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On the twisted Alexander polynomial for metabelian SL 2 ( C ) - - PowerPoint PPT Presentation

On the twisted Alexander polynomial for metabelian SL 2 ( C ) representations with the adjoint action Yoshikazu Yamaguchi JSPS Research fellow (PD) Tokyo Institute of Technology RIMS Seminar Twisted topological invariants and topology of


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On the twisted Alexander polynomial for metabelian SL2(C)–representations with the adjoint action

Yoshikazu Yamaguchi

JSPS Research fellow (PD) Tokyo Institute of Technology

RIMS Seminar “Twisted topological invariants and topology of low-dimensional manifolds”

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Basic notion and notation

The twisted Alexander polynomial The twisted Alexander polynomial = A refinement of ∆K (t) (the Alexander polynomial) with ρ : π1 → GL(V) Notation EK := S3 \ N(K) a knot exterior, Ad ◦ ρ : π1(EK )

ρ

− → SL2(C)

Ad

− − → Aut(sl2(C)) γ → ρ(γ) → Adρ(γ) : v → ρ(γ)vρ(γ)−1 sl2(C) = C 0 1

0 0

  • ⊕ C

1 0

0 −1

  • ⊕ C

0 0

1 0

  • The adjoint action Ad gives a connection with the character

variety Hom(π1(EK ), SL2(C))//SL2(C).

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Metabelian representations

Definition of metabelian reps. ρ : π1(EK ) → SL2(C) is metabelian

⇐ ⇒ ρ([π1(EK ), π1(EK )]) ⊂ SL2(C) an abelian subgroup.

Remark ρ : π1(EK ) → SL2(C) is abelian

⇐ ⇒ ρ(π1(EK )) ⊂ SL2(C) an abelian subgroup, ⇐ ⇒ ρ([π1(EK ), π1(EK )]) = {1}, ⇐ ⇒ π1(EK ) SL2(C) H1(EK; Z) π1(EK )/[π1(EK), π1(EK )] ≃ µ ρ

ρ is determined by only ρ(µ). We focus on non–abelian representations.

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Definitions of reducible and irreducible reps.

ρ : π1(EK ) → SL2(C) ρ : reducible

Def

⇐ ⇒ ∃L ⊂ C2 s.t. ρ(g)(L) ⊂ L (∀g ∈ π1(EK )) by taking conjugation, ρ : π1(EK ) → a ∗ a−1

  • a ∈ C \ {0}
  • ⊂ SL2(C)

ρ : irreducible

Def

⇐ ⇒ ρ : not reducible.

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Reducible and irreducible reps. in metabelian ones

ρ : π1(EK ) → SL2(C) metabelian ρ : reducible ρ : [π1(EK ), π1(EK )] →

  • ±

1 ω 1

  • ω ∈ C
  • ⊂ SL2(C)

since Im ρ ⊂ a ∗ a−1

  • a ∈ C \ {0}
  • and

A, B ∈ SL2(C) : upper triangular ⇒ ABA−1B−1 = 1 ∗ 1

  • ρ : irreducible

ρ : [π1(EK ), π1(EK )] → a a−1

  • a ∈ C \ {0}
  • ⊂ SL2(C)

ρ(µ) = 1 −1

  • by F. Nagasato.

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Background

ρ : π1(EK ) → SL2(C) metabelian ρ : reducible ∆K (t) appears in the twisted Alexander polynomial. − → Hyperbolic torsion at “bifurcation points” in Hom(π1(EK, SL2(C)))//SL2(C). ρ : irreducible “Does ∆K(t) appear in the twisted Alexander?”

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Main Theorem

Theorem Suppose that ρ : π1(EK) → SL2(C) s.t. an irred. metabelian and; “longitude–regular”. Then (the twisted Alexander poly.) ∆α⊗Ad◦ρ

EK

(t)

·

= (t − 1)∆K (−t)P(t), where ∆K (t) is the Alexander polynomial of K.

