shuffling properties for products of random permutations
play

Shuffling properties for products of random permutations Olivier - PowerPoint PPT Presentation

Shuffling properties for products of random permutations Olivier Bernardi (MIT) Joint work with Rosena Du, Alejandro Morales, Richard Stanley 3 9 7 10 2 1 8 5 11 4 6 Halifax, June 2012 Warm up Question: Let be a uniformly random


  1. Shuffling properties for products of random permutations Olivier Bernardi (MIT) Joint work with Rosena Du, Alejandro Morales, Richard Stanley 3 9 7 10 2 1 8 5 11 4 6 Halifax, June 2012

  2. Warm up Question: Let π be a uniformly random permutation of { 1 , 2 , . . . , n } . What is the probability that 1 , 2 , . . . , k are in distinct cycles of π ?

  3. Warm up Question: Let π be a uniformly random permutation of { 1 , 2 , . . . , n } . What is the probability that 1 , 2 , . . . , k are in distinct cycles of π ? Answer: 1 k ! . Proof: Sampling process for π : build the cycles. 4 3 2 3 1 1 2 1 1 2

  4. Warm up Let α = ( α 1 , α 2 , . . . , α k ) be a tuple of positive integers. Definition: A permutation π of { 1 , 2 , . . . , n } is said to be α -separated if letters from different blocks B 1 = { 1 , 2 , . . . , α 1 } , B 2 = { α 1 + 1 , α 1 + 2 , . . . , α 1 + α 2 } , . . . B k = { α 1 + · · · + α k − 1 + 1 , . . . , α 1 + · · · + α k } , are in different cycles of π .

  5. Warm up Let α = ( α 1 , α 2 , . . . , α k ) be a tuple of positive integers. Definition: A permutation π of { 1 , 2 , . . . , n } is said to be α -separated if letters from different blocks B 1 = { 1 , 2 , . . . , α 1 } , B 2 = { α 1 + 1 , α 1 + 2 , . . . , α 1 + α 2 } , . . . B k = { α 1 + · · · + α k − 1 + 1 , . . . , α 1 + · · · + α k } , are in different cycles of π . Example: α = (2 , 2 , 1) . Blocks: { 1 , 2 } { 3 , 4 } { 5 } . 3 9 7 10 2 1 8 5 11 4 6

  6. Warm up Let α = ( α 1 , α 2 , . . . , α k ) be a tuple of positive integers. Question: Let π be a uniformly random permutation of { 1 , 2 , . . . , n } . What is the probability that π is α -separated ? α 1 ! α 2 ! . . . α k ! Answer: ( α 1 + α 2 + . . . + α k )! .

  7. Warm up Let α = ( α 1 , α 2 , . . . , α k ) be a tuple of positive integers. Question: Let π be a uniformly random permutation of { 1 , 2 , . . . , n } . What is the probability that π is α -separated ? α 1 ! α 2 ! . . . α k ! Answer: ( α 1 + α 2 + . . . + α k )! . Proof: Sampling process for π : build the cycles. 4 3 2 3 1 1 2 1 1 2

  8. Results

  9. Type of question Let λ, λ ′ be partitions of n . Let π, π ′ be uniformly random permutations of cycle-type λ, λ ′ . Let α be a composition of m ≤ n . What is the probability that the product π ◦ π ′ is α -separated?

  10. Results Theorem [Du, Stanley]. Let π, π ′ be uniformly random n -cycles. The probability that 1 , 2 , . . . , k are in different cycles of product ππ ′ is 1 if n − k odd, k ! 1 2 k ! + otherwise. ( k − 2)!( n − k + 1)( n + k )

  11. Results Theorem [Du, Stanley]. Let π, π ′ be uniformly random n -cycles. The probability that 1 , 2 , . . . , k are in different cycles of product ππ ′ is 1 if n − k odd, k ! 1 2 k ! + otherwise. ( k − 2)!( n − k + 1)( n + k ) + Extension to product ( n − j ) -cycle × n -cycle for k = 2 . Case k = 2 was conjectured by B´ ona.

