Paweł Caputa
Quantum Entanglement and Local Excitations
HMSCS, GGI, 12/03/2015
Quantum Entanglement and Local Excitations Pawe Caputa HMSCS, - - PowerPoint PPT Presentation
Quantum Entanglement and Local Excitations Pawe Caputa HMSCS, GGI, 12/03/2015 Based on : Entanglement of local operators in large-N conformal field theories with Masahiro Nozaki, Tadashi Takayanagi PTEP 2014 (2014) 9, 093B06
HMSCS, GGI, 12/03/2015
with Masahiro Nozaki, Tadashi Takayanagi PTEP 2014 (2014) 9, 093B06
with Joan Simon, Andrius Stikonas, Tadashi Takayanagi JHEP 1501 (2015) 102
with Joan Simon, Andrius Stikonas, Tadashi Takayanagi, Kento Watanabe
A
A)
A
A)
N
[Ryu,Takayanagi’06]
d
) direction. time
(We
d
CFT
[Hubeny,Rangamani,Takayanagi’07]
Disconnected regions (Mutual Information)
IA:B = SA + SB − SA∪B
[see Cardy,Calabrese…]
Characterise operators from the perspective of quantum entanglement This Talk: Modest step towards this…
∆S(n)
A
= 1 1 ° n log √ Tr(Ωn
A)
Tr(Ω(0)
A )n
! = 1 1 ° n log ∑hO(w1, ¯ w1)O†(w2, ¯ w2)...O(w2n, ¯ w2n)iΣn (hO(w1, ¯ w1)O†(w2, ¯ w2)iΣ1)n ∏
A)
[Nozaki,Numasawa,Takayanagi,’13] [Sierra et al.,’12]
(n=2)
hO(w1, ¯ w1)O(w2, ¯ w2)O(w3, ¯ w3)O(w4, ¯ w4)iΣ2 (hO(w1, ¯ w1)O(w2, ¯ w2)iΣ1)2 = |z|2∆O|1 z|2∆0GO(z, ¯ z)
In rational CFTs
∆S(2)
A = log F00[O] = log dO,
G(z, ¯ z) ' F00[O] · (1 z)−2∆O ¯ z−2∆O,
At late time
quantum dimension (z, ¯ z) → (1, 0)
[He,Numasawa,Takayanagi,Watanabe’14]
d∆ = S0∆ S00
0.0 0.5 1.0 1.5 2.0 2.5 3.0 t 0.2 0.4 0.6 0.8 1.0
SA2
“EPR pair propagating through the system”
`topologically invariant’
tities !
FO(b|z) ' z∆b−2∆O · 2F1(∆b, ∆b, 2∆b, z)
G(z, ¯ z) = X
b
(Cb
OO†)2FO(b|z) ¯
FO(b|¯ z)
A
Conformal block expansion at large central charge c
[Fateev,Ribault’11]
at late time
10 t DSA
H2L
similar to a local quench
[PC,M.Nozaki,T.Takayanagi14]
l t
⟨Ttt⟩ = ⟨O†(w2, ¯ w2)Ttt(x, x)O(w1, ¯ w1)⟩ ⟨O†(w2, ¯ w2)O(w1, ¯ w1)⟩ = ∆O2
((x + l − t)2 + 2)2 + 1 ((x + l + t)2 + 2)2
N w1 = i( − it) − l, w2 = −i( + it) − l, ¯ w1 = −i( − it) − l, ¯ w2 = i( + it) − l.
In our setup:
[Nozaki,Numasawa,Takayanagi’13]
∆S(1) ∼ c 6 log sin ⇡a a t(L − t) ✏L
6 log t ✏
6 log sin ⇡a a
r 1 − µ R2
[PC,Nozaki,Takayanagi’14]
ρ(t) = Ne−iHtO(x4, ¯ x4) |0i h0| O(x1, ¯ x1)eiHt
[Bernamonti et al.’14]
A = hO(x1, ¯
A = |x23|−4∆n|1 − z|4∆nGn(z, ¯
x1 = −i✏, x4 = i✏
x2 = l1 − t, x3 = l2 − t ¯ x2 = l1 + t, ¯ x3 = l2 + t
¯ x1 = i✏, ¯ x4 = −i✏
G(z, ¯ z) ' z
1−α 2 (1 zα)¯
z
1−α 2 (1 ¯
zα) α2 !−2h
[Fitzpatrick et al.’14]
α = r 1 − 24∆O c
[Zamolodchikov….]
z)
Two-heavy and two light operators
h/c → 0 ∆O/c − fixed
∆S(1) ∼ c 6 log sin ⇡↵ ↵ t(L − t) ✏L
Using this we can compute
[Horowitz,Itzhaki’99]
In order to find a back-reaction from a particle in AdS we “just” have to find the map to the r=0 solution in global AdS and insert to the above metric
ds2 = −
rd−2
R2dr2 R2 + r2 − M/rd−2 + r2dΩ2
d−1.
m = (d − 1)πd/2−1 8Γ(d/2) · M GNR2 .
z(t) =
S = −mR
z(t)2 z(t) .
i=1 dx2 i
2z ,
z , rΩi = Rxi z (i = 1, 2, · · ·, d − 1), rΩd = −R2eβ + e−β(z2 + x2 − t2) 2z .
