SLIDE 1 A MATHEMAGICAL MYSTERY TOUR 3:
… A RECURRING RELATION?
MIKE SMITH
MATHEMATICAL ASSOCIATION: STIRLING CONFERENCE OCTOBER 2019
smike314@gmail.com
SLIDE 2 SIMÉON POISSON
"LIFE IS GOOD FOR ONLY TWO THINGS, DISCOVERING MATHEMATICS AND TEACHING MATHEMATICS"
SLIDE 3
LEWIS CARROLL
AKA
CHARLES LUTWIDGE DODGSON
“BEGIN AT THE BEGINNING," THE KING SAID, VERY GRAVELY, "AND GO ON TILL YOU COME TO THE END: THEN STOP.”
SLIDE 4 ALICE’S PUZZLES … … THROUGH THE LOOKING GLASS
- LAWN FOR LUNCH! OR ... IT WASN’T THE GARDEN’S FAULT
- THE FARMER DIDN’T HAVE TIME TO TRIM THE GRASS HIMSELF – SO HE
LEFT THE JOB TO HIS LIVESTOCK
- HIS COW AND HIS GOAT WOULD EAT ALL THE GRASS IN 45 DAYS
- THE COW AND THE GOOSE WOULD EAT ALL THE GRASS IN 60 DAYS
- AND THE GOAT AND THE GOOSE WOULD EAT IT ALL IN 90 DAYS
- ASSUMING THE GRASS IS NO LONGER GROWING, IF THE FARMER
LEFT THE COW, GOAT AND GOOSE IN THE GARDEN TOGETHER HOW LONG WOULD IT TAKE TO EAT ALL THE GRASS?
SLIDE 5 ALICE’S PUZZLES … … THROUGH THE LOOKING GLASS
- LAWN FOR LUNCH! OR ... IT WASN’T THE GARDEN’S FAULT
- THE ANIMALS WILL EAT ALL THE GRASS IN 40 DAYS!
- WHY?
- COW + GOAT =
=
=
= 1 45 8 360 1 60 1 90 6 360 4 360
SLIDE 6 ALICE’S PUZZLES … … THROUGH THE LOOKING GLASS
- LAWN FOR LUNCH! OR ... IT WASN’T THE GARDEN’S FAULT
- 2 COWS + GOAT + GOOSE =
(8 + 6)
(14 – 4)
WHICH MEANS …
AND 1 GOOSE =
- SO COW + GOAT + GOOSE EATS
IN A DAY ( )
- SO 40 DAYS TO EAT ALL THE GRASS
14 360 10 360 5 360 1 360 3 360 9 360 1 40
SLIDE 7
A MATHS TEACHER NEVER SWITCHES OFF!
SLIDE 8 ANTONI GAUDI
- “I AM A GEOMETRICIAN, MEANING I SYNTHESISE.”
SLIDE 9 SAGRADA FAMILIA
- THOUGHT I WAS GOING TO SPEND A COUPLE OF HOURS
LOOKING AT STAINED GLASS WINDOWS! … … …
- [OH! GAUDI I SAID TO MYSELF!]
- BUT NO! SOON DISCOVERED A HUGE AMOUNT OF
MATHEMATICS IN THE CATHEDRAL
- GEOMETRY OF THE PLACE – EVERYTHING IN MULTIPLES OF 7.5
- USE OF CONICS; HYPERBOLOIDS, PARABOLOIDS, HELIOCOIDS,
ELLIPSOIDS, TWISTED COLUMNS
- OF COURSE, THIS APPLICATION OF MATHEMATICS DID NOT
EXCITE ME AS MUCH AS … …
SLIDE 10 THE MAGIC SQUARE ON THE PASSION FACADE
TOOK A WALK OUTSIDE AND WHAT DID I SEE? … …
SLIDE 11 MAGIC SQUARE
- AS YOU KNOW A 4X4 MAGIC SQUARE,
USING 1-16 WOULD HAVE A MAGIC CONSTANT OF 34
- IE ROWS, COLUMNS, DIAGONALS
WOULD ADD TO 34
- LOOK CLOSELY AT THIS ONE
- THE 12 AND 16 HAVE BEEN REPLACED BY
10 AND 14
- THE MAGIC CONSTANT IS 33!
- WHY CHANGE?
SLIDE 12 MAGIC SQUARE
- SUBIRACHS TOOK AN EXISTING MAGIC SQUARE AND
ADAPTED IT. WHY?
- THE MAGIC CONSTANT OF 33 IS THE AGE JESUS IS
TRADITIONALLY BELIEVED TO HAVE BEEN EXECUTED
- BUT THIS IS NOT AN ‘ORDINARY’ MAGIC SQUARE IN MORE
WAYS THAN THAT
- CHECK THAT ALL ROWS, COLUMNS AND DIAGONALS ADD
UP TO 33 … … YUP!
