calculating bounds on expected return and first passage
play

Calculating bounds on expected return and first passage times in - PowerPoint PPT Presentation

Calculating bounds on expected return and first passage times in finite-state imprecise birth-death chains Stavros Lopatatzidis, Jasper De Bock and Gert de Cooman Birth-death chains Birth-death chain special type of Markov chain X : =


  1. Calculating bounds on expected return and first passage times in finite-state imprecise birth-death chains Stavros Lopatatzidis, Jasper De Bock and Gert de Cooman

  2. Birth-death chains Birth-death chain special type of Markov chain X : = { 0 ,..., L } Finite state space , with L ∈ N X k : n Random variable and a sequence of variables , with and X n k , n ∈ N k ≤ n A sequence can be infinite as well X k : ∞ x 1: n : = x 1 ,..., x n Sequence of state values in X n E n + 1 ( ·| x 1: n ) = E n + 1 ( ·| x n ) , ∀ x 1: n ∈ X n Markov condition p ( X n + 1 | x n ) E n + 1 ( ·| x n ) where is the expectation operator with p.m.f 0 1 r 0 p 0 0 · · · · · · 0 q 1 r 1 p 1 0 · · · 0 B C . . B C ... ... ... ... for time-homogeneous . . P = B C p . . B C B C 0 · · · 0 q L − 1 r L − 1 p L − 1 @ A 0 · · · · · · 0 q L r L

  3. Imprecise birth-death chains Consider a matrix with p.m.f. not precisely known P For every , the p.m.f. of the row belong to a credal set i ∈ X M i i φ i and consists of elements of the form  if j = i − 1 q i   if j = L − 1 if j = 0  q L r 0    if j = i  r i    φ L ( j ) = φ 0 ( j ) = if j = L φ i ( j ) = i ∈ X \{ 0 , L } if j = 1 r L p 0 if j = i + 1 p i    0 otherwise 0 otherwise      0 otherwise i ∈ X \{ 0 , L } q i , r i , p i Positivity assumption: and for all strictly positive r 0 , p 0 , r L , q L

  4. Imprecise Markov condition f Lower and upper expectations of real-valued function on X ⇢ � ∑ E ( f | i ) : = min E φ i ( f ) = min φ i ( j ) f ( j ) φ i ∈ M i φ i ∈ M i j ∈ X ⇢ � ∑ E ( f | i ) : = max E φ i ( f ) = max φ i ( j ) f ( j ) φ i ∈ M i φ i ∈ M i j ∈ X x 1: n ∈ X n and for all , the imprecise Markov condition is E n + 1 ( ·| x 1: n ) = E n + 1 ( ·| x n ) : = E ( ·| x n )

  5. Global uncertainty models Based on the notion of submartingales, we derive global uncertainty models These models satisfy a version of the Law of Iterated expectation X N For every and every real-valued function on n ∈ N g (time-homogeneity) E n +1: 1 ( g ( X n +1: 1 ) | i ) = E n +2: 1 ( g ( X n +2: 1 ) | i ) . f 0 i 0 2 X f 0 ( i 0 ) : = E n + 2: ∞ ( g ( i 0 , X n + 2: ∞ ) | i 0 ) By defining on by for all , then X E n + 1: ∞ ( g ( X n + 1: ∞ ) | i ) = E n + 1 ( f 0 | i ) = E ( f 0 | i )

  6. First passage time The first passage time from to with is i , j ∈ X j i ( X n + 1 = j 1 τ i ! j ( i , X n + 1: ∞ ) : = 1 + τ X n + 1 ! j ( X n + 1 , X n + 2: ∞ ) X n + 1 6 = j = 1 + I j c ( X n + 1 ) τ X n + 1 ! j ( X n + 1 , X n + 2: ∞ ) where is the indicator function of j c : = X \{ j } I j c For , we have the return time i = j τ i → j , n : = E n + 1: ∞ ( τ i → j ( i , X n + 1: ∞ ) | i ) Due to time-homogeneity and τ i → j , n : = E n + 1: ∞ ( τ i → j ( i , X n + 1: ∞ ) | i ) will be denoted by and τ i → j τ i → j Due to positivity assumption and are real-valued and strictly positive τ i → j τ i → j τ i → j = 1 + E ( I j c τ • → j | i ) τ i → j = 1 + E ( I j c τ • → j | i ) and have the form and

  7. Lower expected upward first passage time The first passage time from to with and i , j ∈ X j i i < j τ 0 → 1 = 1 p 0 i ∈ X \{ 0 , L } For all , we have that { q i τ i − 1 → i − p i τ i → i + 1 } = − 1 min φ i ∈ M i M i For all satisfying the positivity assumption, with , i ∈ X \{ 0 , L } and a real constant, then is strictly decreasing in { qc − p µ } min c µ φ i ∈ M i

  8. Lower expected upward first passage time { q i τ i − 1 → i − p i τ i → i + 1 } = − 1 min φ i ∈ M i We can calculate recursively τ i → i + 1 Using a bisection method, as long as we have calculated … τ i − 1 → i Moreover, For all , s.t , we have that i ∈ X \{ 0 , L } i + 1 < j τ i → j = τ i → i + 1 + τ i + 1 → j j − 1 ∑ For all , such that , we have that i ∈ X τ i → j = i < j τ k → k + 1 k = i