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Hierarchy of metabelian representations

Remark ρ : π1(EK ) → SL2(C) reducible = ⇒ ρ : metabelian (∵) Im ρ ⊂ a

∗ 0 a−1

a = 0

  • ⇒ ρ([π1(EK ), π1(EK )]) ⊂
  • ±

1 ∗

0 1

  • We have the following hierarchy of metabelian representations:

abelian ⊂ reducible ⊂ metabelian roots of ∆K (t) ∆K (−1)

difference difference

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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The details of reducible metabelian representations

Existence of reducible representations (G. Burde, G. de Rham) ∃ρ : π1(EK ) → SL2(C) : reducible and non–abelian if and only if ∆K (λ2) = 0 where λ is an eigenvalue of ρ(µ). {the characters of non–abelian reducible representations} = Cabel ∩ Cnon–abel in Hom(π1(EK ), SL2(C))//SL2(C), where Cabel is the component of abelian characters and Cnon–abel is the components of non–abelian ones.

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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The twisted Alexander polynomial of reducible SL2(C)-representations

Theorem ρ : π1(EK ) → SL2(C) reducible and non–abelian, corresponding to λ ∈ C s.t. λ is an eigenvalue of ρ(µ) and ∆K (λ2) = 0 , then ∆α⊗Ad◦ρ

EK

(t) = ∆K(λ2t) (λ2t − 1) · ∆K (t) (t − 1) · ∆K(λ−2t) (λ−2t − 1).

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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The details of irreducible metabelian representations

Existence of irreducible metabelian reps. (Nagasato) ♯{the characters of irereducible metabelian reps.} = |∆K (−1)| − 1 2 . ι ∈ H1(EK ; Z2) induces an involution ˆ ι on Hom(π1(EK ), SL2(C))//SL2(C). Remark (Nagasato & Y.) {the characters of irereducible metabelian reps.} = {the fixed point set of ˆ ι} in Hom(π1(EK), SL2(C))//SL2(C). Remark A higher rank analogy was given by H. Boden and S. Friedl.

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Main Theorem (again)

Theorem Suppose that ρ : π1(EK) → SL2(C) s.t. an irred. metabelian and; “longitude–regular”. Then (the twisted Alexander poly.) ∆α⊗Ad◦ρ

EK

(t)

·

= (t − 1)∆K (−t)P(t), where ∆K (t) is the Alexander polynomial of K.

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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The details of ∆α⊗Ad◦ρ

EK

(t)

Homomorphisms ρ : π1(EK ) → SL2(C) is metabelian

⇐ ⇒ ρ([π1(EK ), π1(EK )])(⊂ SL2(C)) is abelian,

Suppose that ρ([π1(EK), π1(EK )]) = {1}. α : π1(EK ) → π1(EK)/[π1(EK ), π1(EK )] ≃ H1(EK ) = t

s.t. α(µ) = t

the twisted Alexander poly. ∆α⊗Ad◦ρ

EK

(t) = det

  • α ⊗ Ad ◦ ρ
  • ∂ri

∂gj

  • i, j=1
  • det (α ⊗ Ad ◦ ρ (g1 − 1))

from a presentation π1(EK) = g1, g2, . . . , gk | r1, . . . , rk−1.

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Main tools

We need a “good” presentation of π1(EK ) for metabelian reps. X-S. Lin introduced a suitable presentation of π1(EK) by using a free Seifert surface of K. a Seifert surface S is free ⇔ S3 = S × [−1, 1] ∪ S3 \ S × [−1, 1] : a Heegaard splitting.

Figure: a free Seifert surface of the trefoil knot

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Main tools

We need a “good” presentation of π1(EK ) for metabelian reps. X-S. Lin introduced a suitable presentation of π1(EK) by using a free Seifert surface of K. a Seifert surface S is free ⇔ S3 = S × [−1, 1] ∪ S3 \ S × [−1, 1] : a Heegaard splitting.

Figure: a free Seifert surface of the trefoil knot

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Main tools

We need a “good” presentation of π1(EK ) for metabelian reps. X-S. Lin introduced a suitable presentation of π1(EK) by using a free Seifert surface of K. a Seifert surface S is free ⇔ S3 = S × [−1, 1] ∪ S3 \ S × [−1, 1] : a Heegaard splitting.

Figure: a free Seifert surface of the trefoil knot

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Main tools

We need a “good” presentation of π1(EK ) for metabelian reps. X-S. Lin introduced a suitable presentation of π1(EK) by using a free Seifert surface of K. a Seifert surface S is free ⇔ S3 = S × [−1, 1] ∪ S3 \ S × [−1, 1] : a Heegaard splitting.