Back reacted metric after inserting:
r = 1 2z
i − t2)2 − 2R2(z2 − x2 − t2),
dτ 2 = d(cos τ)2 + d(sin τ)2, dΩ2
d−1 = d
(dΩi)2.
we can check that we get the appropriate energy density
SA = c 6 2 6 6 4log
∞ · r(2) ∞
2 cos ✓ |∆˜ ⌧∞| √
R2−µ R
◆ − 2 cos ✓ |∆∞| √
R2−µ R
◆ R2 − µ 3 7 7 5
where
tan τ (i)
∞ =
2Rt R2eβ + e−β((l(i))2 − t2), tan θ(i)
∞ = −
2Rl(i) e−β((l(i))2 − t2) − R2eβ , r(i)
∞ = 1
z∞
4
∆S(1) ∼ c 6 log sin ⇡a a t(L − t) ✏L
6 log t ✏
6 log sin ⇡a a
n
2 En |niL |niR
Eternal BH TFD
[Maldacena’01]
[Maldacena Hartman]
A B
IA:B = SA + SB − SA∪B
[Morrison,Roberts]
L/2 t IA:B
HL-HR HL+HR
SA∪B ' t
SA∪B ' 2Sth
t < L/2 t > L/2
TFD
[P.C,Simon,Stikonas,Takayanagi’14]
[Shenker,Stanford] [Roberts,Stanford] [+ Susskind]
z(⌧) = 2⇡ v u u t1 1 ✓2⇡✏
1 tanh2 ✓2⇡⌧
.
X T
ds2 = R2 z2 ✓
dt2 + dz2 (1 Mz2) + dx2 ◆
Sp = mR Z d⌧ z(⌧) s 1 Mz(⌧)2 ˙ z(⌧)2 1 Mz(⌧)2
[PC,Simon,Stikonas,Takayanagi’14]
Entanglement Entropy gravity
Tr⇢n
A(t) = h (x1, ¯
x1)(x2, ¯ x2)˜ (x3, ¯ x3) †(x4, ¯ x4)iCn (h (x1, ¯ x1) †(x4, ¯ x4)iC1)n
CFT large c
∆SA = c 6 log 2 4 ⇡✏ sin ⇡↵ψ ↵ψ sinh ⇣
π(L−t−tw) β
⌘ sinh ⇣
π(t+tw) β
⌘ sinh ⇣
πL β
⌘ 3 5
∆SA ' c 6 log "
sin a a sinh π(t+tw)
β
sinh π(L−t−tw)
β
sinh πL
β
#
w(x) = e
2π β x
O ≡ ψ
ds2 = R24dudv + (1 + uv)2d2 (1 + uv)2 = R24dT 2 + 4dX2 + (1 T 2 + X2)2 d2 (1 + T 2 X2)2
t = ˜ ⌧, ✓ = 0, 1 Mz2 = (1 M✏2) cosh2 ⇣p M(˜ ⌧ + tω) ⌘
we can compute the back reaction using a map with two parameters tanh 2 = p 1 − M✏2 λ1 = √ Mtw
Xh- Xh+ X T
Xm Xh- Xh+ Xs- Xs+ X Tm T
Tr⇢n
A(t) = h (x1, ¯
x1)(x2, ¯ x2)˜ (x3, ¯ x3)(x5, ¯ x5)˜ (x6, ¯ x6) †(x4, ¯ x4)i (h (x1, ¯ x1) †(x4, ¯ x4)iC1)n
A B
[PC,Simon,Stikonas,Takayanagi,Watanabe]
O ≡ ψ
t?
! = f(L, ) +
2⇡ log S ⇡E
sin ✓ ⇡ q 1 24∆O
c
◆ q 1 24∆O
c
' 3∆O c✏ = ⇡EO S
[PC,Simon,Stikonas,Takayanagi,Watanabe]
w) = 0?
C4 ' ✓
◆−4h exp 4⇡h
tw + 2⇡ log ✓ ⇡✏ sin(⇡↵) ↵ ◆◆ C4 = hOhw(x1, ¯ x1)Oh(x2, ¯ x2)Oh(x3, ¯ x3)Ohw(x4, ¯ x4)i hOhw(x1, ¯ x1)Ohw(x4, ¯ x4)i
w(x) = e
2π β x
[see also Roberts,Stanford’15]