SLIDE 31 A proof.
The poles of LHS are at most x, y, x − y. View ⟨·, Iai(Ibi(·, x − y)·, y)·⟩i=1,...,S as a function on (⊕i∈∆Ui)⊕4 with values in functions of x and y. Since {⟨·, Iai(Ibi(·, x − y)·, y)·⟩ | i = 1, ..., S} is linearly independent, we may choose qualtets (u1
1, u2 1, u3 1, u4 1), ..., (u1 S, u2 S, u3 S, u4 S) such that S × S-matrix
A := (⟨u4
j , Iai(Ibi(u1 j , x − y)u2 j , y)u3 j ⟩) has nonzero determinant. Then
.
Equations on vectors over function fields
. . (⟨v4
i , Y (Y (v1 i , x − y)v2 i , y)v3 i ⟩i=1,....,S
= A(⟨w4, J si(J ti(w1, x − y)w2, y)w3⟩j=1,...,s as column vectors, where va
i = ua i ⊗ wa for a = 1, 2, 3, 4. So we have:
⟨w4, J si(J ti(w1, x − y)w2, y)w3⟩ = A−1⟨v4
i , Y (Y (v1 i , x − y)v2 i , y)v3 i ⟩
Masahiko Miyamoto C2-cofiniteness of commutant subVOA 11 / 17