SLIDE 13
SLIDE 14
There are over 300 combinations which add up to 33
And one last thought … …
SLIDE 15
SLIDE 16
AND NOW FOR SOMETHING COMPLETELY DIFFERENT!
SLIDE 17 FUN WITH 79?
79 [SUM + PRODUCT = NUMBER]
- SMALLEST PRIME FOR WHICH THIS WORKS
- EMIRP
[REVERSIBLE PRIME; 79 … 97]
THE SUM OF 3 OTHER EMIRPS
= 11 + 31 + 37 [11+13+73 = 97]
- SMALLEST PRIME WHOSE SUM OF DIGITS IS A 4TH POWER
[16=24]
[YUP! 79]
ITERATION OF 72 + 92 = ENDS AT 1
AND GET ANOTHER EMIRP!
SLIDE 18 ON A LIGHTER NOTE …
SAW THE FIRST EPISODE OF STAR TREK
GREATEST ERUPTION OF MOUNT VESUVIUS
- AROUND THE WORLD IN 80 DAYS
PHINEAS FOGG DID IT IN 79 DAYS
COUSIN PRIME TO 83
- [DIFFER BY 4 AS OPPOSED TO TWIN PRIMES (2) AND SEXY PRIMES (6) 79 IS ALSO A SEXY PRIME [WITH 73]
- THE 79TH TRIANGULAR NUMBER IS
3160
- WHICH IS THE FIRST TO CONTAIN ALL TRIANGULAR NUMBERS IN ITS DIGITS
- THE ATOMIC NUMBER OF CHEMICAL ELEMENT GOLD (AU) IS 79
SLIDE 19 IT WOULDN’T BE MATHEMAGICAL WITHOUT Π
WWW.MYPIDAY.COM
SLIDE 20
260256
SLIDE 21 LIGHTENING MULTIPLICATION
- ASK A STUDENT TO GIVE YOU A 3-DIGIT NUMBER
- SAY 567
WRITE IT DOWN TWICE 567 567
WRITE IT DOWN UNDER LEFT 382 617
- NOW YOU WRITE ANOTHER NUMBER UNDER 2ND 567, SAY, 617
- NOW SAY YOU ARE GOING TO DO THE TWO MULTIPLICATIONS AND ADD THEM
- IN YOUR HEAD!
- AMAZE THEM WITH YOUR ANSWER OF
566 433
- CAN YOU SEE HOW THIS WORKS?
SLIDE 22 LIGHTENING MULTIPLICATION
567 567
382
- YOU WRITE DOWN THE “9 COMPLEMENT”
617
- YOU GET THE SUM OF PRODUCTS BY;
- SUBTRACT 1 FROM MULTIPLICAND … IN THIS CASE 567 – 1
IS 566
- THE 9 COMPLEMENT OF 566 IS
433
- SO THE SUM OF THE PRODUCTS IS
566 433
SLIDE 23 LIGHTENING MULTIPLICATION
- HOW DOES IT WORK?
- IF YOU THINK WHAT YOU ARE DOING IT IS
567 X (382 + 617)
567 X 999
567 X 1000 – 567
566 000 + ‘9 COMPLEMENT’
566 433
SLIDE 24
A NICE LITTLE CODE
SLIDE 25 HOW MUCH CHANGE DO YOU HAVE IN YOUR POCKET?
- A NICE LITTLE TRICK TO DRAW THE STUDENTS IN AT START OF PERIOD
- ASK THEM TO COUNT CHANGE IN POCKET (BEST TO WORK IN PENCE NOT
£S AND P – ALTHOUGH IT WILL WORK FOR £P)
- PROBABLY BEST TO WRITE DOWN!
- MULTIPLY BY 2
- ADD 3
- MULTIPLY BY 5
- SUBTRACT 6
- GET VOLUNTEER TO TELL YOU FINAL NUMBER
(EG 639)
- YOU TELL HIM/HER S/HE HAD 63 PENCE IN POCKET!
- (LAST DIGIT WILL ALWAYS BE 9 – SCORE OUT!)
SLIDE 26 HOW MUCH CHANGE DO YOU HAVE IN YOUR POCKET?
- HOW DOES IT WORK?
- START WITH A
- MULTIPLY BY 2 GIVES
2A
GIVES 2A + 3
5(2A + 3) = 10A + 15
GIVES 10A + 9
- SO WHATEVER NUMBER YOU STARTED WITH HAS BEEN MULTIPLIED BY
10 AND THE LAST DIGIT WILL ALWAYS BE 9
SLIDE 27 NUMBER CHAINS
- ANOTHER NICE ONE – WHICH CAN EXPAND AS MUCH AS YOU WANT!
- TAKE A TWO DIGIT NUMBER, SAY 23.
