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PICOF 2012 Regularity Estimates in High Conductivity Homogenization - - PowerPoint PPT Presentation
PICOF 2012 Regularity Estimates in High Conductivity Homogenization - - PowerPoint PPT Presentation
PICOF 2012 Regularity Estimates in High Conductivity Homogenization Yves Capdeboscq Oxford Centre for Nonlinear PDE, University of Oxford With Marc Briane (Rennes) & Luc Nguyen (Princeton) Outline Enhanced Resolution for finite contrast
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Time Reversal Experiment (Physics)
- C. Prada & M. Fink (Wave Motion ’94). . .
For acoustic waves, with random scatterers in a resonant chamber. Step 1 A pulse is emitted at a source location Step 2 The signal is recorded on an array of microphones, behind the scatterers (for a long time T) Step 3 The signal is amplified and played back, backwards, from the array. At time 2T, a peak appears at the location where the pulse was emitted.
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Time Reversal Mirror (Maths)
Extracted from Guillaume Bal’s webpage, http://www.columbia.edu/˜gb2030/
- J. P. Fouque, J. Garnier, G. Papanicolaou and K. Sølna, Wave
propagation and time reversal in randomly layered media, Springer, 2007.
- G. Bal and L. Ryzhik Time reversal and refocusing in random
media, SIMA, 2003.
- C. Bardos & M. Fink, Mathematical foundations of the time
reversal mirror, Asymptotic Anal. 2002 http://www.claudebardos.com/pdf/retemp.pdf
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Focusing Beyond the Diffraction Limit
- G. Lerosey, J. de Rosny, A. Tourin, A. Derode, M. Fink,Focusing
Beyond the Diffraction Limit with Far-Field Time Reversal Science, 23 February 2007, p.1120-1122 A TRM made of eight commercial dipolar antennas operating at λ = 12 cm. is placed in a 1 m3 reverberating chamber. Ten wavelength away from the TRM is placed a sub-wavelength receiving array consisting of 8 micro-structured antennas λ/30 apart from each other.
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Focusing Beyond the Diffraction Limit
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Focusing Beyond the Diffraction Limit
Interpretation via homogenization and small volume asymptotics, for passive imaging.
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Passive imaging : no source in the medium
Model problem: Helmholtz equation (time harmonic, in TM (transverse magnetic) Polarization). The x3 component of the magnetic field satisfies div(a(x)∇u(x)) + ω2µ(x)u(x) = in BR, u = ϕ on SR with a(x) = 1 ε(x) + iσ(x)/ω, and ε(x): electric permittivity, σ(x) : conductivity, µ(x) : magnetic permeability, ω : 2π λ .
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Difference Imaging
We compare the traces of div(a(x)∇u(x)) + ω2µ(x)u(x) = in BR, and div(ad(x)∇ud(x)) + ω2µd(x)ud(x) = in BR, u, ud = ϕ
- n SR
where ud corresponds to (ad, µd) := (a(x), µ(x)) + 1D(x)(aD(x) − a(x), µD(x) − µ(x)). We want to find inclusions from boundary measurements (or the far field). We consider differential measurements, that is, the map Λ : H1/2(SR) → H−1/2(SR) ϕ → a∇ (ud − u) · n|SR
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Resolution for passive systems
Example: a homogeneous background (ε0, µ0) and a constant inclusion (ε1, µ1). Suppose D = B(0, r) and r → 0.
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Resolution for passive systems
Example: a homogeneous background (ε0, µ0) and a constant inclusion (ε1, µ1). Suppose D = B(0, r) and r → 0. (Λ(φ), φ) = rdR(φ, φ) + o
- rd
The response operator R is the bilinear form given by R(φ, ψ) = 1 rd
- Br
MB∇uφ · ∇uψdy + 1 rd
- Br
ω2mBuφuψdy The term MB is the polarisation tensor, here MB =
2 ε0+ε1 ε1−ε0 ε0
Id, and mB = µ1 − µ0. The function uφ (resp. uψ) satisfies div(ǫ−1
0 ∇uφ) + ω2µ0uφ
= 0 in BR uφ = φ resp. ψ on SR.
