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Symmetric Gro up pe rmutatio ns o f 3 o bje c ts Gro up elements c - PowerPoint PPT Presentation

Symmetric Gro up pe rmutatio ns o f 3 o bje c ts Gro up elements c an be written in this fo rmat: Symmetric Gro up No te Symmetric group Product operation Is the group elements {e,a,b,ab,b,b^2} isomorphic to the above


  1. Symmetric Gro up  pe rmutatio ns o f 3 o bje c ts  Gro up elements c an be written in this fo rmat:

  2. Symmetric Gro up No te

  3. Symmetric group  Product operation  Is the group elements {e,a,b,ab,b,b^2} isomorphic to the above permutation elements?

  4. Symmetric group  Order of , which is a symmetric group involving permutation of n objects, is n!  is called symmetric group of degree n  Subgroups of are called permutation groups  Cayley’s theorem states that every finite group is isomorphic to a permutation group embedded inside  Any permutation element can be equivalently represented as a product of disjoint permutation cycles

  5. Symmetric group  Consider the following permutation element  This can be written in the following disjoint cycle structure  Cycle decomposition is useful for multiplication of two permutation elements

  6. Symmetric Gro up Two-cycle is called transposition . Inverse of the transposition is the same element. Inverse of 3-cycle (123) is (132). Why? Every n-cycle can be written as product of transpositions

  7. Symmetric Gro up Note that the product of the two permutation elements have six-cycle structure. Of course the elements are different.

  8. Symmetric Gro up Any k-cycle can be broken into products of transpositions (2-cycle) Depending on the odd or even number of transpositions, permutation element is called odd or even permutation

  9. Symmetric group  Any permutation element will have where where k runs from 1 to n such that  All permutation elements with the above cycle structure can be shown to be conjugate elements ( prove)  Total number of permutation elements( within the conjugacy class given by the cycle structure) is

  10. Symmetric group  The number of conjugacy classes in the symmetric group is equal to the number of ways of partitioning integer n  For example, n=5 can be broken into 7 distinct conjugacy classes  Convenient way of diagrammatically representing the conjugacy classes using Young diagrams  1-cycles by single box, 2-cycle by double vertical box and so on  Identity element for n=5 is five 1-cycles denoted by

  11. Symmetric group  Product of two 2-cycles and one 1-cycle will be represented by  One 5-cycle will be

  12. Symmetric group  Set of even permutation elements form a group known as alternating group  Conjugate elements of even permutation elements will always be even which implies  is an invariant or normal subgroup  Factor group  Show that there are only two cosets possible or the factor group has only two elements [e, (1,2)]

  13. Direct Product groups  For two groups, direct product group is  Example  Note that the elements of both the groups commute and order of G is product of order of the two groups

  14. Semi-Direct product groups  Let K be invariant subgroup of G and T be another subgroup of G such that identity element is the only common element between K and T  Then, G is the semi-direct product group denoted by  Show that T are coset elements  Example

  15. Symmetry of a molecule  Rotations and reflections which leaves the molecule invariant  Axis of rotational symmetry  Plane of symmetry- two types  Plane perpendicular to axis (horizontal mirror plane)-  Plane containing the axis (vertical mirror plane)-  Roto-reflection symmetry-  There could be diagonal plane of symmetry (cube)-

  16. Water molecule Symmetry σ v ( xz ) C 2

  17. Group symmetry? Ammonia Molecule

  18. Methane symmetry? Group

  19. Streographic projection

  20. Streographic projection

  21. Streographic projection

  22. Schoenflies Notation

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