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Objectives Chapter 23 Sorting To study and analyze time complexity - PDF document

Objectives Chapter 23 Sorting To study and analyze time complexity of various sorting algorithms (23.223.7). To design, implement, and analyze insertion sort (23.2). To design, implement, and analyze bubble sort (23.3).


  1. Objectives Chapter 23 Sorting ✦ To study and analyze time complexity of various sorting algorithms (§§23.2–23.7). ✦ To design, implement, and analyze insertion sort (§23.2). ✦ To design, implement, and analyze bubble sort (§23.3). ✦ To design, implement, and analyze merge sort (§23.4). CS1: Java Programming Colorado State University Original slides by Daniel Liang Modified slides by Chris Wilcox Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All 1 2 rights reserved. rights reserved. Why study sorting? What data to sort? The data to be sorted might be integers, doubles, characters, or Sorting is a classic subject in computer science. There are three objects. §7.8, “Sorting Arrays,” presented selection sort and reasons for studying sorting algorithms. insertion sort for numeric values. The selection sort algorithm was extended to sort an array of objects in §11.5.7, “Example: – First, sorting algorithms illustrate many creative Sorting an Array of Objects.” The Java API contains several approaches to problem solving and these approaches can overloaded sort methods for sorting primitive type values and be applied to solve other problems. objects in the java.util.Arrays and java.util.Collections class. For simplicity, this section assumes: – Second, sorting algorithms are good for practicing fundamental programming techniques using selection data to be sorted are integers, ✦ statements, loops, methods, and arrays. data are sorted in ascending order, and ✦ data are stored in an array. The programs can be easily ✦ – Third, sorting algorithms are excellent examples to modified to sort other types of data, to sort in descending demonstrate algorithm performance. order, or to sort data in an ArrayList or a LinkedList. Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All 3 4 rights reserved. rights reserved.

  2. animation Insertion Sort Insertion Sort Animation int[] myList = {2, 9, 5, 4, 8, 1, 6}; // Unsorted http://www.cs.armstrong.edu/liang/animation/web/Insertio nSort.html The insertion sort Step 1: Initially, the sorted sublist contains the algorithm sorts a list 2 9 5 4 8 1 6 first element in the list. Insert 9 into the sublist. of values by repeatedly inserting Step2: The sorted sublist is {2, 9}. Insert 5 into 2 9 5 4 8 1 6 an unsorted element the sublist. into a sorted sublist Step 3: The sorted sublist is {2, 5, 9}. Insert 4 2 5 9 4 8 1 6 until the whole list into the sublist. is sorted. Step 4: The sorted sublist is {2, 4, 5, 9}. Insert 8 2 4 5 9 8 1 6 into the sublist. Step 5: The sorted sublist is {2, 4, 5, 8, 9}. Insert 2 4 5 8 9 1 6 1 into the sublist. Step 6: The sorted sublist is {1, 2, 4, 5, 8, 9}. 1 2 4 5 8 9 6 Insert 6 into the sublist. Step 7: The entire list is now sorted. 1 2 4 5 6 8 9 Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All 5 6 rights reserved. rights reserved. animation How to Insert? Insertion Sort int[] myList = {2, 9, 5, 4, 8, 1, 6}; // Unsorted The insertion sort [0] [1] [2] [3] [4] [5] [6] algorithm sorts a list list 2 5 9 4 Step 1: Save 4 to a temporary variable currentElement of values by 2 9 5 4 8 1 6 [0] [1] [2] [3] [4] [5] [6] repeatedly inserting 2 9 5 4 8 1 6 list 2 5 9 Step 2: Move list[2] to list[3] an unsorted element [0] [1] [2] [3] [4] [5] [6] into a sorted sublist 2 5 9 4 8 1 6 list 2 5 9 Step 3: Move list[1] to list[2] until the whole list 2 4 5 9 8 1 6 is sorted. [0] [1] [2] [3] [4] [5] [6] list 2 4 5 9 Step 4: Assign currentElement to list[1] 2 4 5 8 9 1 6 1 2 4 5 8 9 6 1 2 4 5 6 8 9 Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All 7 8 rights reserved. rights reserved.

  3. From Idea to Solution From Idea to Solution for (int i = 1; i < list.length; i++) { for (int i = 1; i < list.length; i++) { insert list[i] into a sorted sublist list[0..i-1] so that insert list[i] into a sorted sublist list[0..i-1] so that list[0..i] is sorted list[0..i] is sorted } } Expand list[0] list[0] list[1] double currentElement = list[i]; int k; list[0] list[1] list[2] for (k = i - 1; k >= 0 && list[k] > currentElement; k--) { list[k + 1] = list[k]; } list[0] list[1] list[2] list[3] // Insert the current element into list[k + 1] list[k + 1] = currentElement; list[0] list[1] list[2] list[3] ... Run InsertSort Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All 9 10 rights reserved. rights reserved. Bubble Sort Animation Bubble Sort http://www.cs.armstrong.edu/liang/animation/web/BubbleSort.html 2 9 5 4 8 1 2 5 4 8 1 9 2 4 5 1 8 9 2 4 1 5 8 9 1 2 4 5 8 9 2 4 5 8 1 9 2 4 5 1 8 9 2 5 9 4 8 1 2 1 4 5 8 9 2 5 4 9 8 1 2 4 5 8 1 9 2 4 1 5 8 9 2 5 4 8 9 1 2 4 5 1 8 9 2 5 4 8 1 9 (a) 1st pass (b) 2nd pass (c) 3rd pass (d) 4th pass (e) 5th pass Bubble sort time: O(n 2 ) 2 n n + + + + = ( n 1 ) ( n 2 ) ... 2 1 2 2 Run BubbleSort Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All 11 12 rights reserved. rights reserved.

  4. Merge Sort Merge Sort 2 9 5 4 8 1 6 7 mergeSort(list): split firstHalf = mergeSort(firstHalf); 2 9 5 4 8 1 6 7 divide secondHalf = mergeSort(secondHalf); split 2 9 5 4 8 1 6 7 list = merge(firstHalf, secondHalf); split 2 9 5 4 8 1 6 7 merge 2 9 4 5 1 8 6 7 conquer merge 2 4 5 9 1 6 7 8 merge 1 2 4 5 6 7 8 9 Run MergeSort Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All 13 14 rights reserved. rights reserved. Merge Two Sorted Lists Merge Sort Time Let T(n) denote the time required for sorting an current1 current2 current1 current2 current1 current2 array of n elements using merge sort. Without loss of generality, assume n is a power of 2. The merge 2 4 5 9 1 6 7 8 2 4 5 9 1 6 7 8 2 4 5 9 1 6 7 8 sort algorithm splits the array into two subarrays, sorts the subarrays using the same algorithm 1 2 4 5 6 7 8 1 1 2 4 5 6 7 8 9 recursively, and then merges the subarrays. So, current3 current3 current3 (b) After moving all the (c) After moving 9 to (a) After moving 1 to temp n n = + + elements in list2 to temp temp T ( n ) T ( ) T ( ) mergetime 2 2 to temp Animation for Merging Two Sorted Lists n n = + + T ( n ) T ( ) T ( ) O ( n ) 2 2 Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All Liang, Introduction to Java Programming, Tenth Edition, (c) 2013 Pearson Education, Inc. All 15 16 rights reserved. rights reserved.

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