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Resolution for passive systems
For constant coefficients, R is explicit yielding a representation formula for Λ. The permeability response is, up to o(rd), Λ = C1,BJ1(kr)eiθ J1(kr)eiθ, ·
- +
C0,BJ0(kr)eiθ J0(kr)eiθ, ·
- when d = 2,
- r
Λ = C1,Bj1(kr)eiθ j1(kr)eiθ, ·
- +
C0,Bj0(kr)eiθ j0(kr)eiθ, ·
- when d = 3,
where k2 = µ0ε0ω2
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Resolution for passive system
x K 10 K 5 5 10 0.2 0.4 0.6 0.8 1.0 x K 10 K 5 5 10 0.2 0.4 0.6 0.8 1.0
The size of the focal spot, is given by the size first lobe(s) of the (spherical) Bessel Function J0(√µ0ε0ω·) (J1(√µ0ε0ω·) )
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Resolution for passive system
x K 10 K 5 5 10 0.2 0.4 0.6 0.8 1.0 x K 10 K 5 5 10 0.2 0.4 0.6 0.8 1.0
The size of the focal spot, is given by the size first lobe(s) of the (spherical) Bessel Function J0(√µ0ε0ω·) (J1(√µ0ε0ω·) ) This size does not depend on the inclusion.
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Enhanced resolution in structured media
- lim
|D|→0 ε = 0.
(|D|2, −1/ln|D| . . . ..)
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Enhanced resolution Ammari-Bonnetier-C ’09
Introduce scatterers in the medium, on a periodic grid (for example). Bε,j = jε + εB (aε(x), µε(x)) = (as, µs) in ∪j∈Sε Bε,j (a0, µ0)
- therwise.
(1) The true (defective) medium, material parameters are (aε,d(x), µε,d(x)) = (aD, µD) in D (as, µs) in ∪j Bε,j \ D. (a0, µ0)
- therwise.
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Enhanced Resolution in Structured Media
We want to image inclusions (imperfections) from boundary (far field) measurements. We consider difference measurements, namely the map Λ : H1/2(SR) → H−1/2(SR) ϕ → a∇ (uε,D − uε) · n|SR
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Enhanced Resolution in Structured Media
We want to image inclusions (imperfections) from boundary (far field) measurements. We consider difference measurements, namely the map Λ : H1/2(SR) → H−1/2(SR) ϕ → a∇ (uε,D − uε) · n|SR Result: if ε → 0 as |D| → 0, the response operator is given by < Λ(ϕ), ϕ >=
- D
M∗∇u∗(x)·∇u∗(x)dx+ω2
- D
m∗u2
∗(x)dx+o (|D|) ,
where M∗ and m∗ are constant polarization terms that depend on the contrast in material constants, where o (|D|) /|D| → 0 uniformly for ϕH1/2 ≤ 1
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Enhanced Resolution in Structured Media
We want to image inclusions (imperfections) from boundary (far field) measurements. We consider difference measurements, namely the map Λ : H1/2(SR) → H−1/2(SR) ϕ → a∇ (uε,D − uε) · n|SR Result: if ε → 0 as |D| → 0, the response operator is given by < Λ(ϕ), ϕ >=
- D
M∗∇u∗(x)·∇u∗(x)dx+ω2
- D
m∗u2
∗(x)dx+o (|D|) ,
where M∗ and m∗ are constant polarization terms that depend on the contrast in material constants, where o (|D|) /|D| → 0 uniformly for ϕH1/2 ≤ 1 To be compared with the unscattered response operator, R(ϕ) =
- D
- M∇u0 · ∇u0 + ω2µu2
- dx + o (|D|) .
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different asymptotic limits
1 If ε → 0 first , then |D| → 0: correct focal spot, but incorrect
asymptotic formulae.
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different asymptotic limits
1 If ε → 0 first , then |D| → 0: correct focal spot, but incorrect
asymptotic formulae.
2 If |D| → 0 first, then ε → 0: the “reference” resolution
calculation.
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different asymptotic limits
1 If ε → 0 first , then |D| → 0: correct focal spot, but incorrect
asymptotic formulae.
2 If |D| → 0 first, then ε → 0: the “reference” resolution
calculation.
