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Algorithmic investigation of substitution tilings and their associated graph Laplacians Nicole Harris*, Hayley LeBlanc, Alex Tubbs* Advisor: Professor May Mei Denison University Background Information Aperiodic Tiling An aperiodic tiling


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Algorithmic investigation of substitution tilings and their associated graph Laplacians

Nicole Harris*, Hayley LeBlanc, Alex Tubbs* Advisor: Professor May Mei

Denison University

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Background Information

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Aperiodic Tiling

  • An aperiodic tiling is a tiling of a plane that does not form repeating

patterns.

  • Some aperiodic tilings can be formed by applying

inflate-and-subdivide (substitution) rules to an initial tile.

  • 1-dimensional tilings are better understood than 2-dimensional

tilings. . . .

Figure 1: Fibonacci tiling Figure 2: Penrose tiling

https://commons.wikimedia.org/wiki/File:Penrose Tiling (Rhombi).svg

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Dual Graph

The dual graph G of a tiling has a node for each tile and an edge connect each pair of tiles that share an edge.

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Graph Laplacian

The Laplacian matrix L of a graph is a matrix containing information about the structure of the graph. 1 2 3 4

Figure 3: A basic graph.

(1,2)(2,3)(3,4)(4,1) (2,1)(3,2)(4,3)(1,4)

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Graph Laplacian

The Laplacian matrix L of a graph is a matrix containing information about the structure of the graph. 1 2 3 4

Figure 3: A basic graph.

(1,2)(2,3)(3,4)(4,1) (2,1)(3,2)(4,3)(1,4) D =      2 2 2 2     

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Graph Laplacian

The Laplacian matrix L of a graph is a matrix containing information about the structure of the graph. 1 2 3 4

Figure 3: A basic graph.

(1,2)(2,3)(3,4)(4,1) (2,1)(3,2)(4,3)(1,4) D =      2 2 2 2      A =      1 1 1 1 1 1 1 1     

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Graph Laplacian

The Laplacian matrix L of a graph is a matrix containing information about the structure of the graph. 1 2 3 4

Figure 3: A basic graph.

(1,2)(2,3)(3,4)(4,1) (2,1)(3,2)(4,3)(1,4) D =      2 2 2 2      A =      1 1 1 1 1 1 1 1      L = D − A =      2 −1 −1 −1 2 −1 −1 2 −1 −1 −1 2     

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Goal and Purpose

  • Our goal: find a method to generate the Laplacian of substitution

tilings in a 2-dimensional way based on their inflate-and-subdivide rules.

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Goal and Purpose

  • Our goal: find a method to generate the Laplacian of substitution

tilings in a 2-dimensional way based on their inflate-and-subdivide rules.

  • There exist 1-dimensional methods, but can we do it

2-dimensionally? Yes!

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Chair Tiling

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Chair Tiling

The Chair Tiling is an aperiodic tiling consisting of a single tile. H0

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Chair Tiling

The Chair Tiling is an aperiodic tiling consisting of a single tile. H0

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Chair Tiling

The Chair Tiling is an aperiodic tiling consisting of a single tile. H0 1 2 3 H1

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Chair Tiling

The Chair Tiling is an aperiodic tiling consisting of a single tile. H0 1 2 3 H1

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Chair Tiling

The Chair Tiling is an aperiodic tiling consisting of a single tile. H0 1 2 3 H1 00 01 02 03 10 11 12 13 20 21 22 23 30 31 32 33 H2

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Rotations

There exist four different rotations of a sub-tiling. 1 2 3 A 3 2 1 B 1 2 3 C 1 2 3 D

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Dual Graph

H0 H1 H2

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Dual Graph

H0 H1 H2

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Quadrant Separations

We look at the substitution for each of the 8 line segments separating the quadrants. 1 2 7 3 4 8 5 6

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Example

3B 0B 2B 1B 3B 0B 2B 1B 3B 2B 1B 0B 1C 2C 3C 0C

This case corresponds to the following rule in the 2-dimensional substitution.

  • (2B, 1B) → (1B, 1C) from line 1.

