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The time slice axiom in perturbative QFT on globally hyperbolic - - PowerPoint PPT Presentation
The time slice axiom in perturbative QFT on globally hyperbolic - - PowerPoint PPT Presentation
The time slice axiom in perturbative QFT on globally hyperbolic spacetimes Bruno Chilian June 7 2008 Overview Introduction: The time slice axiom in AQFT Outline of the proof First step: Wick-Polynomials Second step: Perturbation Theory
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Motivation: Predictability in Physics
◮ Requirement on physical theory: Future should be
predictable from present
◮ In classical physics: Well-posed initial value problem for
field equation
◮ In QFT: Initial value problem not well-posed, status of field
equation unclear
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How is predictability implemented in AQFT?
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How is predictability implemented in AQFT?
M A(M) ⊂ A(M)
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How is predictability implemented in AQFT?
M M′ A(M) ⊃A(M′)
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How is predictability implemented in AQFT?
M M′ A(M) ⊂ A(M) Cauchy surface
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How is predictability implemented in AQFT?
M M′ A(M) ⊂A(M′) Cauchy surface
The time slice axiom
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Outline of the proof is organized as follows:
First step: Wick-Polynomials
- 1. Review of Wick polynomial algebra
- 2. Time slice axiom for Wick polynomials
Second step: Perturbation Theory
- 3. Review of perturbation theory
- 4. Time slice axiom for interacting theories
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The algebra of the free field
◮ Free scalar field ϕ satisfies
ϕ
- (✷ + m2 − ξR)f
- = 0 and [ϕ(f), ϕ(g)] = f, ∆g .
◮ Algebra of the free field consists of functionals
F(ϕ) =
N
- n=0
- dx1 · · · dxn ϕ(x1) · · · ϕ(xn) fn(x1, . . . , xn)
◮ Initial value problem for Klein-Gordon equation is well
posed on globally hyperbolic spacetimes ⇒ time slice axiom holds for the free theory.
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The algebra of Wick polynomials
◮ To treat interactions, nonlinear functionals in the field must
be used.
◮ Smear normally ordered products with test-distributions:
φ⊗n(f) =
- dx1 · · · dxn : ϕ(x1) · · · ϕ(xn) : f(x1, . . . , xn)
◮ To get a well-defined algebra, test-distributions f must
satisfy condition on their wavefront sets: WF(f) ∩ V n
− ∪ V n + = ∅
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Time slice axiom in terms of smearing distributions
Let Tn(M) be the space of compactly supported distributions f
- n Mn with WF(f) ∩ V n
− ∪ V n + = ∅.
Proposition
Let f ∈ Tn(M) and let N be a neighborhood of a Cauchy surface in the past of supp f. Then there exists a g ∈ Tn(M) s.th.
◮ g = f + (✷ + m2 − ξR)h, where h ∈ Tn(M) and ◮ supp g ⊂ N .
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Time slice axiom in terms of smearing distributions
Let Tn(M) be the space of compactly supported distributions f
- n Mn with WF(f) ∩ V n
− ∪ V n + = ∅.
Proposition
Let f ∈ Tn(M) and let N be a neighborhood of a Cauchy surface in the past of supp f. Then there exists a g ∈ Tn(M) s.th.
◮ g = f + (✷ + m2 − ξR)h, where h ∈ Tn(M) and ◮ supp g ⊂ N .
Proposition is equivalent to time slice axiom because Wick polynomials have the form φ⊗n(f) =
- dx1 · · · dxn : ϕ(x1) · · · ϕ(xn) : f(x1, . . . , xn)
and : ϕ(x1) · · · ϕ(xn) : satisfies the Klein-Gordon equation.