Figure: a free Seifert surface of the trefoil knot

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Lin’s presentation By using a free Seifert surface S with genus 2g, π1(EK ) = µ, x1, . . . , x2g | µa+

i µ−1 = a− i (i = 1, . . . 2g)

where xi is a closed loop corresponding to 1–handle in S3 \ S × [−1, 1], a±

i is a word in x1, . . . , x2g, corresponding to closed loops

in the spine of S.

Figure: a free Seifert surface of the trefoil knot

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Lin’s presentation By using a free Seifert surface S with genus 2g, π1(EK ) = µ, x1, . . . , x2g | µa+

i µ−1 = a− i (i = 1, . . . 2g)

where xi is a closed loop corresponding to 1–handle in S3 \ S × [−1, 1], a±

i is a word in x1, . . . , x2g, corresponding to closed loops

in the spine of S.

Figure: a free Seifert surface of the trefoil knot

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Remark & Examples of Lin’s presentation

Remark The generators x1, . . . , x2g are null–homologous, i.e., xi ∈ [π1(EK ), π1(EK )]. K = trefoil knot π1(EK ) =

  • µ, x1, x2
  • µx1µ−1 = x1x−1

2 ,

µx−1

2 x1µ−1 = x−1 2

  • K = figure eight knot

π1(EK ) =

  • µ, x1, x2
  • µx1µ−1 = x1x−1

2 ,

µx2x1µ−1 = x2

  • Yoshikazu Yamaguchi

The twisted Alexander poly. for metabelian reps.

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Explicit form of metabelian reps.

X-S. Lin, F. Nagasato The correspondence µ → 1 −1

  • ,

xi → ξi ξ−1

i

  • gives a metabelian rep.

They gives all representatives of conj. classes of metabelian reps. ♯ (conj. classes of irred. metabelian reps) = |∆K (−1)| − 1 2 .

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Sketch of proof

Ad ◦ ρ : π1(EK ) → Aut(sl2(C)) = Aut(C 0 1

0 0

  • ⊕ C

1 0

0 −1

  • ⊕ C

0 0

1 0

  • )

µ →   −1 −1 −1   xi →   ξ2 1 ξ−2   The subspace C 1 0

0 −1

  • is invariant space.

Decomposition of Ad ◦ ρ Ad ◦ ρ = ρ2 ⊕ ρ1 where ρ1 is 1–dim. rep. and ρ2 is 2–dim. rep.

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Observation about ∆α⊗Ad◦ρ

EK

(t)

∆α⊗Ad◦ρ

EK

(t) = ∆α⊗ρ2

EK

(t) · ∆α⊗ρ1

EK

(t) = Q(t) · ∆K (−t) (−t − 1) Wada Milnor = (t − 1)(t + 1)P(t) · ∆K(−t) −t − 1 longitude–regular & inv. of conj. for R–torsion = −(t − 1) · P(t) · ∆K (−t). Remark The P(t) satisfies that P(t) = P(−t).

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Details in the proof

The representations ρ1 and ρ2 are given by ρ1 : µ → −1, xi → 1, ρ2 : µ → −1 −1

  • ,

xi → ξ2

i

ξ−2

i

  • .

Wada’s criterion ψ : π1(EK ) → GLn(R), R : UFD If ∃γ ∈ [π1(EK ), π1(EK )] s. t. 1 is not an eigenvalue of ψ(γ), ⇒ ∆α⊗ψ

EK

(t) is a Laurent polynomial. ρ2 : xi → ξ2

i

ξ−2

i

  • (xi ∈ [π1(EK), π1(EK )])

Wada’s criterion − − − − − − − − − − − − − → ∆α⊗ρ2

EK

(t) = Q(t) (Laurent polynomial)

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Decomposition of Q(t)

ρ : longitude-regular ⇒ ∆α⊗Ad◦ρ

EK

(1) = 0, ∆α⊗Ad◦ρ

EK

(1) = Q(1) · ∆K(−1) −2 = 0 ⇒ Q(1) = 0. Set C = √ −1 − √ −1

  • ,

Cρ2C−1 : µ → 1 1

  • = −ρ(µ), xi →

ξ2

i

1 1 ξ−2

i

  • = ρ(xi)
  • inv. of conj.