- MULTIPLY UNITS DIGIT BY 4 AND ADD TENS DIGIT – WHAT HAPPENS?
- CAN YOU FIND A NUMBER WHICH FORMS A “ONE LINK” CHAIN
- TRY 13
(OR 39) 23 14 17 35 38 29 18 33 15 24 6 21
SLIDE 28 NUMBER CHAINS
- TRY MULTIPLYING UNITS DIGIT BY 3 AND ADD TENS
- REPEAT USING X2, OR X5
- TRY TO FIND SINGLE CHAIN STARTING NUMBER- CAN YOU SEE A PATTERN?.
- EG X2 + T
- 23, 8, 16, 13, 7, 14, 9, 18, 17, 15, 11, 3, 6, 12, 5, 10, 1, 2, 4, 8
- SINGLE LINK NUMBER IS 19
- EXPERIMENT WITH X3 + T, X5 + T, X6 + T ETC
SLIDE 29 NUMBER CHAINS
X unit + tens Single link start number X2 + t 19 9x2+1=19 X3 + t 29 9x3+2=29 X4 + t 39 9x4+3=39 X5 + t 49 X6 + t 59 Any multiple of the number will also take you back to single link number Eg x2 + 1 … … start at 38. 8x2+3 = 19. start at 57, 7x2+5 = 19 Again, can you look at the algebra behind this? What we have is 9n + (n-1) = 10n – 1 so 10 x 2 – 1 = 19 10 x 3 – 1 = 29 etc
SLIDE 30 MOBIUS STRIP
- SQUARES FROM CIRCLES?
- A VALENTINE’S DAY MOBIUS STRIP!
SLIDE 31 MULTIPLYING
Japanese methdod Gelosia method (Napier’s bones) Egyptian method
SLIDE 32 JAPANESE METHOD
2 3 x 1 2 = ( 2 x1 0 + 3 ) ( 1 x1 0 + 2 ) = 2 x1 x1 0 2 + [ 2 x2 x1 0 + 3 x1 x1 0 ] + 3 x2 = 2 7 6
SLIDE 33
GELOSIA OR NAPIER’S BONES
SLIDE 34
NAPIER’S BONES (OR RODS)
SLIDE 35
EGYPTIAN METHOD
23 x 12 1.. 12 2.. 24 4.. 48 8.. 96 16.. 192 32.. 384 16+4+2+1 = 23 Add up corresponding values 192+48+24+12 = 276
SLIDE 36
HAILSTONE NUMBERS
Start with any number. If even divide by 2 If odd x3 + 1 … … … keep on going .. … what happens?
14 11 7 22 52 34 13 26 17 40 5 10 20 16 1 2 4 8
SLIDE 37
TRAINS AND A FLY
2 trains are on the same track 100 miles apart. They are heading towards each other at 50mph A fly leaves the front of one train, flying at 60mph towards the other train When it reaches that train it immediately turns around and flies back The fly repeats this until the trains crash – squishing it completely! How far had the fly travelled in total?
SLIDE 38
TRAINS AND A FLY
You can get caught up in summing a series! Easier to think it through! … Trains 100 miles apart, travelling at 50mph will take 1 hour to meet Fly is moving at 60mph – so will travel 60 miles before getting squashed!
SLIDE 39 AND FINALLY … …
Can you insert the numbers 1- 8 on this cube to make all the faces add up to the same total? A start has been made
SLIDE 40
AND FINALLY … …
SLIDE 41
THANK YOU FOR BEARING WITH ME!
SLIDE 42
ENGLISH IS I M P O R T A N T BUT MATHEMATICS IS I M P O R T A N T E R !
SLIDE 43 SOME EXTRAS!
MULTIPLYING BY 11! 11 X 34 = 3 4 (3+4 = 7) = 3 7 4 = 374 11 X 78 = 7 8 (7+8 = 15) = 7 15 8 = 8 5 8 = 858
SLIDE 44 HAPPY NUMBERS
31 IS A HAPPY NUMBER! WHY? 32 + 12 9 + 1 =10 12 + 02 1 + 0 = 1 IF END UP AT 1 => HAPPY NUMBER!
SLIDE 45 PERFECT NUMBERS
6 IS A PERFECT NUMBER WHY? FACTORS OF 6 (NOT INCLUDING 6) 1, 2, 3 1+2+3 = 6 NEXT PERFECT NUMBER IS 28; 1+2+4+7+14 = 28 WHAT ARE THE NEXT PERFECT NUMBERS? DO YOU SEE ANY PATTERN?
SLIDE 46 NEXT FEW PERFECT NUMBERS
(EUCLID)
(“)
(“)
(“)
(UNKNOWN CIRCA 1456)
(CATALDI 1588)
(“)
- 2 305 843 008 139 952 128
(EULER 1772)
- PATTERN? SO FAR ALL END IN EITHER 6 OR 8