Some Recent Progress in the Applications of Niho Exponents
Nian Li
Faculty of Mathematics and Statistics Hubei University Wuhan, China
July 5, 2017
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Some Recent Progress in the Applications of Niho Exponents Nian Li Faculty of Mathematics and Statistics Hubei University Wuhan, China July 5, 2017 Nian Li Problems From Niho Exponents BFA-2017, OS, Norway 1 / 35 Outline Niho Exponents
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1 Monomial Bent: only 5 classes 2 Binomial Bent: only about 6 classes 3 Polynomial form: quadratic form, Dillon type and Niho type Nian Li Problems From Niho Exponents BFA-2017, OS, Norway 15 / 35
2 +1)
2+1 + bx(2m−1)3+1)
2+1 + bx(2m−1) 1 4 +1)
2+1 + bx(2m−1) 1 6 +1)
2+1 +
2r +1)
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1 f(x) is Bent if p = 2 and gcd(r, m) = 1 (4-valued otherwise), and it
2 The proof (based on quadratic form) is self-contained and much
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1 Up to EA-equivalence, any Niho Bent function has the above form. 2 New Niho Bent functions obtained from quadratic and cubic
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1 Find C(d1,d2,··· ,dk) with optimal or good parameters; 2 Determine the weight distribution of its dual.
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1 p = 2: C(1,e) is optimal if and only if xe is APN
2 p > 3: C(1,e) cannot be optimal (minimal distance ≤ 3)
3 Connection with the correlation distribution between m-sequences
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2
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1 p = 2
2, s2). s2 = 1 2.
2 , 2k−1t + t+1 2 ), k|m + 1, or (k, 2m) = 1.
2 p > 2
4 , 3t+2 4 ), t ≡ 2 (mod 4).
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1 Weight distribution for some other special coefficient matrices? 2 · · · · · · Nian Li Problems From Niho Exponents BFA-2017, OS, Norway 26 / 35
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1 f(x) = xr(x(q2−1)/d + a), Zieve 2009. 2 f(x) = xr+s(q−1) + axr, Zieve 2013. 3 f(x) = xs(q−1)+e + ax(s−l)(q−1)+e, Tu, Zeng, Hu, Li 2013. 4 f(x) = x2q+3 + ax, p = 2, Tu, Zeng, Hu 2014. 5 f(x) = x q 4 (q+3) + ax, p = 2, Tu, Zeng, Hu 2014. 6 f(x) = ax + x3q−2, Hou, Lappano 2015. 7 f(x) = ax + x5q−4, Lappano 2015. 8 f(x) = x(xq+1 + a), Li, Qu, Chen 2015. 9 f(x) = xr(xq−1 + a), Li, Qu, Chen 2015. Nian Li Problems From Niho Exponents BFA-2017, OS, Norway 28 / 35
1 Linearized PPs, Lidl, Niederreiter 1997. 2 f(x) = x + x5 + x7, Dickson polynomial, n ≡ 1, 2 (mod 3). 3 f(x) = xk(2m+1)+3 + xk(2m+1)+2m+2 + xk(2m+1)+3·2m, Zieve 2013. 4 f(x) = x + xkq−k+1 + xk+1−kq, Ding, Qu, Wang, Yuan, Yuan 2014. 5 f(x) = x + ax2q−1 + a q 2 xq(q−1)+1, Ding et al. (a = 1); Li et al. 2015. 6 f(x) = ax + bxq + x2q−1, Hou 2015. 7 f(x) = x + xq + x q 2 (q−1)+1, p = 2, Li, Qu, Chen 2015. 8 f(x) = x + xq+2 + x q 2 (q+1)+1, Li, Qu, Chen 2015. 9 Two n = 3m cases: Blokhuis et al. 2001 and Tu et al. 2014. Nian Li Problems From Niho Exponents BFA-2017, OS, Norway 29 / 35
1 (s, t) = (− 1
2 (s, t) = (3, −1); 3 (s, t) = (− 2
4 (s, t) = ( 1
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1 (s, t) = (
2 (s, t) = (
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1 More general results from Niho exponents? 2 Permutation polynomials from generalized Niho exponents? 3 Permutation polynomials for odd prime p. 4 Differential property of PPs (not from Niho exponents). Nian Li Problems From Niho Exponents BFA-2017, OS, Norway 33 / 35
1 Using Kim function (which is APN) 2 Via simplex codes 3 Dillon et al. found the first APN permutation in even dimension! 4 The obtained APN permutation is CCZ-equivalent to Kim function!
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