− − − − − − − − − → Q(t) = Q(−t). Therefore Q(t) = (t − 1)(t + 1)P(t)

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Observation about ∆α⊗Ad◦ρ

EK

(t) (again)

∆α⊗Ad◦ρ

EK

(t) = ∆α⊗ρ2

EK

(t) · ∆α⊗ρ1

EK

(t) = Q(t) · ∆K (−t) (−t − 1) Wada Milnor = (t − 1)(t + 1)P(t) · ∆K(−t) −t − 1 longitude–regular & inv. of conj. for R–torsion = −(t − 1) · P(t) · ∆K (−t). Remark The P(t) satisfies that P(t) = P(−t).

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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Examples

trefoil knot ∆K(t) = t2 − t + 1 (|∆K (−1)|−1

2

= 1).

∃1 irred. metabelian rep. (up to conjugate) Lin presentation π1(EK ) =

  • µ, x1, x2
  • µx1µ−1 = x1x−1

2 ,

µx−1

2 x1µ−1 = x−1 2

  • ρ(µ) =
  • 1

−1

  • , ρ(x1) =

ζ3 ζ−1

3

  • , ρ(x2) =

ζ2

3

ζ−2

3

  • where ζ3 = e

2π√−1 3

⇒ ∆α⊗Ad◦ρ

EK

(t) = (t − 1)∆K(−t).

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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figure eight knot

Figure: a free Seifert surface of the figure eight knot

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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figure eight knot ∆K (t) = t2 − 3t + 1 (|∆K (−1)|−1

2

= 2).

∃2 irred. metabelian reps. (up to conjugate) Lin presentation π1(EK) =

  • µ, x1, x2
  • µx1µ−1 = x1x−1

2 ,

µx2x1µ−1 = x2

  • (1) ρ(µ) =

1 −1

  • , ρ(x1) =

ζ5 ζ−1

5

  • , ρ(x2) =

ζ2

5

ζ−2

5

  • (2) ρ(µ) =
  • 1

−1

  • , ρ(x1) =

ζ2

5

ζ−2

5

  • , ρ(x2) =

ζ4

5

ζ−4

5

  • where ζ5 = e

2π√−1 5

⇒ ∆α⊗Ad◦ρ

EK

(t) = (t − 1)∆K(−t). (the both reps. have the same result)

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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52 knot

Figure: a free Seifert surface of 52 knot

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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52 knot ∆K (t) = 2t2 − 3t + 2 (|∆K (−1)|−1

2

= 3).

∃3 irred. metabelian rep. (up to conjugate) Lin presentation π1(EK ) =

  • µ, x1, x2
  • µx1µ−1 = x1x−1

2 ,

µx−2

2 x1µ−1 = x−2 2

  • (1) ρ(µ) =

1 −1

  • , ρ(x1) =

ζ7 ζ−1

7

  • , ρ(x2) =

ζ2

7

ζ−2

7

  • (2) ρ(µ) =

1 −1

  • , ρ(x1) =

ζ2

7

ζ−2

7

  • , ρ(x2) =

ζ4

7

ζ−4

7

  • (3) ρ(µ) =

1 −1

  • , ρ(x1) =

ζ3

7

ζ−3

7

  • , ρ(x2) =

ζ6

7

ζ−6

7

  • where ζ7 = e

2π √ −1 7 Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.

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(1) ρ(µ) = 1 −1

  • , ρ(x1) =

ζ7 ζ−1

7

  • , ρ(x2) =

ζ2

7

ζ−2

7

∆α⊗Ad◦ρ

EK

(t) = (t−1)(2+e6π

√ −1/7+e−6π √ −1/7)∆K (−t),

(2) ρ(µ) = 1 −1

  • , ρ(x1) =

ζ2

7

ζ−2

7

  • , ρ(x2) =

ζ4

7

ζ−4

7

∆α⊗Ad◦ρ

EK

(t) = (t−1)(2+e2π

√ −1/7+e−2π √ −1/7)∆K (−t),

(3) ρ(µ) = 1 −1

  • , ρ(x1) =

ζ3

7

ζ−3

7

  • , ρ(x2) =

ζ6

7

ζ−6

7

∆α⊗Ad◦ρ

EK

(t) = (t−1)(2+e4π

√ −1/7+e−4π √ −1/7)∆K (−t).

Yoshikazu Yamaguchi The twisted Alexander poly. for metabelian reps.