Derived proper base change p X X We had proved that for f f q - - PowerPoint PPT Presentation

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Derived proper base change p X X We had proved that for f f q - - PowerPoint PPT Presentation

Derived proper base change p X X We had proved that for f f q Y Y we have q f ! ! p an isomorphism of functors. = f Theorem. q Rf ! ! p is also an isomorphism (between = Rf


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SLIDE 1

Derived proper base change

◮ We had proved that for X ′ X Y ′ Y

p f ′ f q

we have q∗ ◦ f! ∼ = f ′

! ◦ p∗ an isomorphism of functors.

◮ Theorem. q∗ ◦ Rf! ∼ = Rf ′

! ◦ p∗ is also an isomorphism (between

functors from D+(ShR(X)) to D+(ShR(Y ′)). ◮ The derived proper push-forward may be computed using the following kind of f!-injective resolution: a sheaf F ∈ ShR(X) is called c-soft if for any compact K ⊂ X, Γ(X; F) ։ Γ(K; (K ֒ → X)∗F) is

  • surjective. One can see this as a weaker version of flabby.

◮ For a map f : X → Y , F ∈ ShR(X) is called f -soft if F|f −1(y) is c-soft for any y ∈ Y , see [KS,3.1.1] ◮ The full subcategory of f -soft sheaves is f!-injective. Moreover, p∗ takes f -soft sheaves to f ′-soft sheaves. Hence we can compute both q∗ ◦ f! and f ′

! ◦ p∗ using f -soft resolutions, and this proves that the

natural transformation q∗ ◦ Rf! → Rf ′

! ◦ p∗ is again an isomorphism.

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SLIDE 2

Verdier duality

◮ For convenience, let us now work with sheaves of Z-modules, and write ShZ(X) = Sh(X). One can work with R-modules with R of finite global dimension. But Cheng-Chiang refuses to. ◮ The wonderful Verdier duality starts with a seemingly innocent abstract concept that Rf! has a right adjoint for a nice map f : X → Y (e.g. continuous function between finite-dimensional CW-complexes). ◮ In other words, there is a functor f ! : D+(Sh(Y )) → D+(Sh(X)) so that there are natural isomorphisms HomD+(Sh(Y ))(Rf!F, G) = HomD+(Sh(X))(F, f !G) for all F ∈ D+(Sh(X)), G ∈ D+(Sh(Y )).

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SLIDE 3

Poincar´ e duality

HomD+(Sh(Y ))(Rf!F, G) = HomD+(Sh(X))(F, f !G)

◮ Suppose we are in a simple case for which X is a manifold and Y is a point so we identify Sh(Y ) = Ab. Let F = QX[n] and G = Q. We have HomD+(Ab)(H∗

c (X; Q)[n], Q) = HomD+(Sh(X))(QX, f !Q)

◮ We have HomD+(Ab)(H∗

c (X; Q)[n], Q) = Hom(Hn c (X; Q), Q).

◮ What is HomD+(Sh(X))(QX[n], f !Q)? One probably expects HomD+(Sh(X))(QX, f !Q) = H−n(X; f !Q) (i.e. Rf∗(f !Q)) no matter what kind of complex of sheaves f !Q is. Suppose this is true. ◮ Together, this reads Hom(Hn

c (X; Q), Q) = H−n(X; f !Z). Hmmm ...

◮ If X is orientable, we better have f !Q = QX[dim X] so that H−n(X; f !Q) = Hdim X−n(X; Q) and this is Poincar´ e duality!