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Line 1 Substitution

Line 1 North side South side 0B → 0B1B 2B → 2B1B 1B → 1C 1B → 3C2C 1C → 1D2D 3C → 2B1B 1D → 2A3A 2C → 3C2C 2D → 1D2D 2A → 2A3A 3A → 1D2D

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Paired substitution

We pair the substitutions for either side of a line to create 2-d substitutions. Line 1 (2B, 0B) → (2B, 0B)(2B, 1B) (2B, 1B) → (1B, 1C) (1B, 1C) → (3C, 1D)(2C, 2D) (3C, 1D) → (1B, 3A)(2B, 2A) (2C, 2D) → (3C, 1D)(2C, 2D) (1B, 3A) → (3C, 1D)(2C, 2D) (2B, 2A) → (2B, 2A)(1B, 3A)

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Pinwheel Tiling

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Pinwheel Substitution

  • Defined by Radin and Conway
  • Infinite orientations, so look at shapes created
  • 5 quint-ants, so number in base 5
  • For next iteration:
  • Inflate each tile by

√ 5

  • Divide into copy of T1

T0 T1

1 2 3 4 00 01 02 03 04 10 11 12 13 14 20 2122 23 24 30 31 32 33 34

T2

40 41 42 43 44

Figure 4: Pinwheel Tiling

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Lines with New Edges

  • 5 lines
  • Direction will be important when finding 1-D substitution
  • Direction doesn’t affect edges
  • This way makes different lines have the same rules

L1 L2 L3 L4 L5

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2-D Substitution Across Lines

  • Focus on shapes made across 5 lines
  • Example with line between quint-ant 2 and quint-ant 3
  • Split into two so we can see all the shapes
  • Middle tiles are part of 2 shapes because of adjacency to 2 tiles

Figure 5: Shapes Formed between Quint-ants 2 and 3

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2-D Substitution

  • Blue line is where two tiles meet between quint-ants
  • Want to know what shape will be on line after one iteration
  • Use this process for all 7 of shapes that are created

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2-D Substitution

Figure 6: Forward Kite (A) and Backward Kite (B) Figure 7: Forward Acute (C) and Backward Acute (D) Figure 8: Forward Obtuse (E) and Backward Obtuse (F) Figure 9: Rectangle (G)

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1-D Substitution Naming

  • Number based on the position inside the T1 tiling that the tile is in
  • Last digit when in base 5
  • Letter to represent the shape it creates across the edge, as well as

direction

  • i.e. 1A if it’s in the one spot, and a part of a forward kite

1 2 3 4

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1-D Substitution Pairs

Quint-ant 0 Quint-ant 2 1B 0B → → 0F 3D 4C 0F 3D 4C → → 0B 4A 1A 1B 4B 0B 4A 1A 1B 4B → → 0F 3D 4C 4D 3C 0E 4D 3C 0E 3D 4C 0F 3D 4C 0F 3D 4C 4D 3C 0E 4D 3C 0E 3D 4C 0F 3D 4C

Figure 10: Line 2

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Paired 1-D Substitution

Line 2 (0B, 1B) → (0F, 0F)(3D, 3D), (4C, 4C) (0F, 0F) → (0B, 0B) (3D, 3D) → (4A, 4A)(1A, 1A) (4C, 4C) → (1B, 1B)(4B, 4B) (0B, 0B) → (0F, 0F)(3D, 3D)(4C, 4C) (4A, 4A) → (4D, 4D)(3C, 3C)(0E, 0E) (1A, 4A) → (4D, 4D)(3C, 3C)(0E, 0E) (1B, 1B) → (0F, 0F)(3D, 3D)(4C, 4C) (4B, 4B) → (0F, 0F)(3D, 3D)(4C, 4C) (4D, 4D) → (4A, 4A)(1A, 1A) (3C, 3C) → (1B, 1B)(4B, 4B) (0E, 0E) → (0A, 0A) (0A, 0A) → (4D, 4D)(3C, 3C)(0E, 0E)

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The Algorithm

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Li = L∗

i + L′ i

Our algorithm creates two intermediate Laplacians and adds them together to get the final Laplacian.

  • L∗

i is a block matrix with four copies Li−1 on the diagonal blocks.

  • L′

i, is filled in using the pairs created from the paired substitutions.

  • Li is the Laplacian of the full connected graph.

L∗

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Li = L∗

i + L′ i

Our algorithm creates two intermediate Laplacians and adds them together to get the final Laplacian.

  • L∗

i is a block matrix with four copies Li−1 on the diagonal blocks.

  • L′

i, is filled in using the pairs created from the paired substitutions.

  • Li is the Laplacian of the full connected graph.

L∗

2

L′

2

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Li = L∗

i + L′ i

Our algorithm creates two intermediate Laplacians and adds them together to get the final Laplacian.

  • L∗

i is a block matrix with four copies Li−1 on the diagonal blocks.

  • L′

i, is filled in using the pairs created from the paired substitutions.

  • Li is the Laplacian of the full connected graph.

L∗

2

L′

2

L2

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References i

  • M. Baake, D. Damanik, and U. Grimm.

What is . . . aperiodic order? Notices Amer. Math. Soc., 63(6):647–650, 2016.

  • F. R. K. Chung.

Spectral Graph Theory. American Mathematical Society, 1997.

  • C. Radin.

The pinwheel tilings of the plane.

  • Ann. of Math. (2), 139(3):661–702, 1994.