3 If εd ≪ |D|, then (1) is correct.
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Elements of proof
We use the following tools: H-convergence (strong with correctors) uε,d − u∗L2(Ω) , uε − u∗L2(Ω) → 0. (Murat 70s). Local regularity, and smoothness of u∗ The scatterers have a smooth C 1,α boundary (important). Then Li & Vogelius (’01), Li & Nirenberg (’03), and Avellaneda & Lin (’97) give W 1,∞ convergence estimates ||uε − u∗||L∞(D), ||∇uε − Pε∇u∗||L∞(D) → 0, where Pε ∈ L∞(Ω) is the corrector matrix. Similar to Ben Hassen & Bonnetier ’06. Small volume fraction asymptotics This gives an asymptotic formula for 1D∇uε,D/|D| in terms of a polarization tensor, involving Pε, and ∇u∗, not unlike C-Vogelius (’03, ’06).
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Elements of proof
We use the following tools: H-convergence (strong with correctors) uε,d − u∗L2(Ω) , uε − u∗L2(Ω) → 0. (Murat 70s). Local regularity, and smoothness of u∗ The scatterers have a smooth C 1,α boundary (important). Then Li & Vogelius (’01), Li & Nirenberg (’03), and Avellaneda & Lin (’97) give W 1,∞ convergence estimates ||uε − u∗||L∞(D), ||∇uε − Pε∇u∗||L∞(D) → 0, where Pε ∈ L∞(Ω) is the corrector matrix. Similar to Ben Hassen & Bonnetier ’06. Small volume fraction asymptotics This gives an asymptotic formula for 1D∇uε,D/|D| in terms of a polarization tensor, involving Pε, and ∇u∗, not unlike C-Vogelius (’03, ’06). That’s it.
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High Contrast Materials
Meta-materials can be constructed with high contrast periodic media (Felbacq-Bouchitt´ e ’04, ’09). At well chosen frequencies, infinite resolution would be possible. Collaboration with Marc Briane (Rennes) and Luc Nguyen (Princeton)
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High contrast materials ` a la Fenchenko & Khruslov ’81
ω0 ω x3 = −L x3 = L
Consider −div (aε ∇Wε) = 0 in Ω , Wε = Φ
- n ∂Ω .
with aε = 1 except in the rods of radius εrε, where κ− ≤ aεπr2
ε ≤ κ+.
The radius rε satisfies 2π γ+ ≤ −ε2 ln rε ≤ 2π γ− .
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High contrast materials
Suppose lim
ε→0 αε πr2 ε = κ ∈ [κ−, κ+],
lim
ε→0
2π ε2 |ln rε| = γ ∈ [γ−, γ+]. and Φb ∈ C 1(¯ Ω). Then, the solution Wε converges weakly in H1(Ω) to the unique solution W∗ of the coupled system − ∆W∗ + γ (W∗ − V∗) 1Ω0 = 0 in Ω − κ ∂2
33V∗ + γ (V∗ − W∗) = 0
in Ω0 = ω0 × (−L, L) W∗ = Φb
- n ∂Ω
V∗(·, ±L) = Φb(·, ±L) in ω0.
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High contrast materials
The function V∗ is a limit 1 |rods|1rodsWε ⇀ V∗ weakly ∗ in M(Ω). Consider the capacity function cσ
ε for some σ ≥ 1, in Ω
cσ
ε (x) :=
if r = |(x1, x2) − (m, n)ε| ≤ εrε ln r − ln(εrε) ln(εσ/2) − ln(εrε) if r ∈ (εrε, εσ/2), 1 elsewhere. Then ∇Wε · ∇cσ
ε ⇀ γ(U∗ − V∗) weakly ∗ in M(Ω).
∇Wεcσ
ε ⇀ ∇W∗ weakly ∗ in M(Ω).
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Strong H convergence with correctors. No extra-regularity
For a C 1 boundary data, lim
ε→0
- Ω
aε
- ∇Wε−∇cσ
ε (W∗ − V∗)−cσ ε ∇W∗−(1−cσ ε ) ∂3V∗ e3
- 2 dx = 0.
The corrector term is just L2. For a bounded contrast, Pε ∈ L∞.
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Strong H convergence with correctors. No extra-regularity
For a C 1 boundary data, lim
ε→0
- Ω
aε
- ∇Wε−∇cσ
ε (W∗ − V∗)−cσ ε ∇W∗−(1−cσ ε ) ∂3V∗ e3
- 2 dx = 0.
