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Climate Dynamics (lecture 10) Stommel model of the thermohaline - PDF document

Climate Dynamics (lecture 10) Stommel model of the thermohaline circulation (THC) Role of the ocean in climate variability, in particular during last glacial period http://www.phys.uu.nl/~nvdelden/ The meridional overturning circulation (MOC)


  1. Climate Dynamics (lecture 10) Stommel model of the thermohaline circulation (THC) Role of the ocean in climate variability, in particular during last glacial period http://www.phys.uu.nl/~nvdelden/ The meridional overturning circulation (MOC) Wind- and density-driven The thermohaline circulation (THC) is the density-driven part Nature, 1 Dec. 2005 Nature, 19 Jan. 2006 1

  2. Nature 419, 207-214 (12 September 2002) A highly simplified but very interesting model of the THC Stommel model of the THC H 2 H 1 (Taylor, 2005) Two reservoirs of well-mixed water connected by “pipes” represent the polar and equatorial regions of the ocean at temperatures T 1 and T 2 (fixed for simplicity).The principle variable is the salinity of the water, S , which is affected by a “virtual” flux H of salt from the atmosphere (see also the previous slide). The flow of water q between the boxes is proportional to the density difference. Conservation salt is expressed by dS 1 ) ; dS 2 dt = H 1 + q S 2 � S 1 ( dt = H 2 + q S 1 � S 2 ( ) 2

  3. Density of sea- water The flux is given by q = k ( � 1 � � 2 ) � 0 k is an unknown coefficient with the dimension [s -1 ]. The equation of state for sea water is (approximately) (see the figure) � = � 0 1 � � T + � S ( ) α (>0) is the thermal expansion coeff.; β (>0) is the haline contraction coeff. q = k � � = k � � T � � � S ( ) � 0 with Stommel model � T = T 2 � T 1 ; � S = S 2 � S 1 ; � � = � 1 � � 2 dS 1 ) ; dS 2 dt = H 1 + q S 2 � S 1 ( dt = H 2 + q S 1 � S 2 ( ) The salt flux from the atmosphere is given by H i . H i is prescribed as follows* H i = � � i S i � S i 0 ( ) Equilibrium value in absence of meridional transport What processes govern these equilibrium values? * Later we will prescribe H in a different manner 3

  4. Stommel model dS 1 ) ; dS 2 dt = H 1 + q S 2 � S 1 ( dt = H 2 + q S 1 � S 2 ( ) q = k H i = � � i S i � S i 0 ( ) � � = k � � T � � � S ( ) � 0 Two timescales: � 1 � 1 k ; � 2 � 1 � i Associated Associated with with intensity of freshening the ocean of the circulation ocean Stommel model dS 1 ) ; dS 2 dt = H 1 + q S 2 � S 1 ( dt = H 2 + q S 1 � S 2 ( ) q = k H i = � � i S i � S i 0 ( ) � � = k � � T � � � S ( ) � 0 � S � S 2 � S 1 � 1 = � 2 = � d � S dt = � � � S � � S 0 ( ) � 2 k � � T � � � S ( ) � S � S 0 � S 20 � S 10 Free parameters are � T and � S 0 Which relaxation parameter do you think is greater, λ or k ? Why? 4

  5. Stommel model Two timescales: Total global fresh water input is τ 2 associated 1 Sv=10 6 m 3 s -1 . with � 1 � 1 k ; � 2 � 1 freshening of Associated timescale of the ocean � i freshening of the upper 100 m of the ocean is dV / dt � 100 � 0.7 � {area globe} V � 10 3 years 10 6 HUGE! Intensity of the Gulfstream is 30- τ 1 associated 150 Sv. with intensity of the ocean Therefore τ 1 is about a factor 100 circulation smaller than τ 2 Therefore: � i � 3 � 10 � 11 s -1 ; k � 3 � 10 � 9 s -1 ( ) � 1 = � 2 Steady states of Stommel model d � S dt = � � � S � � S 0 ( ) � 2 k � � T � � � S ( ) � S = 0 ( q >0) if � � T > � � S � � � S � � S 0 ( ) � 2 k � � T � � � S ( ) � S = 0 1/2 � 2 � � � S = + 1 � � ± 1 � � � 2 �� � S 0 � � � � T > � � S !!! � 2 k + � � T � � 2 k + � � T � � � if � � � � 2 2 k � � two solutions possible (thermally driven) (solution 1&2) ( q <0) � � � S � � S 0 ( ) � 2 k � � S � � � T ( ) � S = 0 if � � T < � � S 1/2 � 2 � � � S = 1 � � � � ± 1 � � � � + 2 �� � S 0 � � T < � � S !!! 2 k + � � T 2 k + � � T � � � � � � 2 � � 2 � � k � � (solution 3) Minus-sign discarded because � � S > 0 So, this gives one solution (salt driven circulation) 5

