Stability results for a class of second-order evolution equations with intermittent delay
Cristina PIGNOTTI Universit` a di L’Aquila Italy Joint with Serge Nicaise Universit´ e de V alenciennes, France Chambery, June 15-18, 2015
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Stability results for a class of second-order evolution equations - - PowerPoint PPT Presentation
Stability results for a class of second-order evolution equations with intermittent delay Cristina PIGNOTTI Universit` a di LAquila Italy Joint with Serge Nicaise Universit e de V alenciennes, France Chambery, June 15-18, 2015 1 / 43
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0(Ω) × L2(Ω), is exponentially
Ω
t(x, t) + |∇u(x, t)|2]dx,
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Ω
t(x, t) + |∇u(x, t)|2]dx + ξ
Ω
t(x, t − τρ)dρdx ,
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1 2 ) the domain of A 1 2 .
1(t)B∗ 2(t) = 0,
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1(t)ut(t) + B2(t)B∗ 2(t)ut(t − τ) = 0, t > 0, (P)
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Wi ≤ Ci∥u∥2 H,
W1 ≤ ∥B∗ 1(t)u∥2 U1 ≤ M2n∥u∥2 W1 for t ∈ I2n = [t2n, t2n+1),
2(t)u∥2 U2 ≤ M2n+1∥u∥2 W2 for t ∈ I2n+1 = [t2n+1, t2n+2), ∀ n ∈ IN.
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n∈I N
V + ∥ut(t)∥2 H
t−τ
2(s + τ)ut(s)∥2 U2ds,
n∈I N
W .
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W .
1(t)ut(t)∥2 U1 − (B∗ 2(t)ut, B∗ 2(t)ut(t − τ))U2
2∥B∗ 2(t + τ)ut(t)∥2 U2 − ξ 2∥B∗ 2(t)ut(t − τ)∥2 U2.
1(t)ut(t)∥2 U1 + ξ
2(t + τ)ut(t)∥2 U2.
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2(t)ut, B∗ 2(t)ut(t − τ))U2 + ξ 2∥B∗ 2(t + τ)ut(t)∥2 U2
2∥B∗ 2(t)ut(t − τ)∥2 U2.
2(t)ut(t)∥2 U2 + ξ
2(t + τ)ut(t)∥2 U2.
2(t + τ) = 0.
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W ds,
V + ∥ut(t)∥2 H)
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2nM 2 2n)
2nM 2 2n),
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∞
n=0
∞
n=0
2nM 2 2n
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ξ )M2n+1T2n+1E(t2n+1),
ξ )M2n+1T2n+1cnE(t2n),
p=0eC(ξ+ 1
ξ )M2p+1T2p+1cp
∞
p=0
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m2p 4c(1+4C2T 2
2pM2 2p) + 1,
2pM 2 2p)
m2p 1+4C2T 2
2pM2 2p tends to 0 as p → ∞, then
2pM 2 2p).
∞
p=0
m2p 1+4C2T 2
2pM2 2p does not tend to 0, then,
p=0 ln cp = −∞.
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n∈I N
ξ )CM2n+1 ˜
T cn = d < 1,
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0(Ω) × L2(Ω) and b1, b2 in L∞(0, +∞)
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0(Ω) ∩ H2(Ω).
0(Ω). We then define
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i (φ) =
i (φ) = biφχω, for
Ω
t(x, t) + |∇u(x, t)|2}dx
t−τ
ω
t(x, s)dxds.
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0(Ω) × L2(Ω). It is well–known that an observability
ω
t (x, s)dxds,
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0(Ω)n × L2(Ω)n and b1, b2 satisfying the
0(Ω)n ∩ H2(Ω)n.
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0(Ω)n equipped with the
Ω
n
i,j=1
0(Ω)n.
i (φ) =
i (φ) = biφχω, for φ ∈ H and i = 1, 2. So, the problem
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Ω
ω
0(Ω)n × L2(Ω)n. This estimate is obtained
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S(t) ≤ −m2n∥ut(t)∥2 W1.
S(t) ≤ M2n+1
W2 + M2n+1
W2.
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S(t) = −∥B∗ 1(t)ut(t)∥2 U1 − (B∗ 2(t)ut, B∗ 2(t)ut(t − τ))U2.
S(t) = −∥B∗ 1(t)ut(t)∥2 U1.
S(t) = −(B∗ 2(t)ut, B∗ 2(t)ut(t − τ))U2
2(t)ut(t)∥2 U2 + 1
2(t)ut(t − τ)∥2 U2.
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1T 2 2nM 2 2n)
1T 2 2nM 2 2n),
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∞
n=0
∞
n=0
2nM 2 2n
S(t) ≤ M2n+1C2ES(t) + M2n+1C2ES(t − τ)
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p=0
∞
p=0
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0(Ω) × L2(Ω), b1, b2 in L∞(0, +∞) such
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W ≤ C∥u∥2 H,
U1 ≤ ∥B∗ 1(t)u∥2 U1 ≤ M2n∥u∥2 U1 for t ∈ I2n = [t2n, t2n+1),
2(t)u∥2 U2 ≤ M2n+1∥u∥2 W for t ∈ I2n+1 = [t2n+1, t2n+2), ∀u ∈ H,
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S(t) ≤ −∥B∗ 1(t)ut(t)∥2 U1 .
S(t) ≤ M2n+1
W2 + M2n+1
W2 .
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1(t)wt = 0,
1
0 , wn 1 ) ∈ V × H. For our stability result we need that the next
0 , wn 1 ), such that
t2n
1(t)wt(t)∥2 U1dt,
0 , wn 1 ) ∈ V × H.
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∞
n=0
∞
n=0
∞
n=0
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2 on the same intervals, hence it can be easily checked.
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∂u ∂ν (x, t) = −b1(t)ut(x, t)
Γ1(Ω) × L2(Ω), where as usual
Γ1(Ω) := { u ∈ H1(Ω) : u = 0 on Γ1 },
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∂w ∂ν (x, t) = −f(t)wt(x, t),
Γ1(Ω) × L2(Ω) and f ∈ L∞(0, +∞), f(t) ≥ 0 a.e.
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