The corrector term is just L2. For a bounded contrast, Pε ∈ L∞. Let Φ ∈ C 2(¯ Ω) be such that the functions Φ(·, ±L) are both harmonic at most on a set of zero measure. Then, for any Ω′ ⊂ Ω there exists a constant C(Φ, Ω′) > 0 such that for any ρ ∈ (0, 1), lim inf
ε→0
- r2ρ(1−2/p)
ε
∇Wε2
Lp(Ω′)
- ≥ (1 − ρ)C(Φ, Ω′).
Blow-up everywhere at exponential rate (exp(C/ε2)) in W 1,p loc(Ω0).
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Proof
Let Oε =
- x ∈ ω0 : 0 < dist (x, rods) < εrρ
ε
- × (−L, L),
Using the definition of cσ
ε , and the continuity of W ∗ − V ∗,
1Oε |∇cσ
ε |2 (V∗−W∗)2 dx ⇀ γ(1−ρ) (V∗−W∗)2
weakly-∗ in M(Ω0). The limit cannot cancel on any Ω′, by analyticity w.r.t. x3. The corrector result shows that 1Oε
- ∇Wε − ∇cσ
ε (W∗ − V∗)
- 2 −
→ 0 strongly in L1
loc(Ω0).
Therefore 1Oε|∇Wε|2 ⇀ γ(1 − ρ)(V∗ − W∗)2 weakly- ∗ in M(Ω0).
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Proof
Fix Ω′′ ⋐ Ω′ ⊂ Ω0, and ζ a cut-off function.
- Ω′′ γ(1 − ρ)(V∗ − W∗)2 dx ≤
- Ω0
γ(1 − ρ)(V∗ − W∗)2 ζ dx = lim
ε→0
- Oε
|∇Wε|2 ζ dx ≤ lim inf
ε→0
- Oε∩Ω′ |∇Wε|2 dx
≤ lim inf
ε→0
- |Oε|1−2/p∇Wε2
Lp(Ω′\Qε)
- ≤ C1 lim inf
ε→0
- r2ρ(1−2/p)
ε
∇Wε2
Lp(Ω′\Qε)
- .
And this is valid for all Ω′′ ⋐ Ω′. Also true without touching the rods (ρ′ − ρ....)
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Regularity away from the rods
For a fixed ω0 ⋐ ω1 ⋐ ω, define ωε
τ by
ωε
τ = {x ∈ ω1 : dist (x, rods) ≥ ε1+τ}.
(2) Concerning −div(aε∇Uε) = F in H1
0(Ω) we show
Theorem For τ >
1−η 2(1+η) with η ∈
3
4, 1
- , and 0 < ν < 2
- η − 3
4
- , the
solution Uε satisfies Uε − V C 1,ν(ωε
τ×(−L,L)) ≤ C(η, ν)FL2(Ω),
where V ∈ H1
0(Ω) is the solution of
−∆V = F.
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Regularity away from the rods
Concerning −div(aε∇Wε) = 0 in H1(Ω), and u = Φb on ∂Ω we show Theorem Let Ωε
τ = ωε τ × (−l, l), with l < L. For τ > 1−η 2(1+η) with η ∈
3
4, 1
- ,
and 0 < ν < 2
- η − 3
4
- , the solution Wε satisfies
WεC 1,ν(Ωε
τ) ≤ C(η, ν, l) ΦbC 1(¯
Ω).
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Sketch of Proof
Using the 2 + 1 form of the problem, Ω = ω × (−L, L), we can reduce both problems to −div2(aε ∇2uε) + λ aε uε = f + aε g + div2(aεh) in ω , uε = 0
- n ∂ω ,
with f ∈ L2(ω), √aεg ∈ L2(ω), h ∈ L∞(ω)2 and λ = n2π2 L2 . Compare uε with v, −∆2 + λ v = f + g + div2(h) in ω , v = 0
- n ∂ω ,
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Sketch of Proof
Write uε − v = ˜ uε + ˆ uε outside the rods, where ˜ uε ∈ H1(ω \ rods) is the solution to −∆˜ uε + λ ˜ uε = 0 in ω \ rods , ˜ uε = 0
- n ∂ω ,
˜ uε = um,n
- n ∂rodsm,n .
(3) with um,n = 1 |∂rodsm,n|
- ∂rodsm,n
[uε(x) − v(x)] dσ(x), Constant coefficients, specific geometry, and the b.v. are
- constants. Fine estimates are possible..
˜ uεL∞(ωε
τ) + λβ−1/2∇˜
uεL∞(ωε
τ) ≤ C(β)
λ1/2 sup
m,n |um,n|
for 0 < β < 1
2, and τ > 1−2β 1+2β.
