The anomaly triangle and muon g − 2
SANTI PERIS San Francisco State U. and
- U. Autonoma de Barcelona
The anomaly triangle and muon g − 2 – p.1/8
The anomaly triangle and muon g 2 SANTI PERIS San Francisco State - - PowerPoint PPT Presentation
The anomaly triangle and muon g 2 SANTI PERIS San Francisco State U. and U. Autonoma de Barcelona The anomaly triangle and muon g 2 p.1/8 2-loop EW contribution to g 2 Kukhto et al. 92 SP, Perrottet, de Rafael 95
SANTI PERIS San Francisco State U. and
The anomaly triangle and muon g − 2 – p.1/8
Kukhto et al. ’92 SP, Perrottet, de Rafael ’95 Czarnecki, Krause, Marciano ’95, ’96 Knecht, SP, Perrottet, de Rafael ’02 Czarnecki, Marciano,Vainshtein ’03
g−2 2
∝ α
π Gµ 8π2 m2
µ
√ 2
∞
m2
µ dQ2
M2
Z
M2
Z + Q2 wT (Q2)
Q2
(one−loop, mf =0) g−2 2 |e,u,d ∼ 2 × 10−11
Q2 = −q2, “Gluon-irreducible” quark triangle Wµνρ(q, k) = T (3)
f
Q2
f
wT (Q2) kσ q2ǫµνρσ + qνǫµρλσqλ + qµǫρνλσqλ + O(k2)
⇒
ν,e,u,d
f
Q2
f
The anomaly triangle and muon g − 2 – p.2/8
Vainshtein ’02 Knecht, SP, Perrottet, de Rafael, ’03
In the massless limit, to all orders in αs: wL(Q2) = 2 wT (Q2) and, since anomaly does not get renormalized: wL = 2 Nc
Q2 exact!
(Adler,Bardeen ’69; Witten ’83)
⇒ neither does 2wT = 2 Nc
Q2 , to all orders in αs.
Using L(3)
µ
=
ℓ=ν,e ℓLγµT (3)ℓL + q=u,d qLγµT (3)qL, etc...in SU(2)L × U(1)Y :
Q2 wL(Q2) − 2wT (Q2)
T
µ (x)V (Y ) ν
(y)R(Y )
ρ
(0)
The anomaly triangle and muon g − 2 – p.3/8
1) Adler-Bardeen-Witten : wL(Q2) = 2 Nc
Q2
(exact for all Q !) 2) However, for wT (Q2):
2wT (Q2) ≈ 2 Nc Q2
Q6 + O(1/Q8) Magnetic susceptibility, χ = ΠV T (0)
ψψ , very poorly known.
2wT (Q2) ≈ (const.) C(p6)
22
+ O(Q2) , C(p6)
22
∼ 1/M2
Hadron
(unknown) Chiral Pert. Theory, Leff (parity-odd):
(Ebertshauser, Fearing, Scherer ’01; Bijnens, Girlanda, Talavera ’02, Kampf, Moussallam ’09)
LO(p6) = C(p6)
22
ǫµναβ Tr
∇γfγν
+ , fαβ +
+... ; SU(NF )L×SU(NF )R → SU(NF )V
The anomaly triangle and muon g − 2 – p.4/8
Very roughly, 2 wT (Q2) Q2 ∼
Anomaly
Q2 Q2 + Λ2
Hadron
i.e.
2Nc 2w Q
T 2
The anomaly triangle and muon g − 2 – p.5/8
wL(Q2) − 2 wT (Q2) = −2 Nc
f2
π ΠLR(Q2) (Son-Yamamoto ’10)
in wide class of “AdS/QCD” models (chiral limit, Nc → ∞) (not without caveats, e.g. OPE is exponential; wrong chiral limit in pert. theory)
( Knecht, SP, de Rafael ’11)
Chiral log’s respect this relation in SU(2) × SU(2) × U(1) (mu,d = 0, ms = 0)
(Gorsky, Kopnin,Krikun, Vainshtein ’12)
− 64π2 c(p6)
13
(µ) = − Nc
f2
π
ℓ(p4)
5
(µ) However, they don’t in SU(3) × SU(3) (mu,d,s = 0)
(Knecht, SP , ’12 (unpublished))
128π2 C(p6)
22
(µ) = −
Nc f2
π
L(p4)
10
(µ)
χ = −
Nc 4π2f2
π ∼ −9 GeV−2
(Magnetic susceptibility)??
(Vainshtein ’02):
Other results: χ ∼ −3 GeV−2 , sum rules, VMD, (Ioffe, Fadin, Lipatov ’10; Balitsky et al. ’85; Belyaev et al.
’84; Ball et al. ’02)
The anomaly triangle and muon g − 2 – p.6/8
Up to now, special kinematic configuration in V V A.
Jegerlehner,Tarasov ’06
However, it has been found at two loops for arbitrary momenta that : Wµνρ(q, k) = Wµνρ(q, k)|one−loop (1 + O(αs)
=0 !!
) i.e., no renormalization, not just for the anomaly, but for the whole triangle ! Given the non-trivial momentum dependence, can this be just a coincidence ? could this be true to all orders in αs ?
The anomaly triangle and muon g − 2 – p.7/8
→ V V A connection:
( Melnikov, Vainshtein ’04; Prades, de Rafael, Vainshtein ’09)
k1 ≈ k2 ≫ k3
k k k q
1 2 3
q k3
γ γ
γ 5
H
The anomaly triangle and muon g − 2 – p.8/8