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Main idea for proof: Cauchy-Evolution of distributions
Let f be a distribution with compact support. For two Cauchy surfaces in the past of supp f, let χ be a smooth function which is zero in the past and one in the future. Now define another distribution by g = f −(✷+m2−ξR)χ∆advf . It has compact support between the Cauchy surfaces. supp f χ = 1 χ = 0 supp g
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Adaption of this simple argument
Generalize to n variables
Use suitable partition of unity to check support property
Check wavefront property
Use H¨
- rmanders theorem on the propagation of singularities
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The time slice axiom in perturbation theory
◮ Perturbation theory expresses interacting fields by free
fields.
◮ Therefore: Ag(M) ⊂ A0(M). ◮ Using the time slice axiom for the free fields:
Ag(M) ⊂ A0(N) for a neighborhood N of some Cauchy surface.
◮ If one could express free fields in N by interacting fields in
N, one would have Ag(M) ⊂ A0(N) ⊂ Ag(N) which is the time slice axiom for interacting fields.
◮ We need to show that A0(N) ⊂ Ag(N).
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Causal perturbation theory
◮ Interacting fields: Constructed from local S-matrices:
Sg(f) = S(g)−1S(f + g)
◮ S-matrices: Power series of Wick polynomials
causal factorization property
S(f+g+h) = S(f+g)S(g)−1S(g+h) if supp f is in the future and supp h in the past of some Cauchy surface. supp f supp g supp h
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Starting idea for the proof of A0(N) ⊂ Ag(N)
◮ Elements Sg(f) also possess causal factorization property:
Sg(f1 + f2 + f3) = Sg(f1 + f2)Sg(f2)−1Sg(f2 + f3) if supp f1 is in the future and supp f3 in the past of some Cauchy surface.
◮ Multiply interacting fields in a clever way to cancel out
interactions.
◮ Obtain some free field. ◮ Check if every free field can be obtained in this way. ◮ Then: A0(N) ⊂ Ag(N).
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Noncompact interaction regions
If supp g is past compact, define the interacting field Sg(f) def = Sb(f), where b must coincide with g in the past of some compact region containing supp f. This definition does not depend on the choice of b. Proof uses causal factorization property. supp f supp g supp b
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Prove: Definition of Sg(f) is independent of chosen b.
Let ˜ b also coincide with g in the past of the compact region containing supp f. Set c = ˜ b − b. Then supp f supp g supp ˜ b supp b S˜
b(f) = S(˜
b)−1S(˜ b + f) = S(c + b)−1S(c + b + f) = S(c + b)−1S(c + b)S(b)−1S(f + b) = Sb(f) .
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Prove: Definition of Sg(f) is independent of chosen b.
Let ˜ b also coincide with g in the past of the compact region containing supp f. Set c = ˜ b − b. Then supp f supp g supp c S˜
b(f) = S(˜
b)−1S(˜ b + f) = S(c + b)−1S(c + b + f) = S(c + b)−1S(c + b)S(b)−1S(f + b) = Sb(f) .
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Compensating interactions
◮ Consider the expression Sg(−b′)−1Sg(−b′ + f), where b′
coincides with g in a neighborhood of supp f.
◮ Using causal factorization, it can be shown that
Sg(−b′)−1Sg(−b′ + f) = S(b−)−1S(f)S(b−) , where supp b− is in the past and supp f in the future of some Cauchy surface.
1st observation
S(b−)−1S(f)S(b−) ∈ Ag(N)
2nd observation
S(b−)−1S(f)S(b−) ∈ A0(M)
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◮ The map
S(f) → Sg(−b′)−1Sg(−b′ + f) = S(b−)−1S(f)S(b−) defines an endomorphism of A0(M), whose image is contained in Ag(N).
◮ For each relatively compact region, it is just conjugation by
a certain invertible element of A0(M).
◮ The last step is to show that this endomorphism is
invertible, i.e. S(b−)S(h)S(b−)−1 does not depend on the chosen b−.
◮ Place additional restriction on the choice of b−.
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Summary
◮ The time slice axiom holds in perturbative AQFT. ◮ One only needs the causal factorization property... ◮ and the time slice axiom for Wick polynomials.
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