  12. More results: general composition α Theorem [BMDS]. Let π, π ′ be uniformly random n -cycles. Let α = ( α 1 , α 2 , . . . , α k ) be a composition of size m . The probability that the product ππ ′ is α -separated is ( − 1) n − m � n − 1 � m − k � ( n − m )! � k ( − 1) r � m − k �� n + r +1 � � i =1 α i ! k − 2 � r m + . � n + m � n + k + r � ( n + k )( n − 1)! � m − k r =0 r

  13. More results: general composition α Theorem [BMDS]. Let π, π ′ be uniformly random n -cycles. Let α = ( α 1 , α 2 , . . . , α k ) be a composition of size m . The probability that the product ππ ′ is α -separated is ( − 1) n − m � n − 1 � m − k � ( n − m )! � k ( − 1) r � m − k �� n + r +1 � � i =1 α i ! k − 2 � r m + . � n + m � n + k + r � ( n + k )( n − 1)! � m − k r =0 r + Extension to π = uniformly random ( n − j ) -cycle.

  14. More results: general composition α more cycles Theorem [BMDS]. Let π be a uniformly random permutation having p cycles. Let π ′ be a uniformly random n -cycle. Let α = ( α 1 , α 2 , . . . , α k ) be a composition of size m . The probability that the product ππ ′ is α -separated is �� n + k − 1 n − m ( n − m )! � k i =1 α i ! � 1 − k � c ( n − k − r + 1 , p ) � ( n − k − r + 1)! , c ( n, p ) n − m − r r r =0 where c ( n, p ) = [ x p ] x ( x + 1) · · · ( x + n − 1) “signless Stirling numbers of the first kind”.

  15. More results: general composition α more cycles involutions Theorem [BMDS]. Let π be a uniformly random fixed-point free involution. Let π ′ be a uniformly random 2 N -cycle. Let α = ( α 1 , α 2 , . . . , α k ) be a composition of size m . The probability that the product ππ ′ is α -separated is � k i =1 α i ! (2 N − 1)!(2 N − 1)!! × �� 2 N + k − 1 min(2 N − m,N − k +1) � 2 k + r − N − 1 (2 N − k − r )! � 1 − k � . 2 N − m − r ( N − k − r + 1)! r r =0

  16. More results: general composition α more cycles involutions symmetry Theorem [BMDS]. Let λ be a partition. Let π be a uniformly random permutation of type λ . Let π ′ be a uniformly random n -cycle. Let α = ( α 1 , α 2 , . . . , α k ) , β = ( β 1 , β 2 , . . . , β k ) be compositions of size m and length k . λ that the product ππ ′ is α -separated and λ and σ β The probabilities σ α β -separated are related by σ β σ α λ λ = . � k � k i =1 α i ! i =1 β i !

  17. Strategy

  18. Set up: Let α = ( α 1 , . . . , α k ) be a composition of m ≤ n . λ =proba that π ◦ π ′ is α -separated. Notation. σ α random permutation of type λ random n -cycle

  19. Set up: Let α = ( α 1 , . . . , α k ) be a composition of m ≤ n . λ =proba that π ◦ π ′ is α -separated. Notation. σ α random permutation of type λ random n -cycle Def. For tuple A = ( A 1 , . . . , A k ) of disjoint subsets of { 1 , 2 , . . . , n } , we say that a permutation π is A -separated if elements in different blocks of A are in distinct cycles of π . Example: π is ( { 1 , 3 , 6 } , { 2 , 10 } ) -separated. 3 9 7 10 2 1 8 5 11 4 6

