

  • Fj(θ)/Fj−1(θ)
  • .

E is the splitting field of a polynomial g ∈ F[x]. Then E(θ) is the splitting field of g(x)(xn −1). Hence E(θ) is a normal extension of F and of each Fj(θ).

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Proof (concl.).

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ)

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • Bernd Schr¨
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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • Bernd Schr¨
  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F (it’s the splitting field of xn −θ n

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F (it’s the splitting field of xn −θ n = xn −1)

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F (it’s the splitting field of xn −θ n = xn −1) and G

  • E(θ)/F
  • /G
  • E(θ)/F(θ)
  • is

isomorphic to G

  • F(θ)/F
  • .

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F (it’s the splitting field of xn −θ n = xn −1) and G

  • E(θ)/F
  • /G
  • E(θ)/F(θ)
  • is

isomorphic to G

  • F(θ)/F
  • . This group is commutative

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F (it’s the splitting field of xn −θ n = xn −1) and G

  • E(θ)/F
  • /G
  • E(θ)/F(θ)
  • is

isomorphic to G

  • F(θ)/F
  • . This group is commutative (good

exercise, similar to the proof of this presentation’s first theorem).

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F (it’s the splitting field of xn −θ n = xn −1) and G

  • E(θ)/F
  • /G
  • E(θ)/F(θ)
  • is

isomorphic to G

  • F(θ)/F
  • . This group is commutative (good

exercise, similar to the proof of this presentation’s first theorem). Hence G

  • E(θ)/F
  • is solvable.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F (it’s the splitting field of xn −θ n = xn −1) and G

  • E(θ)/F
  • /G
  • E(θ)/F(θ)
  • is

isomorphic to G

  • F(θ)/F
  • . This group is commutative (good

exercise, similar to the proof of this presentation’s first theorem). Hence G

  • E(θ)/F
  • is solvable.

By hypothesis, E is a normal extension of F

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F (it’s the splitting field of xn −θ n = xn −1) and G

  • E(θ)/F
  • /G
  • E(θ)/F(θ)
  • is

isomorphic to G

  • F(θ)/F
  • . This group is commutative (good

exercise, similar to the proof of this presentation’s first theorem). Hence G

  • E(θ)/F
  • is solvable.

By hypothesis, E is a normal extension of F, and by the Fundamental Theorem of Galois Theory G(E/F) is isomorphic to G

  • E(θ)/F
  • /G
  • E(θ)/E)
  • Bernd Schr¨
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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F (it’s the splitting field of xn −θ n = xn −1) and G

  • E(θ)/F
  • /G
  • E(θ)/F(θ)
  • is

isomorphic to G

  • F(θ)/F
  • . This group is commutative (good

exercise, similar to the proof of this presentation’s first theorem). Hence G

  • E(θ)/F
  • is solvable.

By hypothesis, E is a normal extension of F, and by the Fundamental Theorem of Galois Theory G(E/F) is isomorphic to G

  • E(θ)/F
  • /G
  • E(θ)/E)
  • , which is solvable.

Bernd Schr¨

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Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

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Proof (concl.). In the root tower F ⊆ F(θ) = F1(θ) ⊆ F2(θ) ⊆ ··· ⊆ Fq(θ) = E(θ), for each j ∈ {2,...,q} the group G

  • E(θ)/Fj(θ)
  • is a normal subgroup
  • f G
  • E(θ)/Fj−1(θ)
  • and G
  • E(θ)/Fj−1(θ)
  • /G
  • E(θ)/Fj(θ)
  • is isomorphic to G
  • Fj(θ)/Fj−1(θ)
  • , which is commutative.

Moreover, F(θ) is a normal extension of F (it’s the splitting field of xn −θ n = xn −1) and G

  • E(θ)/F
  • /G
  • E(θ)/F(θ)
  • is

isomorphic to G

  • F(θ)/F
  • . This group is commutative (good

exercise, similar to the proof of this presentation’s first theorem). Hence G

  • E(θ)/F
  • is solvable.

By hypothesis, E is a normal extension of F, and by the Fundamental Theorem of Galois Theory G(E/F) is isomorphic to G

  • E(θ)/F
  • /G
  • E(θ)/E)
  • , which is solvable.

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Theorem.

Bernd Schr¨

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SLIDE 175

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

p ∈ F[x] be so that p(x) = 0 is solvable by radicals.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-176
SLIDE 176

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

p ∈ F[x] be so that p(x) = 0 is solvable by radicals. Then the Galois group of p is solvable.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-177
SLIDE 177

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

p ∈ F[x] be so that p(x) = 0 is solvable by radicals. Then the Galois group of p is solvable. Proof.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-178
SLIDE 178

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

p ∈ F[x] be so that p(x) = 0 is solvable by radicals. Then the Galois group of p is solvable.

  • Proof. Let S be the splitting field of p over F.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-179
SLIDE 179

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

p ∈ F[x] be so that p(x) = 0 is solvable by radicals. Then the Galois group of p is solvable.

  • Proof. Let S be the splitting field of p over F. Because there is a

root tower over F whose top field contains all the roots of p, there is a normal extension E of S that has a root tower F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-180
SLIDE 180

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

p ∈ F[x] be so that p(x) = 0 is solvable by radicals. Then the Galois group of p is solvable.

  • Proof. Let S be the splitting field of p over F. Because there is a

root tower over F whose top field contains all the roots of p, there is a normal extension E of S that has a root tower F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E. Moreover, G(E/F) is solvable.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-181
SLIDE 181

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

p ∈ F[x] be so that p(x) = 0 is solvable by radicals. Then the Galois group of p is solvable.

  • Proof. Let S be the splitting field of p over F. Because there is a

root tower over F whose top field contains all the roots of p, there is a normal extension E of S that has a root tower F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E. Moreover, G(E/F) is solvable. By the Fundamental Theorem of Galois Theory, G(S/F) is isomorphic to G(E/F)/G(E/S)

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-182
SLIDE 182

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

p ∈ F[x] be so that p(x) = 0 is solvable by radicals. Then the Galois group of p is solvable.

  • Proof. Let S be the splitting field of p over F. Because there is a

root tower over F whose top field contains all the roots of p, there is a normal extension E of S that has a root tower F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E. Moreover, G(E/F) is solvable. By the Fundamental Theorem of Galois Theory, G(S/F) is isomorphic to G(E/F)/G(E/S), which is solvable.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals

slide-183
SLIDE 183

logo1 Commutative Galois Groups Solvable Groups Better Root Towers Solvable Galois Groups

  • Theorem. Let (F,+,·) be a field of characteristic 0 and let

p ∈ F[x] be so that p(x) = 0 is solvable by radicals. Then the Galois group of p is solvable.

  • Proof. Let S be the splitting field of p over F. Because there is a

root tower over F whose top field contains all the roots of p, there is a normal extension E of S that has a root tower F = F1 ⊆ F2 ⊆ ··· ⊆ Fq = E. Moreover, G(E/F) is solvable. By the Fundamental Theorem of Galois Theory, G(S/F) is isomorphic to G(E/F)/G(E/S), which is solvable.

Bernd Schr¨

  • der

Louisiana Tech University, College of Engineering and Science Consequences of Solvability by Radicals