  6. two solutions for thermally driven circulation Multiple 2 equilibria � � > 2 �� � S 0 � if 2 k + � � T � � � � k Exercise Plot the steady state solutions in a graph with q along the vertical axis and the meridional temperature difference along the horizontal axis and determine the stability of these solutions. Discuss the implications of the result (see also , the following slide). Multiple equilibria The thermohaline circulation is responsible for a large part of the heat transport The thermohaline circulation is sensitive to freshwater”forcing” Stefan Rahmstorf, 2002: Nature, 419, 207-214 6

  7. Numerical integration of the Stommel model ) q = k dS 1 ) ; dS 2 � � = k � � T � � � S ( ) dt = H 1 + q S 2 � S 1 ( dt = H 2 + q S 1 � S 2 ( � 0 H i = � � i S i � S i 0 ( ) d � S dt = � � � S � � S 0 ( ) � 2 k � � T � � � S ( ) � S � S 0 = 10 i.e. it is 10 parts per thousands saltier in the south than in the north � i = 3 � 10 � 11 s -1 ; k = 3 � 10 � 9 s -1 � = 0.0002 K -1 ; � = 0.001 At t = 0 � S = 10 parts per thousand The Runge-Kutta scheme is used to approximate the time derivative Result of an integration lasting 6450 years Circulation intensity See: http://www.phys.uu.nl/~nvdelden/Stommel.htm q: flux at t=6450 years q1: solution 1 q2: solution 2 q3: solution 3 � S 0 = 10 not in a steady state 7

  8. Different formulation salt flux Stommel-Taylor model � T = T 2 � T 1 ; � S = S 2 � S 1 ; � � = � 1 � � 2 dS 1 ) ; dS 2 dt = H 1 + q S 2 � S 1 ( dt = H 2 + q S 1 � S 2 ( ) The salt flux from the atmosphere is given by H i . H i is prescribed as follows H 2 = � H 1 � H > 0 d � S dt = 2 H � 2 k � � T � � � S ( ) � S Y � � � S ; X � � � T dY dt = 2 � H � 2 k X � Y ( ) Y Stommel-Taylor model dY dt = 2 � H � 2 k X � Y ( ) Y Steady states: ( ) Y 0 = 2 � H � 2 k X � Y 1/2 Y � Y 0 = X 2 ± 1 2 X 2 � 4 � H � � if � � T > � � S � � (solution 1&2) � � k 1/2 Y � Y 0 = X 2 ± 1 2 X 2 + 4 � H � � (solution 3) � � if � � T < � � S � � k Minus-sign discarded because � � S > 0 8

  9. Stability analysis 1/2 Y 0 = X 2 + 1 2 X 2 + 4 � H � � (1) � � T < � � S (solution 3) � � � � k Salt driven dY (2) dt = 2 � H � 2 k X � Y ( ) Y Suppose Y � Y 0 + Y ' Y ' << Y 0 (small perturbation to the steady state) Substitute in (2) using (1): 1/2 dY ' dt = � 2 k X 2 + 4 � H � � Y ' � � � k � 1/2 � = � 2 k X 2 + 4 � H � � growthrate: < 0 � � Y ' = A exp � t ( ) � � k Therefore perturbation dies out: solution 3 is always stable to small perturbations Stability analysis temperature driven � � T > � � S Same analysis as on previous slide: 1/2 Y 0 = X 2 � 1 2 X 2 � 4 � H � � solution 1: is stable ( � < 0) � � � � k X 2 > 4 � H if k 1/2 Y 0 = X 2 + 1 2 X 2 � 4 � H � � solution 2: is unstable ( � > 0) � � � � k X 2 > 4 � H if k System can “jump” from one stable steady state to another stable steady state 9

  10. Stability analysis Condition for existence of temperature driven circulation: Solution 3 X 2 > 4 � H Solution 2 k corresponds to Solution 1 E = � H � H 2 < 1 kX 2 = 4 k � � T ( ) Taylor (2005) Does this kind of non-linear behaviour have something to do with… Strong climate variations during last glacial period (?) δ 18 O from the GISP2 ice core . Time runs from left to right. This normalized ratio of 18 0 to 16 0 concentrations is believed to track local atmospheric temperatures in central Greenland to within an approximate factor of two. Large positive spikes are called Dansgaard-Oeschger (D-O) events and are correlated with abrupt warming. Note in particular the quiescence of the Holocene interval (approximately the last 10,000 yr) relative to the preceding glacial period . The Holocene coincides with the removal of the Laurentide and Fennoscandian ice sheets. The range of excursion corresponds to about 15°C. Time control degrades with increasing age of the record. 10

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