  20. Set up: Let α = ( α 1 , . . . , α k ) be a composition of m ≤ n . λ =proba that π ◦ π ′ is α -separated. Notation. σ α random permutation of type λ random n -cycle Remark. σ α λ = proba that π ◦ (1 , 2 , . . . , n ) is A -separated. random permutation of type λ random subsets ( A 1 , . . . , A k ) with # A i = α i

  21. Set up: Let α = ( α 1 , . . . , α k ) be a composition of m ≤ n . λ =proba that π ◦ π ′ is α -separated. Notation. σ α random permutation of type λ random n -cycle λ = proba that π − 1 ◦ (1 , 2 , . . . , n ) is A -separated. Remark. σ α random permutation of type λ random subsets ( A 1 , . . . , A k ) with # A i = α i

  22. Set up: Let α = ( α 1 , . . . , α k ) be a composition of m ≤ n . λ =proba that π ◦ π ′ is α -separated. Notation. σ α random permutation of type λ random n -cycle λ = proba that π − 1 ◦ (1 , 2 , . . . , n ) is A -separated. Remark. σ α random permutation of type λ random subsets ( A 1 , . . . , A k ) with # A i = α i Lemma: # S α σ α λ λ = , n � � # C λ α 1 ,α 2 ,...,α k ,n − m where S α λ is set of triples ( A, π, ω ) such that • A = ( A 1 , . . . , A k ) is a tuple of disjoint subsets of [ n ] , with # A i = α i • permutation π has type λ , • permutation ω is A -separated, • π ◦ ω = (1 , 2 , . . . , n ) .

  23. Set up: We want to count set S α λ of triples ( A, π, ω ) such that • A = ( A 1 , . . . , A k ) is a tuple of disjoint subsets of [ n ] , with # A i = α i • permutation π has type λ , • permutation ω is A -separated, • π ◦ ω = (1 , 2 , . . . , n ) . Example. Let n = 8 , α = (3 , 2) , λ = (3 , 3 , 2) . Triple ( A, π, ω ) is in S α λ where A = ( { 1 , 4 , 8 } , { 3 , 5 } ) , π = (1 , 7 , 4)(3 , 2 , 6)(5 , 8) , ω = (1 , 6)(2)(3 , 7 , 5)(4 , 8) .

  24. A formula for colored factorization of long cycle Def. A colored permutation is a permutation with cycles colored in Z > 0 . It has color-type γ = ( γ 1 , . . . , γ k ) if there are exactly γ i elements of color i . Example: Colors 1 , 2 , 3 . 3 9 7 10 2 1 8 5 11 4 6 Color-type: γ = (4 , 3 , 4) .

  25. A formula for colored factorization of long cycle Def. A colored permutation is a permutation with cycles colored in Z > 0 . It has color-type γ = ( γ 1 , . . . , γ k ) if there are exactly γ i elements of color i . Thm [Schaeffer Vassilieva 08, Vassilieva Morales 09]. Let γ, γ ′ be compositions of size n of length k, k ′ The number of colored permutations π, π ′ of color-types γ, γ ′ such that ππ ′ = (1 , 2 , . . . , n ) is B γ,γ ′ = n ( n − k )!( n − k ′ )! ( n − k − k ′ + 1)! .

  26. Navigating between cycle-type and color-type Def. Symmetric functions in x = x 1 , x 2 , x 3 . . . Bases indexed by partitions λ = ( λ 1 , . . . , λ ℓ ) : p λ ( x ) = � ℓ i ≥ 1 x k i =1 p λ i ( x ) where p k ( x ) = � • Power basis: i . i ≥ 1 x γ i • Monomial basis: m λ ( x ) = � � i . γ 1 ,γ 2 ,... ∼ λ

Download Presentation
Download Policy: The content available on the website is offered to you 'AS IS' for your personal information and use only. It cannot be commercialized, licensed, or distributed on other websites without prior consent from the author. To download a presentation, simply click this link. If you encounter any difficulties during the download process, it's possible that the publisher has removed the file from their server.

Recommend


More recommend