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Proof of Verdier duality, I

HomD+(Sh(Y ))(Rf!F, G) = HomD+(Sh(X))(F, f !G)

◮ So we would like to prove Verdier duality; the existence of the right adjoint f !. ◮ Our proof follow [KS,§3.1] and partially a note of Akhil Mathew. ◮ In particular, we want to represent the functor F → HomD+(Sh(Y ))(Rf!F, G) for any G ∈ Sh(Y ). ◮ Replacing Rf! by Rf∗ makes this impossible, because even f∗ does not commute with infinite direct sum! ◮ Suppose for the moment that every object in whatever category we work on is injective and projective. Then it looks like f !G can be the sheaf with f !G(X) = HomD+(Sh(Y ))(f!ZX, G) and in general f !G(U) = HomD+(Sh(Y ))((f |U)!ZU, G). ◮ This doesn’t make much sense. But we can derive all of them.

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Proof of Verdier duality, II

Suppose for the moment that every object in whatever category we work on is injective and

  • projective. Then f !G = HomD+(Sh(Y ))(f!ZX , G)?

◮ Recall that a sheaf F ∈ ShR(X) is c-soft if for any compact K ⊂ X, Γ(X; F) ։ Γ(K; (K ֒ → X)∗F) is surjective. A sheaf F is called f -soft if F|f −1(y) is c-soft for all y ∈ Y . ◮ Lemma. Suppose there is an integer n such that Rif!F = 0 for all j > n, F ∈ Sh(X). Then for any exact sequence K0 → K1 → ... → Kn → 0 in Sh(X) such that K0, K1, ..., Kn−1 are all f -soft, we have Kn is f -soft as well. ◮ Now let us suppose it is true that Rif!F = 0 for all j > n; we will prove that if X is an n-dimensional CW-complex, then this is true. ◮ Let 0 → ZX → I0 → I1 → I2 → ... → In−1 → In → ... be a flabby resolution of flat Z-modules. This can be done as follows: I0 is the direct product of all the stalks of ZX, where each stalk is realized as a skyscraper sheaf at the same point. After that I1 is the direct product of all the stalks of the cokernel ZX → I0. One checks by induction that the sheaf constructed in each step has flat (i.e. torsion-free) stalks.

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SLIDE 6

Proof of Verdier duality, III

Let 0 → ZX → I0 → I1 → I2 → ... → In−1 → In → ... be a flabby resolution of flat Z-modules.

◮ Let Kn := Im(In−1 → In) so we have exact sequence 0 → ZX → I0 → ... → In−1 → Kn → 0, i.e. a resolution of ZX. ◮ Flabby ⇒ soft ⇒ c-soft ⇒ f -soft. Hence by the previous lemma, Kn is also f -soft. ◮ Write Ka = Ia for a = 0, 1, ..., n − 1. ◮ In dealing with HomD+(Sh(Y ))(Rf!F, G), we would like to compute F via 0 → F → F ⊗ K0 → ... → F ⊗ Kn → 0 This is exact by the flatness. ◮ Here let me remind that tensor product of sheaves is the sheafification of tensor product on sections, and one checks the stalk

  • f tensor product is tensor product of stalks.
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SLIDE 7

Proof of Verdier duality, IV

we would like to compute F via 0 → F → F ⊗ K0 → ... → F ⊗ Kn → 0

◮ We claim that each F ⊗ Ka is again f -soft. ◮ We have the resolution ... → P−1 → P0 → F → 0 by taking P0 to be the direct sum of (U → X)!ZU for each section s ∈ F(U) (so P0 → F sends 1 to s). And P−1 is the analogous for ker(P0 → F), etc. ◮ As Ka is flat, we again have ... → P−1 ⊗ Ka → P0 ⊗ Ka → F ⊗ Ka → 0. ◮ Each Pb ⊗ F can be checked to be f -soft. In particular this is the case for −n + 1 ≤ b ≤ 0. But then the lemma last page again says F ⊗ Ka is f -soft. This proves the claim. ◮ Now for G ∈ Sh(Y ), we define f !G to be the complex of sheaves given as follows: for any open j : U → X we have (f !G)−a(U) = HomSh(Y )(f!(j!j∗Ka), G). ◮ Likewise, for any bounded below complex G•, let f !G• be the complex associated to the double complex (f !Gb)−a.