Strichartz estimates for the wave equation in convex domains
Oana Ivanovici Gilles Lebeau Fabrice Planchon
Laboratoire Jean-Alexandre Dieudonn´ e Universit´ e de Nice Sophia-Antipolis
Strichartz estimates for the wave equation in convex domains Oana - - PowerPoint PPT Presentation
Strichartz estimates for the wave equation in convex domains Oana Ivanovici Gilles Lebeau Fabrice Planchon Laboratoire Jean-Alexandre Dieudonn e Universit e de Nice Sophia-Antipolis Monastir June 2013 The wave equation ( , g ) =
Laboratoire Jean-Alexandre Dieudonn´ e Universit´ e de Nice Sophia-Antipolis
t u − ∆gu = 0,
◮ Ω = Rd: Strichartz estimates for (W):
d=3 1/r 1/q 1/r 1/q 1/2 1/4 1/2 1/2 d=2
2 − 1 r ) − 1 q (scaling condition)
d=3 1/q 1/r 1/2 1/2
t L2 x ∇xu0L2 x + u1L2 x
2+ t
L
∞− x
H1
x + u1L2 x
◮ On average (in time !), a solution to the wave
◮ Or, to have u ∈ L∞− (almost everywhere in time), we
◮ Outside the admissibility set: Knapp counterexample
◮ Strichartz follows from energy conservation,
◮ A fundamental property of the half-wave operator
−∆Rd L1(Rd)→L∞(Rd) λ
d+1 2 |t|− d−1 2 .
transversal rays diffractive ray gliding ray highly!multiply reflected rays
−∆g(δa)L∞(Ω) λ
(d+1) 2 |t|− (d−1) 2 (λ|t|) 1 4
◮ Loss of 1 4 power of λt compared to the Euclidian case ◮ The result is optimal because of the presence of
◮ Currently: the Friedlander model case in full details (ILP)
◮ d = 3
d=3 1/r 1/2 1/2 1/3 3/8 1/r 1/2 1/2 3/8 1/3 1/q 1/q
◮ d = 4
1/6 1/r 1/2 1/2 1/r 1/2 1/q 1/q d=4 1/2 1/10 1/10 1/6
= loss of 1/6(1/4−1/r) derivatives = loss is unavoidble (O.I. ’08,’09) = sharp Stricharz ( I−L−P ’12) = GAP to be filled 1/q
d=2
1/6 1/8 1/4 1/2 5/24 1/4 1/r
d=3
?
1/4 1/4 1/3 5/12 1/2 1/2
?
1/q
◮ open: (partially) fill the GAP (conjecture: it should be
◮ Requires a finer analysis to average out singularities ◮ d = 2 is already known to hold (for any smooth
r + 1 r 2∂2 θ
x + (1 + x)∂2 y Disk Model domain
◮ a λ−4/7 : use gallery modes (e.g. spectral decomposition); ◮ a > λ−4/7 : write the flow as a superposition of waves
◮ Non-tangential directions |ξ| ≫ λ−1/4: at worst, cusp-like
◮ Main contribution comes from |ξ| λ−1/4, where the swallowtail
λk(η)ei(y−b)ηek(x, η)ek(a, η) dη
2 )2/3(1 + O( 1 k )) a zero of
2 3 x − ωk),
x + (1 + x)η2
◮ reduce to d = 2 by rotational symmetry ◮ spectral localization at
◮ localization to tangent directions η ∼ λ:
◮ G is symmetric in x and a:
−∆gψ2(
1+ωk(ηλ)−2/3)ψ(η)ek(a, ηλ)ek(x, ηλ)dη .
x,y ≤ Cλ2 min(1,
◮ the geometry is irrelevant when a is very small (too many
◮ Finer analysis on the sum of gallery modes (inspired by
◮ Why 4/7? for technical reasons not so clear yet..
k
◮ For values L ≤ 1 t (where L = a3/2λ) ⇒ OK ◮ It remains to study t > 1 a3/2λ.
k f(k) = N ˆ
ω3/2
k
ηλa3/2
3a3/2Nζ−t√
1+aζ2/3)χ(ζ)
◮ Stationary phase with ζ1/3 c
t 4N√a ≃ 1 yields:
3 t3 64N2 )ψ(η)
c
c
◮ For a2λ < t we bound each Airy factor by a constant ◮ For t > 1 a3/2λ the supports in y are disjoint! ◮ The condition t > 1 a3/2λ ≥ a2λ gives a λ−4/7.
3 2 )
◮ y (or η) is irrelevant. One solves the boundary value problem in
◮ By construction, the trace at x = 0 is the sum of the N = 0,
◮ the vN do not overlap too much: the supremum of the sum will
◮ each vN is analyzed by degenerate stationary phase: let
3 2 +ψa(t′)
λ2 (2π)2
◮ if N < min(a−1/2, a1/2λ1/3), one critical point in t′ of order
4!) while integration in η
6)...
x,y ≤ Cλ2
N − t2)1/6,
√a N , tN + √a N ) and where tN = 4N√a. ◮ Follows directly from the stationnary phase argument
◮ allows to track precisely where the usual TT ⋆
t L∞ x,y C(λ)fL6/5 s
L1
a,b.
◮ the swallowtail occurs only at tN = 4N√a, x = a,
◮ they have an effect on IN := (tN − √a N , tN + √a N ). ◮ outside IN only cusps with (λt)1/6 loss.