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Sketch of Proof
The remainder ˆ uε ∈ H1(ω \ rods) is the solution to −∆ˆ uε + λ ˆ uε = 0 in ω \ rods , ˆ uε = uε − v − um,n,
- n ∂rodsm,n.
(4) Poincar´ e inequality, energy estimates for uε and local estimates for v make this term negligible compared to the first two (v and ˜ uε). So we have a proof if we can bound sup
m,n |um,n| ≤ uεL∞(ω) + vL∞(ω)
appropriately (with the enough decay w.r.t λ).
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Sketch of Proof
For any q > 2, and any ω′ ⋐ ω, vL∞(ω′) ≤ C(q, ω′) λ
1 q
- f L2(ω) + gL2(ω) + hL∞(ω)
- .
And if g = 0 and h = 0, we have also uεL∞(ω) ≤ C(q) λ1/q f L2(ω) (5) (de Giorgi-Moser-Nash iteration)
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Counter-example
Consider −div2(aε ∇2uε) + λ aε uε = aε f in ω , uε = 0
- n ∂ω ,
Let 1D0,0,ε be the indicator function of the disk D0,0,ε ⊂ R2 centered at the origin and of radius εrε. Set fε := ε−11D0,0,ε and h ≡ 0. Then, we have √aεfεL2(ω) ≤ √κ+, and uεL∞(ω) ≥ 1 ε κ− κ+ κ− γ+ + λ κ+ + o(1), where limε→0 o(1) = 0.
- Proof. Write the energy bound
- ω
aε |∇uε|2 dx +
- ω
λ aε u2
ε dx =
- ω
aε fε uε dx ≤ κ+ ε uεL∞(ω) .
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Counter-example
- 2. Set gε := ε−1(1 − cσ
ε ) 1εY ∈ H1 0(ω), for σ = 1, and compute its
energy
- ω
aε |∇gε|2 dx +
- ω
λ aε g2
ε dx ≤ γ+ + λ κ+ + o(1).
- 3. Use Cauchy-Schwarz :
- κ+ ε uεL∞(ω)
1
2 (γ+ + λ κ+ + o(1)) 1 2
≥
- ω
aε ∇uε · ∇gε dx +
- ω
aε uε gε dx =
- ω
aε fε gε dx =
- D0,0,ε
aε ε−2dx ≥ κ−.
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Sketch of Proof
However, this is only powers of ε, not of exp(1/ε2). Optimal Sobolev constant:
- ω
aε |v|s dx ≤ C(s) ε2−s
- ω
aε |∇v|2 dx s
2
∀ v ∈ H1
0(ω).
for all s > 2. For ϕε ∈ H1
0 (ω) solution of
−div (aε∇ϕε) + λaεϕε = aεfε + div (aεh) . Then, for any 1 < α < 2, 0 < β < 1 − α/2, we have ϕεL∞(ω) ≤ C(α, β) εαλβ
- √aεf L2(ω) + ε
α+1 2 √aεhL∞(ω)
- .
Can be controlled with the regularity of Φb.
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What have we obtained ?
H-convergence (strong with correctors). Uniform Local C 1,α regularity ǫ1+τ away from the rods (everywhere except in a set ∝ ε2τ). Uniform global W 1,p, p > 2 regularity is false (lower bounds) Small volume fraction asymptotics?
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Small volume asymptotics for high contrast
Assume that Gε ⊂ Ωε, |Gε| → 0, and |Gε|−11Gε tends to a limit measure µ. There exists a subsequence still denoted ε, and a matrix-valued function M ∈ L2(Ω, µ)3×3 such that the bilinear response form has the following asymptotic form R(Φ) = |Gε|
- Ω
M∇W ∗ · ∇W ∗ dµ + o (|Gε|) for any Φ ∈ C 1(¯ Ω), where W ∗ denotes the solution to the homogenized problem with boundary condition Φ, and lim
ε→0
sup
ΦC1(¯
Ω)≤1
- (|Gε|)
|Gε| = 0. In addition, the matrix-valued function M is symmetric, independent of Φ, and satisfies (γ1 − 1) min
- 1, 1
γ1
- ≤ M(y)ξ · ξ ≤ max
- 1, 1
γ1
- µ-a.e.
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