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Chapter 8 Section 2 MA1032 Data, Functions & Graphs Sidney Butler Michigan Technological University November 29, 2006 S Butler (Michigan Tech) Chapter 8 Section 2 November 29, 2006 1 / 9 Exercise Let f 1 ( x ) = x , f 2 ( x ) = 1 1


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SLIDE 1

Chapter 8 Section 2

MA1032 Data, Functions & Graphs Sidney Butler

Michigan Technological University

November 29, 2006

S Butler (Michigan Tech) Chapter 8 Section 2 November 29, 2006 1 / 9

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SLIDE 2

Exercise

Let f1(x) = x, f2(x) = 1

x , f3(x) = 1 − x, f4(x) = 1 1−x , f5(x) = x−1 x , and

f6(x) =

x x−1. Note that

  • f1

f2 f3 f4 f5 f6 f1 f1 f2 f3 f4 f5 f6 f2 f2 f1 f4 f3 f6 f5 f3 f3 f5 f1 f6 f2 f4 f4 f4 f6 f2 f5 f1 f3 f5 f5 f3 f6 f1 f4 f2 f6 f6 f4 f5 f2 f3 f1

S Butler (Michigan Tech) Chapter 8 Section 2 November 29, 2006 2 / 9

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Inverse

Definition Suppose Q = f (t) is a function with the property that each value of Q determines exactly one value of t. Then f has an inverse function, f −1 and f −1(Q) = t if and only if Q = f (t). If a function has an inverse, it is said to be invertible.

S Butler (Michigan Tech) Chapter 8 Section 2 November 29, 2006 3 / 9

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Properties

If y = f (x) is an invertible function and y = f −1(x) is its inverse, then f −1(f (x)) = x for all values of x for which f (x) is defined. f (f −1(x)) = x for all values of x for which f −1(x) is defined. Example Check that g(x) = 1 −

1 x−1 and f (x) = 1 + 1 1−x are inverses of each other.

S Butler (Michigan Tech) Chapter 8 Section 2 November 29, 2006 4 / 9

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Finding an Inverse

Example Find the inverse of h(x) =

√x √x+1.

S Butler (Michigan Tech) Chapter 8 Section 2 November 29, 2006 5 / 9

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Non-Invertible Functions

Example Does f (x) = x2 have an inverse? Horizontal Line Test Domain of f −1 = Range of f Range of f −1 = Domain of f

S Butler (Michigan Tech) Chapter 8 Section 2 November 29, 2006 6 / 9

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SLIDE 7

Restricting the Domain Could we make x2 invertible?

S Butler (Michigan Tech) Chapter 8 Section 2 November 29, 2006 7 / 9

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SLIDE 8

Summary

Definition Properties Finding an Inverse Domain & Range

S Butler (Michigan Tech) Chapter 8 Section 2 November 29, 2006 8 / 9

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SLIDE 9

Exercise

Let f1(x) = x, f2(x) = 1

x , f3(x) = 1 − x, f4(x) = 1 1−x , f5(x) = x−1 x , and

f6(x) =

x x−1. Note that

  • f1

f2 f3 f4 f5 f6 f1 f1 f2 f3 f4 f5 f6 f2 f2 f1 f4 f3 f6 f5 f3 f3 f5 f1 f6 f2 f4 f4 f4 f6 f2 f5 f1 f3 f5 f5 f3 f6 f1 f4 f2 f6 f6 f4 f5 f2 f3 f1 Using the table above, find the following:

1 f −1 6 2 (f3 ◦ f6)−1 3 F if f2 ◦ f5 ◦ F = f5.

S Butler (Michigan Tech) Chapter 8 Section 2 November 29, 2006 9 / 9