DAY 82 – ELIMINATION
y 2 10 x y 3 x 10 3. Combine the two models. Remove - - PowerPoint PPT Presentation
y 2 10 x y 3 x 10 3. Combine the two models. Remove - - PowerPoint PPT Presentation
D AY 82 E LIMINATION U SING THE ADDITION PROPERTY OF EQUALITY 1. Let x represent the number of correct answers. Let y represent the incorrect answers. Write a system of equations. Janets scoring Matthews scoring system system 2
USING THE ADDITION PROPERTY OF
EQUALITY
- 1. Let x represent the number of correct answers. Let y
represent the incorrect answers. Write a system of equations. Janet’s scoring system Matthew’s scoring system 2 spaces for a correct answer 1 space forward for + an incorrect answer 3 spaces for a correct answer 1 space backward for + an incorrect answer 10 spaces forward 10 spaces forward ? + ? =10 ? + ? =10
USING THE ADDITION PROPERTY OF
EQUALITY
- 1. Let x represent the number of correct answers. Let y
represent the incorrect answers. Write a system of equations. Janet’s scoring system Matthew’s scoring system 2 spaces for a correct answer 1 space forward for + an incorrect answer 3 spaces for a correct answer 1 space backward for + an incorrect answer 10 spaces forward 10 spaces forward 2x + y = 10 3x + (-y) = 10
- 2. Rewrite the equation representing Matthew's
scoring system using a minus sign. Model this system of equations using the x-tiles and y-tiles.
10 2 y x
10 3 y x
- 3. Combine the two models. Remove neutral pairs, and
write the new equation.
10 10 ) 3 ( ) 2 ( y x y x
- 3. Combine the two models. Remove neutral pairs, and
write the new equation. 5x = 20
10 10 ) 3 ( ) 2 ( y x y x
- 4. Which variable was eliminated? Why?
Solve the resulting equation for the remaining variable.
- 4. Which variable was eliminated? Why?
Solve the resulting equation for the remaining variable.
4 x pairs; neutral variable; = y
- 5. Use substitution in either of the original
equations to find the value of the variable that was eliminated by removing neutral
- pairs. The solutions to the system is (?,?).
- 5. Use substitution in either of the original
equations to find the value of the variable that was eliminated by removing neutral
- pairs. The solutions to the system is (?,?).
) 2 , 4 (
- 6. Henry answered _?_ questions
correctly and _?_ questions incorrectly.
- 6. Henry answered _?_ questions
correctly and _?_ questions incorrectly. 4 correctly , 2 incorrectly
USING THE SUBTRACTION PROPERTY OF EQUALITY
1.
Use the x-titles and y-titles to model the system
4 10 4 y x y x
10 4 y x
4 y x
- 2. Combine the two models, remove any
neutral pairs. Is a variable eliminated? Why or why not?
- 2. Combine the two models, remove any
neutral pairs. Is a variable eliminated? Why or why not?
no variable are eliminated because neither combines with an equal number of opposites.
14 2 5 y x
- 3. Use tiles to model the system of
equations again.
- 4. You can eliminate the y-variable in this
system by using the Subtraction Property of
- Equality. Recall that to subtract, you add
the opposite. First model the opposite of the equation x + y = 4.
4 y x
4 ) 4 ( 1 ) ( 1 y x y x
- 5. Now subtract by adding the opposite. Combine the
model of the opposite of x + y = 4 with the model of 4x y = 10, and remove neutral pairs. What is the resulting equation? What variable was eliminated?
) 4 ( 10 ) ( ) 4 ( y x y x
6.Use the model to solve the resulting equation for x.
- 7. Substitute the solution for x into one
- f the original equations, and solve
for y.
6.Use the model to solve the resulting equation for x.
- 7. Substitute the solution for x into one
- f the original equations, and solve
for y.
2 x
2 y
8.Check your solution in both of the
- riginal equations.
9.Describe how to solve a system of equation using the Subtraction Property of Equality.
8.Check your solution in both of the
- riginal equations.
9.Describe how to solve a system of equation using the Subtraction Property of Equality.
) ( 10 2 8 ) ( 4 2 2 true and true
SOLVE THE SYSTEM USING THE
ELIMINATION METHOD.
22 5 4 4 5 2 y x y x
The coefficients of the y-terms are opposites. By adding the equations, you can eliminate the y-term. This leaves an equation with only one variable, which you can solve for x.
3 18 6 22 5 4 4 5 2 x x y x y x
Add the equations, Solve for x
To find y, substitute 3 for x in either of the original equations.
y y y y x y for Solve 2 sides. both to 6 Add 10 5 Simplify. 4 5 6 1 Equation in for Substitute 4 5 ) 3 ( 2
Check the solution, (3,-2), in both original equations. If the coefficients of the variable you want to eliminate are identical, subtract the
- equations. If the equations are not in
standard form Ax + By = C, begin by writing them in standard form.
SOLVE BY THE ADDITION METHOD:
2 5 2 1 10 3 y x y x
Since the coefficients of the y terms are additive inverses, adding the corresponding sided of the equations will eliminate the y terms.
2 Equation in
- r
1 Equations in 3
- n
Substituti 3 3 2 15 5 5 2 1 10 3 x x x y x y x
4 1 y 10 y 3(3) 1 10 y 3x 3 1 y
1 3 y x
Thus, Is an equivaltent system