  9. Lower expected downward first passage time The first passage time from to with and i , j ∈ X j i i > j Similarly to the upward case… τ L → L − 1 = 1 q L For all , we have that { − q i τ i → i − 1 + p i τ i + 1 → i } = − 1 i ∈ X \{ 0 , L } min φ i ∈ M i i − 1 ∑ i ∈ X For all , such that , we have that i > j τ i → j = τ k + 1 → k k = j

  10. Lower expected return time The first passage time from to with and i , j ∈ X j i i = j Combining the results from expected upward with these of downward first passage times { p 0 τ 1 → 0 } = 1 + p 0 τ 1 → 0 τ 0 → 0 = 1 + min φ 0 ∈ M 0 { q L τ L − 1 → L } = 1 + q L τ L − 1 → L τ L → L = 1 + min φ L ∈ M L and for all i ∈ X \{ 0 , L } { q i τ i − 1 → i + p i τ i + 1 → i } τ i → i = 1 + min φ i ∈ M i

  11. Linear vacuous mixtures The set is a subset of the simplex M i Σ X For any , is the subset of containing p.m.f. Σ X i φ i i ∈ X Σ X ε i ∈ [ 0 , 1 ) Given precise and for any φ ∗ 0 , φ ∗ L , φ ∗ i ∈ X i � ( 1 � ε 0 ) φ ⇤ 0 + ε 0 φ 0 0 : φ 0 M 0 = 0 2 Σ X 0 � ( 1 � ε L ) φ ⇤ L + ε L φ 0 L : φ 0 M L = L 2 Σ X L and for all i ∈ X \{ 0 , L } � ( 1 � ε i ) φ ⇤ i + ε i φ 0 i : φ 0 M i = i 2 Σ X i

  12. Linear vacuous mixtures We can also define q i : = ( 1 − ε i ) q ∗ q i : = ( 1 − ε i ) q ∗ i + ε i i ∈ X \{ 0 } and for all i p i : = ( 1 − ε i ) p ∗ i ∈ X \{ L } and for all p i : = ( 1 − ε i ) p ∗ i + ε i i Expected lower upward, downward first passage and return times ∏ i ∏ k − 1 ` = k + 1 q ` ` = i p ` τ i → i + 1 = ∑ i τ i → i − 1 = ∑ L k = 0 ∏ i k = i ∏ k m = k p m m = i q m τ i → i = 1 + q i τ i − 1 → i + p i τ i + 1 → i

  13. Linear vacuous mixtures Q π ∗ X : = { 0 ,..., 4 } Consider state space , and ε i = ε = 0 . 4 q   0 . 55 0 . 45 0 0 0 then, for all 0 . 3 0 . 5 0 . 2 0 0   P ∗ =   0 0 . 3 0 . 5 0 . 2 0 i ∈ X \{ 0 , L } π ∗     0 0 0 . 3 0 . 5 0 . 2   0 0 0 0 . 6 0 . 4 p r we calculate lower and upper expected return times i τ i → i τ i → i 0 1.584 91.41 1 1.526 24.956 2 1.678 17.845 3 1.656 79.71 4 2.037 503.724

  14. General example X : = { 0 ,..., 4 } Consider state space p 0 ∈ [ 0 . 15 , 0 . 4 ] q L ∈ [ 0 . 2 , 0 . 6 ] M 0 M L is determined by and by ( q i , r i , p i ) i ∈ X \{ 0 , L } M i For all , is characterised by triplets of the form q (0 . 65 , 0 . 15 , 0 . 2) , (0 . 6 , 0 . 25 , 0 . 15) , (0 . 5 , 0 . 4 , 0 . 1) , (0 . 43 , 0 . 45 , 0 . 12) , (0 . 33 , 0 . 5 , 0 . 17) , (0 . 27 , 0 . 43 , 0 . 3) , ⇒ (0 . 25 , 0 . 35 , 0 . 4) , (0 . 3 , 0 . 25 , 0 . 45) , (0 . 4 , 0 . 17 , 0 . 43) , (0 . 55 , 0 . 1 , 0 . 35) p r lower and upper expected upward and downward first passage times 2.5 1.666 τ 0 → 1 τ 4 → 3 3.889 2.051 τ 1 → 2 τ 3 → 2 4.814 2.169 τ 2 → 3 τ 2 → 1 5.432 2.206 τ 3 → 4 τ 1 → 0 6.666 5 τ 0 → 1 τ 4 → 3 43.333 12 τ 1 → 2 τ 3 → 2 226.666 23.2 τ 2 → 3 τ 2 → 1 1143.333 41.12 τ 3 → 4 τ 1 → 0

  15. Conclusions and future work Simple methods for computing lower and upper expected first passage and return times Applying similar methods to other type of chains, e.g. Bonus-Malus systems Applying similar methods to continuous time systems

Download Presentation
Download Policy: The content available on the website is offered to you 'AS IS' for your personal information and use only. It cannot be commercialized, licensed, or distributed on other websites without prior consent from the author. To download a presentation, simply click this link. If you encounter any difficulties during the download process, it's possible that the publisher has removed the file from their server.

Recommend


More recommend